A gas occupies 49 liters at a pressure of 367 mm Hg. What is the volume when the pressure is increased to 784 mm Hg?

Answer:

they start to decompose

Explanation:

the easiest way to wxplain this is that all organic matter decomposees and turns into nutrients for other organisms, its a cycle. but after an organism dies then it starts to decompose and rot.

Answer:

they begin to rot

Explanation:

Answer:

oxygen

Explanation:

?

Answer:

1. C. Chemical bond

2. A. Chemical reaction

3. Product

4. C. Balanced

5. B. Atoms of the same kind are of equal number on either side of the arrow

Explanation:

A chemical bond is a bond between two or more atoms. There are different types of chemical bonds, but the one that the question is pertaining to is called a covalen bond. A covalent bond occurs when the atoms are sharing electrons.

2. A chemical reaction is characterized by the production of light and/or heat, and a change in color in the product. By definition, it is the process where one or more substances react to produce one or more products.

3. When one or more reactants react with each other, it creates another substance or substances called products. In the case of your question, sodium  reacts with chlorine (these are your reactants), which produces the product sodium chloride, which is a compound.

4. By definition, a balanced equation is an equation where the number of atoms of each element in the reactants are equal to the number of atoms of each element in the product.

ex.

Reactants        Product

Na + Cl      →      NaCl

Na = 1                Na = 1

Cl = 1                 Cl = 1

5. As explained above and shown, you can see that the number of atoms of each element in the reactants is equal to the number of each element in the product. So this means that the equation is balanced.

Answer:

1chemical bond 2chemical reaction 3 reaction 4 atomic 5atoms of the same kind ate not of equal number on either side of the arrow

Answer:

Like a jungle with trees everywhere

Hope This Helps!   Have A Nice Day!!

I would suggest reading Genesis chapter 1 to 2. It'll explain it all.

Answer:Five grams of sugar is mixed with 300 mL of water. In the solution, water would be classified as the —

solvent

Explanation:

It is the solvent because it can dissolve the sugar.

Solvent- able to dissolve other substances.

The sugar has been dissolved in the water, sugar has been considered as solute. The water has been dissolving sugar in itself so it has been considered as solvent.

Since sugar has been dissolved in the water, sugar has been considered as solute. The water has been dissolving sugar in itself so it has been considered as solvent.

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After 104 minutes, or 4 half-lives, of the radioactive isotope zirconium 84 with a half-life of 26 minutes, the remaining quantity from an initial 175-gram sample would be 10.9375 grams.

The question concerns the calculation of the amount of a radioactive substance remaining after a certain period, based on its half-life. In this case, we are looking at zirconium 84, which has a half-life of 26 minutes. To calculate how much of the substance remains after 104 minutes, we need to determine how many half-lives have passed in that time frame. Since 104 minutes is 4 times 26 minutes, that's 4 half-lives.

The amount of substance remaining after each half-life is reduced by 50%. Therefore, after one half-life, we will have 50% of the initial amount, after two half-lives, 25%, and so on. Applying this knowledge:

So after 104 minutes, there would be 10.9375 grams of zirconium 84 remaining.

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Answer:

2.317 kg

Explanation:

Density = mass / vol

Vol = 10 x4 x 3 =120

Density=19.3 gm/cm3

Mass= density x vol =2316 gm or 2.317 kg

Answer: The mass of gold is 2316 grams.

Explanation:

To calculate the volume of cuboid, we use the equation:

[tex]V=lbh[/tex]

where,

V = volume of cuboid

l = length of cuboid = 10 cm

b = breadth of cuboid = 4 cm

h = height of cuboid = 3 cm

Putting values in above equation, we get:

[tex]V=10\times 4\times 3=120cm^3[/tex]

To calculate mass of a substance, we use the equation:

[tex]Density=\frac{Mass}{Volume}[/tex]

Putting values in above equation, we get:

[tex]19.3g/cm^3=\frac{\text{Mass of Gold}}{120cm^3}\\\\\text{Mass of osmium}=2316g[/tex]

Hence, the mass of gold is 2316 grams.

Answer:

1246 mg = 1.246 g.

Explanation:

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 10.6 minutes).

∴ k = ln2/(t1/2) = 0.693/10.6 = 6.54 x 10⁻² min⁻¹.

where, k is the rate constant of the reaction (k = 6.54 x 10⁻² min⁻¹.).

t is the time of the reaction (t = 1.25 hr x 60 = 75.0 min).

a is the initial concentration (original amount) (a = ??? mg).

(a-x) is the remaining concentration (a-x = 9.25 mg).

∴ kt = lna/(a-x)

(6.54 x 10⁻² min⁻¹)(75.0 min) = ln a/(9.25 mg)

4.903 =  ln a/(9.25 mg)

Taking e for the both sides:

134.7 = a/(9.25 mg)

∴ a = (134.7)(9.25 mg) = 1246 mg = 1.246 g.

Answer:

there are no graphs

Explanation:

Answer:

The graph has to switch into the values.

Explanation:

So if you're asked to graph a function and its inverse, all you have to do is graph the function and then switch all x and y values in each point to graph the inverse. Just look at all those values switching places from the f(x) function to its inverse g(x) (and back again), reflected over the line y = x.

Answer:

24.5%

Explanation:

You just add up the atomic masses.  

Ca - 40.078  

Cl2 - 35.4527 x 2 = 70.9054  

------ 110.9834  

H4 - 1.00794 x 4 = 4.03176  

O2 - 31.9998  

------ 36.03056  

TOTAL - 147.01396  

So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%

This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.

Answer: 24.5%

Explanation: Molar mass of CaCl2 * 2 H2O = 40.078 + ( 2 x 35.453) + ( 2 x 18.02)=147.024 g/mol  

% H2O = 2 x 18.02 x 100/ 147.024 =24.5

Answer:

Assume that the initial concentration of both B and C are zero.

Kc = 7.5 × 10⁻³.

Explanation:

What's the expression for the equilibrium constant of this reversible reaction? Note that the steps here apply only to equilibriums where all species are either gaseous (g) or in an aqueous solution (aq). Solids and liquids (water in particular) barely influence the equilibrium; in many cases they should not appear in the expression for the equilibrium constant.

Raise the concentration of each product to their coefficient's power.

The product of these terms will be the numerator in the expression of the equilibrium constant. For this reaction, the numerator shall be [tex][\text{B}]^{2} \cdot[\text{C}][/tex].

Repeat these steps for the reactants:

If there are more than one reactants, multiple each of those terms. The product shall be the denominator of the expression for the equilibrium constant. For this reaction, the denominator shall be [tex][\text{A}][/tex].

Hence the equilibrium constant:

[tex]\displaystyle K_c = \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}[/tex],

where [tex][\text{A}][/tex], [tex][\text{B}][/tex], and [tex][\text{C}][/tex] are concentrations when the reaction is at equilibrium.

Construct a RICE table to find the equilibrium concentration of each species. R stands for reaction, I for initial conditions, C for change in concentration, and E for equilibrium conditions. Assume that only A is initially present in the system. Let the decrease in the concentration of [tex]\text{A}[/tex] be [tex]x\;\text{M}[/tex].

[tex]\begin{array}{c|ccccc}\text{R}&\text{A}\;(g) &\rightleftharpoons &2\;\text{B}\;(g)& +& \text{C}\;(g)\\ \text{I}& 0.071 \;\text{M} & & 0\;\text{M} && 0 \;\text{M} \\ \text{C} &-x \;\text{M}&&+2x\;\text{M} & & +x\;\text{M}\\\text{E}&0.071 - x\;\text{M} && 2x\;\text{M} & &x\;\text{M}  \end{array}[/tex].

The coefficient in front of B is twice that in front of A. In other words, for each unit of A consumed, two units of B are produced. Assume that volume stays the same. The decrease in the concentration of [tex]\text{A}\;(g)[/tex] is [tex]x\;\text{M}[/tex]. Accordingly, the increase in the concentration of [tex]\text{B}\;(g)[/tex] shall be [tex]2x\;\text{M}[/tex].

The question states that the equilibrium concentration of [tex]A\;(g)[/tex] is [tex]0.03195\;\text{M}[/tex].

[tex]0.071 - x = 0.03195[/tex],

[tex]x = 0.03905[/tex].

At equilibrium:

Hence the equilibrium constant.

[tex]\displaystyle \begin{aligned}K_c &= \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}\\&=\frac{{0.0781}^{2} \times 0.03905}{0.03195}\\&=7.5\times 10^{3}\;\text{M}\end{aligned}[/tex].

If the concentration of A at equilibrium is 0.03195M,the equilibrium constant is Kc ≈ 0.0072 (option a).

To begin solving for the equilibrium constant (Kc), we first need to determine the changes in concentrations for each species.

Step-by-Step Solution:

1. Initial and equilibrium concentrations:

Initial concentration of A ([A]i) = 0.071 MEquilibrium concentration of A ([A]eq) = 0.03195 M  

2. Change in concentration for A:

Change in [A] = 0.071 M - 0.03195 M = 0.03905 M

Since the reaction stoichiometry is 1A → 2B + 1C, the change in concentration will also affect B and C:

Change in [B] = 2 × 0.03905 M = 0.0781 MChange in [C] = 0.03905 M

3. Equilibrium concentrations:

Equilibrium concentration of A, [A]eq = 0.03195 MEquilibrium concentration of B, [B]eq = 0.0781 MEquilibrium concentration of C, [C]eq = 0.03905 M

4. Equilibrium constant expression:

The equilibrium constant expression for the reaction A(g) = 2B(g) + C(g) is:

Kc = [B]² [C] / [A]

5. Substituting the equilibrium concentrations:

Kc = (0.0781)² × 0.03905 / 0.03195

6. Calculating Kc:

Kc ≈ 0.0072

Therefore, the equilibrium constant for the reaction is approximately 0.0072.

Complete Question - Before the reaction occurs, the concentration of A is 0.071 M. If the concentration of A at equilibrium is 0.03195 M, what is the equilibrium constant? A(g) = 2B(g) + C(g) Select the correct answer below:

a. Kc - 0.0072

b. Kc - 0.095

c. Kc - 14

d. Kc - 130

Answer: Capillary walls main function is to exchange materials between the blood and tissue cells, While Arteries carry blood away from the heart to parts of your body like your lungs for instance, and your Veins carry blood back to your heart.

I hope this helps :)

Explanation:

Answer:

A chemical equation that is balanced will help you to determine how much product they will produce from their reactants.

Hope this helps :)

Have a great day !

5INGH

Explanation:

Answer:

= 10 M or 10 moles/liter

Explanation:

Molarity is calculated by the formula;

Molarity = Moles/volume in liters

In this case;

The number of moles = 0.5 moles

Volume = 0.05 liters

Therefore;

Molarity = 0.5 moles/0.05 liters

             = 10 M or 10 moles/liter

Thus the molarity is 10 M or 10 moles/liter

Final answer:

To calculate the molarity, divide the number of moles of sodium chloride (0.5 moles) by the volume of the solution in liters (0.05 liters), resulting in a molarity of 10 M for the NaCl solution.

Explanation:

The question relates to the concept of molarity, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution. The student's question involves calculating the molarity given a certain amount of solute (sodium chloride, NaCl) and the volume of the resulting solution. To calculate molarity, you would divide the number of moles by the volume in liters. In the case of the student's question, if 0.5 moles of NaCl are dissolved to make 0.05 liters of solution, the calculation would be:

Molarity = moles of solute / liters of solution

Molarity = 0.5 moles / 0.05 liters

Molarity = 10 M (molar)

This result indicates a 10 M NaCl solution, which signifies a highly concentrated solution.

Answer:

I. Kindly, see the attached image.

II. The reaction is exothermic.

III. - 51.88 kJ/mol.

IV. The reaction is spontaneous.

Explanation:

I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

Kindly see the attached image to show you the potential energy diagram of the reaction.

II. Is the reaction endothermic or exothermic? Explain your answer.

If the sign is positive, the reaction is endothermic.

If the sign is negative, the reaction is exothermic.

Herein, ΔH = - 33.1 kJ/mol, so the reaction is exothermic.

III. What is the Gibbs free energy of the reaction at 25°C?

∵ ΔG = ΔH - TΔS.

Where, ΔG is the Gibbs free energy change (J/mol).

ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).

T is the temperature (T = 25°C + 273 = 298 K).

ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).

∴ ΔG = ΔH - TΔS = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = - 51.88 kJ/mol.

IV. Is the reaction spontaneous or nonspontaneous at 25°C?

The sign of ΔG indicates the spontaneity of the reaction:

If ΔG < 0, the reaction is spontaneous.

If ΔG = 0, the reaction is at equilibrium.

If ΔG > 0, the reaction is nonspontaneous.

Herein, ΔG = - 51.88 kJ/mol, so the reaction is spontaneous.

The reaction NO2(g) → N2(g) + O2(g) is exothermic as indicated by the negative ΔH. The Gibbs free energy (ΔG) at 25°C is calculated to be -51.9996 kJ/mol, which signifies that the reaction is spontaneous at this temperature.

For the reaction NO2(g) → N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS = 63.02 J/(mol·K):

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After trapping its prey, the plant turns into a external stomach, sealing the trap so no air gets in or out. The digestion takes several days depending the size of the insect, and then the leaf re-opens.

Answer:

= 36.185 °C

Explanation:

Using the combined gas law;

P1V1/T1 = P2V2/T2

In this case;

P1 = 0.87 atm

V1 = 6.0 cm³

T1 = ?

P2 = 0.52 atm

V2 = 10 cm³

T2 = 35 °C + 273 = 308 K

Therefore;

T1 = P1V1T2/P2V2

   = ( 0.87 × 6.0 × 308)/( 0.52 ×10)

   = 309.185 K

Therefore; Initial temperature = 309.185 K - 273 = 36.185 °C

Answer:

63.86 mg

Explanation:

Molar mass is the mass of 1 mol of compound / atom.

molar mass of the compound is - 310 g/mol

mass of 1 mol is - 310 g

therefore mass of 2.06 x 10⁻⁴ mol is - 310 g/mol x 2.06 x 10⁻⁴ mol = 0.06386 g

mass of calcium phosphate is - 63.86 mg

Final answer:

To find the mass of 2.06 x 10⁻⁴ moles of calcium phosphate (Ca₃(PO₄)₂), calculate the formula mass using atomic masses of calcium, phosphorus, and oxygen. The formula mass of calcium phosphate is 310.18 g/mol. Multiplying this by the moles gives you 0.0639 grams of calcium phosphate.

Explanation:

To calculate the mass in grams of 2.06 x 10⁻⁴ moles of calcium phosphate (Ca₃(PO₄)₂), you must know the formula mass of calcium phosphate. The empirical formula indicates the compound contains three calcium ions (Ca⁺²) and two phosphate ions (PO₄⁻³). The formula mass is calculated by adding together the atomic masses of the constituent atoms: three calcium atoms, two phosphorus atoms, and eight oxygen atoms.

The atomic masses are approximately 40.08 g/mol for calcium, 30.97 g/mol for phosphorus, and 16.00 g/mol for oxygen. Calculating the formula mass, we have:

3(Calcium) + 2(Phosphorus) + 8(Oxygen) = 3(40.08 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 310.18 g/mol

Now, to find the mass of 2.06 x 10-4 moles of calcium phosphate:

2.06 x 10⁻⁴ moles x 310.18 g/mol = 0.0639 grams

Therefore, there are 0.0639 grams of calcium phosphate in 2.06 x 10⁻⁴ moles of the compound.

Answer:

12.11.

Explanation:

∵ pOH = - log[OH⁻]

∴ pOH = - log(1.3 x 10⁻²) = 1.886.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.886 = 12.11.

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of  CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

Answer:

c) 10 millimeters (mm)

Explanation:

The unit conversions are as follows:

1 cm = 10 mm (millimeter)

1 cm = 0.01 m (meter)

1 cm = 0.00001 km (kilometer)

1 cm = 10000 μm (micrometer)

Based on the above conversions:

[tex]0.1 cm = \frac{10 mm*0.1 cm}{1 cm} = 0.1 mm[/tex]

[tex]0.1 cm = \frac{0.01 m*0.1 cm}{1 cm} = 0.001 m[/tex]

[tex]0.1 cm = \frac{0.00001 km * 0.1 cm}{1 cm} = 0.000001 km[/tex]

[tex]0.1 cm = \frac{10000 um*0.1cm}{1 cm} =1000 um[/tex]

Therefore, 0.1 cm = 10 mm is incorrect instead it is 0.1 mm

Answer:

Explanation:

the Americans maintained their control of Bunker Hill.

the British army sustained heavy casualties.

the Americans forced British soldiers to retreat to Boston.

the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because

the Americans maintained their control of Bunker Hill.

the British army sustained heavy casualties.

the Americans forced British soldiers to retreat to Boston.

the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because

The answer should be 3 moles of Carbon.

To convert the number of atoms of carbon to moles, divide the given number of atoms by Avogadro's number, which is 6.022 × 10^23 particles per mole. In this case, there are approximately 3 moles of carbon.

To find the number of moles of carbon from the given number of atoms, we can use Avogadro's number. Avogadro's number is defined as 6.022 × 1023 particles per mole.

So, to convert the number of atoms of carbon to moles, we divide the given number of atoms by Avogadro's number:

Number of moles of carbon = (Number of atoms of carbon) / (Avogadro's number)

Plugging in the given values, we have:

Number of moles of carbon = (1.806 × 1024 atoms of carbon) / (6.022 × 1023 atoms/mol) ≈ 3 moles of carbon

The climate most likely found in a high-pressure belt is a dry climate. An example of a high-pressure belt with a dry climate is the subtropical high-pressure belt.

The climate most likely found in a high-pressure belt is a dry climate.

High-pressure systems are associated with sinking air, which inhibits the formation of clouds and precipitation. These areas tend to have clear skies and little moisture, resulting in dry conditions.

An example of a high-pressure belt with a dry climate is the subtropical high-pressure belt found around 30 degrees latitude in both the Northern and Southern Hemispheres, such as the Sahara Desert or the Mojave Desert.

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Answer:

The solution is basic.

Explanation:

We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):

no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.

no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.

∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).

So, the solution is: basic.

Answer:

mole fraction of NaCl = 0.03145.

mole fraction of water = 0.9686.

Explanation:

mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).

no. of moles of NaCl = mass/molar mass = (6.87 g)/(58.44 g/mol) = 0.1176 mol.

no. of moles of water = mass/molar mass = (65.2 g)/(18.0 g/mol) = 3.622 mol.

∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.

∵ mole fraction of NaCl + mole fraction of water = 1.0.

∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.

Answer:

Nitrate is a polyatomic ion with the molecular formula NO⁻₃ and a molecular mass of 62.0049 u. Organic compounds that contain the nitrate ester as a functional group are also called nitrates.

The color of the precipitate intensifies on moving from well 1 to well 9, as there has been an increased concentration of reactant and thereby the product.

Thus, for the copper hydroxide moving from well 1 to well 9, the blue color intensifies.

Thus, for the iron hydroxide moving from well 1 to well 9, the blue color intensifies.

Thus, for the ferric hydroxide moving from well 1 to well 9, the red-orange color intensifies.

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Answer:

16 Molarity

Step-by-step:

M= mols/L

M= 8mols/.5L

M= 16 Molarity

Answer:

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]

Moles of NaOH = 8 moles

Volume of the solution = 0.5 L

[tex]Molarity=\frac{8 mol}{0.5 L}=16.0 M[/tex]

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.

The molar mass of Aluminium Chlorate is 277.3351

The molar mass of Aluminium Chlorate is 277.3351.

The molar mass of Aluminium Chlorate is 277.3351.

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Answer:

C₄H₈ + Br₂ → C₄H₈Br₂

Explanation:

To balance a chemical equation, you need to ensure that the number of each element in the reactant side, matches the number of each element on the product side.

 Reactants                   Product

C₄H₈ + Br₂         →          C₄H₈Br₂

C = 4                                 C= 4

H = 8                                 H= 8

Br = 2                                Br = 2

Since they match up on both sides, the chemical equation is balanced, so we keep it as is.

Answer:

blank for all

Explanation:

Answer:

Thermal decomposition reaction.

Explanation:

Solid mercury(II) oxide is decomposed with heating into liquid mercury and oxygen gas. This reaction takes place at a 600-700°C.

The balanced chemical reaction is:

2HgO  →  2Hg  +  O₂.

Considering the definition of decomposition reaction, the reaction HgO → Hg + O₂ is a thermal decomposition reaction.

A single substance decomposes through a reaction called decomposition, producing two or more diferent compounds. That is, in this type of reaction two or more compounds are formed from a compound.

The atoms that make up a compound are separated to give the products according to the formula:

AB → A + B

This type of reaction can occur spontaneously or caused by certain external factors, such as heat. So, there are 3 types of decomposition reactions:

The reaction HgO → Hg + O₂ is a thermal decomposition reaction where mercuric oxide (HgO) decomposes on heating to give mercury (Hg) and oxygen (O₂​).

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