A force of 40 Newtons is applied to a mass resulting in an acceleration of 8 m/s2What force would need to be applied to this mass to cause an acceleration of 25 m/s2?

Final answer:

The best inference is that Mr. F's body is raising blood pressure by increasing blood volume with all the fluid intake and increasing heart rate. Something may be wrong with his blood volume.

Explanation:

The best inference from the given scenario is option D: His body is raising blood pressure by both increasing blood volume with all this fluid intake and increasing heart rate. Something may be wrong with his blood volume.

When Mr. F takes in a lot of fluid but puts out very little, it suggests that his body is retaining fluid. The increased fluid intake is causing an increase in blood volume, which in turn raises blood pressure. The slight increase in heart rate is also a compensatory mechanism to maintain adequate blood flow.

A fluid twice as dense as mercury would rise to approximately half the height of mercury in a barometer under normal sea-level conditions. This is due to the relation between hydrostatic pressure, density, and height of the fluid column.

Under normal sea-level conditions, atmospheric pressure supports a column of mercury about 760 mm high. This occurs due to the hydrostatic pressure, which is essentially the pressure exerted by a fluid due to gravity. In the case of a liquid twice as dense as mercury, the height of the liquid column would be half that of mercury under the same conditions. This is because the hydrostatic pressure is directly proportional to the density and height of the fluid column, which implies that for a given pressure, if we increase the density, the height decreases correspondingly. So, a liquid twice as dense as mercury would rise to approximately 380 mm in the barometer.

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The magnitude of the force is 990 N

Explanation:

The work done by a force on an object is given by:

[tex]W=Fd cos \theta[/tex]

where

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

In this problem, we have the following:

W = 3500 J (work done by Max)

d = 5 m (displacement)

[tex]\theta=45^{\circ}[/tex] (direction at which the force is applied)

Solving for F, we find the magnitude of the force:

[tex]F=\frac{W}{dcos \theta}=\frac{3500}{(5)(cos 45^{\circ})}=990 N[/tex]

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To find the force Max exerts while moving the Pacman arcade game, use the formula Work = Force x Distance x cos(θ). Solve for force, giving Force = Work / (Distance x cos(θ)). Substituting the given values into the formula will provide the answer.

The work done can be used in the equation that relates work, force, and displacement to identify the force exerted by Max. The relationship between these concepts is expressed as: Work = Force x Distance x cos(θ), where 'θ' is the angle at which the force is applied.

In this scenario, the work done (W) is 3,500 joules, the distance (d) is 5 meters, the angle (θ) is 45 degrees, and the force (F) is what we're trying to find.

Rearranging the formula to solve for Force, we get: Force = Work / (Distance x cos(θ)).

Substituting the given values and doing the math, Max's exerted force will be calculated. The cos(45) is approximately 0.7071, and substituting this in our formula might aid us in accurately finding the force exerted by Max while moving the Pacman arcade game.

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Answer:

constant deceleration required is 9 m/s²

Explanation:

Data provided in the question:

Initial Speed of the driver = 41 mph = 60 ft/s

Stopping distance = 200 ft

Now,

Since the car stops after 200 ft therefore final speed, u = 0 ft/s

from the Newton's equation of motion

we have  

v² - u² = 2as

where,  

v is the final speed  

u is the initial speed  

a is the acceleration

s is the distance

thus,

0² - 60² = 2a(200)

or

-3600 = 400a

or

a = - 9 m/s²

here, negative sign means deceleration

Hence,

The constant deceleration required is 9 m/s²

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 208 m/s

        Acceleration, a = -9.81 m/s²  

        Time, t = 8.9 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 208 x 8.9 + 0.5 x -9.81 x 8.9²

                      s = 1462.68 m

      Displacement after 8.9 seconds  is 1462.68 m

Answer:

A technique in MRA where signal intensity depends on the direction of flow and thus requires gradient application in all three planes for proper signal acquisition is: Phase-contrast (PC-MRA)

Phase-contrast magnetic resonance imaging MRA  is a technique used in moving blood flow, where its speed is encoded in the magnetic resonance signal's phase after the applying bipolar gradient along any axis and the measurement point.

Explanation:

In this technique the bipolar gradient is manipulated varying its magnetic fields to be preset to a maximum expected flow velocity and it´s applied along any axis or axes depending on the direction along which flow is to be measured to get a reversed image of the bipolar gradient and the difference of the two images is calculated. The unaffected phase accrued during the application of the gradient, is 0 for stationary spins.  Since phase-contrast can only acquire flow in one direction at a time, 3 separate image acquisitions in all three directions must be computed to give a complete quantitative measurements of blood flow.  

Although this technique is slow,its strength lays in the possibility of calculating spins moving with a constant velocity of the applied bipolar gradient.  The accrued phase is proportional to both and the 1st moment of the bipolar gradient, thus providing a means to estimate gamma is the Larmor frequency of the imaged spins on moving tissues such as blood, which acquire a different phase since it moves constantly through the gradient, thus also giving its speed of the flow.

Answer:

1. (a)strongly attractive

2 (c) weakly attractive.

Explanation:

Consider three plastic balls (A, B, and C), each carrying a uniformly distributed charge equal to either +Q, -Q or zero, and an uncharged copper ball (D). A positive test charge (T) experiences the forces shown in the figure when brought very near to the individual balls. The test charge T is strongly attracted to A, strongly repelled from B, weakly attracted to C, and strongly attracted to D.

should be the concluding part to this question as presented above

1. What is the nature of the force between balls A and B?

a) strongly attractive.

b) strongly repulsive.

c) weakly attractive.

d) neither attractive nor repulsive.

since there is an attractive force between ball A and the test charge, the charge on ball A must be negative

A = -Q

since ball B is repulsive to the test charged , then B must be positively charged

B = +Q

since A is negative and B is positive , then they will experienced a  strong attraction

option A

2. What is the nature of the force between balls A and C?

a) strongly attractive.

b) strongly repulsive.

c) weakly attractive.

d) neither attractive nor repulsive .

Since C is weakly attracted to the test charge, we can say that Ball C will be weakly attracted to A, because it possess some weka charges

option C

Answer:its c trust me

Explanation:

Answer:

(a) Horizontal component of the launch velocity = 60.7m/s

(b) Vertical component of the launch velocity = 56.0m/s

Explanation:

Initial Kinetic Energy = (IKE)= 1670J, mass (m) = 0.49kg, hmax = 160m

IKE = 1/2mu^2

1670×2/0.48 = u^2

u^2 = 6816.3

u = √6816.3 = 82.6m/s

hmax = u^2sin^2A/2g

160×2×9.8/6816.3 = sin^2A

Sin^2A = 0.46

SinA = √0.46 = 0.6782

A = inverse (sin 0.6782)

A = 42.7° (angle of inclination to the horizontal)

(a) Horizontal component (Ux) = ucosA = 82.6×cos42.7° = 82.6×0.7349 = 60.7m/s

(b) Vertical component (Uy) = usinA = 82.6×sin42.7° = 82.6×0.6782 = 56.0m/s

To find the horizontal and vertical components of the projectile's launch velocity, use the principle of conservation of energy.

To find the horizontal and vertical components of the projectile's launch velocity, we'll use the principle of conservation of energy. The projectile's initial kinetic energy is equal to its potential energy at its maximum displacement.

The projectile's initial kinetic energy is given as 1670 J. At the maximum displacement of 160 m, the potential energy is given as m*g*h, where m is the mass of the projectile (0.49 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the maximum displacement (160 m).

Using these values, we can solve for the vertical component of the launch velocity using the equation for potential energy: m*g*h = 0.49 kg * 9.8 m/s^2 * 160 m. The horizontal component of the launch velocity remains unchanged throughout the projectile's motion.

Answer:

Third-degree price discrimination

Explanation:

Third degree price discrimination according to Investopedia.com occurs when companies price products and services differently based on the unique demographics of subsets of its consumer base, such as students, military personnel, or seniors.

Answer: D) 35.7km × 1 mile/1.609 km

Explanation:

Given that;

We need to convert 35.7km to miles

And we know that 1.609km makes 1 mile = 1.609km/1mile

To convert it to mile we need to obtain the number of miles per kilometre

= 1/(1.609km/mile)

= 1mile/1.609km

Then we can now multiply the conversion rate by the number.

= 35.7km × 1mile/1.609km

= 22.19 miles

Note that the sign must cancel out to give miles.

Final answer:

The gravitational acceleration on planet X is approximately 34.4 m/s².

Explanation:

The gravitational acceleration on planet X can be determined using the equation:

g = (G * M) / r^2

Where:
g is the gravitational acceleration
G is the gravitational constant (approximately 6.674 × 10^-11 N m^2/kg^2)
M is the mass of the planet
r is the radius of the planet

Since the diameter of planet X is 3 times the diameter of Earth, its radius would be 1.5 times that of Earth. The mass of planet X is 30 times the mass of Earth.

Let's assume the radius of Earth (rE) is 6371 km and the mass of Earth (ME) is 5.972 x 10^24 kg.

Using these values, the radius of planet X (rX) would be 1.5 * rE = 9556.5 km, and the mass of planet X (MX) would be 30 * ME = 1.7916 x 10^26 kg.

Now, we can plug these values into the equation to calculate the gravitational acceleration on planet X:

gX = (G * MX) / rX^2

gX = (6.674 x 10^-11 N m^2/kg^2 * 1.7916 x 10^26 kg) / (9556.5 km)^2

Converting km to meters and solving for gX gives us approximately 34.4 m/s².

Answer:

option (A)

Explanation:

Torque is defined as the

Torque = Force x distance x SinФ

Where, Ф is the angle between force vector and the displacement

In case I:

torque = F x r x Sin 90 = F x r

In case II:

Torque = F x r x Sin 60 = 0.866 F r

So, the torque is more in first case.

Thus, option (a) is correct.

Answer:

4.8063m

Explanation:

Horzontal range is given by the formula;

R=(u²sin2θ)/g

u=7m/s,  θ=53°, g=9.8m/s

[tex]R=\frac{7^{2}sin2*53 }{9.8}[/tex]

[tex]R=\frac{7^{2}sin106 }{9.8}[/tex]

[tex]R=\frac{49*sin2*53 }{9.8}[/tex]

[tex]R=\frac{47.102 }{9.8}[/tex]

R=4.8063m

A rock thrown at an angle of 53 degrees with an initial speed of 7.0 m/s from a 50-m-height cliff will hit the ground approximately 8.3 meters away from the base of the cliff.

The problem regards the range of a projectile which is given by the formula R = (v²/g) * sin(2*Theta), where v is the initial velocity, g is the acceleration due to gravity, and Theta is the launch angle. Given the initial velocity v = 7.0 m/s, launch angle Theta = 53 degrees, and g = 9.8 m/s², it's a matter of substituting these values into the range formula: R = ((7.0 m/s)² / 9.8 m/s²) * sin(2 * 53 degrees).

After performing the calculations, you obtain that the rock will hit ground approximately 8.3 meters away from the base of the cliff.

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The particle with both forces acting on it will move at constant velocity

Explanation:

We can solve this problem by applying Newton's second law of motion, which states that the net force acting on a body is equal to the product between its mass and its acceleration:

[tex]F=ma[/tex]

where

F is the net force

m is the mass

a is the acceleration

For the particle in this problem, initially it has a forward force of

[tex]F_1 = 10 N[/tex]

Later, it encounters a second additional force in the opposite direction, therefore

[tex]F_2 = -10 N[/tex]

This means that the net force on the particle now is

[tex]F=F_1+F_2 = +10 +(-10) = 0[/tex]

As a consequence, the acceleration of the particle is zero:

[tex]a=0[/tex]

And this means that the particle moves with constant velocity.

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The particle will not accelerate due to the offsetting forces, it will maintain a constant velocity or remain at rest, pursuant to Newton's Third Law of motion.

In the realm of Physics, the scenario outlined is a classic representation of Newton's Third Law of motion, which states that 'every action has an equal and opposite reaction'. Here, a particle is initially accelerated by a 10-N force. Then, it encounters a second force of the same magnitude but in the opposite direction. Essentially, these two forces cancel each other out because they are equal in magnitude, but opposite in direction. Therefore, the particle with both forces acting on it will not accelerate and will maintain a constant velocity, assuming it had a nonzero velocity to begin with. If it was initially at rest, it will remain at rest.

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Answer:

1/2

Explanation:

This will lead us to simultaneous equation since there are two person involved doing the same job each day.

For Ted;

Since Ted can wax 8 cars or wash 10 cars in a day. Mathematically, we have

8x + 10w = 1... (1)

Where x is for waxing cars, w is for washing cars

Similarly for Tom,

Tom can wax 3 cars or wash 5 cars in a day as well, this gives us;

3x + 5w = 1... (2)

Equating 1 and 2, we have;

8x + 10w = 1... (1)

3x + 5w = 1... (2)

Using elimination method, we will multiply eqn 1 by 3 and eqn 2 by 8 to have;

24x + 30w = 3

24x + 40w = 8

Subtracting eqn 4 from 5 we have;

30w - 40w = 3 - 8

-10w = -5

w = 5/10

w = 1/2

Therefore each man's opportunity cost of washing a car is 1/2

Answer:

3.33 m/s

Explanation:

given,

mass of bullet, m = 20 g = 0.02 Kg

speed of bullet, v = 250 m/s

mass of rifle, M = 1.5 kg

speed of recoil, u = ?

initial speed of the bullet and the rifle is zero.

using conservation of momentum

(M + m) V = m v +  M u

(M + m) x 0 = 0.02 x 250 +  1.5 x u

 1.5 u = -5

   u = -3.33 m/s

negative sign represent that the recoil velocity is opposite to bullet velocity.

Hence, the recoil velocity is equal to 3.33 m/s

The altitude of a geosynchronous orbit is [tex]3.59\cdot 10^7 m[/tex]

Explanation:

A geostationary (or geosynchronous) orbit is the orbit of a satellite that stays over the same spot on the equator of the rotating Earth.

This means that the period of a geostationary satellite is equal to the period of rotation of the Earth, which is 24 hours:

[tex]T=24 h \cdot 3600 s/h = 86400 s[/tex]

We can find the altitude of the orbit in the following way. First, we notice that the orbital speed of the satellite is given by

[tex]v=\frac{2\pi r}{T}[/tex]

where r is the radius of the orbit.

Then we also notice that the gravitational force between the satellite and the Earth is equal to the centripetal force, so we can write:

[tex]\frac{GMm}{r^2}=m\frac{v^2}{r}[/tex]

where

G is the gravitational constant

M is the mass of the Earth

m is the mass of the satellite

Re-arranging the equation,

[tex]\frac{GM}{r}=v^2[/tex]

And substituting the expression for the velocity,

[tex]\frac{GM}{r}=(\frac{2\pi r}{T})^2=\frac{4\pi^2 r^2}{T^2}[/tex]

Solving for r,

[tex]r=\sqrt[3]{\frac{GMT^2}{4\pi^2}}[/tex]

And substituting:

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}\\M=5.98\cdot 10^{24} kg\\T=86400 s[/tex]

we find:

[tex]r=\sqrt[3]{\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(86400)^2}{4\pi^2}}=4.225\cdot 10^7 m[/tex]

And since the radius of the Earth is

[tex]R=6.37\cdot 10^6 m[/tex]

The altitude of the satellite is

[tex]h=r-R=4.225\cdot 10^7 - 6.37\cdot 10^6 = 3.59\cdot 10^7 m[/tex]

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A satellite in a synchronous orbit stays over a certain spot on the equator as the Earth rotates beneath it. The altitude of a synchronous orbit can be calculated using the formula: altitude = (radius of the Earth) + (height of the geostationary orbit), which gives an altitude of approximately 42,157 kilometers.

In order for a satellite to stay over a certain spot on the equator of Earth, it needs to be in a synchronous orbit. A synchronous orbit is an orbit in which the satellite's orbital period matches the rotation period of the Earth. This means that the satellite stays above the same spot on the equator as the Earth rotates beneath it.

The altitude of a synchronous orbit can be determined using the formula:

altitude = (radius of the Earth) + (height of the geostationary orbit)

The radius of the Earth is approximately 6,371 kilometers, and the height of the geostationary orbit is approximately 35,786 kilometers. So the altitude of a synchronous orbit is:

altitude = 6,371 km + 35,786 km = 42,157 km

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Answer:

The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. RTT = 2.56s

Explanation:

Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m

Speed of data travel = speed of light ≈ 3 x 10⁸m/s

As, v=d/t

t=d/v

[tex]t=\frac{3.85*10^{8} }{3*10^{8}}[/tex]

t=1.28s

RTT = Double of single way time taken = 2x1.28

RTT=2.56s

Answer:

he diameter of the oil slick is 2523 m

Explanation:

given information?

V = 1 L = 1000 cm³ = 0.001 m³

h = 2 x 10⁻¹⁰ m

first we have to find the radius using the following equation

V = πr²h

r = √V/(πh)

  = √(0.001)/(π x 2 x 10⁻¹⁰ )

  = 1261.56 m

now, we can calculate the diameter of the oil slick

d = 2r

  = 2 (1261.56)

  = 2523 m

To estimate the diameter of oil slick, we can calculate the volume of one oil molecule and then divide the total volume of the spilled oil by the volume of one molecule. The diameter of the oil slick would be the diameter of one molecule multiplied by the square root of the number of oil molecules.

To estimate the diameter of the oil slick, we can first calculate the volume of one oil molecule. The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius. Given the diameter of the oil molecule is 2 × 10-10 m, the radius would be half of that, which is 10-10 m. Plugging in the values, we get V = (4/3)π(10-10)^3 = 4.19 × 10-29 m3.

The total volume of the spilled oil is given as 1000 cm3, which is equal to 1000 × 10-6 m3. To find the number of oil molecules in the spilled oil, we can divide the total volume of oil by the volume of one molecule: 1000 × 10-6 m3 / 4.19 × 10-29 m3 = 2.39 × 1022.

Since the oil slick is one molecule thick, the diameter of the slick would be the diameter of one oil molecule multiplied by the square root of the number of oil molecules: 2 × 10-10 m × √ (2.39 × 1022) ≈ 4.89 × 106 m.

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Answer:

Direction

Explanation:

The arrival of seismic waves namely P and S wave are essential as it helps in the determination of the distance from the recording seismic station. In order to cover all the possibilities that are related to an earthquake, seismologists draw a circle around the station but this does not help in obtaining the proper information. By the use of two seismic stations, it can draw two circles that intersect at two points, which again does not help in determining the exact epicenter location. So, at least three seismic stations are needed, by which the triangulation method can be implemented, and as the three circles drawn from the three seismic stations intersect at one common point, it represents the exact location of the earthquake epicenter, and the exact direction also is obtained from this.

Answer:

Preassure plate

Explanation:

The flywheel, clutch disc, pressure plate, throw-out bearing clutch fork, and the pilot bearing are the components of a clutch. It works when the flywheel bolts onto the crankshaft and therefore the pressure plate bolts back into the flywheel.

I hope you find this information useful and interesting! Good luck!

A) The change in internal chemical energy is [tex]1.15\cdot 10^7 J[/tex]

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

[tex]P=Fv[/tex]

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

[tex]P=(80)(8.0)=640 W[/tex]

The energy output is related to the power by the equation

[tex]P=\frac{E}{t}[/tex]

where:

P = 640 W is the power output

E is the energy output

[tex]t = 30 min \cdot 60 = 1800 s[/tex] is the time elapsed

Solving for E,

[tex]E=Pt=(640)(1800)=1.15\cdot 10^6 J[/tex]

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

[tex]\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J[/tex]

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

[tex]E=1.15\cdot 10^7 J[/tex]

Here we want to find the time t' needed to convert an amount of chemical energy of

[tex]E'=3.8\cdot 10^5 J[/tex]

So we can setup the following proportion:

[tex]\frac{t}{E}=\frac{t'}{E'}[/tex]

And solving for t',

[tex]t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min[/tex]

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Answer:

The steam engine of James watt is more efficient than Newcomen ans more suitable for the industrial revolution.

Explanation:

James Watt is more widely know for working steam engine because Watt has created better engine which is suitable for the industrial revolution. The steam engine of James watt is more efficient than Newcomen. Watt developed the condensing arrangement by using piston which lessen the initial pressure leading to effectively worked than Newcomen's

The steam engine made by James Watt has a separate condenser from the original design which increases the efficiency of the engine.

A machine that converts hot steam and heat energy into work is called the steam engine.

Thomas Newcomen invented the first useful steam engine in 1712. The Newcomen's engine was used to pump water out of mines.

James Watt came up with a revolution in the steam engine in 1765. He invented a steam engine with a separate condenser. A steam engine with a separate condenser results in improved efficiency and the size of the engine is reduced as compared to the previous design. The engine uses less coal.

Hence we can conclude that the steam engine invented by James Newcomen is more efficient as compared to the engine invented by Thomas Newcomen.

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Answer:

E

Explanation:

Using Coulomb's law equation

Force of the charge = k qQ /d²

and E = F/ q

substitute for F

E = ( K Qq/ d² ) / q

q cancel q

E = KQ / d²

so twice  the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²

Answer:

4.18 kg.

Explanation:

Work done: Work is said to be done when ever a force move a body through a given distance. The S.I unit of work done is Joules (J)

Mathematically, work done is expressed as

W' = F×d.................... Equation 1

Where W' = work done, F = force , d = distance.

making F the subject of the equation,

F = W'/d............................. Equation 2

Note: The force need to lift the small dog n a basket = combined weight of the dog ans the basket.

Therefore,

W = F

Where W = combined weight of the dog and the basket.

Also

W = Mg

M = W/g............................. Equation 3

Where M = combined mass of the dog and the basket, g = acceleration due to gravity.

Given: W' = 201 J, d = 4.90 m.

Substitute into equation 2

F = 201/4.9

F = 41.02 N.

Since F = W = 41.02 N and g = 9.81 m/s²

Substitute these values into equation 3

M = 41.02/9.81

M = 4.18 kg.

Thus the combined mass of the dog and the basket = 4.18 kg.

Answer:

B > C > A > D

Explanation:

As we see four pairs of bees; conducting spheres; it seems as below

A down 4

B up 8

C down 6

D down 3

so

B > C > A > D

Answer: The results are Documented and published.

Explanation: The process of surveying, recording,mapping,and post-excavation analysis are activities that has to do with Real estates like Lands. All these activities must be documented and published according to the enabling laws guiding it,in all the States of the Federation their are Archeological guidelines which clearly states how all this activities are to be conducted.

Answer:

def print_Grade(grade):

print("Grade: ",grade)

Explanation:

The above code segment is a function that takes grade as a string parameter and returns nothing.

The line 1 starts with def keyword.

The keyword is used to start a function and the function will be uniquely identified with it.

The name of the declared function is print_Grade

Variable grade is then declared along with the function.

Line 2 prints "Grade: " without the strings along with the value of grade variable.

The code segment is written in Python

To define a function named printGrade that takes a string parameter and prints 'Grade: ' followed by the string, you'd create a function in a programming language like Python without a return statement, which outputs the concatenated string.

In programming, when you are asked to write the definition of a function like printGrade, which takes a string parameter and prints it with some additional text, you are essentially writing a small part of a program. For example, in Python, a simple function that meets the requirements might look like this:

This function definition includes the name printGrade, a single parameter grade, and a body that executes the print statement, which is returning nothing. When you call printGrade with a string argument, it will output the text "Grade: " concatenated with the string provided as an argument to the function.

The type of material makes up the functional aspect of the transducer that creates the high-frequency sound is Crystals which is a ceramic.

Explanation:

High frequency of sound can be produced in the transducer with the help of materials like ceramic materials.These are non-metallic compounds.  The ceramic materials are those that are brittle in nature. Crystals, glasses are some of the examples of ceramic materials.

Ceramic materials like crystals are used in transducers that makes them functionally fit to produce high frequency sounds. The materials that are given in the options tungsten, iron oxide and silver/chromium alloy are not fit for these type of materials manufacturing. These belongs to metals and metal oxides and alloy types of metals.

Explanation:

Let east be positive x axis and north be positive y axis

Velocity of boat = 2.8 m/s in a direction 52° north of west.

Velocity, v = -2.8 cos 52 i + 2.8 sin 52 j = -1.72 i + 2.21 j m/s

Time taken = 35 min = 35 x 60 = 2100 s

Displacement = Velocity x Time

Displacement =  (-1.72 i + 2.21 j)  x 2100

Displacement =  -3612 i + 4633.50 j m

Displacement along west = 3612 m

Displacement along north = 4633.50 m

Final answer:

To find the westward and northward distances traveled by the sailboat, we decompose the boat's velocity into westward and northward components and then multiply each component by the travel time of 2100 seconds (35 minutes). Calculations involving trigonometry such as cosine for the westward component and sine for the northward component will yield the respective distances.

Explanation:

The question asks for the distance traveled westward and northward by a sailboat that runs before the wind with a constant speed of 2.8 m/s, heading 52° north of west. To solve this, we can decompose the sailboat's velocity into its westward and northward components using trigonometry. The total time traveled is 35 minutes, which is equivalent to 2100 seconds (35 min x 60 s/min).

Westward Component (a)

The westward component of the velocity can be found using the cosine function:

Vwest = V * cos(θ)

Where V is the speed of the boat, and θ is the angle north of west. Plugging in the given values:

Vwest = 2.8 m/s * cos(52°)

The distance traveled westward is the westward component of the velocity multiplied by the time:

Distancewest = Vwest * time

Northward Component (b)

Similarly, the northward component of the velocity is:

Vnorth = V * sin(θ)

The distance traveled northward is:

Distancenorth = Vnorth * time

By calculating these components, we can determine how far the sailboat has traveled in both the westward and northward directions.