A fire truck has a long ladder that is made of 3 sections. Each section is 43/4 meters long.
How long is the ladder when all 3 sections are extended to make one long ladder

Answers

Answer 1
You need to simplify the improper fraction into a mixed number. 

43/4 = 10 3/4 (or 10.75)
You will want to have your answer as a mixed number, but multiplying might be easier if you use the decimal for calculations.

Now you multiply your mixed number or decimal by 3 (3 sections).

10.75 * 3 = 32.25 or 32 1/4

Your answer would be 32 1/4 meters. 

Hope this helps :)


Related Questions

Find the percent change from 48 to 228. Tell whether it is a percent increase or decrease. If necessary, round your answer to the nearest percent.

Answers

228 - 48 = 180

180/48 = 3.75

Its increase 375%

Strike out bowling balls produces 800 bowling balls per day using 2 workers who each work 8 hours per day. what is strike out's productivity?

Answers

Each worker produces 25 bowling balls per hour 

Hope this helps!

The sum of two numbers is 18 less than twice the first number. their difference is 32 less than twice the second number. find each of the numbers

Answers

let the two numbers be x and y
(x+y)-18=2x
x+y-18=2x
x+y-2x=18
-x+y=18_______(1)

(x-y) -32=2y
x-y-32=2y
x-y-2y=32
x-3y=32_______(2)

from eqn (1) y=18+x____(3)
substitute eqn (3) into eqn(2)
x-3{18+x} = 32
x-54-3x=32
-2x=32+54
-2x = 86
x= -43

sub x=-43 into eqn (3)
y=18+(-43) = 18-43 = -25
Final answer:

The problem asks to solve a system of two equations by representing each condition as an equation. By simplifying and substituting, we can find the values of the two unknowns.

Explanation:

The question involves solving a system of two equations. Let's denote the first number as x and the second number as y. The given conditions can be represented as follows:

x + y = 2x - 18x - y = 2y - 32

To simplify, we can rewrite the equations as:

y = x - 18x = 2y + 32

We can substitute equation (1) into equation (2) to get:

x = 2(x - 18) + 32

Solving the equation will give us the value of x and substituting x into equation (1), we will get the value of y.

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please show work along with answer:
[tex] \frac{1 + \tan(x) }{1 + \cot(x) } [/tex]

Answers

Hello,

[tex] \dfrac{1+tan(x)}{1+cotg(x)} = \dfrac{1+ \frac{sin(x)}{cos(x)} }{1+ \frac{cos(x)}{sin(x)}} \\\\ = \dfrac{cos(x)+sin(x)}{cos(x)*( \frac{sin(x)+cos(x)}{sin(x)} } )\\\\ = \dfrac{sin(x)}{cos(x)} \\\\ \boxed{=tan(x)}\\\\ [/tex]



What is the perimeter of a polygon with vertices at

(−1, 3) , ​ (−1, 6) ​, (2, 10) , ​ (5, 6) ​​, and ​​ ​ (5, 3) ​?

Enter your answer in the box. Do not round any side lengths.​

Answers

(-6,6) to (2,10) and (2,10) to (5,6) = square root of 3 squared plus 4 squared = 5 3 plus 5 plus 5 plus 3 plus 6 = 22

we know that

the perimeter of a polygon is the sum of the length sides

in this problem we have five vertices

so

the polygon has five sides

Let

[tex]A(-1,3)\\B(-1,6)\\C(2,10)\\D(5,6)\\E(5,3)[/tex]

the perimeter is equal to

[tex]P=AB+BC+CD+DE+AE[/tex]

The formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

Step 1

Find the distance AB

[tex]A(-1,3)\\B(-1,6)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(6-3)^{2}+(-1+1)^{2}}[/tex]

[tex]d=\sqrt{(3)^{2}+(0)^{2}}[/tex]

[tex]dAB=3\ units[/tex]

Step 2

Find the distance BC

[tex]B(-1,6)\\C(2,10)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(10-6)^{2}+(2+1)^{2}}[/tex]

[tex]d=\sqrt{(4)^{2}+(3)^{2}}[/tex]

[tex]dBC=5\ units[/tex]

Step 3

Find the distance CD

[tex]C(2,10)\\D(5,6)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(6-10)^{2}+(5-2)^{2}}[/tex]

[tex]d=\sqrt{(-4)^{2}+(3)^{2}}[/tex]

[tex]dCD=5\ units[/tex]

Step 4

Find the distance DE

[tex]D(5,6)\\E(5,3)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(3-6)^{2}+(5-5)^{2}}[/tex]

[tex]d=\sqrt{(-3)^{2}+(0)^{2}}[/tex]

[tex]dDE=3\ units[/tex]

Step 5

Find the distance AE

[tex]A(-1,3)\\E(5,3)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(3-3)^{2}+(5+1)^{2}}[/tex]

[tex]d=\sqrt{(0)^{2}+(6)^{2}}[/tex]

[tex]dAE=6\ units[/tex]

Step 6

Find the perimeter

the perimeter is equal to

[tex]P=AB+BC+CD+DE+AE[/tex]

substitute the values

[tex]P=3+5+5+3+6=22\ units[/tex]

therefore

the answer is

the perimeter of the polygon is [tex]22\ units[/tex]

He box plot shows the total amount of time, in minutes, the students of a class spend reading each day: a box plot is titled daily reading time and labeled time (min). the left most point on the number line is 15 and the right most point is 55. the box is labeled 21 on the left edge and 48 on the right edge. a vertical line is drawn inside the rectangle at the point 37. the whiskers are labeled as 16 and 53 what information is provided by the box plot? the mean for the data the median for the data the number of students who provided information the number of students who read for more than 21.5 minutes

Answers

the information provided is the median....it is that vertical line drawn inside the rectangle at point 37.

what is the solution to 7ln(x+2.8)=11.2

Answers

Attached solution with steps.

Which expressions are equivalent to ? Check all that apply.

Answers

Final answer:

To determine if expressions are equivalent, we simplify them or substitute variables with actual values to see if they yield the same result. We simplify by eliminating terms where possible, grouping like terms, and applying mathematical operations.

Explanation:

Without the original mathematical expressions, it's difficult to provide direct answers to your question. Normally, we determine whether expressions are equivalent by simplifying them using algebraic rules or substituting variable with actual values to see if they produce the same results.

For example, the expressions 2(3 + 5) and 6 + 10 are equivalent because they both simplify to 16. We identify equivalent expressions by simplifying which includes eliminating terms where possible, grouping like terms, and applying mathematical operations.

Ultimately, the exact process may vary depending on the complexity and specific form of the expressions in question.

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The expressions equivalent to [tex]$\sqrt[3]{128}^x$[/tex] are (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] due to their compatible structures with the original expression.

To determine which expressions are equivalent to [tex]$\sqrt[3]{128}^x$[/tex], let's simplify the given expression first:

[tex]\[\sqrt[3]{128}^x = 2^x \times \sqrt[3]{2}^x\][/tex]

Now, let's compare this with the provided options:

a. [tex]$128^{\frac{x}{3}}$[/tex] - Not equivalent.

b. [tex]$128^{\frac{3}{x}}$[/tex] - Not equivalent.

c. [tex]$(4 \sqrt[3]{2})^x$[/tex] - Equivalent, as [tex]$4 = 2^{\frac{3}{2}}$[/tex].

d. [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] - Equivalent, as [tex]$2^{\frac{1}{3}} = \sqrt[3]{2}$[/tex].

e. [tex]$(2 \sqrt[3]{4})^x$[/tex] - Not equivalent.

Therefore, the expressions (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] are equivalent to [tex]$\sqrt[3]{128}^x$[/tex].

which is an equivalent form of the expresion 1800(1.2)?
1800=(1/2)
1800=(5/6)
1800=(6/5)
1800=(2/1)

Answers

1800(120/100) = 1800(6/5)

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

1800(1.2).

We need to find the equivalent form:

we can rewrite 1.2 as [tex]\dfrac{12}{10}[/tex]

After find the lowest term which is [tex]\dfrac{6}{5}[/tex]

[tex]1800(1.2)\\\\=18000(\dfrac{12}{10})\\\\=18000(\dfrac{6}{5})[/tex]

Hence, it is equivalent to [tex]18000(\dfrac{6}{5})[/tex]

Thus, Third option is correct.

Find the length of the arc subtended by a central angle of 30degrees on a circle of radius 2 feet

Answers

1847483993722748494736384 is your answer lolz

y=x+2;x=-3 solve each system by graphing step by step

Answers

I will solve for you right now.
to graph a line, you need to use the equation y=mx+b
y=x+2
go to the positive number 2 on the y-axis and plot a point
now, since its postive, your line is gonna go like this:
            p
          p 
       p
     p
   p   
p
so go up one, and to the right one from the 2 on the y-axis
and then go down one, to the left one from the 2 on the y-axis
connect the dots and this is your first line

now for the second line, go to the -3 on the x-axis and draw a vertical line up and down
this is your second line
now find where the two lines interesect and that is your answer

it'll be a point and look something like this if you write it out (x,y)
take the two points out nd write your answer in this form: x=a, y=b

tah dah!

The length of a rectangle is 5 cm more than twice its width. find the largest possible if the perimeter is at most 64 cm

Answers

The largest the length can be is 23 cm and the largest the width can be is 9 cm.

A 20.0 kg sled is being pulled across a horizontal surface at constant velocity. The pulling force has a magnitude of 80.0N and is directed at an angle of 30.0º above the horizontal. Determine the coefficient of kinetic friction.

Answers

The coefficient of kinetic friction is 0.58

To determine the coefficient of kinetic friction [tex](\(\mu_k\))[/tex], we can use the following approach:

1. Identify the horizontal component of the pulling force [tex](\(F_{\text{pull, horizontal}}\))[/tex] and set it equal to the force of kinetic friction [tex](\(f_k\))[/tex].

2. The equation for the horizontal component of the pulling force is:

[tex]\[ F_{\text{pull, horizontal}} = F_{\text{pull}} \cdot \cos(30^\circ) \][/tex]

3. The equation for the force of kinetic friction is:

[tex]\[ f_k = \mu_k \cdot N \][/tex]

4. Since the sled is on a horizontal surface, the normal force [tex](\(N\))[/tex] is equal to the weight of the sled [tex](\(m \cdot g\))[/tex], where m is the mass of the sled and g is the acceleration due to gravity.

Putting these equations together and setting them equal to each other because the sled is moving at constant velocity, we get:

[tex]\[ F_{\text{pull}} \cdot \cos(30^\circ) = \mu_k \cdot m \cdot g \][/tex]

Now, substitute the given values:

[tex]\[ 80 \cdot \cos(30^\circ) = \mu_k \cdot 20 \cdot 9.8 \][/tex]

Solve for [tex]\(\mu_k\)[/tex]:

 [tex]\[ \mu_k = \frac{80 \cdot \cos(30^\circ)}{20 \cdot 9.8} \][/tex]

Calculating this expression yields:

[tex]\[ \mu_k \approx 0.58 \][/tex]

So, the calculated coefficient of kinetic friction is approximately 0.58, which matches the provided answer.

Complete question:

A 20 kg sled is being pulled across a horizontal force at a constant velocity the pulling force has a magnitude of 80 N and it's directed at an angle of 30° above the horizontal determine the coefficient of kinetic friction.

Alex sells cars at Keith Palmer Ford. He earn$400 a week plus $150 per car he sells. if he earn $1450 last week, how many cars did he sell? brainly

Answers

1450-400=1050
1050/150=7
7 cars

Let g(x)=2x and h(x)=x^2+4

(g o h)(0)

Answers

Answer would be 0 because whatever you get when you plug in g&h in the equation you have to multiply that by 0. And a number multiplied by 0 is always 0.
Hope this helped. Have a great day!

The ______ is the total area drained by a river and its tributaries.

Answers

The drainage basin is the total area drained by a river and its tributaries

what is the equation of the graphed line in point-slope form?

a. y – 1 = (x + 3)
b. y – 1 = (x – 3)
c. y + 1 = (x – 3)
d. y + 1 = (x + 3)

Answers

(3,1)(-3,-3)
slope = (-3 - 1) / (-3 - 3) = -4/-6 = 2/3

y - y1 = m(x - x1)
slope(m) = 2/3
(3,1)...x1 = 3 and y1 = 1
now we sub
y - 1 = 2/3(x - 3) <==

Answer:

[tex]y-1 = \frac{2}{3}(x-3)[/tex]

Step-by-step explanation:

To find the equation of graphed line we pick two points from the line

(3,1) and (-3,-3)

Equation of a line is y=mx+b

where 'm' is the slope and b is the y intercept

slope [tex]m= \frac{y2-y1}{x2-x1} =\frac{1+3}{3+3} = \frac{2}{3}[/tex]

we use point slope formula

y-y1= m(x-x1)

here point(x1,y1) is (3,1)  and slope m = 2/3

Plug in all the value

[tex]y-1 = \frac{2}{3} (x-3)[/tex]

Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.

Answers

Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.

Which of the following is equivalent to [tex]( \frac{1}{2} ) ^{-2t} [/tex]
[tex](( \frac{1}{2}) ^{2} ))\ x^{t} [/tex]
[tex] \frac{1 ^{t} }{2 ^{2} } [/tex]
[tex](2 ^{2} ) ^{t} [/tex]
[tex]2 ^{2} * 2^{t} [/tex]

Answers

[tex]\bf \left( \cfrac{1}{2} \right)^{-2t}\implies \left( \cfrac{2}{1} \right)^{2t}\implies (2)^{2t}\implies 2^{2\cdot t}\implies (2^2)^t[/tex]

A zoo has 3 mammals for every 5 reptiles. If the zoo has 72 mammals, how many reptiles does it have? [Type your answer as a number.]

Answers

u will cross multiply, so it'll be 120
120 reptiles. 72/3=24 24x5=120

Quinn used compensation to find the product of 37x4. First, she found 40x4=160. Then she adjusted that product by adding 3 groups of 4 to get her final answer of 172. What did she do incorrectly?

Answers

Quin is adding the compensation needed instead of subtracting. First she calculated 40x4. She is trying to find 37x4. To do this, she would have to instead gather all the data: 3x4 = 12 40x4 = 160 Subtract instead of add: 40x4 - 3x4 = ? 160 - 12 = 148 The answer is 148.

Which formula gives the coordinates of the midpoint of the segment connecting points (a,
b.and (c, d)?

Answers

midpoint formula : (x1 + x2)/2 , (y1 + y2)/2
(a,b)...x1 = a and y1 = b
(c,d)...x2 = c and y2 = d

so ur formula would be :
m = (a + c)/2 , (b + d)/2 <==

Answer:

Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Step-by-step explanation:

Given point are ( a , b ) and ( c , d )

To find : Coordinates of the mid point of the segment connecting given points.

We know that if point are [tex](x_1,y_1)\:\:and\:\:(x_2,y_2)[/tex]

then coordinate of the midpoints given by [tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

So, Coordinates of the given points = [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Therefore, Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

What numbers have the absolute value of 1/2

Answers

1/2 and -1/2

hope it helps, brianliest pls

On anne's bicycle, the ratio of pedal turns to rear-wheel turns in second gear is 4 to 7. if her rear wheel turns 875 times per mile,how many times does she turn the pedal in one mile?hint:set up and solve as a propportion to find x.

Answers

Let the number of times she turns the pedal in one mile be x.

Given that her rear miles turns 875 times in one mile and the ratio of pedal turns to rear wheel turns is 4 to 7, then

[tex] \frac{4}{7} = \frac{x}{875} \\ \\ \Rightarrow 7x=4(875)=3,500 \\ \\ \Rightarrow x= \frac{3,500}{7} =\bold{500}[/tex]

Therefore, she turns the pedal 500 times in one mile.
4 pedal turns (PT) = 7 rear-wheel turns (RT) RT=4PT/7 If RT = 875 xPT = 875RT substituting RT as 4PT/7 xPT = 875*4PT/7 x = 500 Therefore she needs to turn the pedal 500 times to 875 rear-wheel turns in one mile.

Solve for 8x please

Answers

The answer is A..... hope this helps :D

8x=-c+k
x=-c+k/8
The first option is the answer

Solve for x. x3 = 343 A) 6 B) 7 C) 8 D) 9

Answers

The answer is:  [B]:  " 7 " .
__________________________________
 
Note:  Given:  " x³ = 343 " ;  Solve for "x" ; 
__________________________________
     ∛(343) = 7 .
__________________________________
    7³  =  7 × 7 × 7 = 343 .
 7³  =  7 × 7 × 7 =
→  7³  =  7 × 7 × 7 = 49 * 7 = 343 . 
__________________________________

The value of x is 7 .

Hence the correct option B .

Given:  " x³ = 343  

Solve for x,

Rewriting x³ = 343

∛(343) = 7

7³  =  7 × 7 × 7 = 343 .

7³  =  7 × 7 × 7

= 49 * 7

= 343

Therefore correct option is B .

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For sets a={1,2,3} and b={a,b,c,d}, find the number of functions from a to b,

Answers

I think is (B) i think so



Evaluate BC for A = 5, B = -4, and C = 2.

Answers

8 becuase C(2) x B(4) = 8

Answer: -8

Step-by-step explanation: Substitute the value of the variable into the expression and then simplify you should get the answer -8

BC= (-4)(2)=-8

Which algebraic expression has a term with a coefficient of 3?

Answers

Greetings!

A coefficient is a constant value, multiplying the variable in an expression/equation.

Examples:
[tex]4x^2+3y^3[/tex]

The coefficient of the second term would be three. 

Hope this helps.
-Benjamin

the correct answer is option (b) 3x² - 7.

The coefficient is the numerical factor in front of the variable. Let's calculate the coefficient for each option:

a) The coefficient of x in 2x is 2, not 3.

b) The coefficient of x² in 3x² is 3, which matches our requirement.

c) The coefficient of x in 4x is 4, not 3.

d) There is no x term in x³ + 2, so the coefficient for x is 0.

Therefore, the correct answer is option (b) 3x² - 7.

In option (b), the term with the coefficient of 3 is 3x². The coefficient of this term is indeed 3 because it's the number multiplied by x squared. The other terms in the expression do not have a coefficient of 3.

In options (a) and (c), the coefficients for the x terms are 2 and 4, respectively, which do not match the requirement.

Option (d) doesn't have an x term; it only has x raised to the power of 3 (x³), and the coefficient for this term is 0.

So, by process of elimination and calculation, we determine that option (b) is the correct answer with the term 3x² having a coefficient of 3.

complete question

Which algebraic expression has a term with a coefficient of 3?

a) 2x + 5  

b) 3x² - 7  

c) 4x - 3  

d) x³ + 2

How do you solve rearranging equations

Answers

step one: you can add, subtract, multiply and divide by anything, as long as you do the same thing to both sides of the equals sign. In an equation, the equals sign acts like the fulcrum of a balance: if you add 5 of something to one side of the balance, you have to add the same amount to the other side to keep the balance steady. The same thing goes for an equation - doing the same operation to both sides keeps the meaning of the equation from changing.Show me an examplestep two: to move or cancel a quantity or variable on one side of the equation, perform the "opposite" operation with it on both sides. 
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