A farmer has 90 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wide, what are the dimensions

Answers

Answer 1

Answer:

W = 15 ft. and L = 30 ft.

Step-by-step explanation:

Perimeter = 90 ft.

Twice as long as it is wide: L=2W

P = 2(L + W) = 2(2W + W) = 6W

90 = 6W

W = 15 ft. and L = 30 ft.

Answer 2

Answer:

The dimensions are: Width= 15ft

Length=30ft

Step-by-step explanation:

Perimeter of fence=90feet

He wants to make a rectangle with dimensions length and with.

The rectangle length is twice as long as the width= L= 2W

Perimeter of a rectangle = 2(L + W)

90= 2(2W +W)

90= 6W

90/6=W=15ft

L=2W= 2× 15=30ft


Related Questions

An airplane pilot fell 370 m after jumping without his parachute opening. He landed in a snowbank, creating a crater 1.5 m deep, but survived with only minor injuries. Assume that the pilot's mass was 84 kg and his terminal velocity was 50 m/s.estimate

Answers

Answer:

he ded

Step-by-step explanation:

\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \tohe no alive  because ⇆ω⇆π⊂∴∨α∈\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to[tex]\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to[/tex]

George is a fast worker. He can mop 50 ft2 in 1 minute. The court is shaped like a rectangle. It is 95 ft long by 50 ft wide. How many minutes will it take George to mop the gym floor?
a.) 95 minutes

b.) 3958.3 minutes

c.) 4,750 minutes

d.) 190 minutes

Answers

A. 95     95x50=4750    then you divide 4750 by 50 and you get your answer

Final answer:

To find how long George will take to mop the floor, calculate the area of the court (95 ft x 50 ft = 4,750 ft²) and divide it by his mopping rate (50 ft²/min). The calculation shows it will take George 95 minutes to mop the floor.

Explanation:

To determine how long it will take George to mop the gym floor, we first calculate the area of the rectangular court.

Multiplying the length by the width gives us the total area that needs to be mopped:

Area = length × widthArea = 95 ft × 50 ftArea = 4,750 ft²

Now, since George can mop 50 ft² in 1 minute, we divide the total area by the rate at which George can mop:

Time = total area / mopping rateTime = 4,750 ft² / 50 ft² per minuteTime = 95 minutes

Therefore, it will take George 95 minutes to mop the gym floor, which corresponds to option (a).

Match the answers on the left with their properly rounded answers.a. 264.34928 rounded to the nearest tenth b. 264.34928 rounded to the nearest thousandth c. 265.34928 rounded to the nearest one d. 264.34928 rounded to the nearest hundreds e. 265.34928 rounded to the nearest tens f. 264.34928 rounded to the nearest hundredths

Answers

Answer:  a) 264.3, b) 264.349, c) 265, d) 300, e) 260, f) 264.35.

Step-by-step explanation:

Since we have given that

264.34928 rounded to the nearest tenth.

So, it becomes [tex]264.3[/tex]

264.34928 rounded to the nearest thousandths.

So, it becomes [tex]264.349[/tex]

264.34928 rounded to the nearest one.

So, it becomes [tex]265[/tex]

264.34928 rounded to the nearest hundreds.

So, it becomes [tex]300[/tex]

264.34928 rounded to the nearest tens.

So,it becomes [tex]260[/tex]

264.34928 rounded to the nearest hundredths.

So, it becomes [tex]264.35[/tex]

Hence, a) 264.3, b) 264.349, c) 265, d) 300, e) 260, f) 264.35.

a. 264.34928 rounded to the nearest tenth = 264.3

b. 264.34928 rounded to the nearest thousandth = 264.349

c. 265.34928 rounded to the nearest one = 265

d. 264.34928 rounded to the nearest hundred = 264.35

e. 265.34928 rounded to the nearest ten = 265.3

f. 264.34928 rounded to the nearest hundredth = 264.35

Here are the answers matched with their properly rounded values along with explanations:

a. 264.34928 rounded to the nearest tenth: 264.3

Explanation: The tenths digit is 4, and the digit immediately to the right of it is 9, which is greater than or equal to 5. So, you round up to 264.3.

b. 264.34928 rounded to the nearest thousandth: 264.349

Explanation: The thousandths digit is 9, which is greater than or equal to 5. So, you round up to 264.349.

c. 265.34928 rounded to the nearest one: 265

Explanation: The nearest one for 265.34928 is simply 265 because it is already a whole number.

d. 264.34928 rounded to the nearest hundred: 264.35

Explanation: The hundredths digit is 4, and the digit immediately to the right of it is 9, which is greater than or equal to 5. So, you round up to 264.35.

e. 265.34928 rounded to the nearest tens: 270

Explanation: The tens digit is 6, and the digit immediately to the right of it is 5 or greater. So, you round up to 270.

f. 264.34928 rounded to the nearest hundredth: 264.35

Explanation: The hundredths digit is 4, and the digit immediately to the right of it is 9, which is greater than or equal to 5. So, you round up to 264.35.

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4. Explain the meaning of a level of significance of 5%. Why is a level of
significance needed for every hypothesis test?

Answers

Answer:

5% significance level indicates the level of risk, error or exactness. It guides our conclusion on which hypothesis a data supports

Level of significance defined as the possibility, probability or chances of rejecting a null hypothesis when it's results is valid.

For every statistical hypothesis, the result has propency or likeliness to be exact or not. That is, it has chances of containing a type of error referred to as level of significance.

Now, a 5% significance level implies that, the statistical results or analysis has 95% reliability or confidence level.

In other words, a 5% significance level indicates that a result has 0.05 RISK level.

The level of significance is needed for every hypothetical test because it indicates validity of each hypothesis data. It gives confidence such that one is at peace to know the hypothesis a particular data supports

30 60 90 triangles (quick answers please)

Answers

1) EF = 2 and DF = 4

2) KL = 4√3 and JL = 8

3) ST = 6 and RS = 6√3

4) PQ = 4.5√3 and RQ = 4.5

Step-by-step explanation:

Rules for special triangles 30°,60°,90° :

The length of the side opposite to 30° is a.The length of the side opposite to 60° is a√3.The length of the side opposite to 90° is 2a.

1) DE = 2√3 is opposite to 60°

⇒ 2√3 = a√3

a = 2

EF = a which is opposite to 30°.

⇒ EF = 2

DF = 2a which is opposite to 90°.

⇒ DF = 4

2) KJ = 4 is opposite to 30°

a = 4

KL = a√3 which is opposite to 60°.

⇒ KL = 4√3

JL = 2a which is opposite to 90°.

⇒ JL = 8

3) RT = 12 is opposite to 90°

⇒ 2a = 12

⇒ a = 6

ST = a which is opposite to 30°.

⇒ ST = 6

RS = a√3 which is opposite to 60°.

⇒ RS = 6√3

4) PR = 9 is opposite to 90°

⇒ 2a = 9

⇒ a = 4.5

PQ = a√3 which is opposite to 60°.

⇒ PQ = 4.5√3

RQ = a which is opposite to 30°.

⇒ RQ = 4.5

In a certain data distribution, 85 is 0.25 standard deviation above the mean and 50 is 1.5 standard deviations below the mean. What value is 0.75 standard deviation below the mean

Answers

Answer:

The mean is 80 and the standard deviation is 20. Therefore we have

65 is 0.75 standard deviation below the mean.

Step-by-step explanation:

z = [tex]\frac{x-\mu}{\sigma}[/tex]

Since 85 is 0.25 standard deviations above the mean we have

[tex]0.25 = \frac{85-\mu}{\sigma}[/tex] or 0.25·σ  = 85 - μ......1

1.5 = [tex]\frac{\mu-50}{\sigma}[/tex] or 1.5·σ  = μ - 50..............2

From 1 we have σ = 340 - 4·μ substituting into 2 gives

1.5·(340 - 4·μ) =  μ - 50 ⇒ 510 - 6·μ = μ - 50

7·μ = 560 or μ = 80

Therefore σ = 340 - 4·μ = 340 - 4·80 = 20

A value, x, 0.75 standard deviation below the mean is given by

0.75 = [tex]\frac{80-x}{20}[/tex] which gives 15 = 80 - x or

x = 65.

A worksheet contains over 400 rows. The first 10 rows contain input data, and functions containing summary statistics are in the last 10 rows. What is the most efficient method to see the input area and summary statistics at the same time without having to scroll back and forth between sections?(a) Open multiple windows of the same workbook and use the Arrange Windows command to tile the windows.(b) Display a Watch Window for the input section as you view the summary statistics section.(c) Select the summary statistics and use the Freeze Panes option.(d) Use the Split command and adjust one pane to see the input section and another pane to see the summary statistics.

Answers

Answer:

the most efficient method to see the input area and summary statistics at the same time without having to scroll back and forth between sections is b) Display a Watch Window for the input section as you view the summary statistics section.

Step-by-step explanation:

A Watch Window in Excel is a window that floats in front of your workbook that lets you see selected cells from anywhere in your workbook, or even other workbooks. This can be very helpful when you want to see how changes affect cells on other tabs or that aren't within view on a large spreadsheet.

A workbook is a file that contains one or more worksheets to help you organize data. You can create a new workbook from a blank workbook or a template.

The definition of a spreadsheet is a piece of paper or a computer program used for accounting and recording data using rows and columns into which information can be entered. Microsoft Excel, a program in which you enter data into columns, is an example of a spreadsheet program.

Final answer:

The Split command is the most efficient way to view both the input data and summary statistics simultaneously in a worksheet, by allowing independent scrolling of different worksheet areas.

Explanation:

The most efficient method to see both the input area and summary statistics at the same time in a worksheet is option (d) Use the Split command and adjust one pane to see the input section and another pane to see the summary statistics. This command divides the screen into separate panes that each scroll independently, allowing you to view non-adjacent areas of your worksheet simultaneously.

Here's how you can use the Split command:

Select the row or column where you want the split to appear. For your case, you may want to select the row just below the input data or just above the summary statistics.

Go to the View tab on the Excel ribbon.

Click on the Split button within the 'Window' group of commands.

Adjust the split bars to position the panes so that one shows the input data while the other shows the summary statistics.

This will allow you to keep an eye on both the input data and the summary statistics without having to scroll up and down the worksheet.

At the ice cream shoppe ,one banana split and five milkshakes cost $16.24.If three banana splits and two milkshakes cost $15.05,find the cost of a milkshake.

Answers

Answer: the cost of a milkshake is $2.59

Step-by-step explanation:

Let x represent the cost of a banana split.

Let y represent the cost of a milkshake.

At the ice cream shop, one banana split and five milkshakes cost $16.24. This is expressed as

x + 5y = 16.24- - - - - - - - - - - - -1

If three banana splits and two milkshakes cost $15.05. This is expressed as

3x + 2y = 15.05- - - - - - - - - - - - -2

Multiplying equation 1 by 3 and equation 2 by 1, it becomes

3x + 15y = 48.72

3x + 2y = 15.05

Subtracting, it becomes

13y = 33.67

y = 33.67/13

y = 2.59

Substituting y = 2.59 into equation 1, it becomes

x + 5 × 2.59 = 16.24

x + 12.95 = 16.24

x = 16.24 - 12.95

x = 3.29

The cost of one banana split = $3.29

The cost of one milkshake is = $2.59

Let the cost of one banana split = x

the cost of one milkshake is = y.

So, according to the question:

x+5y=16.24

3x+2y=15.05

Solving the equations we get: x=3.29 and y=2.59.

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8. Which statements describe properties of the diagonals of a rectangle ? I The diagonals are congruent . II The diagonfils are perpendicular . III The diagonals bisect each other. A) II and III, only B) I and II, only C) I and IIIonly D) I, II, and III

Answers

I and III are always true: the diagonals of a rectangle are congruent, and they intersect at their midpoint.

Finally, the diagonals are perpendicular if and only if the rectangle is actually a square.

So, I and III are true for every rectangle, while II is true only for some rectangles.

The correct answer is option (c) I and  III only .

What is rectangle?

A plane figure with four straight sides and four right angles, especially one with unequal adjacent sides, in contrast to a square

How to solve this problem?Statement I and III are always true: the diagonals of a rectangle are congruent, and they intersect at their midpoint.The diagonals are perpendicular if and only if the rectangle is actually a square.So, I and III are true for every rectangle, while II is true only for some rectangles

Therefore we can say that The diagonals are congruent & The diagonals bisect each other i.e the correct choice is option (c)

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Find 6/7 of £60 to the nearest penny.

Answers

6/7th of £60 to the nearest penny is £51. 43 penny

Step-by-step explanation:

The amount = £60

The fraction that needs to be decided= 6/7th part

For solving the problem, we need to find out the 6/7th part of £60 and then round off the answer to the nearest 2 digits after decimals.

Thus the amount to the nearest penny= (6/7) *60

Amount= £51.42857714285

When the above amount is rounded off to the nearest penny than the amount becomes= £51.43 meaning 51 pounds and 43 pennies.  

Find the probability of winning a lottery in which you win when the six numbers on yourticket must match the six unique numbers selected from a set of positive integers not ex-ceeding 30. The order of the numbers on your ticket, do not matter as in order to win, allyou must do is match all the numbers.

Answers

Answer:

0.00016841%

Step-by-step explanation:

The winning group of numbers consist of 6 unique number inside a pool of 30 numbers. To calculate the number of groups of 6 that can be done in a pool of 30 numbers, we do a combination of 30 chosen 6 (groups of 6 numbers in 30 numbers).

The formula of combination is:

C(n,p) = n![p!*(n-p)!]

In our case, n=30 and p=6, so we have

C(30,6)=30!/(6!24!) = 30*29*28*27*26*25/(6*5*4*3*2) = 593775

As we have 593775 numbers of different possibilities of winning ticket, the probability of winning one over this value:

p = 1/593775 = 0.0000016841 = 0.00016841%

Other way to do this question is:

We have to match all 6 numbers. The first number to match have a chance of 6 over 30 to be guessed right, as there are 6 winning number in a pool of 30.

The second number to match have a chance of 5 over 29, as we already picked one winning number, and have only 29 choices left.

Then, following this logic, we have the other 4 numbers with chance 4/28, 3/27, 2/26 and 1/25.

Multiplying all these chances, we have:

p = (6*5*4*3*2*1)/(30*29*28*27*26*25) = 0.0000016841 = 0.00016841%

Which statements are true about the ordered pair (10, 5) and the system of equations? {2x−5y=−5 x+2y=11 Select each correct answer. The ordered pair (10, 5) is a solution to the first equation because it makes the first equation true. The ordered pair (10, 5) is a solution to the second equation because it makes the second equation true. The ordered pair (10, 5) is not a solution to the system because it makes at least one of the equations false. The ordered pair (10, 5) is a solution to the system because it makes both equations true.

Answers

Answer:

The ordered pair (10, 5) is not a solution to the system because it makes at least one of the equations false.

Step-by-step explanation:

2x−5y=−5

x+2y=11

In equation (1), substitution of (10,5)

2x−5y=2(10)-5(5)=20-25=-5

However in equation (2), on substitution of (10,5)

x+2y=10+2(5)=10+10=20 ≠11.

However, the solutions of the simultaneous equations

2x−5y=−5

x+2y=11

are (5,3)

Final answer:

The ordered pair (10, 5) is a solution to the first equation of the system but not the second, which means it is not a solution to the entire system of equations.

Explanation:

To determine if the ordered pair (10, 5) is a solution to the given system of equations, we need to substitute x with 10 and y with 5 into each equation and see if the equations hold true:

First equation: 2x - 5y = -5 becomes 2(10) - 5(5) = -5 which simplifies to 20 - 25 = -5. This is true, so (10, 5) is a solution to the first equation.Second equation: x + 2y = 11 becomes 10 + 2(5) = 11 which simplifies to 10 + 10 = 11. This is false, so (10, 5) is not a solution to the second equation.

Since the ordered pair does not satisfy both equations, it is not a solution to the system of equations. Therefore, the correct statements are:

The ordered pair (10, 5) is a solution to the first equation because it makes the first equation true.The ordered pair (10, 5) is not a solution to the system because it makes at least one of the equations false.

What is the missing reason for the seventh statement?
a. CPCTC
b. AA postulate
c. All right triangles are similar.
d. Transitive property of similarity.

Answers

Answer:

b. AA postulate

Step-by-step explanation:

DONT SKIP HELP PLZZZZZZZZZZZZZ

Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-5, -2) and point (8, -3) rounded to the nearest tenth?

10.3 units

12.6 units

1 unit

13 units

Answers

Option D: The distance between the two points is 13 units

Explanation:

It is given that the two points are [tex](-5,-2)[/tex] and [tex](8,-3)[/tex]

We need to determine the distance between the two points.

It is also given that the distance between the two points can be determined using the formula,

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substituting the points [tex](-5,-2)[/tex] and [tex](8,-3)[/tex] for the coordinates [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Thus, we get,

[tex]d=\sqrt{(8-(-5))^2+(-3-(-2))^2}[/tex]

Simplifying, we have,

[tex]d=\sqrt{(8+5)^2+(-3+2)^2}[/tex]

Adding the terms, we get,

[tex]d=\sqrt{(13)^2+(-1)^2}[/tex]

Squaring the terms, we have,

[tex]d=\sqrt{169+1}[/tex]

Adding the terms, we get,

[tex]d=\sqrt{170}[/tex]

Simplifying and rounding off the value to the nearest tenth, we have,

[tex]d=13.0 \ units[/tex]

Hence, the distance between the two points is 13 units.

Therefore, Option D is the correct answer.

Please I am really Confused If you can help that would be great!

Answers

Answer:

The answer to your question is Ariel is correct, x = 27 ft

Step-by-step explanation:

Data

angle = Ф = 47°

Adjacent side = 25

Opposite side = x

Process

1.- To solve this problem, we must use trigonometric functions. The trigonometric function that relates the Opposite side and the adjacent side is tangent.

            tan Ф = Opposite side / Adjacent side

- Solve for Opposite side

            Opposite side (x) = Adjacent side x tan Ф

-Substitution

                                      x = 25 tan 47

                                     x = 25 (1.0724)

-Result

                                    x = 26.8 ≈ 27 ft

Ariel is correct

Answer:

Incorrect angle; 23 feet

Step-by-step explanation:

She has marked the angle incorrectly

Angle of depression is marked between the line of sight and the hypotenuse

The angle she should use is:

90 - 47 = 43

tan(43) = x/25

x = 25tan(43)

x = 23.31287715

Answer your following questions based on the quadrilateral is given. You must show all your work and
indicate the property you use to find the answers

The rectangle is given below. Find the measurements of 21, 22 and 23.

Answers

The measurements of ∠1 = 60°, ∠2 = 30° and ∠3 = 90°.

Solution:

By the property of rectangle,

Opposite sides of rectangle are parallel.

By another property of parallel lines,

If two parallel lines cut by a transversal (diagonal) then alternate interior angles are congruent.

60° and ∠1 are alternate interior angles.

Hence m∠1 = 60°.

In rectangle, all the angles are right angle.

m∠1 + m∠2 = 90°

60° + m∠2 = 90°

Subtract 60° from both sides of the equation.

m∠2 = 30°

In rectangle, all the angles are right angle.

m∠3 = 90°

Hence the measurements of ∠1 = 60°, ∠2 = 30° and ∠3 = 90°.

Sum of Two Dice
An experiment was conducted in which two fair dice
were thrown 100 times. The sum of the pips
showing on the dice was then recorded. The
frequency histogram to the right gives the results.
Use the histogram to complete parts (a) through (f). O
Frequency
T
óŚ . 10 12
Value of dice
(a) What was the most frequent outcome of the experiment?
(b) What was the least frequent?

Answers

Answer:

a) Most frequent outcome of the experiment is 7

b) Least frequent is 2

Step-by-step explanation:

a)

x= value of dice =7  is with highest frequency = 21  

(b)

x = Value of dice = 2 is with least frequency = 1

Final answer:

Without a visual, it's challenging to provide exact responses to the question. However, typically the most frequent outcome when rolling two dice is 7 or 8, and the least frequent is 2 or 12.

Explanation:

Without a visual representation of the frequency histogram provided, it is challenging to provide exact responses to parts (a) and (b) of your question. However, in general, when two fair dice are thrown, the most likely sums are 7 and 8, while the least likely sums are 2 and 12. This is because there are more combinations of dice rolls that result in sums of 7 and 8 compared to 2 or 12. For example, for 7, the combinations could be (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1).

To answer your original question, in general, (a) the most frequent outcome will typically be 7 or 8, and (b) the least frequent outcome will usually be 2 or 12.

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simplify by like combining terms: 5+m+m+8m+12-9-4m

Answers

Answer: 6m+8

m+m+8m-4m = 6m

5+12-9=8

Directions: Using the digits 0 – 9, no more than one time each,
place a digit in each box to create an equation with a solution x=-1/2
.
Create three such equations.

Answers

Three equations with a solution of x = -1/2:

(2x - 1) = 0

(-x + 3) = 1

(4x + 2) = -3

Here are three equations, each created using the digits 0 – 9, with a solution of x = -1/2:

(2x - 1) = 0

Solution: When you solve for x, you get x = -1/2.

(-x + 3) = 1

Solution: Solving for x, you find x = -1/2.

(4x + 2) = -3

Solution: Upon solving for x, the result is x = -1/2.

In each of these equations, the placement of the digits ensures that when you calculate the value of x, it equals -1/2. This demonstrates that it's possible to use the digits 0 – 9 once to form equations with the specified solution.

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Complete question below :

Using the digits 0 – 9, no more than one time each, place a digit in each box to create three equations with a solution x = -1/2.

12. What three things should you be sure to do before signing a contract?

Answers

Answer: 1. Pay clear attention to details of the contract

2. Negotiate

3. Hire a lawyer

Step-by-step explanation:

Pay clear attention by reading the contract agreement over and over again to be sure you are clear with terms and conditions stated.

Negotiate if need be, such that the terms are jointly agreed upon. It is essential to negotiate on the relevant terms and come to a mutual agreement so that there is no misunderstanding after the contract has been signed.

In hiring a lawyer, it is important to note that contract documentation often contains legal term that requires deep analysis. It is better to be clear and take precautions before a deal is concluded.

Hannah is making calzones to sell her restaurant she starts with nine cans of tomato sauce and then use is 9/10 of the cans for her first batch of calzones how many cans of tomato sauce does Hannah use for the first batch of calzones

Answers

Answer:

About 8 cans.

Step-by-step explanation:

Given:

She starts with nine cans of tomato sauce.

Then use is 9/10 of the cans for her first batch of calzones

To find:

How many cans of tomato sauce does Hannah use for the first batch of calzones ?

Solution:

She starts with number of cans = 9

Then use is [tex]\frac{9}{10}[/tex] of the cans.

Now, we will find number of cans used for the first batch of calzones by multiplying number of cans she starts with by fraction of  cans she used  for the first batch of calzones .

[tex]\frac{9}{10} of 9 cans = \frac{9}{10} \times9\\\frac{81}{10} = 8.1[/tex]

Therefore,  number of cans used for the first batch of calzones is about 8 cans.

StatTutor: Independence and the multiplication rule A bent coin has probability 0.55 of landing heads up. What is the probability that five tosses of the coin will result in at least one heads? Use four decimal places in your answer.

Answers

Answer:

0.9815

Step-by-step explanation:

P(head) = 0.55

P(tail) = 1 - 0.55 = 0.45

P(Atleast one head)

= 1 - P(all tails)

= 1 - 0.45⁵

= 0.9815471875

= 0.9815

Final answer:

In probability, the complementary event of 'at least one heads' is 'getting no heads'. Calculate the probability of the complement (getting tails five times) and subtract it from 1. The result is 0.8155.

Explanation:

This type of problem deals with

probability

. The best way to approach it is to consider the complementary event. In this case, the complementary event to getting 'at least one heads' is 'getting no heads'. The probability of getting heads is 0.55, so the probability of getting tails is 1 - 0.55 = 0.45. This is because the sum of the probabilities of all possible outcomes (heads or tails) equals 1. So, the probability of getting tails on all five tosses is (0.45)^5 = 0.1845. Now, we subtract this from 1 to get the probability of the desired event, 'at least one heads': 1 - 0.1845 = 0.8155. Therefore, the probability of getting at least one heads in five coin tosses is 0.8155.

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ALGEBRA 2 HELP!
Find all the zeros

f(x)=[tex]x^{3}+64[/tex]

Answers

To find the zeros we have to put:

[tex]f(x)=0[/tex]

Now we have:

[tex]x^3+64=0[/tex]

[tex]x^3=-64[/tex]

[tex]x=\sqrt[3]{-64}[/tex]

[tex]x=-4[/tex]

So, the only zero is x=-4

can someone explain this to me please
the answer is 2023 but idk how u get to that

btw the equation for the population of the rabbits was
[tex]r = 50 {e}^{0.5t} [/tex]
for the year 2016

Answers

Step-by-step explanation:

Start by finding when the populations become equal.

C = R

1000e^(0.1t) = 50e^(0.5t)

Divide both sides by 50.

20e^(0.1t) = e^(0.5t)

Divide both sides by e^(0.1t).

20 = e^(0.4t)

Take natural log of both sides.

ln 20 = 0.4t

Multiply both sides by 2.5

t = 2.5 ln 20

t ≈ 7.5

The population of rabbits first exceeds the population of crickets in the middle of the 7th year after 2016, or 2023.

Answer:

8th year

Step-by-step explanation:

r > C

50(e^0.5t) > 1000(e^0.1t)

(e^0.5t)/(e^0.1t) > 20

e^(0.5t-0.1t) > 20

e^0.4t > 20

ln(e^0.4t) > ln20

0.4t × lne > ln20

t > ln(20)/0.4

t > 7.489330685

Population of rabbits first exceeds the population of crickets during the 8th year

REN fine six peanuts, four raisins, 3 cranberries, and 5 chocolate chips in a handful of trail mix. For every 9 pieces in Ren's handful of trail mix there are 2

Answers

Answer:

2 raisins.

Step-by-step explanation:

Let x represent total number of required ingredient.

We have been given that Ren finds 6 peanuts, 4 raisins, 3 cranberries, and 5 chocolate chips in a handful of trail mix. We are asked to find of which ingredient Ren will have 2 pieces for a total of 9 pieces.

First of all, we will find total number of ingredients by adding each ingredient as:

[tex]\text{Total number of ingredients}=6+4+3+5[/tex]

[tex]\text{Total number of ingredients}=18[/tex]

Now, we will use ratio to solve for our given problem as:

[tex]\frac{\text{Required ingredient}}{\text{Total ingredient}}=\frac{2}{9}[/tex]

[tex]\frac{x}{18}=\frac{2}{9}[/tex]

[tex]\frac{x}{18}\cdot 18=\frac{2}{9}\cdot 18[/tex]

[tex]x=\frac{2}{1}\cdot 2[/tex]

[tex]x=4[/tex]

Since there are 4 raisins, therefore, for  every 9 pieces in Ren's handful of trail mix there are 2 raisins.

A taxi driver charges $3.50 per mile traveled. The driver gave a 10-mile ride, a 5.5-mile ride, and a 19-mile ride. The driver then spends $50 to fill up the gas tank before giving a final ride of 26 miles. Which numeric expression represents the dollar amounts the driver had after each action, in order?

Answers

Answer:

Step-by-step explanation:

y = 3.5(10) + 3.5(5.5) + 3.5(19) - 50 + 3.5(26)

What is the solution of the equation (4x + 3)2 = 18?

x = StartFraction 3 Over 2 EndFraction and x = –3
x = StartFraction negative 3 Over 2 EndFraction and x = 3
x = StartFraction negative 3 + 3 StartRoot 2 EndRoot Over 4 EndFraction and x = StartFraction negative 3 minus 3 StartRoot 2 EndRoot Over 4 EndFraction
x = StartFraction 3 + 3 StartRoot 2 EndRoot Over 4 EndFraction and x = StartFraction negative 3 + 3 StartRoot 2 EndRoot Over 4 EndFraction

Answers

Step-by-step explanation:

open brackets by multiplying with 2

8x+6=18

8x=12

x=3/2

The solution of the quadratic equation using the discriminant formula is option C. -3 ± √18 / 4 or 0.31 and a negative of 1.81.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The quadratic expression is given as

(4x + 3)² = 18

On solving, we have

(4x + 3)² = 18

(4x + 3) = √18

  4x = - 3 ± √18

 x = -3 ± √18 / 4

Therefore, x = 0.31, -1.81

The solution of the quadratic equation using the discriminant formula is option C. -3 ± √18 / 4 or 0.31 and a negative of 1.81.

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Chuy wants to buy a new television. The television costs $1,350. Chuy decides to save the same amount of money each week, for 27 weeks. After 8 weeks Chuy saved $440. Which of the following conclusions can you make about Chuy's plan? A. Chuy has a good plan and will have exactly $1,350 saved at the end of 27 weeks. B. Chuy must increase the amount he saves each week in order to meet his goal at the end of 27 weeks. C. Chuy will save more than he needs and will meet his goal in less than 27 weeks.

Answers

Answer: option C is the correct answer.

Step-by-step explanation:

The television costs $1,350. Chuy decides to save the same amount of money each week, for 27 weeks. After 8 weeks Chuy saved $440. This means that the amount that she saved per week is

440/8 = $55

If she saves $55 in 8 weeks, the number of weeks left is

27 - 8 = 19 week

Amount that she would save in 19 weeks is

19 × 55 = 1045

Total amount saved in 27 weeks is

1045 + 440 = $1485

Therefore, the conclusion that you can make about Chuy's plan is

C. Chuy will save more than he needs and will meet his goal in less than 27 weeks.

Answer:

c

Step-by-step explanation:

What is an equation of the line that passes through the points (−5,−7) and (5,1)?

Answers

Answer:

y = [tex]\frac{4}{5}[/tex] x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 5, - 7) and (x₂, y₂ ) = (5, 1)

m = [tex]\frac{1+7}{5+5}[/tex] = [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex], thus

y = [tex]\frac{4}{5}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (5, 1), then

1 = 4 + c ⇒ c = 1 - 4 = - 3

y = [tex]\frac{4}{5}[/tex] x - 3 ← equation of line

Which construction of parallel lines is justified by the theorem "when two lines are intersected by a transversal and the corresponding angles are congruent the lines are parallel?"

Answers

Answer:

c

Step-by-step explanation:

I think you missed attaching the photo, please see my attachment.

And the correct answer is C,

When you look at where the arc meets the parallel lines, if you create a seam between two points, you get a straight line parallel to the horizontal lines  so it makes the corresponding angles are congruent.

The theorem stating that when two lines are intersected by a transversal and the corresponding angles are congruent means the lines are parallel, guides a specific construction method in geometry. This method involves using a transversal to determine if the intersected lines are parallel by comparing corresponding angles.

The theorem 'when two lines are intersected by a transversal and the corresponding angles are congruent, the lines are parallel' justifies a particular construction of parallel lines in geometry.

This principle is a fundamental aspect of geometric theorems on parallel lines and angles created by a transversal. To construct parallel lines using this theorem, one might follow these steps:

Identify or draw a transversal that intersects two lines.

Measure the corresponding angles created by the intersection of the transversal with these lines.

If the corresponding angles are congruent, then by this theorem, the two lines are determined to be parallel.

This concept is essential in understanding the relationships between angles and lines in a plane, providing a cornerstone for proofs and constructions within geometry.

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