a car with an initial velocity of 16.0 meter per second east slows uniformly to 6.0 meters per second east in 4.0 seconds. what is the acceleration of the car during this 4.0 second interval.
The acceleration of the car during [tex]4.0 s[/tex] is [tex]\boxed{-2.5\,{\text{m/}}{{\text{s}}^{\text{2}}}}[/tex] i.e. towards the west.
Further explanation:
Acceleration is caused due to the force exerted on the body. In case when body is in equilibrium, the net force on the body will be zero therefore, acceleration will also be zero.
In case when body is moving with certain initial velocity and the net force on the body is zero, body will continue to move with the same velocity or we can say body is moving with uniform velocity.
Given:
Initial velocity of the car is [tex]16\text{ m/s}[/tex] towards east.
Final velocity of the car is [tex]6\text{ m/s}[/tex] towards east.
Time interval is .[tex]4.0\text{ s}[/tex].
Concept:
Instantaneous acceleration is defined as the rate of change of velocity with respect to time. Average acceleration is defined as the change of velocity over a certain period of time.
Mathematically,
[tex]\boxed{a = \dfrac{{\Delta V}}{{\Delta t}}}[/tex] ……(1)
Here, [tex]a[/tex] is the average acceleration of car, [tex]\Delta V[/tex] is the change in velocity and [tex]\Delta t[/tex] is the time interval.
Write the expression for change in velocity
[tex]\Delta V = {V_{\text{f}}} - {V_{\text{i}}}[/tex] …… (2)
Here, [tex]{V_{\text{f}}}[/tex] is the final velocity of car and [tex]{V_{\text{i}}}[/tex] is the initial velocity of the car.
Velocity is a vector quantity so take magnitude as well as direction of the velocity, while substituting in the above expression.
Let’s assume unit vector in the east direction is [tex]\hat i[/tex] and unit vector in west direction is [tex]- \hat j[/tex].
Substitute [tex]6\,\hat i[/tex] for [tex]{V_{\text{f}}}[/tex] and [tex]16\,\hat i[/tex] for [tex]{V_{\text{i}}}[/tex] in equation (2).
[tex]\begin{aligned}\Delta V&=\left( {6{\kern 1pt} \hat i} \right) - \left( {16\,\hat i\,} \right)\\&=10\,\left( { - \hat i} \right)\\\end{aligned}[/tex]
Substitute [tex]10\,\left( { - \hat i} \right)[/tex] for [tex]\Delta V[/tex] and [tex]4.0\text{ s}[/tex] for [tex]\Delta t[/tex] in equation (1).
[tex]\begin{aligned}a&=\frac{{\left( { - 10\,\hat i\,{\text{m/s}}} \right)}}{{\left( {4.0\,{\text{s}}} \right)}} \\&=2.5\,\left( { - \hat i} \right)\,{\text{m/}}{{\text{s}}^{\text{2}}} \\ \end{aligned}[/tex]
Thus, the acceleration of the car during [tex]4.0 s[/tex] is [tex]\boxed{-2.5\,{\text{m/}}{{\text{s}}^{\text{2}}}}[/tex] i.e. towards the west.
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords:
Car, initial, velocity, 16.0 m/s, east, 16 m/s, 16 meter per second, 16.0 meter per second, uniformly, 6.0 m/s, 6 m/s, 6.0 meter per second, 6 meter per second, 4.0 second, 4.0 s, 4 second, 4 s, acceleration, during, interval.
The car decelerated at a rate of -2.5 m/s² east during the four-second interval.
Explanation:The acceleration of a body can be calculated using the formula a = Δv/Δt, where 'a' is acceleration, 'Δv' is the change in velocity and 'Δt' is the change in time.
Here, the change in velocity (Δv) is the final velocity minus the initial velocity, hence Δv = 6.0 m/s - 16.0 m/s = -10.0 m/s. The change in time (Δt) is 4.0 seconds.
Plugging these values into our formula, we get a = -10.0 m/s / 4.0 s = -2.5 m/s².
The negative sign indicates that the car is decelerating or slowing down.
Therefore, the acceleration of the car during this 4.0 second interval is -2.5 m/s² east, meaning it is slowing down.
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Which of the following forces can change velocity?
Acceleration forces
Equal and opposite horizontal forces
Equal and opposite vertical forces
Unequal, opposite forces
Answer:
Option A and Option D are correct.
Explanation:
We have the Newton's second law, that is rate of change of momentum is force.
[tex]\frac{dP}{dt}=F\\\\\frac{mv-mu}{dt}=F[/tex]
So if there is a force mv - mu ≠ 0
v - u ≠ 0
v ≠ u
Final velocity ≠ Initial velocity.
a) Option A is correct since there is a force
b) Option B is wrong since total force is zero.
c) Option C is wrong since total force is zero.
d) Option D is correct since there is an effective force
Option A and Option D are correct.
Known as the twilight zone, the mesopelagic zone meets the photic zone above and becomes very dark as depth increases. Temperature decrease; pressure increases. Because nutrients are limited here, some animals rise to the photic zone at night for food. Many animals in this subzone can eat animals larger than themselves because they are equipped with large sharp teeth with expandable jaws and stomachs. Another key physical feature of animals living in this zone is ____________, which has a variety of purposes, including predator deterrence, communication, and lures for prey.
A) symbiosis
B) transparency
C) bioluminescence
D) oversized scales
Answer: C) bioluminescence
The middle layer of the world's ocean receives very little sunlight. This oceanic layer is called as twilight zone or diphotic zone or mesopelagic zone. This zone appears blue to black in color. The animals that live in this zone are adapted to survive in darkness, high pressure and cold water conditions.
The animals in this zone exhibit large eyes, which helps them to see in dark waters. Most animals are small, thin and dark which helps them to camouflage the predators in darkness. Some animals also possess large teeth and jaws. Many of these animals show bio luminescence, which means they can produce their own light. They have special organs which helps them to produce light by chemical reactions. Animals use light to find food and mates, they camouflage and distract the predators by light.
Answer:
C. Bio-luminescence
Explanation:
Twilight zones is also called meso-pelagic of diphotic zone. this is the zone in the ocean which receives very less sunlight so it appears blue or black in color.The animal which lives in this zone have adapted the capability to live under high pressure, in darkness and in low temperature so they have big eyes to watch the things in dark. Generally they are dark in color to camouflage the predators.
A 0.5-kg ball accelerated at 50 m/s2 . What force was applied?
Answer:
The answer is Force is equal to 25N
Explanation:
1) Taking into account Newton's second law, which expresses that the acceleration that a body acquires is directly proportional to that resulting from the forces acting on it, and has the same direction as that resulting.
2) This law is expressed with the formula F = ma where (F) represents force, (m) represents mass and (a) represents acceleration.
3) knowing this we can replace the values given in the problem and solve:
F = (0,5kg)(50m/s^2)
F = 25N
What building material did you use to build your house? Did your results support or fail to support your hypotheses?
Answer:
Wood Cement base boards
Explanation:
The building material which is required to build our house is cement, wood, and pillars.
Which building material?
Building materials are required to build a house. Wood, aggregates, and cement are some examples of building materials. Some natural materials are the clay, sand and rocks are some of the examples of building materials.
Types of construction materials are:
Natural construction material.FabricMud and clay.Rock BrushMetalConcrete.Plastic pipes and metal pillars are required to build a building. The process of building is called construction. If the building materials are good the quality and durability of houses increases.
Therefore, The building material which is required to build our house is cement, wood, and pillars.
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The strength of the electric field of a charged particle becomes greater as the distance from the particle increases. True or false
The strength of the electric field of a charged particle becomes greater as the distance from the particle increases. this statement is False.
What is electric field ?Electric field is field around electrically charged particle where columbic force of attraction or repulsion can be experienced by other charged particles. It is denoted by letter E and it's SI unit is V/m Volt per meter or N/C newton per coulomb. Electric field comes inward to the center of the negative charge and it is going outward for positive charge. Electric field E is given by E = F/q where F is columbic force experienced by the unit charge.
Electric around a charge having magnitude q is given by
[tex]E = \frac{1}{4\pi r^{2} } \frac{q}{r^{2} }[/tex] where r is the distance from the center of the charge.
from formula we can see that as distance increases electric field decreases because electric field is inverse function of distance r.
Hence above statement is false.
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The fastest plane ever made, the Lockheed SR71, was able to travel 2200 miles per hour. Based on this speed, how far can it travel in 2 hours, 3 hours, and 5 hours?
The distance traveled by the plane in 2 hours, 3 hours, and 5 hours are:
4400 miles6600 miles11000 milesWhat is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
How to determine the distance in 2 hoursSpeed = 2200 mphTime = 2 hDistance =?Distance = speed × time
Distance = 2200 × 2
Distance = 4400 miles
How to determine the distance in 3 hoursSpeed = 2200 mphTime = 3 hDistance =?Distance = speed × time
Distance = 2200 × 3
Distance = 6600 miles
How to determine the distance in 5 hoursSpeed = 2200 mphTime = 5 hDistance =?Distance = speed × time
Distance = 2200 × 5
Distance = 11000 miles
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What might happen to the mass and/or the distance between two objects to increase the gravitational force of attraction?
20 POINTS!!!!
What Rock Would You Be?
Over time, rocks transform from one type to another through the geological processes that occur on Earth. Consider this fact as you read and respond to this lesson's discussion prompts.
Imagine that you are a rock. What type of rock would you be and where would you be located—for example, would you be deep within the Earth or on the surface?
What were you like before you became the rock you are now and what type of rock will you be in the future?
Be sure to describe the processes involved in the changes you have gone through to get to where you are now, as well as the changes you will undergo as you change your rock type again.
Look at Tyler's post:
I am a piece of a sedimentary rock sitting here in the crust. I used to be a magnificent metamorphic rock, but over time, I was weathered down to small pieces by the wind. I became sediment and then was covered by other sediments. In time, I was cemented together with these sediments as they pushed against me with more and more pressure. As the rocks continue to pile on top of me, I will get pushed further underground. Eventually, I will melt and become igneous rock. I know this because it has happened before. It's all part of the rock cycle.
Metamorphism often occurs on two scales: contact and regional. Contact metamorphism occurs relatively locally, in areas adjacent to igneous intrusions or in areas that are in contact with hot water known as hydrothermal fluids.
Typically this kind of metamorphism is caused by moderate pressure and extreme heat that may last for a period of days to thousands of years. In cases of contact metamorphism, the most extreme metamorphism occurs at the contact point between the parent rock and the intrusive magma or hydrothermal fluid. The degree of metamorphism then decreases rapidly as distance from the heat source increases. Depending on the source, zones of contact metamorphism may range from a few millimeters to tens of meters.
In contrast to contact metamorphism, regional metamorphism occurs over much larger areas. In areas such as rising mountain ranges, large igneous intrusions can form and warp overlying strata increasing the pressures above the intrusion. Also the extreme heat and pressures caused by tectonic forces or deep burial will cause widespread metamorphism.
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a soccer ball is kicked with a speed of 15.6m/s at an angle of 32.5 degrees above the horizontal. If the ball lands at the same level from which it was kicked for what amount of time was it in the air?
Answer:
Time of flight, t = 1.71 seconds
Explanation:
It is given that,
Speed of the soccer ball, u = 15.6 m/s
Angle made with the horizontal, [tex]\theta=32.5^{\circ}[/tex]
Let t is the time for which the ball was in the air. The time duration for which the ball is in air is called the time of flight of the projectile. It is given by :
[tex]t=\dfrac{2u\ sin\theta}{g}[/tex]
[tex]t=\dfrac{2(15.6)\ sin(32.5)}{9.8}[/tex]
t = 1.71 seconds
So, the ball was in the air for 1.71 seconds. Hence, this is the required solution.
To find the amount of time the soccer ball was in the air, we can break the initial velocity of the ball into its horizontal and vertical components. The time in the air can be calculated using the vertical velocity component and the vertical distance traveled.
Explanation:To find the amount of time the soccer ball was in the air, we can break the initial velocity of the ball into its horizontal and vertical components. The horizontal component will remain constant throughout the motion, while the vertical component will change due to the force of gravity.
Using the initial velocity of 15.6 m/s and the angle of 32.5 degrees above the horizontal, we can find the vertical velocity component using trigonometry. The vertical velocity component is given by Vy = V * sin(θ), where Vy is the vertical velocity, V is the initial velocity, and θ is the angle above the horizontal.
With the vertical velocity component, we can calculate the time the ball was in the air by dividing the vertical distance it travels by the vertical velocity. Since the ball lands at the same level, the vertical distance can be assumed to be zero. Therefore, the time in the air is given by Δt = 2 * (Vy / g), where Δt is the time in the air, Vy is the vertical velocity component, and g is the acceleration due to gravity (approximately 9.8 m/s²).
What is the “p” process for elements heavier than iron
If you were trying to build a soundproof room, which of the following materials would you choose in order to absorb the most sound, based on the coefficient of absorption for each material?
A. Heavy curtains
B. Wood
C. Concrete
D. Carpet
Explanation :
Absorption coefficient of a material determines how much sound is absorbed by the material.
To build a soundproof room, Heavy curtains and carpet can be used. They reduce reverberation.
Reverberation means an echoing sound which persists for some time. For example, when we bang on a huge piece of metal, we hear the reverberation even after we stop banging.
Hence, option (A) and (D) are correct.
Concrete, carpet, and heavy curtains would be the best materials to choose in order to absorb the most sound in a soundproof room.
Explanation:If you were trying to build a soundproof room, concrete, carpet, and heavy curtains would be the best materials to choose in order to absorb the most sound, based on their coefficient of absorption.
Concrete is a dense and solid material that effectively absorbs sound waves. Carpet and heavy curtains also have a high coefficient of absorption as they are made from materials that can trap and absorb sound.
Wood, on the other hand, is a harder material that reflects sound rather than absorbing it, making it less effective for soundproofing purposes.
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A 30 kg body is moving through space in the positive direction of an x axis with a speed of 170 m/s when, due to an internal explosion, it breaks into three parts. One part, with a mass of 6.1 kg, moves away from the point of explosion with a speed of 69 m/s in the positive y direction. A second part, with a mass of 11 kg, moves in the negative x direction with a speed of 580 m/s. What are the (a) x-component and (b) y-component of the velocity of the third part? (c) How much energy is released in the explosion? Ignore effects due to the gravitational force.
A homeowner installs an electrical heated mirror into the shower room. When a person has a shower, the heated mirror does not go misty but stays clear, why?
Donna stretched a spring to increase its length. Nearby in an electrical device, a positive charge attracted a negative charge. Which statement is true about the spring and the negative charge?
They both experienced contact forces.
They both experienced non-contact forces.
The spring experienced a contact force and the charge experienced a non-contact force.
The spring experienced a non-contact force and the charge experienced a contact force.
The spring experienced a contact force and the charge experienced a non-contact force.
If she stopped pulling no contact spring released.
No contact between charge and - charge, not necessarily, at least.
so i believe the correct answer is C)
a substance that contains only one kind of matter is known as a (n)
how many stars are in the sky
Which term describes the relationship between wax and wane
The term that describes the relationship between wax and wane is "phases." Waxing and waning refer specifically to the phases of the Moon.
The term that describes the relationship between wax and wane is "phases." Waxing and waning refer specifically to the phases of the Moon. The Moon goes through a repeating cycle of phases, transitioning from a new moon (not visible) to a waxing crescent, first quarter, waxing gibbous, full moon, waning gibbous, third quarter, and finally waning crescent before returning to a new moon again.
Waxing describes the Moon's illumination increasing while waning describes the Moon's illumination decreasing.
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if you jump from a window that is 2 meters up you will most likely break the bones in your legs when you land however on a trampoline people can jump up to 6 meters without getting hurt explain why this is true?
Which of the following planets most likely has the coldest surface temperature?
A.
Mercury
B.
Mars
C.
Saturn
D.
Venus
Saturn, Of the planets listed, Saturn is the greatest distance from the Sun. As a result, Saturn receives little of the Sun's warming energy and has a relatively cold surface temperature.
Answer:
The answer is C. Saturn
Explanation:
I had this question on stusdy lsland.
Which type of energy is the greatest at the bottom of a roller coaster hill? A) Potential Energy B) Thermal Energy Eliminate C) Sounds Energy D) Kinetic Energy
Which of the following elements has the highest atomic mass?
1. Helium: 2 protons and 2 neutrons
2. Nitrogen: 7 protons and 7 neutrons
3. Oxygen: 8 protons and 8 neutrons
4. hydrogen: 1 proton and no neutrons
Answer:
Oxygen has the highest atomic mass out of all the four elements.
An atom with an atomic number of 12 and a mass number of 25 can best be described by which of these?
A) An atom that contains 12 protons and 13 neutrons.
B) An atom that contains 13 protons and 12 neutrons.
C) An atom that contains 12 protons and 25 neutrons.
D) An atom that contains 25 protons and 12 neutrons.
Answer:The awnser is A
Explanation:
Just did the test
is the following sentence true or false.. winds blowing inland from oceans carry less water than winds blowing from land
Why is energy needed to break chemical bonds
Julie is an amateur astronomer. Using her telescope, she observes a planet that has large rings with beige and reddish bands. What is Julie most likely observing?
a solid inner planet
a gaseous outer planet
a gaseous inner planet
a solid outer planet
A gaseous outer planet. It has rings so she is most likely looking at Saturn which is a gaseous outer planet with rings.
Reactants → Products
In the picture, which box on the right is the correct products according to the Law of Conservation of Mass?
A) A
B) B
C) C
D) D
Answer: D) D
Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
As the atoms should remain conserved thus there should be 3 yellow atoms, three red atoms and 4 blue atoms in the products.
Thus the correct option is D.
A package of supplies is to be dropped from an airplane so that it hits the ground at a designated spot near some campers. The airplane, moving horizontally at a constant velocity of 130 km/h, approaches the spot at an altitude of 0.520 km above level ground. Having the designated point in sight, the pilot prepares to drop the package. (a) What should the angle be between the horizontal and the pilot's line of sight to the drop point when the package is released? (Neglect air resistance)
Hi there! Can someone help me out please?
Please add details to support your idea.
Thanks!
a student walks 3 miles west and then 4 miles south to get to school the student displacement was
We have that a student walks 3 miles west and then 4 miles south to get to school the student displacement was
D=7miles
From the question we are told
a student walks 3 miles west and then 4 miles south to get to school the student displacement was
Generally the equation for the displacement is mathematically given as
D=intial travel +final Travel
Therefore
D=3+4
D=7miles
Therefore
A student walks 3 miles west and then 4 miles south to get to school the student displacement was
D=7miles
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