Final answer:
Two teams working together will take approximately 133.33 hours or about 5.56 days to clean the city streets. This is less than the one week (7 days) available before filming begins, so the streets will be clean in time.
Explanation:
To calculate how long it will take for two teams working together to clean the city streets, we use the concept of combined work rates.
The first team requires 200 hours to clean the streets, while the second team requires 400 hours.
When working together, we can add their rates of work, which means the first team cleans 1/200 of the city per hour, and the second team cleans 1/400 of the city per hour.
The combined rate of work will be:
1/200 (team A's rate) + 1/400 (team B's rate)
= 2/400 + 1/400
= 3/400
So, together they clean 3/400 of the city per hour. To find out how many total hours it will take to clean the entire city, we take the reciprocal of their combined rate
1 / (3/400)
= 400/3
≈ 133.33 hours
Since there are 24 hours in a day, we divide the total hours by 24 to find out how many days it will take:
133.33 hours / 24 hours/day
≈ 5.56 days
Given that the crew will arrive in one week, which is 7 days, this is within the time frame required before filming begins. The teams have enough time to clean the streets before the cameras start rolling.
9. If the diagonal of a square is 12 centimeters, the area of the square is
A. 102 cm2.
B. 36 cm2.
C. 144 cm2.
D. 72 cm2.
Answer:
D. 72 cm²
Step-by-step explanation:
The area of a square is given by ;
Area= l² where l = length
Given that the diagonal is 12 cm, let assume length of the square to be l
Apply the Pythagorean relationship where a=b=l
l² + l² = 12²
2 l² = 144
l²= 144/2
l²= 72
l =√72 =8.485 cm
⇒length of the square= l= 8.485 cm
⇒Area of the square= l² = 8.485² = 72 cm²
Answer:
36 cm2.
Step-by-step explanation:
The area of square A is 324 cm2. Since the dimensions of square A are three times larger than the dimensions of square B, the scale factor is 3.
To find the area of square B, first square the scale factor, 3.
3 squired =9
Next, divide the area of square A by 9.
324÷ cm2 ÷ 9 =36 cm2
Suppose you invest $100 a month in an annuity that
earns 4% APR compounded monthly. How much money
will you have in this account after 2 years?
A. $2400.18
B. $2518.59
C. $1004.48
D. $3908.26
Answer:
$2502.60
Step-by-step explanation:
The formula for the amount of an annuity due is ...
A = P(1 +r/n)((1 +r/n)^(nt) -1)/(r/n)
where P is the monthly payment (100), r is the annual interest rate (.04), n is the number of compoundings per year (12), and t is the number of years (2). Given these numbers, the formula evaluates to ...
A = $100(1.00333333)(1.00333333^24 -1)/0.00333333
= $100(301)(0.08314296)
= $2502.60
_____
This value is confirmed by a financial calculator. The given answer choices all appear to be incorrect. The closest one corresponds to an annual interest rate (APR) of 4.286%, not 4%.
The blueprints for a new barn have a scale of 1/2 inch = 1 foot. A farmer wants to make sure she will have enough room for 12 new horse stalls to fit along one of the barn walls. Each stall has a width of five feet. If the blueprint of the barn is 20 inches by 30 inches, will there be enough room for the stalls?
Answer: yes
Step-by-step explanation: Wall would be 60 feet wide. 60 / 5 = 12.
Answer:
Yes
Step-by-step explanation:
Given :
1/2 in = 1 foot
re-written as : 1 in = 2 feet
THe blueprint is drawn to be 30 inches long
this is equivalent to 30 in x 2 feet/in = 60 feet long
With a minimum width of 5 feet per stall,
the number of stalls in 60 feet = 60 feet / 5 feet = 12 stalls
Hence there will be enough room for 12 stalls.
What should be done to solve the equation? x+14=21 Add 14 to both sides of the equation. Subtract 14 from the left side of the equation. Add 14 to the left side and subtract 14 from the right side of the equation. Subtract 14 from both sides of the equation.
Answer:
Subtract 14 from both sides of the equation.
Step-by-step explanation:
The subtraction property of equality tells you the equal sign only remains valid if you subtract the same value from both sides of the equation.
Here, we want the 14 on the left side to be replaced by 0. Thus we must add its opposite. Since we must do the same thing to both sides of the equation, we must subtract 14 from both sides of the equation.
Answer:
Last option: Subtract 14 from both sides of the equation.
Step-by-step explanation:
To solve the equation [tex]x+14=21[/tex] you must solve for the variable "x".
To calculate the value of the variable "x" it is important to remember the Subtraction property of equality. This states that:
[tex]If\ a=b\ then\ a-c=b-c[/tex]
Therefore, applying this property, you should subtract 14 from both sides of the equation to find the value of the variable "x". Then:
[tex]x+14-(14)=21-(14)\\\\x=7[/tex]
For the functions f(x) = 2x^2- 5x + 2 and g(x) = x– 2, find (f/g)(x) and (f/g)(4)
Answer:
[tex]\frac{f}{g}(x)=2x-1\\\\\frac{f}{g}(4)=7[/tex]
Step-by-step explanation:
[tex]\frac{f}{g}(x)=\dfrac{2x^2-5x+2}{x-2}=\dfrac{(x-2)(2x-1)}{(x-2)} =2x-1 \quad\text{x$\ne$2}\\\\\frac{f}{g}(4)=2\cdot 4-1=7 \qquad\text{fill in 4 for x and do the arithmetic}[/tex]
[tex]\left(\dfrac{f}{g}\right)(x)=\dfrac{2x^2-5x+2}{x-2}\\\\\left(\dfrac{f}{g}\right)(4)=\dfrac{2\cdot 4^2-5\cdot 4+2}{4-2}=\dfrac{32-20+2}{2}=7[/tex]
Solve the equation 32 – 5y = 87.
A. 11
B. –23.8
C. –11
D. 23.8
Answer:
C. :)
Step-by-step explanation:
Move all terms not containing
y
y
to the right side of the equation.
−
5
y
=
55
-5y=55
Divide each term by
−
5
-5
and simplify.
y
=
−
11
y=-11
Answer: the answer is - A. -11
Step-by-step explanation:
Your fish tank holds 35 liters of water. How much is that in milliliter
Answer:
1 litre = 1000 millilitres (ml)
35 litres = 35×1000 => 35000 ml
So your fish tank holds 35000 ml of water
The parabola y = x² - 4 opens:
A.) up
B.) down
C.) right
D.) left
Answer:
Up
Step-by-step explanation:
Here the easy rules to remember the orientation of the parabolas are
a) If x is squared it opens up or down. And its coefficient of {[tex]x^{2}[tex] is negative it opens down.
b) If y is squared it opens side ways right or left. It its coefficient of [tex]y^{2}[/tex]
Hence in our equation of parabola
[tex]y = x^ 2-4[/tex]
x is squared and its coefficient is positive , hence it opens up towards positive y axis.
Determine all positive number replacements (less than the modulus) for the question mark that make the statement true.
3 x ? = 1 (mod 6)
Answer:
There are none.
Step-by-step explanation:
3 is a divisor of the modulus, so the product mod 6 will be either 3 or 0.
In the modular arithmetic problem 3 x ? = 1 (mod 6), the correct positive number replacement for the question mark is 3.
The problem given is a modular arithmetic equation: 3 x ? = 1 (mod 6). To solve for the question mark (?), we need to find a number that when multiplied by 3 and divided by 6, leaves a remainder of 1. Since we are working with mod 6, the potential replacements for the question mark can only be positive numbers less than 6.
The steps to find the solution are as follows:
Try each positive number less than 6 to see which, when multiplied by 3, yields a remainder of 1 when divided by 6.
By testing, we find that 3 x 5 = 15, and 15 mod 6 = 3 x 6 + 1 (15 = 2*6 + 3).
Since we need a remainder of 1, and not 3, we should keep looking.
Next, 3 x 3 = 9, and 9 mod 6 = 1 since 9 = 1*6 + 3 = 3 x 3.
Thus, the number that satisfies the equation is 3 since it makes the modular equation true: 3 x 3 = 9, and 9 mod 6 = 3 x 6 + 3, which gives us a remainder of 1.
The correct positive number replacement for the question mark making the statement true is 3.
Last year, a construction worker had a gross income of $29,700, of which he contributed 7% to his 401(k) plan. If he got paid monthly, how much was deducted from each paycheck for his 401 (k) plan?
Answer:
$173.25
Step-by-step explanation:
His annual contribution is ...
0.07 × $29,700 = $2079
If 1/12 of that is contributed each month, the monthly contribution is ...
$2079/12 = $173.25
A right rectangular prism has these dimensions: Length ? Fraction 1 and 1 over 2 units Width ? Fraction 1 over 2 unit Height ? Fraction 3 over 4 unit How many cubes of side length Fraction 1 over 4 unit are required to completely pack the prism without any gap or overlap? 36 45 51 60
The volume of the rectangular prism is length x width x height:
Volume = 1 1/2 x 1/2 x 3/4 = 9/16 cubic units.
The volume of cube is length^3 = 1/4^3 = 1/64
Divide the volume of the rectangular prism by the volume of the cube:
Number of cubes = 9/16 / 1/64 = 36
The answer is 36
Need help with this math question
Answer:
[tex]x =7\sqrt{3}[/tex]
Step-by-step explanation:
By definition, the tangent of a z-angle is defined as
[tex]tan(z) =\frac{opposite}{adjacent}[/tex]
For this case
[tex]opposite = 7[/tex]
[tex]adjacent = x[/tex]
[tex]z=30\°[/tex]
So
[tex]tan(30) =\frac{7}{x}[/tex]
[tex]x =\frac{7}{tan(30)}[/tex]
[tex]x =7\sqrt{3}[/tex]
Answer:
7√3 = x
Step-by-step explanation:
Arbitrarily choose to focus on the 30 degree angle. Then the side opposite this angle is 7 and the side adjacent to it is x.
tan 30 degrees = (opp side) / (adj side), or (1√3) = 7 / x.
Inverting this equation, we get √3 = x/7.
Multiplying both sides by 7 results in 7√3 = x
Triangle $ABC$ has side lengths $AB = 9$, $AC = 10$, and $BC = 17$. Let $X$ be the intersection of the angle bisector of $\angle A$ with side $\overline{BC}$, and let $Y$ be the foot of the perpendicular from $X$ to side $\overline{AC}$. Compute the length of $\overline{XY}$.
Answer:
[tex]\dfrac{72}{19}[/tex]
Step-by-step explanation:
Consider triangle ABC. Segment AX is angle A bisector. Its length can be calculated using formula
[tex]AX^2=\dfrac{AB\cdot AC}{(AB+AC)^2}\cdot ((AB+AC)^2-BC^2)[/tex]
Hence,
[tex]AX^2=\dfrac{9\cdot 10}{(9+10)^2}\cdot ((9+10)^2-17^2)=\dfrac{90}{361}\cdot (361-289)=\dfrac{90}{361}\cdot 72=\dfrac{6480}{361}[/tex]
By the angle bisector theorem,
[tex]\dfrac{AB}{AC}=\dfrac{BX}{XC}[/tex]
So,
[tex]\dfrac{9}{10}=\dfrac{BX}{17-BX}\Rightarrow 153-9BX=10BX\\ \\19BX=153\\ \\BX=\dfrac{153}{19}[/tex]
and
[tex]XC=17-\dfrac{153}{19}=\dfrac{170}{19}[/tex]
By the Pythagorean theorem for the right triangles AXY and CXY:
[tex]AX^2=AY^2+XY^2\\ \\XC^2=XY^2+CY^2[/tex]
Thus,
[tex]\dfrac{6480}{361}=XY^2+AY^2\\ \\\left(\dfrac{170}{19}\right)^2=XY^2+(10-AY)^2[/tex]
Subtract from the second equation the first one:
[tex]\dfrac{28900}{361}-\dfrac{6480}{361}=(10-AY)^2-AY^2\\ \\\dfrac{22420}{361}=100-20AY+AY^2-AY^2\\ \\\dfrac{1180}{19}=100-20AY\\ \\20AY=100-\dfrac{1180}{19}=\dfrac{1900-1180}{19}=\dfrac{720}{19}\\ \\AY=\dfrac{36}{19}[/tex]
Hence,
[tex]XY^2=\dfrac{6480}{361}-\left(\dfrac{36}{19}\right)^2=\dfrac{6480-1296}{361}=\dfrac{5184}{361}\\ \\XY=\dfrac{72}{19}[/tex]
Molly shared a spool of ribbon with 12 people. Each person received 3 feet of ribbon. Which equation can she use to find r, the number of feet of ribbon that her spool originally had?
For this case we have that if Molly spent all the spool ribbon with 12 people, then "r" would be given by the product of 12 for the amount of ribbon that each person received, that is:
[tex]r = 12 * 3\\r = 36 \ft[/tex]
Thus, the spool initially had 36 feet of ribbon.
If Molly also keeps 3 feet of ribbon, then the value of "r" is given by:
[tex]r = 13 * 3\\r = 39 \ ft[/tex]
In this case, the ribbon spool initially had 39 feet of ribbon.
Answer:
[tex]r = 36 \ ft[/tex]shared between 12 people
[tex]r = 39 \ ft[/tex]shared between 12 people and Molly
Answer:
It is C. aka 3r = 12.
Step-by-step explanation:
Ethan goes to a store an buys an item that costs x dollars. He has a coupon for 5% off, and then a 9% tax is added to the discounted price. Write an expression in terms of x that represents the total amount that Ethan paid at the register.
Final answer:
Ethan pays a total of 1.0355x dollars at the register for an item with an original price of x dollars, after applying a 5% discount and adding a 9% sales tax to the discounted price.
Explanation:
To calculate the total amount Ethan paid at the register, we need to take into account both the discount and the tax applied to the item's original price. First, we calculate the discounted price by subtracting the 5% off. Then, we add a 9% sales tax to that discounted price.
The original price is x dollars. The discount of 5% is 0.05x, so the discounted price is x - 0.05x, which simplifies to 0.95x. Next, we need to calculate the sales tax on the discounted price. The 9% tax on the discounted price is 0.09 * 0.95x, which is 0.0855x. Finally, to find the total amount paid, we add the sales tax to the discounted price:
Total Amount Paid = (0.95x) + (0.09 * 0.95x) = 0.95x + 0.0855x = 1.0355x
. Evaluate –x + 3.9 for x = –7.2.
Given.
-x + 3.9
Plug in.
-7.2 + 3.9 = -3.3
Answer.
-3.3
Answer:
11.1
Step-by-step explanation:
−(−7.2)+3.9
=7.2+3.9
=11.1
Which statement is true about a skewed distribution?
A.) the mean lies to the right of the median for a positively skewed distribution.
B.) the mean lies to the left of the median for a positively skewed distribution.
C.) the mean lies to the left of the median for a symmetric distribution
D.) a distribution skewed to the left is said to be negatively skewed.
E.) a distribution skewed to the right is said to be positively skewed.
Answer:
B.) the mean lies to the left of the median for a positively skewed distribution.
Step-by-step explanation:
Pls answer fast
Cos65=x/18
Answer:
7.61
Step-by-step explanation:
[tex]cos65=\frac{x}{18}\\x=18cos65\\x=7.61[/tex]
Note: I assumed that all angles were in degrees
Shay works each day and earns more money per hour the longer she works. Write a function to represent a starting pay of $20 with an increase each hour by 4%. Determine the range of the amount Shay makes each hour if she can only work a total of 8 hours.
A.20 ≤ x ≤ 22.51
B.20 ≤ x ≤ 25.30
C.20 ≤ x ≤ 26.32
D.20 ≤ x ≤ 27.37
Answer:
Function: [tex]p(x)=20(1.04)^x[/tex]Range: option D. 20 ≤ x ≤ 27.37Explanation:
The function must meet the rule that the pay starts at $20 and it increases each hour by 4%.
A table will help you to visualize the rule or pattern that defines the function:
x (# hours) pay ($) = p(x)
0 20 . . . . . . . . [starting pay]
1 20 × 1.04 . . . [ increase of 4%]
2 20 × 1.04² . . . [increase of 4% over the previous pay]
x 20 × 1.04ˣ
Hence, the function is: [tex]p(x)=20(1.04)^x[/tex]
The range is the set of possible outputs of the function. To find the range, take into account that this is a growing exponential function, meaning that the least output is the starting point, and from there the output will incrase.
The choices name x this output. Hence, the starting point is x = 20 and the upper bound is when the number of hours is 8: 20(1.04)⁸ = 27.37.
Then the range is from 20 to 27.37 (dollars), which is represented by 20 ≤ x ≤ 27.37 (option D from the choices).
Answer:
its D for shure
Step-by-step explanation:
Easy Points!
Solve for x:
2x + 5 = 9
Happy Summer
Answer:
x = 2
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS = Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction,
and is the order in which you follow for order of operation questions.
First, subtract 5 from both sides.
2x + 5 (-5) = 9 (-5)
2x = 9 - 5
2x = 4
Isolate the x, Divide 2 from both sides:
(2x)/2 = (4)/2
x = 4/2
x = 2
x = 2 is your answer.
~
If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplying the two polynomial equations also have real solutions?
No, there are polynomials that have real solutions but when combined would be possible to have no real solutions.
Answer:
No.
Step-by-step explanation:
No, one easy way to see it is with quadratic formulas. There exists quadratic polynomials with no real solutions, then if you add, subtract or multiply two polynomials and obtain a quadratic formula, possibly this polynomial won't have real solutions.
I am going to give one counterexample:
We have the two polynomials [tex]p(x) = x^2+2x+3[/tex] and [tex]q(x)= 2x^2+3x+4[/tex], then is we subtract q(x)-p(x) we obtain
[tex]2x^2+3x+4-(x^2+2x+3) = 2x^2+3x+4-x^2-2x-3 = x^2+x+1.[/tex]
The resulting polynomial is a quadratic polynomial of the form [tex]ax^2+bx+c[/tex] with a=1, b=1 and c=1. This polynomial has no real solutions, you can check it with the discriminating [tex]b^2-4ac = 1^2-4(1)(1) = 1-4 = -3.[/tex] As the discriminating is negative, the polynomial has no real solutions.
Find an equation for the nth term of the arithmetic sequence.
-3, -5, -7, -9, ...
Answer:
a(n) = -3 - 2(n-1)
Step-by-step explanation:
The most general formula for the nth term of an arithmetic sequence (such as this sequence is) is
a(n) = a(1) + c(n-1), where c is the common difference.
Here a(1) = -3 and c = -2.
Thus,
a(n) = -3 - 2(n-1).
let f(x)=3x+5 and g(x)=x^2.
find (f+g)(x)
i need the answer now plese and thack you
Answer: x² + 3x + 5
Step-by-step explanation:
f(x) = 3x + 5 g(x) = x²
(f + g)(x) = f(x) + g(x)
= 3x + 5 + x²
= x² + 3x + 5
Consider the following sequence of numbers.
The common ratio of the sequence is =?
The sum of the first five terms of the sequence is=?
Blank 1 options: -1/3,-3,1/3,3
Blank 2 options: -303,183,-60,363
Answer:
Blank 1 is -3
Blank 2 is 183
Step-by-step explanation:
Let r be common ratio
[tex]r = \frac{ - 9}{3} \\ r = - 3[/tex]
Sum of first 5 terms
[tex]s = \frac{a( {r}^{n} - 1)}{r - 1} \\ s = \frac{ 3( {( - 3)}^{5} - 1) }{ - 3 - 1} \\ s = 183[/tex]
Answer:
1) Second option: -3
2) Second option: 183
Step-by-step explanation:
1) You can use any two consecutive terms to find the common ratio. This is given by:
[tex]r=\frac{a_n}{a_{n-1}}[/tex]
You can choose these consecutive terms:
[tex]a_n=-9\\a_{n-1}=3[/tex]
Then the common ratio "r" is:
[tex]r=\frac{-9}{3}=-3[/tex]
2) The sum of the first "n" terms can be found with this formula:
[tex]S_n=\frac{a_1(r^n-1)}{r-1}[/tex]
Since ther first term is 3 and you need to find the sum of the first 5 terms, then:
[tex]a_1=3\\n=5[/tex]
Substituting into [tex]Sn=\frac{a_1(r^n-1)}{r-1}[/tex], you get:
[tex]S_{(5)}=\frac{3((-3)^5-1)}{-3-1}=183[/tex]
What would the coordinates of the new image be? (View Picture)
Answer:
T(1, 5), R(7, 7), A(7, 1), M(4, 5)
Step-by-step explanation:
The mapping for -90° rotation is (x, y) ⇒ (y, -x).
for example, T(-5, 1) ⇒ T'(1, 5)
__
If you're doing this with pencil and paper, you can draw the image and axes the way it is, then rotate your drawing 90° clockwise (so the axes line up) and copy it into the first quadrant.
Find the circumference
[tex]\bf \textit{arc's length}\\\\ s=\cfrac{\pi \theta r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ \cline{1-1} \theta =87\\ s=14 \end{cases}\implies 14=\cfrac{\pi (87)r}{180} \\\\\\ 2520=87\pi r \implies \cfrac{2520}{87\pi }=\boxed{r} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad \implies C=2~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \left(\boxed{\cfrac{2520}{87~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}} \right)\implies C = \cfrac{5040}{87} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill C\approx 57.93~\hfill[/tex]
Given x^4 − 4x^3 = 6x^2 − 12x, what are the approximate values of the non-integral roots of the polynomial equation?
Answer:
the values of the non-integral roots of the polynomial equation are:
4.73 and 1.27.
Step-by-step explanation:
To find the roots of the polynomial equation, we need to factorize the equation:
x^4 − 4x^3 = 6x^2 − 12x ⇒ x^4 − 4x^3 -6x^2 +12x = 0
⇒ x(x+2)(x -3 + sqrt(3))(x -3 - sqrt(3))
Then, the non integral roots are:
x1 = 3 - sqrt(3) = 1.26 ≈ 1.27
x2 = 3 + sqrt(3) = 4.73
Then, the values of the non-integral roots of the polynomial equation are:
4.73 and 1.27
The approximate values of the non-integral roots of the polynomial equation are:
1.27 and 4.73
Step-by-step explanation:We are given an algebraic equation as:
[tex]x^4-4x^3=6x^2-12x[/tex]
i.e. it could be written as:
[tex]x^4-4x^3-6x^2+12x=0\\\\i.e.\\\\x(x^3-4x^2-6x+12)=0[/tex]
Since, we pulled out the like term i.e. "x" from each term.
Now we know that [tex]x=-2[/tex] is a root of the term:
[tex]x^3-4x^2-6x+12[/tex]
Hence, we split the term into factors as:
[tex]x^3-4x^2-6x+12=(x-2)(x^2-6x+6)[/tex]
Now, finally the equation could be given by:
[tex]x(x-2)(x^2-6x+6)=0[/tex]
Hence, we see that:
[tex]x=0,\ x-2=0\ and\ x^2-6x+6=0\\\\i.e.\\\\x=0,\ x=2\ and\ x^2-6x+6=0[/tex]
[tex]x=0\ and\ x=2[/tex] are integers roots.
Now, we find the roots with the help of quadratic equation:
[tex]x^2-6x+6=0[/tex]
( We know that the solution of the quadratic equation:
[tex]ax^2+bx+c=0[/tex] is given by:
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex] )
Here we have:
[tex]a=1,\ b=-6\ and\ c=6[/tex]
Hence, the solution is:
[tex]x=\dfrac{-(-6)\pm \sqrt{(-b)^2-4\times 1\times 6}}{2\times 1}\\\\i.e.\\\\x=\dfrac{6\pm \sqrt{36-24}}{2}\\\\i.e.\\\\x=\dfrac{6\pm \sqrt{12}}{2}\\\\i.e.\\\\x=\dfrac{6}{2}\pm \dfrac{2\sqrt{3}}{2}\\\\i.e.\\\\x=3\pm 3\\\\i.e.\\\\x=3+\sqrt{3},\ x=3-\sqrt{3}[/tex]
Now, we put [tex]\sqrt{3}=1.732[/tex]
Hence, the approximate value of x is:
[tex]x=3+1.732,\ x=3-1.732\\\\i.e.\\\\x=4.732,\ x=1.268[/tex]
Match each item in Column A to an answer in Column B. 2. What is the distance between the two points on a number line? Column A Column B 1. X = –6, Y = 11 2. P = 8, Q = –15 3. U = –3, V = –20 4. J = 16, K = 7 A. 9 B. 17 C. 23
Answer:
17 (B)23 (C)17 (B)9 (A)Step-by-step explanation:
The distance between two points on a number line is the difference between the rightmost point and the leftmost point.
1. 11 -(-6) = 11+6 = 17
2. 8 -(-15) = 8+15 = 23
3. -3 -(-20) = -3+20 = 17
4. 16 -7 = 9
Mike is a salesperson in a retail carpet store. He is paid $500 base salary per month plus 5% commission on sales over $10,000. His sales this month were $23,750. His total deductions were $152.75. What is Mike’s net pay?
Answer:
$1034.75
Step-by-step explanation:
Mike's net pay is ...
base pay + commission - deductions
= $500 + 5%(23750 -10000) -152.75
= 347.25 + 0.05×13750
= $1034.75
Answer:
$1034.75
Step-by-step explanation:
Here we are given that the base salary of Mike is $500. He is also rewarded with some commission depending on sales. Hence we can bifurcate his gross pay as
Gross Pay = Base Pay + Commission
Commission = 5% of Sales over $10000
= 5% of (23750-10000)
= 5% of 13750
= 0.05*13750
= 687.50
Hence Gross pay = 500 + 687.50
= 1187.50
Also given that he has some deductions also i.e. $152.75 .
Therefor Net pay = Gross pay - Deductions
= 1187.50-152.75
= 1034.75
Hence Net Pay = $1034.75
Which expression is equivalent?
Answer:
Third choice from the top is the one you want
Step-by-step explanation:
This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out. For example:
[tex]\sqrt[6]{x^6} =x[/tex] and another example:
[tex]\sqrt[12]{2^{12}}=2[/tex]
Let's take this step by step. First we will rewrite both the numerator and the denominator in rational exponential equivalencies:
[tex]\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}[/tex]
In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number. The LCM of 3 and 4 is 12. So we rewrite as
[tex]\frac{6^{\frac{3}{12} }}{2^{\frac{4}{12} }}[/tex]
Now we will put it back into radical form so we can rationalize the denominator:
[tex]\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }[/tex]
In order to rationalize the denominator, we need the power on the 2 to be a 12. Right now it's a 4, so we are "missing" 8. The rule for multiplying like bases is that you add the exponents. Therefore,
[tex]2^4*2^8=2^{12}[/tex]
We will rationalize by multiplying in a unit multiplier equal to 1 in the form of
[tex]\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }[/tex]
That looks like this:
[tex]\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }*\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }[/tex]
This simplifies down to
[tex]\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }[/tex]
Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2! Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:
[tex]\frac{\sqrt[12]{55296} }{2}[/tex]
Phew!!!