A concrete highway curve of radius 60.0 m is banked at a 19.0 ∘ angle. what is the maximum speed with which a 1400 kg rubber-tired car can take this curve without sliding? (take the static coefficient of friction of rubber on concrete to be 1.0.)

Answer:Friction force

Explanation:

The frictional force is responsible for stopping the moving object.

The friction force is provided by nature in the form of air resistance, fluid resistance, Surface resistance.

For surface resistance, the friction force is of two types namely kinetic friction force and static friction force.

Static friction acts when the object is stationary and a force is applied to cause the motion while kinetic friction acts when the body starts moving.

kinetic friction is lesser is in magnitude as compared to static friction.

The misunderstood force that causes objects to seem to stop on their own is known as friction. This force opposes the motion of objects. The misconception was fixed with Newton's first law of motion.

The force that people did not understand before they realized that objects have a tendency to maintain their velocity in a straight line unless acted upon by a net force is friction. Friction is a force that opposes movement. It's the reason why objects seem to stop on their own when in contact with other objects or surfaces. The perception that an object moves and then eventually stops due to its own 'nature' occurs because friction was at play, causing it to slow down and finally stop. It was Sir Isaac Newton who, in his first law of motion, clarified this misperception by stating that an object in motion stays in motion unless acted upon by an external force.

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Answer:

The current in R₁ is 0.0816 A.

The current at H point is 0.0243 A.

Explanation:

Given that,

Voltage = 64.5

Resistance is

[tex]R_{1}=711\ \Omega[/tex]

[tex]R_{2}=182\ \Omega[/tex]

[tex]R_{3}=663\ \Omega[/tex]

[tex]R_{4}=534\ \Omega[/tex]

[tex]R_{5}=265\ \Omega[/tex]

Suppose, The specified points are R₁ and H.

According to figure,

R₂,R₃,R₄ and R₅ are connected in parallel

We need to calculate the resistance

Using parallel formula

[tex]\dfrac{1}{R}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}+\dfrac{1}{R_{4}}+\dfrac{1}{R_{5}}[/tex]

Put the value into the formula

[tex]\dfrac{1}{R}=\dfrac{1}{182}+\dfrac{1}{663}+\dfrac{1}{534}+\dfrac{1}{265}[/tex]

[tex]\dfrac{1}{R}=\dfrac{35501}{2806615}[/tex]

[tex]R=79.05\ \Omega[/tex]

R and R₁ are connected in series

We need to calculate the equilibrium resistance

Using series formula

[tex]R_{eq}=R_{1}+R[/tex]

[tex]R_{eq}=711+79.05[/tex]

[tex]R_{eq}=790.05\ \Omega[/tex]

We need to calculate the equivalent current

Using ohm's law

[tex]i_{eq}=\dfrac{V}{R_{eq}}[/tex]

Put the value into the formula

[tex]i_{eq}=\dfrac{64.5}{790.05}[/tex]

[tex]i_{eq}=0.0816\ A[/tex]

We know that,

In series combination current distribution in each resistor will be same.

So, Current in R and R₁ will be equal to [tex]i_{eq}[/tex].

The current at h point will be equal to current in R₅

We need to calculate the voltage in R

Using ohm's law

[tex]V=I_{eq}\timesR[/tex]

Put the value into the formula

[tex]V=0.0816\times79.05[/tex]

[tex]V=6.45\ Volt[/tex]

In resistors parallel combination voltage distribution in each part will be same.

So, [tex]V_{2}=V_{3}=V_{4}=V_{5}=6.45 V[/tex]

We need to calculate the current at H point  

Using ohm's law

[tex]i_{h}=\dfrac{V_{5}}{R_{5}}[/tex]

Put the value into the formula

[tex]i_{h}=\dfrac{6.45}{265}[/tex]

[tex]i_{h}=0.0243\ A[/tex]

Hence, The current in R₁ is 0.0816 A.

The current at H point is 0.0243 A.

Answer: C. L

Explanation:

Internal forces are forces that are produced from external forces which are acting on structure members. Example of such members include beams, and columns. There are three types of internal forces which are, axial, shear and moment.

Angular momentum is the rotational or angular equivalent of linear momentum. It is a conserved quantity.

As angular momentum is a conserved quantity, internal forces are unable to change it.

The magnitude of the new angular momentum for the uniform sphere of radius ([tex]\frac{R}{2}[/tex]) is: C. L.

An internal force refer to a force that is typically generated from an external force which acts on structure members such as columns, poles and beams.

Also, internal forces are exchanged between the objects in a system.

Generally, there are three (3) main types of internal forces and these include:

Angular momentum is specific to rotational motion and it is the product of an object's moment of inertia and its angular velocity.

According to law of conservation of momentum, the initial angular momentum of an object is always equal to the final angular momentum.

This ultimately implies that, angular momentum is a conserved quantity.

In this context, the magnitude of the new angular momentum for the uniform sphere of radius ([tex]\frac{R}{2}[/tex]) is equal to L because it is conserved.

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Answer:

The total work done by the mover is 2.81 kJ.

Explanation:

Given the 46 kg crate is displaced by 10.4 meters.

And the acceleration is zero. Also, [tex]\mu_k=0.60[/tex]

let [tex]P[/tex] is applied force, [tex]F_N[/tex] is the net force, [tex]m[/tex] is the mass and [tex]g=9.81\ m/s^2[/tex]

and [tex]\mu_k=0.60[/tex]

[tex]F_N=P- \mu_k\times mg[/tex]

As the acceleration is zero, the net force will also be zero.

[tex]0=P- \mu_k\times mg\\P=\mu_k\times mg[/tex].

[tex]P=0.6\times 46\times 9.81=270.76\ N[/tex]

Now, we know the work done is force times displacement.

So,

[tex]W=P\times d\\W=270.76\times 10.4=2815.90\ J\\W=2.81\ kJ[/tex]

So, the total work done by the mover to displace 46 kg crate by 10.4 meters 2.81 kJ.

Answer:

Average power = 0.240Watts

Explanation:

The insect requires double the force on its wings to counteract the gravitational force pulling it down.it generates upward force as below

Upward Force=2Gravitational force

force =2x(mass x gravitational pull)

F=(0.007x9,8)x 2

F=0.137 Nm

Power generated is =work/time

power =force *displacement/time

convert 1.5cm to SI units meters=0.015meters

displacement in one second is=0.015 x number of strokes

displacement =0.015*117

displacement =1.755 meters

power=(0.137*1.755)/1second

power=0.240 Watts

Answer:

The correct option is option "a" i.e.  8.4 m

Explanation:

Frequency (f) = 500 Hz

speed of sound (v) = 340 m/s

wavelength = [tex]\frac{v}{f}[/tex]  

                    = [tex]\frac{340}{500}[/tex]

                    = 0.68 meters

Half wavelength = [tex]\frac{1}{2}[/tex] wavelength

                           = 0.34 meters

For the sound interference to be destructive, the second source must be an odd multiple of 1/2 wavelength away from the first.  so:

5 m + 0.34 m = 5.34 m

5 m + 3×0.34 m = 6.02 m

5 m + 5×0.34 m = 6.7 m

5 m + 7×0.34 m = 7.38 m

5 m + 9×0.34 m = 8.06 m  

5 m + 11×0.34 m = 8.74 m

The value closest to any options provided above is 8.06 m. So the correct option is 8.4 m.

Answer:

Emission spectrum

Explanation:

The emmison spectrum is unique to every elements

Light consists of electromagnetic radiation of different wavelengths. Therefore, when the elements or their compounds are heated either on a flame or by an electric arc they emit energy in the form of light.

The color band indicate the amount of energy emitted in form of electromagnetic radiation.

When electrons in an atom gain energy, the become excited, on falling and losing their energy, they return to their ground state releasing the measure of energy they absorbed in transitioning.

The characteristic color bands emitted by an element when heated are called line spectra, which act as a unique fingerprint for the element and are important for identifying various physical properties.

The characteristic color bands that represent the range of radiations emitted by an element when it is heated are known as the line spectra. When elements are heated to incandescence, like in Bunsen and Kirchhoff's experiments, they emit light with a series of sharp wavelengths characteristic of that element's atomic composition.

This light, when analyzed using a spectrometer or a simple prism, results in visible narrow bands of colors, each corresponding to a specific wavelength. For instance, hydrogen emits a red light with a strong line at 656 nm, and sodium is known to emit in the yellow portion of the spectrum at about 589 nm.

The line spectra serve as a unique fingerprint for each element and are crucial for understanding not only the chemical composition but also various physical properties such as temperature and density of the radiant gas. In terms of non-visible bands, color palettes are often chosen to represent different levels of brightness, energies of photons, and inferred physical properties from data modeling, which are essential in the study of astronomy and spectroscopy.

Answer:

The correct option is false

Explanation:

Awning windows are easy to open windows (made of glass) that are hinged at the top and are opened from the bottom. These windows form a slant (of about 45 degree) after opening hence do not open 100%; this slant opening is advantageous in preventing rain from entering the building.

The windows can also be tightly sealed (from the inside) during extreme/cold weather conditions but are not commonly used everywhere in the world because of there limitations (slight openings) which can prevent proper ventilation in hot regions.

Answer:

The final pressure of the whole system is 34.80 atm.

Explanation:

Given that,

Volume = 45.0 ml

Volume of first bulb = 77.0 mL

Pressure  = 8.89 atm

Volume of second  bulb = 250 mL

Pressure = 2.82 atm

Volume of third  bulb = 21.0 mL

Pressure = 8.42 atm

We need to calculate the final pressure of the whole system

Using formula of pressure

[tex]P_{1}V_{1}+P_{2}V_{2}+P_{3}V_{3}+P_{t}V_{t}=P_{f}V_{f}[/tex]

Where, [tex]P_{1}[/tex]= pressure of first bulb

[tex]P_{2}[/tex]= pressure of second bulb

[tex]P_{3}[/tex]= pressure of third bulb

[tex]P_{4}[/tex]= initial pressure of tube

[tex]V_{1}[/tex]= Volume of first bulb

[tex]V_{2}[/tex]=Volume of second bulb

[tex]V_{3}[/tex]= Volume of third bulb

[tex]V_{4}[/tex]= Initial volume of tube

Put the value into the formula

[tex]8.89\times77.0+250\times2.82+21.0\times8.42+0=P_{f}\times45[/tex]

[tex]P_{f}=\dfrac{1566.35}{45}[/tex]

[tex]P_{f}=34.80\ atm[/tex]

Hence, The final pressure of the whole system is 34.80 atm.

Answer:

Mass needed to fire is [tex]3 \times 10^4 kg[/tex]

Explanation:

Mass of the spaceship [tex]m_{0} = 5.30 \times 10^4 kg[/tex]

Initial velocity of the spaceship[tex]v_{0} = 5.75 \times 10^3 m/s[/tex]

Final velocity of the spaceship [tex]v_{f} = 8.39 \times 10^3 m/s[/tex]

Take exhaust velocity [tex]u = 4.6\times 10^3 m/s[/tex]

The velocity of the spaceship in the  space is

[tex]v_{f}=v_{0}+u\times ln(\frac{m_{0}}{m} )\\8.39 \times 10^3= 5.75 \times 10^3+ 4.6 \times 10^3 \times ln(\frac{5.30 \times 10^4}{m} )\\8.39 \times 10^3-5.75 \times 10^3= 4.6 \times 10^3 \times ln(\frac{5.30 \times 10^4}{m} )\\2.64 \times 10^3=4.6 \times 10^3 \times ln(\frac{5.30 \times 10^4}{m} )\\\frac{2.64 \times 10^3}{4.6 \times 10^3} = ln(\frac{5.30 \times 10^4}{m} )\\0.57=ln(\frac{5.30 \times 10^4}{m} )\\e^{0.57}=\frac{5.30 \times 10^4}{m}\\m=\frac{5.30 \times 10^4}{1.768} \\m=3 \times 10^4 kg[/tex]

Mass needed to fire is [tex]3 \times 10^4 kg[/tex]

The HCP structure has the fewest slip directions, making HCP metals like Mg and Zn more difficult to deform at room temperature compared to those with BCC or FCC structures.

The crystal structure that has the fewest slip directions and is thus generally more difficult to deform at room temperature is the hexagonal close-packed (HCP) structure. Metals with the HCP structure include Cd, Co, Li, Mg, Na, and Zn. The nature of HCP's stacking arrangement, with alternating type A and type B close-packed layers (ABABAB...), results in fewer slip systems compared to body-centered cubic (BCC) and face-centered cubic (FCC) structures. BCC structures, found in metals like K, Ba, Cr, Mo, W, and Fe, have a coordination number of 8, whereas FCC structures have a coordination number of 12 and include metals like Ag, Al, Ca, Cu, Ni, Pb, and Pt. The closer atomic packing found in FCC, identified as CCP or cubic close-packed, is reflected in the ABCABCABC... stacking sequence, which affords a higher number of slip directions.

2 m/s² is the acceleration.

Explanation:

Acceleration is defined as the rate of change in velocity with respect to time.

Here the initial velocity, u = 4 m/s

   the final velocity , v = 12 m/s

time = 4 seconds

Acceleration = [tex]\frac{v-u}{t}[/tex]

Plug in the values, we will get,

Acceleration = [tex]\frac{12-4}{4}[/tex]

                  = [tex]\frac{8}{4}[/tex] = 2 m/s²

The speed of the cannon immediately after it was fired is approximately 0.903 m/s in the opposite direction to the cannonball, as determined by the conservation of momentum.

To find the speed of the cannon immediately after it was fired, we can use the principle of conservation of momentum. In this scenario, the total momentum before the firing is zero (since both the cannon and the cannonball are initially at rest), and the total momentum after the firing is also zero (as there are no external horizontal forces acting on the system). Therefore, the momentum of the cannon and cannonball must cancel each other out.

The conservation of momentum can be expressed as:

Initial momentum = Final momentum

The initial momentum of the system is zero, so:

0 = momentum of cannon + momentum of cannonball

Now, we need to calculate the momentum of the cannonball. Momentum (p) is given by the formula:

p = mass × velocity

The mass of the cannonball is 16.7 kg, and its velocity after leaving the barrel is 113 m/s. Therefore:

Momentum of cannonball = 16.7 kg × 113 m/s

Now, since the total momentum is zero:

0 = momentum of cannon + (16.7 kg × 113 m/s)

Now, we can solve for the momentum of the cannon:

momentum of cannon = - (16.7 kg × 113 m/s)

momentum of cannon ≈ -1887.1 kg m/s

The negative sign indicates that the cannon moves in the opposite direction to the cannonball. Now, we can find the velocity of the cannon using its mass:

momentum of cannon = mass of cannon × velocity of cannon

-1887.1 kg m/s = 2090 kg × velocity of cannon

Now, solve for the velocity of the cannon:

velocity of cannon ≈ -0.903 m/s

So, the speed of the cannon immediately after it was fired is approximately 0.903 m/s in the opposite direction to the cannonball.

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The question probable may be:

A revolutionary war cannon, with a mass of 2090 kg, fires a 16.7 kg ball horizontally. The cannonball has a speed of 113 m/s after it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immedi-ately after it was fired?

Answer in units of m/s

Answer: 800N

Explanation:

Given :

Mass of ball =0.8kg

Contact time = 0.05 sec

Final velocity = initial velocity = 25m/s

Magnitude of the average force exerted on the wall by the ball is can be calculated using the relation;

Force(F) = mass(m) * average acceleration(a)

a= (initial velocity(u) + final velocity(v))/t

m = 0.8kg

u = v = 25m/s

t = contact time of the ball = 0.05s

Therefore,

a = (25 + 25) ÷ 0.05 = 1000m/s^2

Therefore,

Magnitude of average force (F)

F=ma

m = mass of ball = 0.8

a = 1000m/s^2

F = 0.8 * 1000

F = 800N

Answer:

THE ANSWER IS: TRUE

Explanation:

Strategic planning is indeed long-range and formulated by top management but not under the assumption that the company operates in a vacuum. Effective strategic planning acknowledges and incorporates external factors.

The statement is partially true and partially false. It is accurate that strategic planning is long-range and formulated by top management. These types of plans typically look several years into the future to set comprehensive goals for the company. However, the statement is false in suggesting that strategic planning is done as if a company operates in a vacuum. In truth, effective strategic planning must incorporate external influences like market trends, competitive activities, and regulatory changes.

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Answer:

fail to reject the null hypothesis; there is not sufficient evidence to support the claim that the songs are from a population with a standard deviation less than one minute  

Explanation:

Answer:

Work done = 87.5 J

Explanation:

Given:

Force required to stretch the spring (F) = 250 N

Extension of the spring (x) = 30 cm = 0.30 m     [1 cm = 0.01 m]

So, spring constant (k) of the spring is given as:

[tex]k=\frac{F}{x}\\\\k=\frac{250\ N}{0.30\ m}=833.33\ N/m[/tex]

Also given:

Initial length of the spring (x₁) = 20 cm = 0.20 m

Final length of the spring (x₂) = 50 cm = 0.50 m

Now, work done in stretching the spring from an initial length (x₁) to final length (x₂) is given as:

[tex]W=\frac{1}{2}k(x_2^2-x_1^2)[/tex]

Plug in the given values and solve for 'W. This gives,

[tex]W=\frac{1}{2}\times \frac{250}{0.3}\times (0.50^2-0.20^2)\\\\W=\frac{1250}{3}\times (0.25-0.04)\\\\W=\frac{1250\times 0.21}{3}=87.5\ J[/tex]

Therefore, work is done in stretching the spring from 20 centimeters to 50 centimeters is 87.5 J

The work done in stretching a spring can be calculated using Hooke's law. Here, to find the work done in stretching a spring from 20 centimeters to 50 centimeters, we first find the spring constant using the given force and distance, then compute the work using the difference in the squares of the final and initial stretching distances. The work done is 104.1 Joules.

The subject of this question pertains to the physics concept of work done on an object, in this case, a spring. When a force is applied to a spring, it stretches, and in doing so, work is done. The work done can be calculated using Hooke's Law, which states that the force (F) needed to extend or compress a spring by some distance X is proportional to that distance. This is represented by the equation F = kX, where k is the spring constant.

First, we need to find the spring constant k using the provided force (250 newtons) and the initial stretching distance (30 centimeters or 0.3 meters), so k = F/X = 250/0.3 = 833.33 N/m.

Next, we compute the work done in stretching the spring from 20 centimeters (0.20 meters) to 50 centimeters (0.50 meters). The work done (W) on a spring is given by the equation W =1/2*k*(X2^2-X1^2), where X2 and X1 are the final and initial stretching distances respectively. So, W = 1/2 * 833.33 * ((0.5)^2 - (0.2)^2) = 104.1 Joules.

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Answer:

[tex]2.72\times 10^{6} J[/tex]

Explanation:

Molar mass of isooctane will be 12*8+8=114 g/mole

Combustion of 21.8 gal yields energy of

21.8*3780*0.692*-5440/114=-2721124.6484210 J

In scientific notation, this is [tex]2.72\times 10^{6} J[/tex]

Answer:

The three lowest possible values for d are 0.85 m, 2.55 m and 4.25 m.

Explanation:

Given that,

Distance = d

Frequency = 200 Hz

Speed of sound = 340 m/s

We need to calculate the wave length

Using formula of frequency

[tex]f= \dfrac{v}{\lambda}[/tex]

[tex]\lambda=\dfrac{v}{f}[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{340}{200}[/tex]

[tex]\lambda=1.7\ m[/tex]

We need to calculate the three lowest possible values for d

Using formula of destructive interference

[tex]\Delta\phi=2\pi\dfrac{\Delta x}{\lambda}[/tex]

[tex]2\pi\dfrac{\Delta x}{\lambda}=(m+\dfrac{1}{2})2\pi[/tex]

Where, [tex]\Delta x[/tex] = distance

Put the value into the formula

For m = 0,

[tex]\dfrac{\Delta x}{1.7}=(0+\dfrac{1}{2})[/tex]

[tex]\Delta x=\dfrac{1.7}{2}[/tex]

[tex]\Delta x=0.85\ m[/tex]

For m =1 ,

[tex]\dfrac{\Delta x}{1.7}=(1+\dfrac{1}{2})[/tex]

[tex]\Delta x=\dfrac{1.7\times3}{2}[/tex]

[tex]\Delta x=2.55\ m[/tex]

For m=2,

[tex]\dfrac{\Delta x}{1.7}=(2+\dfrac{1}{2})[/tex]

[tex]\Delta x=\dfrac{1.7\times5}{2}[/tex]

[tex]\Delta x=4.25\ m[/tex]

Hence, The three lowest possible values for d are 0.85 m, 2.55 m and 4.25 m.

The three lowest possible values for d are 0.85 m, 2.55 m and 4.25 m.

Since we are looking for the points of no sound, these are points of destructive interference. So, the path difference, ΔL which is the distance between the two speakers, d is

ΔL = d = (n + 1/2)λ where

So, d = (n + 1/2)v/f

d = (n + 1/2)340m/s ÷ 200 Hz

d = (n + 1/2)1.7 m

The lowest possible values of d are when n = 0, 1 and 2.

So,

d = (n + 1/2)1.7 m

d = (0 + 1/2)1.7 m

d = (1/2)1.7 m

d = 0.85 m

d = (n + 1/2)1.7 m

d = (1 + 1/2)1.7 m

d = (3/2)1.7 m

d = (1.5)1.7 m

d = 2.55 m

d = (n + 1/2)1.7 m

d = (2 + 1/2)1.7 m

d = (5/2)1.7 m

d = 2.5 × 1.7 m

d = 4.25 m

So, the three lowest possible values for d are 0.85 m, 2.55 m and 4.25 m.

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Meselson and Stahl

Explanation:

The classic experiment that supported the semiconservative model of dna replication was performed by Matthew Meselson and Franklin W. Stahl. In this model, the two strands of DNA unwind from each other, and each acts as a template for synthesis of a new, complementary strand. This results in two DNA molecules with one original strand and one new strand. They used E. coli bacteria as a model system.

Answer:

ΔPE= -4.8×10⁻²⁰J

Explanation:

Given data

Electric field of strength E=3.0 N/C

Charge of proton q=1.60×10⁻¹⁹C

Proton moves distance d=10 cm=0.10 m

To find

Change in electrical potential energy ΔPE

Solution

As we know that:

ΔPE= -qEd

[tex]=-(1.60*10^{-19}C )(3.0N/C)(0.10m)\\=-4.8*10^{-20}J[/tex]

ΔPE= -4.8×10⁻²⁰J

Answer:

Explanation:

Given:

D = 10 cm

= 0.1 m

E = 3.0 N/C

Qp = 1.602 × 10^-19 C

U = Q × V

But,

V = E × D

= 3 × 0.1

= 0.3 V

U = 1.602 × 10-19 × 0.3

= 4.806 × 10^-20 J.

Answer:

Explanation:

Given

Person travel 180 km with [tex]v_1=95\ km/h[/tex]

and slow down to [tex]v_2=65\ km/h[/tex] due to rain

time taken to cover 180 km is

[tex]t_1=\dfrac{180}{95}[/tex]

[tex]t_1=1.89\ hr[/tex]

total time [tex]T=4.5\ hr[/tex]

suppose [tex]t_2[/tex] is the time for which it travels with [tex]v_2=65\ km/h[/tex]

[tex]t_2=T-t_1[/tex]

[tex]t_2=4.5-1.89[/tex]

[tex]t_2=2.61\ hr[/tex]

so distance travel during this time [tex]d_2=v_2\times t_2[/tex]

[tex]d_2=65\times 2.61[/tex]

[tex]d_2=169.65\ km[/tex]

total distance [tex]d=180+d_2[/tex]

[tex]d=180+169.65[/tex]

[tex]d=349.65\ km[/tex]

(b)Average speed

[tex]v_{avg}=\dfrac{Distance}{time}[/tex]

[tex]v_{avg}=\dfrac{349.65}{4.5}[/tex]

[tex]v_{avg}=77.7\ km/h[/tex]

Answer: C

Explanation:

Matter is anything that has mass and takes up space. People, paper, goats, chairs and even water is Matter!

Matter can be defined as something that has mass and occupies space. They are present in the atmosphere in different phases. Thus, the correct option is C.

Matter is any substance which is made up of various types of particles that occupies some physical space and has mass. According to the modern physics, there are various types of particles with each having a specific mass and size. The most common examples of these material particles are electrons, protons and neutrons.

Matter is present in different phases in the atmosphere. The three phases are solids, liquids, and gases. All of these phases show mass and occupies some space.

Therefore, the correct option is C.

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Answer:

Explanation:

Imagine that current runs in all the 5 sides . In that case the pentagon will have a magnetic moment directed in z- direction . So in the magnetic field it will experience a torque equal to MB where M is magnetic moment and B is magnetic field. But net force on it will be zero.

So , force on four sides due to magnetic field will be equal and opposite to force on fifth side if current runs through it.

force on fifth side if current runs through it

= BIL

= .222 x 3.33 x .0555

= 41.03 x 10⁻³ N .  

Answer:

The required torque is 1.17 N-m.

Explanation:

The given data :-

The magnitude of force ( F ) = 4.5 N.

The length of arm ( r ) = 0.26 m.

Here given that force is applied at perpendicular means ( ∅ ) = 90°.

The torque ( T ) is given by

T = F * r * sin∅

T = 4.5 * 0.26 * sin 90°

T = 4.5 * 0.26 * 1

T = 1.17 N-m.

The magnitude of the torque produced by the given force perpendicular to the lever is 1.17N.m.

Given the data in the question;

Torque; [tex]T = \ ?[/tex]

Torque simply the measure of the force that can cause an object to rotate about an axis. It is expressed as:

[tex]T = rFsin\theta[/tex]

Where r is radius, F is force applied and θ is the angle between the force and the lever arm.

We substitute our given values into the equation;

[tex]T = 0.26m * 4.5N * sin90^o\\\\T = 0.26m * 4.5N * 1\\\\T = 1.17N.m[/tex]

Therefore, the magnitude of the torque produced by the given force perpendicular to the lever is 1.17N.m.

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Answer:

[tex]Q_{H}=6.4kJ/s[/tex]

Explanation:

Given data

Coefficient of performance of a residential heat pump=1.6

Electrical power P=4kW

Required

Heat Q

Solution

The rate of heat produced is given as

[tex]Q_{H}=COP_{HP}Win\\[/tex]

Substitute the given values

So

[tex]Q_{H}=4kW*1.6\\Q_{H}=6.4kJ/s[/tex]

The tangential speed v that the bob must have is: v = [tex]\sqrt{gLsin(\theta)tan(\theta)[/tex]

And the time for one full revolution is: T = [tex]\frac{2\pi \sqrt{Lsin(\theta)}}{\sqrt{g tan(\theta)}}[/tex]

To solve this problem, we need to find the tangential speed, v, that the bob must have to move in a horizontal circle and the time, T, it takes to make one complete revolution. Here’s a step-by-step approach to the solution:

Determine the radius of the circular motion (R):

Given that the string length is L and the angle from the vertical is θ, the radius of the horizontal circle can be expressed as:

R = L sin(θ)

Analyze the forces acting on the bob:

The forces acting on the bob are:

Equations of motion:

In the vertical direction, since there is no vertical acceleration, the vertical component of the tension must balance the weight of the bob:

Tcos(θ) = mg

In the horizontal direction, the horizontal component of the tension provides the centripetal force necessary for the circular motion:

Tsin(θ) = mv²/R

Solve for the tension (T):

From the vertical force balance equation:

T = mg ​/cos(θ)

Substitute T into the horizontal force equation and solve for v:

mgsin(θ) /cos(θ) ​= mv²/R

Simplifying, we get:

gtan(θ) = v² /R​

Substitute R = L sin(θ):

gtan(θ) = Lsin(θ)v²

Solving for v, we get:

v = [tex]\sqrt{gLsin(\theta)tan(\theta)}[/tex]

Determine the period of the motion (T):

The time for one complete revolution (T) is the circumference of the circle divided by the tangential speed v:

T = 2πR /v​

Substitute R and v:

T = [tex]\frac{2\pi Lsin(\theta)}{\sqrt{gLsin(\theta)tan(\theta)}}[/tex]

Simplifying further:

T = [tex]\frac{2\pi \sqrt{Lsin(\theta)}}{\sqrt{g tan(\theta)}}[/tex]

Therefore, the tangential speed v:  v = [tex]\sqrt{gLsin(\theta)tan(\theta)[/tex]  ,and the period of revolution is: T = [tex]\frac{2\pi \sqrt{Lsin(\theta)}}{\sqrt{g tan(\theta)}}[/tex].

Answer:going uphill; downhill.

Explanation:A steep road is a road has a that 45-degree pitch and both mean that a run descends one vertical foot for each horizontal foot. For a one way mountainous road,if two vehicles meet at a steep point, the enabling traffic law states that the vehicle going uphill must back up for the one going downhill to pass through. This is to prevent any form of accident,as the vehicle descending will be coming with a very high velocity than the one trying to go uphill.

Answer:

1.9 s

Explanation:

We are given that

Length of cable=l=15 m

We have to find the time you have to move out of the way.

We know that

Time period,T=[tex]2\pi\sqrt{\frac{l}{g}}[/tex]

Where g=[tex]9.8m/s^2[/tex]

By using the formula

[tex]T=2\pi\sqrt{\frac{15}{9.8}}[/tex]

[tex]T=2\times 3.14\times \sqrt{\frac{15}{9.8}}=7.77 s[/tex]

Time you have to move out

[tex]t=\frac{T}{4}=\frac{7.77}{4}=1.9 s[/tex]

Hence,time you have to move out of the way=7.77 s

Answer:

[tex]h=24\ in[/tex] is the height of the TV screen.

Explanation:

Given:

diagonal of TV screen, [tex]d=40\ in[/tex]

width of TV scree, [tex]w=32\ in[/tex]

As we know that the TV screen is rectangular in shape so including its height and with along with the diagonal forms a right angled triangle in which the diagonal is the hypotenuse of the triangle formed so.

[tex]h=\sqrt{d^2-w^2}[/tex]

[tex]h=\sqrt{40^2-32^2}[/tex]

[tex]h=24\ in[/tex] is the height of the TV screen.