A child on a merry-go-round takes 3.9 s to go around once. What is his angular displacement during a 1.0 s time interval?

Answer:

10.56 ft/s.

Explanation:

given,

Speed of side walk = 7 ft/s

time taken to travel 74 ft on the moving sidewalk = time taken to walk 15 ft on non moving side walk.

We know,

[tex]time = \dfrac{distance}{speed}[/tex]

[tex]\dfrac{74}{w+7}=\dfrac{15}{w-7}[/tex]

[tex]59 w = 7\times 74 + 15\times 7[/tex]

[tex] 59 w = 623[/tex]

[tex]w = 10.56\ ft/s[/tex]

Rate at which person walk on non moving side walk is equal to 10.56 ft/s.

The person's walking speed on a non-moving sidewalk is approximately 1.78 ft/sec, determined by setting up and solving the equation based on equal times on the moving and non-moving sidewalks.

To find the rate at which a person would walk on a non-moving sidewalk, we need to set up an equation based on the given information.

We know the speed of the moving sidewalk is 7 ft/sec. Let's denote the walking speed of the person (on a non-moving sidewalk) as v ft/sec.

From the problem, the time taken by the person to walk 74 ft on the moving sidewalk should be equal to the time taken to walk 15 ft on a non-moving sidewalk in the opposite direction:

       [tex]\frac{74}{7 + v} = \frac{15}{v}[/tex]

   74v = 15(v+7)
   74v = 15v + 105

  74v − 15v = 105

 59v = 105

  [tex]v = \frac{105}{59}[/tex]

 v ≈ 1.78 ft/sec

Therefore, the person's walking speed on a non-moving sidewalk is approximately 1.78 ft/sec.

Explanation:

Below is an attachment containing the solution.

Explanation:

Below is an attachment containing the solution.

Answer:

Acceleration = 1.428m/s2

Tension = 102.85N

Explanation:

The detailed solution is attached

Answer:

The acceleration of the system is 1.401 m/s² and

The tension in the cord is 100.902 N

Explanation:

Let the 9 kg mass be m

Let the 12 kg mass be M

By Newton's second law of motion we have

For the 9 kg mass, T - mg = ma and for the 12 kg mass we have T - Mg  = -Ma

Here we took the upward acceleration as positive a of the 9 kg mass and the downward acceleration of the 12 kg mass as -a

Solving for T for the 9 kg mass we have

T = mg + ma

Substituting  the value of T in to the 12 kg mass equation, we have

mg + ma - Mg = -Ma or  a = [tex](\frac{M-m}{M+m} )g[/tex] therefore the acceleration is

1.401 m/s²

and the tension is T = mg + ma = 9×(9.81+1.401) = 100.902 N

Answer:

The smallest separation distance between the speakers is 0.71 m.

Explanation:

Given that,

Two speakers, one directly behind the other, are each generating a 240-Hz sound wave, f = 240 Hz

Let the speed of sound is 343 m/s in air. The speed of sound is given by the formula as :

[tex]v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343\ m/s}{240\ Hz}\\\\\lambda=1.42\ m[/tex]

To produce destructive interference at a listener standing in front of them,

[tex]d=\dfrac{\lambda}{2}\\\\d=\dfrac{1.42}{2}\\\\d=0.71\ m[/tex]

So, the smallest separation distance between the speakers is 0.71 m. Hence, this is the required solution.

According to the question,

The wavelength will be:

→ [tex]\lambda = \frac{v}{f}[/tex]

By substituting the values, we get

     [tex]= \frac{343}{240}[/tex]

     [tex]= 1.43 \ m[/tex]

hence,

The smallest separation distance will be:

= [tex]\frac{\lambda}{2}[/tex]

= [tex]\frac{1.43}{2}[/tex]

= [tex]0.715 \ m[/tex]

Thus the above solution is correct.

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Explanation:

Given:

u = 20 m/s

a = 5 m/s^2

v = 30 m/s

t = ?

Use the first kinematic equation of motion:

v = u + at

t = (v - u)/a = 10/5 = 2 seconds

Eddie will take 2 sec to reach a speed of 30 m/s

What is velocity ?

velocity is defined as rate of change of displacement of the object with respect to rate of change in time. In mathematics It is written as :

                                          [tex]\begin{aligned}v&=\frac{\Delta d}{\Delta t}\end{aligned}[/tex]

Here it is given that :

initial speed of car (u) = 20 m/s

acceleration of car (a) = 5 m/s²

final speed of car (v) = 30 m/s²  

it is to find the time t to achieve this speed which is calculated using the first equation of motion:

[tex]\begin{aligned}v&=u+at\\30&=20+5t\\&t=\frac{10}{5}\\&=2\text{\:sec}\end{aligned}[/tex]

Therefore, Eddie will take 2 sec to reach a speed of 30 m/s

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Answer:

a)

The expression for the electric potential in this problem is:

[tex]V=5x-3x^2y+2yz[/tex]

where

x, y, z are the three spatial coordinates

The relationship between components of the electric field and electric potential is:

[tex]E_x=-\frac{dV}{dx}\\E_y=-\frac{dV}{dy}\\E_z=-\frac{dV}{dz}[/tex]

Therefore, we have to calculate the derivatives of the potential over the three variables.

Doing so, we find:

[tex]E_x=-\frac{d}{dx}(5x-3x^2y+2yz)=-(5-6xy)=6xy-5[/tex]

[tex]E_y=-\frac{d}{dy}(5x-3x^2y+2yz)=-(-3x^2+2z)=3x^2-2z[/tex]

[tex]E_z=-\frac{d}{dz}(5x-3x^2y+2yz)=-(2y)=-2y[/tex]

b)

Here we want to find the magnitude of the electric field at the point P that has coordinates

P (1.00, 0, 22.00) m

First of all, we find the components of the electric field at that point by substituting

x = 1.00

y = 0

z = 22.0

We find:

[tex]E_x=6xy-5=6(1)(0)-5=-5 N/C\\E_y=3x^2-2z=3(1)^2-2(22)=-41 N/C\\E_z=-2y=-2(0)=0[/tex]

Now, the magnitude of the electric field is given by

[tex]E=\sqrt{E_x^2+E_y^2+E_z^2}[/tex]

And by substituting,

[tex]E=\sqrt{(-5)^2+(-41)^2+0}=41.3 N/C[/tex]

Answer:

option A.

Explanation:

given,

rate constant. k = 0.241/min

[A_0] = 0.859 M

[A_t] = ?

t = 10 minutes.

using first order reaction formula

[tex]k=\dfrac{2.303}{t}log(\dfrac{[A_0]}{[A_t]})[/tex]

[tex]0.241=\dfrac{2.303}{10}log(\dfrac{[0.859]}{[A_t]})[/tex]

[tex]log(\dfrac{[0.859]}{[A_t]}) = 1.0464[/tex]

[tex]\dfrac{[0.859]}{[A_t]} = 11.129[/tex]

[tex][A_t]=\dfrac{0.859}{11.129}[/tex]

[tex][A_t]=0.0772\ M[/tex]

the concentration of A after 10 minutes is equal to 0.0772 M.

Hence, the correct answer is option A.

Answer:

Dispersion

Explanation:

Chromatic aberration refers to the failure of a lenses to focus all the wavelengths or colours in white light at the same point. This is due to dispersion of light in glass. The refractive index of the lenses elements varies with different wavelengths of light. The different colours of white light will travel at different speeds through the lens hence they cannot all be focused at the same point. Dispersion results from the refraction of the various wavelengths of light to varying degrees.

Chromatic aberration in lenses is a result of the property of light, wavelength. It leads to dispersion of different colors of light due to the dependence of lens's refractive index on color or wavelength, causing different colors to have different focal points. This can be partially corrected in optical systems using multiple lenses of different materials.

Chromatic aberration in lenses is caused by the property of light known as wavelength. This concept is related to the wave nature of light, where the wavelength is the distance between successive peaks or troughs of a light wave. Chromatic aberration occurs because the index of refraction in a lens is dependent on the light's wavelength, which is related to its color. Because the index of refraction varies with wavelength, different colors (wavelengths) of light are bent by different amounts when they pass through a lens and hence have different focal points.

For example, in a single convex lens, violet light, which has a shorter wavelength, is bent more than red light, which has a longer wavelength. Therefore, violet light converges to a focal point closer to the lens compared to red light, which results in the dispersion of colors, as depicted in Figure 26.28. However, this chromatic aberration can be partially corrected by employing a two-lens system, often consisting of a converging and a diverging lens made of different materials with different dispersions, referred to as an achromatic doublet. However, completely rectifying chromatic aberration is typically not possible, which is why systems such as telescopes often prefer mirrors as they do not depend on wavelength for reflection.

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Answer:

Number of revolution made by tire is 1.57 x 10⁷

Explanation:

Radius of tire, r = 0.220 m

Circumference of tire, C = 2πr

Substitute the value of r in the above equation.

C = 2 x π x 0.220 m = 1.38 m

Total distance covered by tire in a year, D = 13500 miles

But 1 mile = 1609.34 m

So, D = 13500 x 1609.34 m

Number of revolutions take by tire, N = [tex]\frac{D}{C}[/tex]

[tex]N=\frac{13500\times1609.34}{1.38}[/tex]

N = 15743543

Final answer:

The peak emf from a generator can be maximized by increasing the number of turns, increasing the area of the wired loop, and increasing the frequency. Both the one-turn and two-turn square coils can produce the same peak emf for a given frequency and magnetic field strength.

Explanation:

The peak emf from a generator can be maximized by maximizing the number of turns, maximizing the area of the wired loop, or maximizing the frequency. The one-turn and two-turn square coils are both options that can be used, as they both give the same peak emf for a given frequency and magnetic field strength. However, the other factors, such as the number of turns and area of the loop, may differ between the two options and can affect the overall performance of the generator.

Answer:

d. ΔU = q + w

Explanation:

Internal energy is the sum of kinetic energy (which comes from motion of molecules) and potential energy ( which comes from chemical bonds between atoms and other intermolecular forces that maybe present).

First law of thermodynamics states that: "the change in internal energy of a closed system is equal to the energy added to it in form of  heat(q) and work (w) done on the system by the surroundings.

Mathematically written as:

[tex]E_{internal}[/tex] = q + w

Conventionally, the first law is based on the system doing work and the surrounding doing work.

[tex]E_{internal}[/tex] can also be written as ΔU.

Therefore [tex]E_{internal}[/tex] = ΔU = q + w

ΔU = q + w

Answer:

d. epicentral distance scale

Explanation:

The depth of focus from the epicenter, called as Focal Depth, is an important parameter in determining the damaging potential of an earthquake. Most of the damaging earthquakes have shallow focus with focal depths less than about 70km. Distance from epicenter to any point of interest is called epicentral distance

Answer:

a) 38.3mA

b) 109.396A/m^2

c) 1.283cm/s

d) 226.582V/m

Explanation:

The equation for current is given by:

I = V/R = 35.6/ 935 = 0.03829 A Approximately 38.3mA

b) The equation to find the magnitude is given by:

J = I/A = 0.03829/ 0.000350m^2

J = 109.396A/m^2

c) The equation to calculate drift velocity of the electron is given by: Vd = J/ ne = 109.396/( 5.33×10^23 )(1.60×10^-19)

Vd = 0.01283 approximately 1.283cm/s

d) The magnitude of electric field in the block, E = V/L = 35.8/ 0.158m = 226.582V/m

Answer:

(9/35) = 0.257

Explanation:

Box contains 9 new light bulbs and 6 used light bulbs, total number of bulbs = 15.

Probability of selecting two bulbs; a new light bulb and then, a used light bulb in that order = [(probability of selecting a new bulb) × (probability of selecting a used bulb from the rest)] = [(9/15) × (6/14)] = (9/35) = 0.257

The probability that Meredith will select a new bulb and then a used bulb in sequential order without replacement is around 26%.

The question asks about the probability of selecting a new light bulb and then a used light bulb from a box containing 9 new light bulbs and 6 used light bulbs. Probability events like these are solved using multiplication rules of probability that each event is independent.

First, the probability of picking a new bulb is 9/15 (total bulbs are 15). If you pick one out, you don't replace it, so there are only 14 bulbs left. Thus, the probability of picking a used bulb now is 6/14. Hence the probability of both events happening in order is the multiplication of both, i.e., (9/15)*(6/14) = 54/210 = 0.257 or around 26%.

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Answer:

c, About the same for both balls.

Explanation:

If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height.

Answer: True

Explanation: Awning windows

are Weather-tight, good choice in damp climates and can protect your home against moisture, even when they’re open during a rainstorm. Because of the way awning windows are constructed, they allow for nearly 100 percent of viable ventilation, without the threat of water seeping into the home. They also offer a superior seal against air pass through

These windows form a slant (of about 45 degree) after opening hence do not open 100%; this slant opening is advantageous in preventing rain from entering the building.

The windows can also be tightly sealed (from the inside) during extreme/cold weather conditions.

True, awning windows can be fully opened and are beneficial for creating a tight seal in extreme weather conditions. They also allow for maximum ventilation while preventing unwanted energy transfer, making them widely used regardless of climate. Design elements like overhangs and window orientation further enhance energy efficiency.

True, awning windows can be 100% openable and are indeed best used in areas that experience extreme weather conditions, thanks to their capability to form a tight seal when closed. The design of these windows allows them to prevent unwanted energy transfers by keeping the harsh weather out when they are closed, while still allowing for maximum ventilation when opened. This makes them highly versatile and thus they are in common use in various locations, not just those with extreme weather. Factors such as the orientation of the windows, the use of overhangs, and the placement of deciduous trees also play important roles in maximizing energy efficiency by modulating the amount of sunlight and heat entering a building.

For instance, overhangs above south-facing windows help keep a house cool in summer by casting a shadow over the window when the sun is high, and allowing sunlight to warm the rooms in winter when the sun stays closer to the horizon. Moreover, in climates where preventing heat gain is crucial, the largest windows may face north to avoid the sun, with south-facing windows being smaller and well insulated to allow for cross-ventilation without admitting much sunlight. Additionally, windows equipped with weatherstripping, and double-paned, low-emissivity glass can significantly reduce energy losses, contributing to a building's overall energy efficiency.

Final answer:

To find the torque to accelerate Earth in 5 days to its angular speed, calculate the moment of inertia and use τ = Iα. The energy required is given by E_k = (1/2)Iω^2, and average power is P = E_k / t.

Explanation:

To calculate the torque required to accelerate the Earth from rest to its present angular speed about its axis in 5 days, we first need to determine the Earth's moment of inertia (I) and its angular acceleration (α). The Earth's moment of inertia can be estimated using the formula I = (2/5)MR^2, where M is the mass of the Earth and R is its radius. The angular speed (ω) is 2π rad/day since there are 2π radians in a full rotation and the Earth completes one rotation per day. The angular acceleration, α, is then ω divided by the time in seconds to accelerate, which is 5 days or 5 x 24 x 3600 seconds. The formula τ = Iα is used to calculate torque.

To find the energy required, we can use the rotational kinetic energy formula E_k = (1/2)Iω^2, where ω is the final angular velocity. Subsequently, the average power required is the energy divided by the time over which it is expended, P = E_k / t, where t is the time in seconds.

Answer:

[tex]v_{f} = 9.5\,\frac{m}{s}[/tex]

Explanation:

The final velocity is:

[tex]v_{f} = v_{o} + a \cdot t[/tex]

[tex]v_{f} = 14\,\frac{m}{s} + (-1.5\,\frac{m}{s^{2}} )\cdot (3\,s)[/tex]

[tex]v_{f} = 9.5\,\frac{m}{s}[/tex]

The velocity of the soccer ball after 3 s of rolling would be 9.5 m/s.

For a soccer ball rolling with a constant acceleration of -1.5 m/s², we can use the equation for velocity with constant acceleration: v = (initial velocity) + (acceleration)(time). At t = 3 s, the ball has an initial velocity of 14 m/s and has been rolling for 3 s, so we can plug these into the equation to find the velocity:

v = 14 m/s + (-1.5 m/s²)(3 s) = 14 m/s - 4.5 m/s = 9.5 m/s

Therefore, after 3 s of rolling, the velocity of the ball would be 9.5 m/s.

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Answer: Beta, alpha and gamma ray

Explanation: The component being deflected to the positive side is the beta radiation because it is negatively charged and thus is attracted by the positive terminal of the Electric Field.

The component being deflected to the negative side is the alpha radiation, it's is positively charged and thus being attracted by the negative part of the Electric Field.

The component that went straight down without deflection is the gamma radiation. It is neutral and possess no charge and thus is not deflected.

Answer:

Beta rays (symbol β) are negatively charged because they are electrons.

Alpha rays (symbol α) are positively charged because they are helium nuclei.

Gamma rays (symbol γ or. ) are neutral, since they are photons only. Comprises of the shortest electromagnetic wavelength and thus provides the highest photon energy.

Answer:

2 kg

Explanation:

Note: For the meter stick to be balanced,

Sum of clock wise moment must be equal to sum of anti clock wise moment

Wd = W'd' ................ Equation 1

Where W = weight of the rock, d = distance of the meter stick from the point of support, W' = weight of the that must be suspended for the meter stick to be balanced, d' = distance of the mass to the point of support.

make W' the subject of the equation

W' = Wd/d'............... Equation 2

Taking our moment about the support,

Given: W = mg =  1 ×9.8 = 9.8 N, d = 50 cm, d' = (75-50) = 25 cm

Substitute into equation 2

W' = 9.8(50)/25

W' = 19.6 N.

But,

m = W'/g

m = 19.6/9.8

m = 2 kg.

To find the mass M suspended from the meter stick, we can use the principle of rotational equilibrium. By setting the torques on either side of the fulcrum equal to each other, we can calculate the mass M at the 75 cm mark to be 3 kg.

To determine the mass M suspended from the meter stick at the 75 cm mark, we can use the principle of rotational equilibrium. Since the system is balanced, the torques on both sides of the meter stick must be equal.

The torque of the rock can be calculated using its weight, which is equal to its mass multiplied by the acceleration due to gravity. The torque of the mass M can be calculated by multiplying its mass by the distance from the fulcrum (75 cm) to its center of mass. By setting the torques equal to each other, we can solve for M.

The torque of the rock: TR = (1 kg)(9.8 m/s²)(0.75 m).

The torque of the mass M: TM = M(9.8 m/s²)(0.25 m).

Setting TR equal to TM and solving for M, we get M = (1 kg)(0.75 m)/(0.25 m) = 3 kg.

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Answer:

Explanation:

capacitance of sphere 2 will be 4.5 times sphere 1

a ) when spheres are in contact they will have same potential finally . So

V_1 / V_2 = 1

b )

Charge will be distributed in the ratio of their capacity

charge on sphere1 = q  x 1 / ( 1 + 4.5 )

= q / 5.5

fraction = 1 / 5.5

c ) charge on sphere 2

= q x 4.5 / 5.5

fraction = 4.5 / 5.5

d ) surface charge density of sphere 1

= q /( 5.5 x A ) where A is surface area

surface charge density of sphere 2

= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area

= q  /( 5.5 x 4.5 A )

q_1/q_2 = 4.5

Answer:

Explanation:

Given that,

Number of turn is 48

N=48

Radius is 4.8cm

r=0.048m

Magnetic Field

B=0.48T

Current in coil

i=23.3mA

i=0.233A

Maximum Torque?

Maximum torque occur at angle 90°

Torque is given as

τ = N•I•A•B•sinθ

Where N is number of turn =48

I is current in coil =0.233A

A is area of circular coil form

Area of a circle is given as

A=πr²

A=π×0.048²

A=0.007238m²

B is magnetic field =0.48T

Maximum torque occurs at 90°

τ = N•I•A•B•sinθ

τ=48×0.233×0.007238×0.48×Sin90

τ = 0.0389Nm

This torque is large enough to exert the coil

Given Information:

Magnetic field = B =  0.480 T

Current = I = 23.3 mA = 0.0233 A

Number of turns = N = 48 turns

Radius = r = 5.50 cm = 0.055 m

Required Information:

Maximum possible torque = τ = ?

Answer:

Maximum possible torque = 0.0051 N.m

Explanation:

We know that toque τ is given by

τ = NIABsin(θ)

Where N is the number of turns of the circular coil, I is the current flowing through the circular coil, A is the area of circular coil, B is the magnetic field induced in the circular coil.

The area of the circular coil is

A = πr²

A = π(0.055)²

A = 0.009503 m²

The maximum torque is possible when θ = 90°

τ = 48*0.0233*0.009503*0.480*sin(90°)

τ = 0.0051 N.m

Answer:

A) [tex]v_b=0.8\ m.s^{-1}[/tex] is the final velocity of the cart B after collision.

B) [tex]KE_A=0.176\ J[/tex]

C) [tex]KE_B=0\ J[/tex]

D) [tex]ke_a=0\ J[/tex]

E) [tex]ke_B=0.176\ J[/tex]

F) Yes, here the kinetic energy is conserved because the mass of both the bodies involved in the collision is same.

G) Yes, momentum is always conserved for an elastic collision.

Explanation:

Given:

A)

As given in the question that the cars undergo an elastic collision:

According to the conservation of momentum:

[tex]m_a.u_a+m_b.u_b=m_a.v_a+m_b.v_b[/tex]

[tex]0.55\times 0.8+0.55\times 0=0.55\times 0+0.55\times v_b[/tex]

[tex]v_b=0.8\ m.s^{-1}[/tex] is the final velocity of the cart B after collision.

B)

Initial kinetic energy of cart A:

[tex]KE_A=\frac{1}{2} m_a.u_a^2[/tex]

[tex]KE_A=0.5\times 0.55\times 0.8^2[/tex]

[tex]KE_A=0.176\ J[/tex]

C)

Initial kinetic energy of cart A:

[tex]KE_B=\frac{1}{2} \times m_b.u_b^2[/tex]

[tex]KE_B=0.5\times 0.55\times 0^2[/tex]

[tex]KE_B=0\ J[/tex]

D)

The final kinetic energy of cart A:

[tex]ke_A=\frac{1}{2} m_a.v_a^2[/tex]

[tex]ke_a=0.5\times 0.55\times 0^2[/tex]

[tex]ke_a=0\ J[/tex]

E)

The final kinetic energy of cart B:

[tex]ke_B=\frac{1}{2} m_b.v_b^2[/tex]

[tex]ke_B=0.5\times 0.55\times 0.8^2[/tex]

[tex]ke_B=0.176\ J[/tex]

F)

Yes, here the kinetic energy is conserved because the mass of both the bodies involved in the collision is same.

G)

Yes, momentum is always conserved for an elastic collision.

(a) The velocity of cart B is [tex]0.8m/s[/tex]

(b) Initial kinetic energy of cart A is [tex]0.176J[/tex]

(c) Initial kinetic energy of cart B is 0

(d) The final kinetic energy of cart A is 0

(e) The final kinetic energy of cart B is [tex]0.176J[/tex]

(f) The kinetic energy is conserved

(g) The momentum is conserved

(a) The momentum of the system must be conserved, which means momentum before the collision must be equal to momentum after the collision.

Momentum before collision = [tex]m_Au_A+m_bu_B=0.55\times0.8+0.55\times0=0.44kgm/s[/tex]

Momentum after collision:

[tex]m_A+m_A+m_Bv_B=0.55\times0+0.55v_B=0.44\\\\v_B=0.8m/s[/tex]

(b) Initial kinetic energy of cart A:

[tex]K_{iA}=\frac{1}{2}m_Au_A^2=0.5\times0.55\times0.64=0.176J[/tex]

(c) Initial kinetic energy of cart B:

[tex]K_{iB}=\frac{1}{2}m_Bu_B^2=0.5\times0.55\times0=0J[/tex]

(d) The final kinetic energy of cart A:

[tex]K_{fA}=\frac{1}{2}m_Av_A^2=0.5\times0.55\times0=0J[/tex]

(e) Initial kinetic energy of cart B:

[tex]K_{iB}=\frac{1}{2}m_B_v_B^2=0.5\times0.55\times0.64=0.176J[/tex]

(f) yes the kinetic energy of the system is conserved for elastic collision

(g) The momentum is conserved in any case including the elastic collision

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Answer: The distance is 723.4km

Explanation:

The velocity of the transverse waves is 8.9km/s

The velocity of the longitudinal wave is 5.1 km/s

The transverse one reaches 68 seconds before the longitudinal.

if the distance is X, we know that:

X/(9.8km/s) = T1

X/(5.1km/s) = T2

T2 = T1 + 68s

Where T1 and T2 are the time that each wave needs to reach the sesmograph.

We replace the third equation into the second and get:

X/(9.8km/s) = T1

X/(5.1km/s) = T1 + 68s

Now, we can replace T1 from the first equation into the second one:

X/(5.1km/s) = X/(9.8km/s) + 68s

Now we can solve it for X and find the distance.

X/(5.1km/s) - X/(9.8km/s) = 68s

X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s

X = 68s/0.094s/km = 723.4 km

Options to the question :

A- blood viscosity

B- osmolarity of interstitial fluid

C- turbulence

D-length of a blood vessel

E- blood vessel diameter

Answer:

Total peripheral resistance is NOT related to B ( osmolarity of interstitial fluid).

Explanation:

Total peripheral resistance( also called systemic vascular resistance) is defined as the total opposition to the flow of blood in systemic circulation. Increase in total peripheral resistance leads to high blood pressure while it's decrease leads to low blood pressure. Factors that contributes to total peripheral resistance in systemic circulation includes:

- blood vessel diameter

- blood viscosity,

- lengthy of a blood vessel and

- turbulence.

Answer:

Explanation:

When he accelerates the heavy object up , the reading increases because an extra downward normal force acts on it, then scale reading returns to the same reading as when standing stationary, and then decreases as although he is lifting the heavy object , the acceleration is decreasing ,so the extra upward normal force acts.

Answer:

Explanation:

To identify forces acting on an object

1. Draw a closed curve around the system.

2.Identify "the system" and "the environment."

3. Draw a picture of the situation. Which of these are steps used to identify the forces acting on an object?

All of these are correct.

A close loop doesn't allow external forces to act on the system and this only allows the the forces on the object to act alone.

Drawing the free body diagram will show the forces acting on the body.

Also, isolating the system from the environment so that it won't be affected by external forces or resistance

Final answer:

Johnnie's move from automotive manufacturing to the IT sector due to changes in the economy is an example of structural mobility, which reflects broad societal shifts affecting whole groups within the social class system. Option a

Explanation:

Johnnie's career change from the declining auto industry that his father was a part of, to the burgeoning information technology sector, is an example of structural mobility. This type of mobility occurs due to large-scale economic and societal shifts rather than individual actions. For instance, in the past, industrialization led to the general upliftment of the population, causing widespread upward structural mobility. In more recent times, factors such as recessions and outsourcing have resulted in many experiencing downward structural mobility, as traditional jobs have become obsolete or have moved overseas.

Moreover, technological advancements have altered the kinds of skills employers seek in their workforce, leading to a situation where some individuals may find themselves structurally unemployed if they lack the necessary analytical and communication skills, despite having traits like reliability and physical strength that were formerly highly valued.

Therefore, Johnnie's entrance into a different industry than his father's, brought upon by changes in the economic landscape, is a reflection of the broader trend where entire groups in society move up or down the social class ladder due to changes in the social structure itself.

Answer:

The correct answer is

a little less than 15 km/s.

Explanation:

The distance between the sun and Jupiter varies by about 75 million km between the perihelion and the aphelion with an average distance of 778 million km from the sun for which it takes Jupiter about 12 years to complete its orbit round the sun giving it an orbital speed of about 13.07 km/s

The size of Jupiter is more than the twice the combined size of all the other planets, which is about 1.300 times the size of earth.

Jupiter is orbiting the Sun from b. 15 km/s.

Jupiter orbits the Sun at an average distance (semi-major axis) of about 5.2 Astronomical Units (AU), where 1 AU is the average distance from the Earth to the Sun, approximately 149.6 million kilometers.

Using Kepler's third law of planetary motion and the fact that Jupiter takes approximately 11.86 Earth years to complete one orbit around the Sun, we can estimate its average orbital speed. The orbital speed (v) of a planet can be roughly calculated by the formula:

[tex]v = \frac{2 \pi r}{T}[/tex]

where:

Converting the semi-major axis from AU to kilometers:-

[tex]r = 5.2 \times 149.6 \times 10^6 \text{ km} \\= 777.92 \times 10^6 \text{ km}[/tex]

Converting the orbital period from years to seconds:

[tex]T = 11.86 \text{ years} \times 3.154 \times 10^7 \text{ seconds/year} \\= 3.74 \times 10^8 \text{ seconds}[/tex]

Now, plugging in these values to our formula:

[tex]v = \frac{2 \pi \times 777.92 \times 10^6}{3.74 \times 10^8} \text{ km/s} \\\approx 13.07 \text{ km/s} \ {or} 15 km[/tex]