They put 20% down so that means 80% was financed ( 100% - 20% = 80%).
Multiply the purchase price by 80%:
23750 x 0.80 = $19,000 was financed.
If you roll a pair of fair dice, what is the probability of each of the following? (round all answers to 4 decimal places, .XXXX)
a) getting a sum of 1?
b) getting a sum of 5?
c) getting a sum of 12?
Answer: The required probabilities are
[tex](a)~0\\\\(b)\dfrac{1}{9},\\\\(c)~\dfrac{1}{36}.[/tex]
Step-by-step explanation: Given that a pair of fair dice is rolled.
We are to find the probability of getting
(a) getting a sum of 1.
b) getting a sum of 5.
c) getting a sum of 12.
Let S be the sample space for the experiment of rolling a pair of fair dice.
Then, S = {(1,1), (1,2), (1,3), (1, 4), (1,5), (1,6), . . . , (6,5), (6,6)}.
And, n(S) =36.
(a) Let E denote the event of getting a sum of 1.
Since the sum of the numbers on two dice is minimum 2, so
E = { } ⇒ n(E) = 0.
Therefore, the probability of event E is
[tex]P(E)=\dfrac{n(E)}{n(S)}=\dfrac{0}{36}=0.[/tex]
(b) Let F denote the event of getting a sum of 5.
Then,
F = {(1,4), (2,3), (3,2), (4,1)} ⇒ n(F) = 4.
Therefore, the probability of event F is
[tex]P(F)=\dfrac{n(F)}{n(S)}=\dfrac{4}{36}=\dfrac{1}{9}.[/tex]
(c) Let G denote the event of getting a sum of 12.
Then,
G = {(6,6)} ⇒ n(G) = 1.
Therefore, the probability of event G is
[tex]P(G)=\dfrac{n(G)}{n(S)}=\dfrac{1}{36}.[/tex]
Thus, the required probabilities are
[tex](a)~0\\\\(b)\dfrac{1}{9},\\\\(c)~\dfrac{1}{36}.[/tex]
The probability of getting a sum of 1, the sum of 5, and the sum of 12 are 0, 1/9, and 1/36 respectively
Probability is the likelihood or chance that an event will occur.
For a pair of rolled dice, the total outcome will be 6² = 36
Probability = Expected outcome/Total outcome
a) Pr(getting a sum of 1) = 0/36 = 0
Note that since we have a pair of dice, the least sum we can have is 2
b) The event for getting a sum of 5 are (1, 4), (4, 1), (3, 2), (2, 3)
n(E) = 4
Pr( getting a sum of 5) = 4/36 = 1/9
c) The event for getting a sum of 12 are (6, 6)
n(E) = 1
Pr( getting a sum of 12) = 1/36
Hence the probability of getting a sum of 1, the sum of 5, and the sum of 12 are 0, 1/9, and 1/36 respectively
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Help!!!
Given the function f(x) = x/3 + 7. Find the input for which f(x) = 13
[tex]
\begin{cases}
f(x)=x/3+7\\
f(x)=13
\end{cases}
[/tex]
We find that
[tex]13=x/3+7\Longrightarrow x=\boxed{18}[/tex]
Hope this helps.
the units digit of a two digit number is 10. If the digits are reversed, the new number is 9 less than the original number. find the original number
Answer: the units digit has to be a 1 digit number not 2
Step-by-step explanation:
Let U represent the set of people in a certain community who were asked if they subscribe to an information source. Let D ={ x ∈ U | x subscribes to The Daily Informer } and N ={ x ∈ U | x subscribes to News Magazine } (Assume these sets are not disjoint.) Write the set that represents the set of people surveyed who subscribe to exactly one of the two news sources given.
a. N ∪ D
b. ( N c ∩ D ) ∪ ( N ∩ D c )
c. N c ∩ D
d. ( N ∩ D )c
e. ( N c ∪ D ) ∩ ( N ∪ D c )
Answer:
b. [tex]( N^c \cap D ) \cup ( N \cap D^c )[/tex]
Step-by-step explanation:
Here,
N = { x ∈ U | x subscribes to News Magazine },
D = { x ∈ U | x subscribes to The Daily Informer },
Such that N∩D ≠ ∅,
Now, the number of the set of people surveyed who subscribe only News Magazine
= Subscribe News Magazine and not Daily Informer
= [tex]N\cap D^c[/tex]
Similarly, the number of the set of people surveyed who subscribe only Daily informer
= Subscribe Daily informer and not subscribe News Magazine
= [tex]D\cap N^c[/tex]
Hence, the set of people surveyed who subscribe to exactly one of the two news sources given
= Subscribe News Magazine and not subscribe Daily Informer or subscribe Daily informer and not subscribe News Magazine
[tex]= (N\cap D^c)\cup (D\cap N^c)[/tex]
[tex]=( N^c \cap D ) \cup ( N \cap D^c )[/tex]
The set of people who subscribe to exactly one of the two news sources is represented by ( Nc ∩ D ) ∪ ( N ∩ Dc ). This includes people who subscribe to The Daily Informer but not News Magazine and those who subscribe to News Magazine but not The Daily Informer.
Explanation:The set that represents the set of people surveyed who subscribe to exactly one of the two news sources, The Daily Informer (D) or News Magazine (N), can be written as ( Nc ∩ D ) ∪ ( N ∩ Dc ). The notation Nc represents the set of all people who do not subscribe to News Magazine and Dc represents the set of all people who do not subscribe to The Daily Informer. Thus, Nc ∩ D represents those who subscribe to The Daily Informer but not News Magazine, while N ∩ Dc represents those who subscribe to News Magazine but not The Daily Informer. The union of these two sets, denoted by ∪, represents the complete set of people who subscribe to exactly one of the two news sources.
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A plane traveled from California and back. It took one hour on the way out than it did on the way back. The plane's average speed out wad 300 mph. The speed on the way back was 350mph. How many hours did the trip out take?
Answer:
6 hours
Step-by-step explanation:
You can set up a chart:
R T D
O 300 1+x ~ O=out B=back R=Rate/Speed T=time D=distance
B 350 x ~
The distance is the same. On the way out the speed was 300 mph, so you can see where that is on the chart. And the speed back was 350 mph. It took an extra hour on the way out than on the way back, so you can call the way back's time x and then say the way out's time was x+1.
It's important to know that R times T = D
Therefore we can say 300(x+1)=D and 350(x)=D
Since the distance is the same, 300(x+1)=350(x)
Solve:
300(x+1)=350x
300x+300=350x
50x=300
x=6
Therefore, the trip out took 6 hours.
I hope that helps! :)
Answer:the trip out took 7 hours
Step-by-step explanation:
Distance travelled = speed × time
Let t represent the time it took the plane to travel from California.
It took one hour on the way out than it did on the way back. This means that the time it took the plane to return would be t - 1
The plane's average speed out ward 300 mph. Distance travelled when going out would be
300 × t = 300 = 300t
The speed on the way back was 350mph. Distance travelled when returning would be
350(t - 1) = 350t - 350
Since the distance is the same, it means that
300t = 350t - 350
350t - 300t = 350
50t = 350
t = 350/50 = 7
Time taken to go out is 7 hours
Northern Light Health Partners offers routine physical examinations as part of a health service program for its employees. The exams showed that 8% of the employees needed corrective shoes, 15% needed major dental work, and 3% needed both corrective shoes and major dental work. Based o n this information what is the probability that an employee selected at random will need either corrective shoes or major dental work?
Answer: Our required probability is 20%.
Step-by-step explanation:
Since we have given that
Probability of the employees needed corrective shoes = 8%
Probability of the employees needed major dental work = 15%
Probability of employees needed both corrective shoes and major dental work = 3%
So, we need to find the probability that an employee will need either corrective shoes or major dental work.
So, it becomes,
[tex]P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\\P(S\cup D)=8+15-3\\\\P(S\cup D)=23-3\\\\P(S\cup D)=20\%[/tex]
Hence, our required probability is 20%.
Eight-year-old Terry's performance on an intelligence test is at a level characteristic of an average 5-year-old. In other words, Terry was average for his age group. Which of the following is most likely Terry’s IQ score?
6
4
5
8
Answer:
5
Step-by-step explanation:
Assuming the intelligence test had 10 questions, since Terry was average for his age group, his most likely IQ score is 5