A bullet is fired straight up from a gun with amuzzle velocity of 208 m/s.Neglecting air resistance, what will be itsdisplacement after 8.9 s?

Using mass measurements with six significant figures does not increase the precision of your results if your volume measurement is only accurate to two significant figures, due to the rule that in multiplication or division, the result must be reported with the same number of significant figures as the measurement with the least number of significant figures.

If your volume measurement is only good to two significant figures, will your results be more precise if you use mass measurements that have six significant figures? The answer is no. When determining the precision of your results in chemistry, particularly in calculations involving volume and mass, it is vital to understand the rules governing significant figures. According to these rules, when performing multiplication or division, the result should be reported with the same number of significant figures as the measurement with the least number of significant figures. For instance, if a calculation involving the density formula (density = mass/volume) uses a mass with six significant figures and a volume with only two, the final density value should be expressed with two significant figures.

This principle ensures that the precision of your results reflects the precision of the least precise measurement. It prevents the false impression of greater accuracy than the measurements allow. Therefore, even if your mass measurements are incredibly precise, having six significant figures, the precision of your results will still be limited by the two significant figures in your volume measurement. This rule highlights the importance of consistency in measurement precision for enabling accurate and reliable scientific work. The concept of significant figures serves as a fundamental aspect of data analysis and reporting in chemistry, ensuring that reported results accurately reflect the uncertainties inherent in experimental measurements.

Explanation:

We have equation of motion v = u + at

     Initial velocity, u =  0 m/s

     Final velocity, v = 50 miles/hr = 80 km/hr = 22.22 m/s    

     Time, t = 2.22 s

     Substituting

                      v = u + at  

                      22.22 = 0 + a x 2.22

                      a = 10 m/s²

     Acceleration is 10 m/s²

Acceleration of cheetah is 10 m/s²

The net force of the cart when it is pushed to the right with a force of 15N.

Explanation:

To find the force of net, which is calculated by the  formula.

The Net Force= Addition of the force applied on the respective  direction.

The Net Force here is given by

The Net Force = 15-20 (A force towards the right and a force towards left, two opposite so subtraction).

Hence

Thus the Net Force = -5(The force towards left, so it gets a  negative value).

The net force on the cart is -5 N, which means the cart is experiencing a force of 5 N in the opposite direction of its motion.

The net force on the cart can be found by subtracting the force pulling the cart to the left from the force pushing the cart to the right. In this case, the force pushing the cart to the right is 15 N and the force pulling the cart to the left is 20 N. So, the net force on the cart is:

Net force = Force pushing to the right - Force pulling to the left

Net force = 15 N - 20 N

Net force = -5 N

The net force on the cart is -5 N, which means the cart is experiencing a force of 5 N in the opposite direction of its motion.

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Explanation:

We know that in series connection current in all the resistors are same.

Effective resistance is sum of individual resistances.

Here three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit

Effective resistance = 3 + 5 + 22 = 30 ohms

Voltage = 28 V

We know

        Voltage = Current x Resistance

         V = IR

         28 = 30 x I

         I = 0.93 A

Current in each resistor is 0.93 A

Option C is the correct answer.

Answer:

0.43 s

Explanation:

speed (s) = 95 mi/h = 95 x 1600/3600 = 42.5 m/s  (converting to m/s)

distance (d) = 60 ft 6 inches = (60 x 0.3048) + (6 x 0.025) = 18.44 m (converting to meters)

speed = distance / time

time = distance / speed = 18.44 / 42.5 = 0.43 s

Answer:

Explanation:

Given

Object 1 is  of mass [tex]\frac{m}{2}[/tex]

Object 2 has mass of [tex]m[/tex]

They undergone inelastic collision and do not move after collision i.e. the collision is perfectly inelastic

Final momentum of both the object is zero

suppose [tex]v_1[/tex] and [tex]v_2[/tex] are the velocities of object 1 and 2 respectively then

[tex]m_1v_1+m_2v_2=0[/tex]

[tex]\frac{v_1}{v_2}=-\frac{m_2}{m_1}[/tex]

[tex]\frac{v_1}{v_2}=-2[/tex]

[tex]v_1=-2v_2[/tex]

i.e. velocity of object 1 is twice the velocity of object 2 but opposite to the direction of object 2

The comparison of the velocity of both objects before the collision is [tex]u_1=-2u_2[/tex]

According to the law of conservation of momentum, the momentum of a body before collision is equal to the momentum after collision. Mathematically;

[tex]m_1v_1 + m_2u_2=m_1v_1+m_2v_2[/tex]

Since both objects do not move after the collision, the equation becomes:

[tex]m_1v_1 + m_2u_2=0[/tex]

Also if Objects 1 has half the mass of object 2, then [tex]m_1=0.5m_2[/tex]

Substitute into the formula above:

[tex]0.5m_2u_1 + m_2u_2=0\\0.5m_2u_1 =-m_2u_2\\0.5u_1=-u_2\\u_1=-2u_2[/tex]

The comparison of the velocity of both objects before the collision is [tex]u_1=-2u_2[/tex]

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Answer:

Explanation:

Given

Charge of [tex]Q=0.8\ nC[/tex]  

Length of side of cube [tex]a=4\ m[/tex]  

Total Flux through the cube [tex]\phi =\frac{Q}{\epsilon _0}[/tex]  

[tex]\epsilon _0=8.854\times 10^{-12}\ C^2/N-m^2[/tex]  

total Flux [tex]\phi=\frac{0.8\times 10^{-9}}{8.854\times 10^{-12}}[/tex]  

[tex]\phi =90.35\ N-m^2/C[/tex]  

As cube has 6 faces , so flux through each face will be similar

thus flux through  each face [tex]\phi'=\frac{\phi }{6}[/tex]  

[tex]\phi '=\frac{90.35}{6}=15\ N-m^2/C[/tex]    

According to the question,

Object's relative speed,

[tex]v_{rel} = 1.30+1.30[/tex]

      [tex]= 2.60 \ m/s[/tex]

Time taken by the two steamrollers,

[tex]t = \frac{d}{v_{rel}}[/tex]

  [tex]= \frac{105}{2.60}[/tex]

  [tex]= 40.39 \ seconds[/tex]

hence,

The distance of fly travel will be:

→ [tex]s = vt[/tex]

By putting the values,

     [tex]= 2.40\times 40.39[/tex]

     [tex]= 96.94 \ m[/tex]

Thus the above response is right.

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Final answer:

The red and green trains apply brakes with a deceleration of 1.0 m/s^2 when 920 m apart, and will stop without colliding, leaving a separation of 80 m.

Explanation:

When the red train traveling at 72 km/h and the green train traveling at 144 km/h are 920 meters apart and both apply brakes with a deceleration of 1.0 m/s2, we can calculate whether a collision will happen.

First, convert the speeds from km/h to m/s: the red train's speed is 20 m/s (72 km/h) and the green train's speed is 40 m/s (144 km/h).

Next, calculate the stopping distance for both trains using the formula s = v2 / (2a), where v is the initial speed and a is the deceleration. For the red train: s = (20 m/s)2 / (2 x 1 m/s2) = 200 m. For the green train: s = (40 m/s)2 / (2 x 1 m/s2) = 800 m.

The total stopping distance for both trains is 200 m + 800 m = 1000 m. Since they start 920 m apart, they will not collide because their combined stopping distance is greater than the initial separation.

Thus, (a) the speed of the red train when they stop will be 0 m/s, (b) the speed of the green train will be 0 m/s, and (c) the separation between the trains when they stop will be 80 meters.

Answer:

In the Mediterranean sea

Explanation:

The water present in the deeper part of the North Atlantic ocean is warm and comprised of high salinity, and abundance in oxygen as well as rich in terms of nutrient ones. On the other hand, the opposite occurs in the southern part of the Atlantic ocean. This warm water is typically found up to a depth of about 1000 meters below the mean sea level.

This Atlantic ocean is directly connected to the Mediterranean sea through the Gibraltar Strait.

Therefore, this mass of water that is comprised of higher salinity and higher temperature that is found at a depth of 1000 meters in the northern part of the Atlantic ocean has been formed in the Mediterranean sea.

Answer:

Explanation:

Given

mass of bullet [tex]m=5\ gm[/tex]

speed of bullet [tex]v=355\ m/s[/tex]

bullet is stopped by building and heat produced is shared between building and bullet

Kinetic Energy of bullet is converted into Thermal energy

Kinetic Energy of bullet [tex]K=\frac{1}{2}mv^2[/tex]

[tex]K=0.5\times 5\times 10^{-3}\times (355)^2[/tex]

[tex]K=315.06\ J[/tex]

So 315.06 J of Energy is converted in to thermal energy

Answer:

It's answer : 44 atm

Explanation:

Answer:

98.15 lb

Explanation:

weight of plane (W) = 5,000 lb

velocity (v) = 200 m/h =200 x 88/60 = 293.3 ft/s

wing area (A) = 200 ft^{2}

aspect ratio (AR) = 8.5

Oswald efficiency factor (E) = 0.93

density of air (ρ) = 1.225 kg/m^{3} = 0.002377 slugs/ft^{3}

Drag = 0.5 x ρ x [tex]v^{2}[/tex] x A x Cd

we need to get the drag coefficient (Cd) before we can solve for the drag

Drag coefficient (Cd) = induced drag coefficient (Cdi) + drag coefficient at zero lift (Cdo)

where

        where lift coefficient (Cl)= [tex]\frac{2W}{pAv^{2} }[/tex]=[tex]\frac{2x5000}{0.002377x200x293.3^{2} }[/tex] = 0.245

        therefore

       induced drag coefficient (Cdi) = [tex]\frac{Cl^{2} }{n.E.AR}[/tex] = [tex]\frac{0.245^{2} }{3.14x0.93x8.5}[/tex] = 0.0024

Now that we have the coefficient of drag (Cd) we can substitute it into the formula for drag.        

 Drag = 0.5 x ρ x [tex]v^{2}[/tex] x A x Cd

Drag = 0.5 x 0.002377 x (293.3 x 293.3) x 200 x 0.0048 = 98.15 lb

The total drag on the airplane is approximately 376.4 pounds (lb).

To calculate the total drag on the airplane, we'll use the following formula for total drag:

[tex]\[D = \frac{W^2}{q \cdot S \cdot \pi \cdot e \cdot AR}\][/tex]

Where:

- \(D\) is the total drag in pounds (lb).

- \(W\) is the weight of the airplane in pounds (lb), which is 5000 lb in this case.

- \(q\) is the dynamic pressure in lb/ft^2, given by [tex]\(q = 0.5 \cdot \rho \cdot V^2\)[/tex], where[tex]\(\rho\)[/tex] is the air density at standard sea level (0.002377 lb/ft^3) and \(V\) is the velocity in ft/s (200 mi/h converted to ft/s).

- S is the wing area in square feet (ft^2), which is 200 ft^2.

- pi is approximately 3.1416.

- e is the Oswald efficiency factor, which is 0.93 in this case.

- AR is the aspect ratio, which is 8.5 in this case.

Let's calculate it step by step:

1. Convert the velocity from miles per hour (mi/h) to feet per second (ft/s):

 [tex]\[V = 200 \, \text{mi/h} \times \frac{5280 \, \text{ft/mi}}{3600 \, \text{s/h}} = 293.33 \, \text{ft/s}\][/tex]

2. Calculate the dynamic pressure (\(q\)):

  [tex]\[q = 0.5 \cdot \rho \cdot V^2 = 0.5 \cdot 0.002377 \, \text{lb/ft}^3 \cdot (293.33 \, \text{ft/s})^2 = 21.81 \, \text{lb/ft}^2\][/tex]

3. Now, plug the values into the total drag formula:

[tex]\[D = \frac{5000 \, \text{lb}^2}{21.81 \, \text{lb/ft}^2 \cdot 200 \, \text{ft}^2 \cdot 3.1416 \cdot 0.93 \cdot 8.5} \approx 376.4 \, \text{lb}\][/tex]

So, the total drag on the airplane is approximately 376.4 pounds (lb).

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Answer:

Wen we place a cold alcohol in glass in a hot tub of water then the glass will be warmed first so it will expand a little due to which the level of alcohal decreases. After some time when thermal equilibrium is achevied then the alcohol will expand more then glass as the alcohol has the greater coeficient of expansion then glass so there will be an incerease in the level of alcohol which will indicate how much high the temperature is.

Explanation:

The alcohol level in a thermometer initially drops when placed in hot water because the glass expands first, temporarily increasing the volume before the alcohol heats up and rises. This illustrates the principle of thermal expansion.

When a cold alcohol-in-glass thermometer is initially placed in a hot tub of water, the column of alcohol first descends slightly before rising. This phenomenon can be explained by the principles of thermal expansion.

Answer:

b) Earth is passing Saturn in its orbit, with both planets on the same side of the Sun.

Explanation:

Retrograde motion is an optical effect due to the fact that Earth rotates more quickly than the planet that apparently has a retrograde motion in the sky.

For this particular case, Saturn has a slower speed in its orbit around the sun. That means that the Earth will pass it, and that will give the effect that the planet is moving backward. That same scenario can be seen between two cars on a highway, the faster car will see the slower car when it passes going in backward for a short fragment of time.

Remember that all the object in the night sky moves from east to west (since the Earth rotates counterclockwise in its daily movement), in the case of a planet with retrograde motion, it will move from west to east for a couple of months.        

Apparent retrograde motion of Saturn occurs when Earth overtakes Saturn in their respective orbits around the Sun, creating the illusion that Saturn is moving backward (westward) against the star's background. This is a result of our perspective from Earth and not an actual reversal of Saturn's orbit.

When we observe Saturn going through a period of apparent retrograde motion, it is not because Saturn is actually moving backwards in its orbit. Instead, this phenomenon occurs because Earth is passing Saturn in its orbit, with both planets on the same side of the Sun. As Earth, which moves faster in its orbit due to being closer to the Sun, overtakes Saturn, Saturn appears to move westward against the background stars. This westward motion is temporary and is perceived from Earth due to our vantage point.

As Earth continues in its orbit, reaching a point where the direct line of sight aligns with Saturn once more, Saturn will resume its normal prograde motion (eastward relative to the stars) in the night sky. This retrograde motion is much simpler to understand now with our knowledge of Earth and other planets orbiting the Sun, rather than from the historically held geocentric view which placed Earth at the center of the universe.

Answer:

[tex]\frac{25}{3}ft/s[/tex]

Explanation:

Height of man= 6ft

Height of light=1 5ft

Let BC=x and CD=y

BD=x+y

Triangle ABD and ECD are similar

When two triangles are similar then the ratio of their corresponding sides are equal

[tex]\frac{AB}{EC}=\frac{BD}{CD}[/tex]

[tex]\frac{15}{6}=\frac{x+y}{y}[/tex]

[tex]\frac{5}{2}=\frac{x+y}{y}[/tex]

[tex]5y=2x+2y[/tex]

[tex]5y-2y=2x[/tex]

[tex]3y=2x[/tex]

Differentiate w.r.t t

[tex]2\frac{dx}{dt}=3\frac{dy}{dt}[/tex]

We have [tex]\frac{dx}{dt}=5ft/s[/tex]

Substitute the value then we get

[tex]2\times 5=3\frac{dy}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s[/tex]

Rate at which the tip of  shadow is moving=[tex]\frac{dx}{dt}+\frac{dy}{dt}[/tex]

Rate at which the tip of  shadow is moving=[tex]5+\frac{10}{3}=\frac{15+10}{3}ft/s[/tex]

Rate at which the tip of  shadow is moving=[tex]\frac{25}{3}ft/s[/tex]

Answer:

The player and the ball have the same displacement

Explanation:

Displacement is the distance between the final position and initial position, When the ball is hit upwards, it is caught at the same height. The vertical displacement of the ball is zero. The horizontal displacement of the ball would be equal to the displacement of the player because the player runs in a straight line to catch the ball.

The student's question concerns the calculation of the stalling speed for a Piper Super Cub airplane at sea level based on the maximum gross weight, wing area, and the maximum lift coefficient. By using the lift equation and rearranging it to solve for velocity, we can find the stalling speed that must be maintained for the airplane to generate enough lift to balance its weight.

The student is asking to calculate the stalling speed of a Piper Super Cub airplane at sea level. The stalling speed is the minimum speed at which an airplane can maintain level flight. To find this, we can use the equation for lift, which at the stalling point must equal the weight of the airplane. The lift equation is L = (1/2) ∙ ρ ∙ V² ∙ S ∙ Cl where L is the lift force, ρ is the air density, V is the velocity, S is the wing area, and Cl is the maximum lift coefficient.

Given that:

We can rearrange the lift equation to solve for velocity (V) and then plug in the numbers to calculate the stalling speed.

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Answer:

ACO cable mate

Explanation:

Answer:

You are right. The answer to this question is option A. The metallic sphere is a conductor and can allow electric charges flow through it from one region to another. The reason the sphere is insulted from the ground is to block out the transfer of charges from the sphere to the ground or from the ground to the sphere. The ground itself can serve as infinitely large sink or source for electric charges.

The act of touching the sphere with the charged rod deposits some electric charge on the sphere. These charges in the absence of an insulator between the sphere and the ground will flow straight into the ground. But because there is an insulator connected to the sphere the charges remain on the sphere with no way of getting out of the sphere.

These charges are the same with that on the rod as they were conducted and not induced by polarization (in general if the shepre became charged by polarization, it would have a charge opposite that on the rod). Since like charges repeatedly and unlike charges attract. The sphere would always repel the rod.

Thank you for reading and I hope this was helpful to you.

When the plastic rod is charged and brought close to the neutral metallic sphere, charges are redistributed. After touching and separating, the rod is repelled by the sphere due to the imbalance of charges. Insulating the sphere from the ground prevents charge redistribution.

When the plastic rod is rubbed with a wool cloth, it becomes charged and gains electrons. The charged rod is brought close to the initially neutral metallic sphere, which causes a redistribution of charges on the sphere's surface. Electrons in the sphere are attracted to the positively charged rod, causing an imbalance of charges.

When the rod touches the sphere, electrons from the sphere are transferred to the rod, neutralizing the rod's charge. The sphere gains a negative charge due to the excess electrons it lost to the rod. When the rod is separated from the sphere, it is now negatively charged and repelled by the negatively charged sphere.

Insulating the sphere from the ground means that the sphere is not in contact with any conductive material that can provide or receive charge. This ensures that the charge on the sphere remains constant and does not redistribute to the ground, allowing for the charge redistribution between the rod and the sphere.

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Answer:

Work done, W = 0

Explanation:

Given that, a container of water is lifted vertically 3.0 m then returned to its original position.The total weight of the container is 30 N. We need to find the total work done by the container. We know that the work done by an object is given by :

W = F × d

Where

F is the applied force

d is the displacement of the object

It is mentioned that the container returns to its original position, the displacement of the container is equal to 0. Hence, no work was done by the container of water.

Answer: No work was done when a container of water is lifted vertically 3.0 m and then returned to its original position.

Explanation:

Work is defined as a force causing the movement or displacement of an object.

work=[tex]f\times s[/tex]

Given: f = force = 30N

s = displacement = 0.0 m (as the initial and final position is same, there is no displacement)

Putting in the values we get,

work=[tex]30N\times 0m=0J[/tex]

Thus amount of work will be 0 J.

Incomplete question.The complete question is here

An energy storage system based on a flywheel (a rotating disk) can store a maximum of 4.1 MJ when the flywheel is rotating at 14000 revolutions per minute.What is the moment of inertia of the flywheel?

Answer:

Moment of inertia=3.82 kg.m²

Explanation:

Given data

Energy E=4.1 MJ=4.1×10⁶J

Angular speed ω= 14000 rev/min= 14000×2π/60=1465.3 rad/s

To find

Moment of Inertia

Solution

A rotating flywheel must store its energy as kinetic energy

Let I be moment of inertia of the flywheel.We Know

[tex]E(Energy)=\frac{1}{2}Iw^{2}\\  I=\frac{2E}{w^{2} }\\ I=\frac{2(4.1*10^{6}) }{(1465.3)^{2} }\\ I=3.82 kgm^{2}[/tex]

The subject of this question is Physics and it relates to an energy storage system based on a flywheel.

The subject of this question is Physics. The question relates to an energy storage system based on a flywheel.

A flywheel is a rotating disk that can store energy in the form of rotational kinetic energy. The maximum energy that can be stored in the flywheel depends on its moment of inertia and the square of its angular velocity.

In this case, the flywheel can store a maximum of 4.1 MJ when it is rotating at 14000 revolutions per minute.

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Answer:

cultural

Explanation:

Cultural anthropology studies the characteristics of the behavior learned in human societies, that is, science of human culture. In general, it is the science that studies the origin, development, structure, characteristics and variations of human culture in both past and present societies. Ethnography, ethnology, archeology, linguistics and physical anthropology are the disciplines on which cultural anthropology is founded.

Answer:

   E = 1.024 x 10⁴ V/m

Explanation:

given,

KE of the particle = 3.25 x 10⁻¹⁵ J

mass of the proton = 1.673 x 10⁻²⁷ Kg

charge of the proton = 1.602 x 10⁻¹⁹ C

distance = 2 m

Electric field = ?

we know

work done = KE, and also

W = q V

now,

[tex]V = \dfrac{W}{q}[/tex]

[tex]V = \dfrac{3.25\times 10^{-15}}{1.602\times 10^{-19}}[/tex]

  V = 2.028 x 10⁴ V

now, using equation of electric field

[tex]E = \dfrac{V}{d}[/tex]

[tex]E = \dfrac{2.028\times 10^4}{2}[/tex]

   E = 1.024 x 10⁴ V/m

hence, the magnitude of the electric field is equal to  E = 1.024 x 10⁴ V/m

Answer:

 E = 1.024 x 10⁴ V/m

Explanation:

given,

KE of the particle = 3.25 x 10⁻¹⁵ J

mass of the proton = 1.673 x 10⁻²⁷ Kg

charge of the proton = 1.602 x 10⁻¹⁹ C

distance = 2 m

Electric field = ?

we know

work done = KE, and also

W = q V

now,

 V = 2.028 x 10⁴ V

now, using equation of electric field

  E = 1.024 x 10⁴ V/m

hence, the magnitude of the electric field is equal to  E = 1.024 x 10⁴ V/m

Answer:

(a) 4.0334Ω

(b)parallel

Explanation:

for resistors connected in parallel;

[tex]\frac{1}{R_{eq} } =\frac{1}{R1}+\frac{1}{R2}[/tex]

Req =3.03Ω , R1 =12.18Ω

[tex]\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}[/tex]

[tex]\frac{1}{R2}=\frac{1}{3.03 }-\frac{1}{12.18}[/tex]

[tex]\frac{1}{R2}=0.2479[/tex]

R2=1/0.2479

R2=4.0334Ω

(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.

Req = R1+R2

To achieve a total resistance of 3.03 Ω when an unknown resistor is connected in parallel with a 12.18 Ω resistor, the unknown resistance must be 4.03 Ω.

To determine the unknown resistance that needs to be connected to a 12.18 Ω resistor to produce a total resistance of 3.03 Ω, we can use the formula for resistors in parallel, since the total resistance is given and is less than the resistance of the known resistor. The formula is:

1 / Rtotal = 1 / R1 + 1 / R2

We can arrange the formula to solve for R2, the unknown resistance:

1 / R2 = 1 / Rtotal - 1 / R1

By plugging in the given values (Rtotal = 3.03 Ω, R1 = 12.18 Ω), we get:

1 / R2 = 1 / 3.03 - 1 / 12.18

Calculating the right side of the equation:

1 / R2 = 0.330 - 0.0821

1 / R2 = 0.2479

Finally, we take the reciprocal of both sides to find R2:

R2 = 1 / 0.2479

R2 = 4.03 Ω

So, the unknown resistance must be 4.03 Ω to achieve the specified total resistance when connected in parallel with a 12.18 Ω resistor.

Answer: Machanical advantage of the machine is 1.86

Explanation: Machanical advantage of a machine is the ratio of the Force to overcome which is the load in this case 24kg * 10= 240N to the force exerted(Effort) to overcome the load in this case 129N.

So, we have

MA = load/effort

= 240N/129N

= 1.86.

The mechanical advantage of the pulley system is equal to 1.82.

Given the following data:

Scientific data:

To determine the mechanical advantage of the pulley system:

First of all, we would calculate the force acting on the load as follows;

[tex]Force = mg\\\\Force = 24 \times 9.8[/tex]

Force = 235.2 Newton

Now, we can solve for mechanical advantage:

[tex]M.A = \frac{Load}{Effort} \\\\M.A=\frac{235.2}{129}[/tex]

Mechanical advantage = 1.82.

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Answer:

a) [tex]v \approx 28.010\,\frac{m}{s}[/tex], b) B. Time interval for stopping is greater.

Explanation:

a) The initial velocity is found with the help of the Principle of Energy Conservation:

[tex]K = U_{g}[/tex]

[tex]m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}[/tex]

[tex]v = \sqrt{2\cdot g \cdot h}[/tex]

[tex]v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (40\,m)}[/tex]

[tex]v \approx 28.010\,\frac{m}{s}[/tex]

b) According to the Impact Theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Hence, the right answer is option B.

1) The water leaves the ground at a velocity of 28 m/sec. Therefore the correct option is B).

2) An egg dropped on the road usually breaks, while one dropped on the grass usually does not break because contact force is significantly lower and time interval is greater.

Given :

Yellowstone National Park shoots water every hour to a height of 40 m.

Solution :

1) From conservation of momentum -

KE = PE

[tex]\rm \dfrac{1}{2}mv^2 = mgh[/tex]

[tex]\rm v = \sqrt{2gh}[/tex]  --- (1)

where,

[tex]\rm g = 9.8\;m/sec^2[/tex]

h = 40 m

Now put the values of g and h in equation (1) we get,

[tex]\rm v = \sqrt{2\times 9.8\times 40}[/tex]

v = 28 m/sec

2) According to the impact theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Therefore, the correct option is B).

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https://brainly.com/question/13949051

Answer:a) 20.944rad/s (b) 12.57m/s (c) 800rev/min²

Explanation:

Final answer:

The angular speed of the flywheel in radians per second is 20π/3 radians/s. The linear speed of a point in the rim of the flywheel is 40π/9 m/s. The constant angular acceleration of the flywheel cannot be determined without additional information.

Explanation:

(a) To convert the angular speed from revolutions per minute (rpm) to radians per second, we need to multiply by a conversion factor of

2π radians = 1 revolution

First, convert the angular speed from rpm to revolutions per second:

200 rev/min × (1 min/60 s) = 200/60 rev/s

Next, convert the revolutions per second to radians per second:

200/60 rev/s × (2π radians/1 rev) = 20π/3 radians/s

So, the angular speed of the flywheel in radians per second is 20π/3 radians/s.

(b) The linear speed of a point on the rim of the flywheel can be calculated using the formula:

Linear speed = angular speed × radius

Given that the diameter of the flywheel is 1.20 m, the radius is 0.60 m.

Linear speed = (20π/3 radians/s) × (0.60 m) = 40π/9 m/s

So, the linear speed of a point in the rim of the flywheel is 40π/9 m/s.
(c) The flywheel has a constant angular acceleration if its angular velocity changes at a constant rate over time. The formula for angular acceleration is:

Angular acceleration = change in angular velocity / change in time

Since the question does not provide information about the change in angular velocity or time, we cannot determine the constant angular acceleration of the flywheel.

Answer:

The answer is 3597501.48 km

Explanation:

The speed of light is 299792 km/s.

The speed of sound is 0.343 km/s

The difference is 299791.76 km/s

and of there is 12 second difference between sound and the light. The distance will be:

[tex]299791.76*12=3597501.48[/tex]

It should be far from the storm is the observer is 3597501.48 km.

It measured how hot or cold the air should be. It explained the kinetic energy, or energy of motion, of the gases that make up air. Since gas molecules move faster due to which there is an increment in the air temperature

Since the temperature of the air is 20c and there is 12 seconds.

Also,

The speed of light is 299792 km/s.

The speed of sound is 0.343 km/s

The difference is 299791.76 km/s

Now it is

[tex]= 299791.76 km/s \times 12[/tex]

= 3597501.48 km

Learn more about the temperature here: https://brainly.com/question/22463901

Answer:

2. 113 degrees F increase

Explanation:

Formula for converting °C to °F is

(°C × 9/5)+32

Where °C is the temperature value in degree Celsius. Given temperature to be 45°C, converting to °F we have;

(45°C × 9/5) + 32

= 81+32

= 113°F