A bobsled team pushes a 132-kg bobsled. If the combined push of the team is 450.0 N and the bobsled also experiences a force of friction of 35 N, what is the acceleration of the bobsled?

Answer:

9 Km

Explanation:

given,

distance of the river = 4 Km = 4000 m

speed of the boy = 2 m/s

speed of the dog back and forth = 4.5 m/s

distance ran by the dog = ?

time taken by the boy to cover the distance

we know,

distance = speed x time

[tex]t = \dfrac{4000}{2}[/tex]

t = 2000 s.

now, distance travel by the dog.

d= 4.5 x 2000

d = 9000 m

d = 9 Km

distance covered by the dog is equal to 9 Km.

Answer:

[tex]\displaystyle CD=BE\ \frac{CA}{BA}[/tex]

Explanation:

Thales Theorem

It applies when a line is drawn parallel to one side of a triangle and it intersects the other two sides. The theorem states that line divides the two sides in the same ratio or proportion.

We have drawn the triangle that describes the situation stated in the question, where we want to know the value of CD, knowing the values of BE, BA, and CA. The red line BE is parallel to the line CD, so the Tales theorem must stand meaning that the sides AC and AB are proportionally divided at the same ratio as CD and BA, thus

[tex]\displaystyle \frac{CD}{BE}=\frac{CA}{BA}[/tex]

We can solve for CD (the height of the flagpole)

[tex]\boxed{\displaystyle CD=BE\ \frac{CA}{BA}}[/tex]

Answer:If we want to find the height of an object like a flagpole, we can use right triangles. In the graphic above, triangle ABE is similar to triangle ACD. In the graphic line segment DC is the height of the flagpole. Using the length of BE (your height), AB (your shadow), and AC (the shadow of flagpole), we can use a proportion to determine the height of the flagpole.

Explanation: fill in the blank

Answer:

Explanation:

Given

Object 1 is  of mass [tex]\frac{m}{2}[/tex]

Object 2 has mass of [tex]m[/tex]

They undergone inelastic collision and do not move after collision i.e. the collision is perfectly inelastic

Final momentum of both the object is zero

suppose [tex]v_1[/tex] and [tex]v_2[/tex] are the velocities of object 1 and 2 respectively then

[tex]m_1v_1+m_2v_2=0[/tex]

[tex]\frac{v_1}{v_2}=-\frac{m_2}{m_1}[/tex]

[tex]\frac{v_1}{v_2}=-2[/tex]

[tex]v_1=-2v_2[/tex]

i.e. velocity of object 1 is twice the velocity of object 2 but opposite to the direction of object 2

The comparison of the velocity of both objects before the collision is [tex]u_1=-2u_2[/tex]

According to the law of conservation of momentum, the momentum of a body before collision is equal to the momentum after collision. Mathematically;

[tex]m_1v_1 + m_2u_2=m_1v_1+m_2v_2[/tex]

Since both objects do not move after the collision, the equation becomes:

[tex]m_1v_1 + m_2u_2=0[/tex]

Also if Objects 1 has half the mass of object 2, then [tex]m_1=0.5m_2[/tex]

Substitute into the formula above:

[tex]0.5m_2u_1 + m_2u_2=0\\0.5m_2u_1 =-m_2u_2\\0.5u_1=-u_2\\u_1=-2u_2[/tex]

The comparison of the velocity of both objects before the collision is [tex]u_1=-2u_2[/tex]

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The formula U = mgy is not accurate for calculating the gravitational potential energy of a satellite orbiting at a significant height because g is not constant at such distances. Instead, the formula U = -GMm/r should be used. This reflects the gravitational potential becoming more negative at larger distances, which means orbits at those distances are bound due to the total energy remaining negative.

It's inaccurate to use the simple formula U = mgy to calculate the gravitational potential energy of a satellite orbiting Earth at a significant height because this formula assumes that the gravitational acceleration (g) is constant. However, g varies with altitude and is less at higher altitudes. For satellites in orbit, especially at a height of one Earth radius above the surface, we need to use a more general expression that accounts for the change in g with distance from the center of Earth.

The correct formula for calculating the gravitational potential energy (GPE) of a satellite at a distance r from the center of Earth (where r is significantly greater than the Earth's radius) is derived from the law of universal gravitation and is U = -GMm/r, where G is the gravitational constant, M is the mass of Earth, and m is the mass of the satellite.

This more general expression shows that at large distances, GPE becomes increasingly negative, approaching zero as r becomes infinitely large. A satellite with negative total energy is in a bound orbit because the kinetic energy (which is always positive) is not enough to overcome the magnitude of the negative GPE, hence the satellite remains gravitationally bound to Earth. As for the trend in the ratio of kinetic energy to the change in potential energy as the size of the orbit increases, it generally decreases, indicating that for larger orbits, the kinetic energy constitutes a larger fraction of the total energy needed to maintain the orbit.

The assumption made in this derivation is that the satellite orbits around the center of the astronomical body (such as Earth), and not around a common center of mass, which is not exact but works well since Earth is much more massive compared to the satellite, as in the case of the Moon orbiting the Earth.

Answer:

convection

Explanation:

Convective heat transfer, often referred to simply as convection, is the transfer of heat from one place to another by the movement of fluids. this time fluid is out atmosphere.

Answer:a) 20.944rad/s (b) 12.57m/s (c) 800rev/min²

Explanation:

Final answer:

The angular speed of the flywheel in radians per second is 20π/3 radians/s. The linear speed of a point in the rim of the flywheel is 40π/9 m/s. The constant angular acceleration of the flywheel cannot be determined without additional information.

Explanation:

(a) To convert the angular speed from revolutions per minute (rpm) to radians per second, we need to multiply by a conversion factor of

2π radians = 1 revolution

First, convert the angular speed from rpm to revolutions per second:

200 rev/min × (1 min/60 s) = 200/60 rev/s

Next, convert the revolutions per second to radians per second:

200/60 rev/s × (2π radians/1 rev) = 20π/3 radians/s

So, the angular speed of the flywheel in radians per second is 20π/3 radians/s.

(b) The linear speed of a point on the rim of the flywheel can be calculated using the formula:

Linear speed = angular speed × radius

Given that the diameter of the flywheel is 1.20 m, the radius is 0.60 m.

Linear speed = (20π/3 radians/s) × (0.60 m) = 40π/9 m/s

So, the linear speed of a point in the rim of the flywheel is 40π/9 m/s.
(c) The flywheel has a constant angular acceleration if its angular velocity changes at a constant rate over time. The formula for angular acceleration is:

Angular acceleration = change in angular velocity / change in time

Since the question does not provide information about the change in angular velocity or time, we cannot determine the constant angular acceleration of the flywheel.

Answer:

b) Earth is passing Saturn in its orbit, with both planets on the same side of the Sun.

Explanation:

Retrograde motion is an optical effect due to the fact that Earth rotates more quickly than the planet that apparently has a retrograde motion in the sky.

For this particular case, Saturn has a slower speed in its orbit around the sun. That means that the Earth will pass it, and that will give the effect that the planet is moving backward. That same scenario can be seen between two cars on a highway, the faster car will see the slower car when it passes going in backward for a short fragment of time.

Remember that all the object in the night sky moves from east to west (since the Earth rotates counterclockwise in its daily movement), in the case of a planet with retrograde motion, it will move from west to east for a couple of months.        

Apparent retrograde motion of Saturn occurs when Earth overtakes Saturn in their respective orbits around the Sun, creating the illusion that Saturn is moving backward (westward) against the star's background. This is a result of our perspective from Earth and not an actual reversal of Saturn's orbit.

When we observe Saturn going through a period of apparent retrograde motion, it is not because Saturn is actually moving backwards in its orbit. Instead, this phenomenon occurs because Earth is passing Saturn in its orbit, with both planets on the same side of the Sun. As Earth, which moves faster in its orbit due to being closer to the Sun, overtakes Saturn, Saturn appears to move westward against the background stars. This westward motion is temporary and is perceived from Earth due to our vantage point.

As Earth continues in its orbit, reaching a point where the direct line of sight aligns with Saturn once more, Saturn will resume its normal prograde motion (eastward relative to the stars) in the night sky. This retrograde motion is much simpler to understand now with our knowledge of Earth and other planets orbiting the Sun, rather than from the historically held geocentric view which placed Earth at the center of the universe.

Final answer:

The red and green trains apply brakes with a deceleration of 1.0 m/s^2 when 920 m apart, and will stop without colliding, leaving a separation of 80 m.

Explanation:

When the red train traveling at 72 km/h and the green train traveling at 144 km/h are 920 meters apart and both apply brakes with a deceleration of 1.0 m/s2, we can calculate whether a collision will happen.

First, convert the speeds from km/h to m/s: the red train's speed is 20 m/s (72 km/h) and the green train's speed is 40 m/s (144 km/h).

Next, calculate the stopping distance for both trains using the formula s = v2 / (2a), where v is the initial speed and a is the deceleration. For the red train: s = (20 m/s)2 / (2 x 1 m/s2) = 200 m. For the green train: s = (40 m/s)2 / (2 x 1 m/s2) = 800 m.

The total stopping distance for both trains is 200 m + 800 m = 1000 m. Since they start 920 m apart, they will not collide because their combined stopping distance is greater than the initial separation.

Thus, (a) the speed of the red train when they stop will be 0 m/s, (b) the speed of the green train will be 0 m/s, and (c) the separation between the trains when they stop will be 80 meters.

Answer:

a) [tex]v \approx 28.010\,\frac{m}{s}[/tex], b) B. Time interval for stopping is greater.

Explanation:

a) The initial velocity is found with the help of the Principle of Energy Conservation:

[tex]K = U_{g}[/tex]

[tex]m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}[/tex]

[tex]v = \sqrt{2\cdot g \cdot h}[/tex]

[tex]v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (40\,m)}[/tex]

[tex]v \approx 28.010\,\frac{m}{s}[/tex]

b) According to the Impact Theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Hence, the right answer is option B.

1) The water leaves the ground at a velocity of 28 m/sec. Therefore the correct option is B).

2) An egg dropped on the road usually breaks, while one dropped on the grass usually does not break because contact force is significantly lower and time interval is greater.

Given :

Yellowstone National Park shoots water every hour to a height of 40 m.

Solution :

1) From conservation of momentum -

KE = PE

[tex]\rm \dfrac{1}{2}mv^2 = mgh[/tex]

[tex]\rm v = \sqrt{2gh}[/tex]  --- (1)

where,

[tex]\rm g = 9.8\;m/sec^2[/tex]

h = 40 m

Now put the values of g and h in equation (1) we get,

[tex]\rm v = \sqrt{2\times 9.8\times 40}[/tex]

v = 28 m/sec

2) According to the impact theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Therefore, the correct option is B).

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Answer:

[tex]\frac{25}{3}ft/s[/tex]

Explanation:

Height of man= 6ft

Height of light=1 5ft

Let BC=x and CD=y

BD=x+y

Triangle ABD and ECD are similar

When two triangles are similar then the ratio of their corresponding sides are equal

[tex]\frac{AB}{EC}=\frac{BD}{CD}[/tex]

[tex]\frac{15}{6}=\frac{x+y}{y}[/tex]

[tex]\frac{5}{2}=\frac{x+y}{y}[/tex]

[tex]5y=2x+2y[/tex]

[tex]5y-2y=2x[/tex]

[tex]3y=2x[/tex]

Differentiate w.r.t t

[tex]2\frac{dx}{dt}=3\frac{dy}{dt}[/tex]

We have [tex]\frac{dx}{dt}=5ft/s[/tex]

Substitute the value then we get

[tex]2\times 5=3\frac{dy}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s[/tex]

Rate at which the tip of  shadow is moving=[tex]\frac{dx}{dt}+\frac{dy}{dt}[/tex]

Rate at which the tip of  shadow is moving=[tex]5+\frac{10}{3}=\frac{15+10}{3}ft/s[/tex]

Rate at which the tip of  shadow is moving=[tex]\frac{25}{3}ft/s[/tex]

Answer:

given,

Force acting perpendicularly to the door = 46 N

distance from the hinge = 0.740 m

we know,

torque = Force x distance

τ = F x r

τ = 46 x 0.740

τ = 34.04 N.m

b) No it does not matter if we push at the same height as the hinges.

now, From the expression we  can clearly see that what matters is the perpendicular distance from the point of force application.

Answer:

   E = 1.024 x 10⁴ V/m

Explanation:

given,

KE of the particle = 3.25 x 10⁻¹⁵ J

mass of the proton = 1.673 x 10⁻²⁷ Kg

charge of the proton = 1.602 x 10⁻¹⁹ C

distance = 2 m

Electric field = ?

we know

work done = KE, and also

W = q V

now,

[tex]V = \dfrac{W}{q}[/tex]

[tex]V = \dfrac{3.25\times 10^{-15}}{1.602\times 10^{-19}}[/tex]

  V = 2.028 x 10⁴ V

now, using equation of electric field

[tex]E = \dfrac{V}{d}[/tex]

[tex]E = \dfrac{2.028\times 10^4}{2}[/tex]

   E = 1.024 x 10⁴ V/m

hence, the magnitude of the electric field is equal to  E = 1.024 x 10⁴ V/m

Answer:

 E = 1.024 x 10⁴ V/m

Explanation:

given,

KE of the particle = 3.25 x 10⁻¹⁵ J

mass of the proton = 1.673 x 10⁻²⁷ Kg

charge of the proton = 1.602 x 10⁻¹⁹ C

distance = 2 m

Electric field = ?

we know

work done = KE, and also

W = q V

now,

 V = 2.028 x 10⁴ V

now, using equation of electric field

  E = 1.024 x 10⁴ V/m

hence, the magnitude of the electric field is equal to  E = 1.024 x 10⁴ V/m

Answer:

It's an ORDINAL Level of measurement.

The level of measurement for data collected on a Always/Sometimes/Never scale is ordinal.

The level of measurement for data collected on a Always/Sometimes/Never scale is ordinal. In an ordinal scale, data can be categorized and ordered, but the intervals between data points may not necessarily be equal or meaningful. In this case, the habit categories would have a natural order (Always, Sometimes, Never), but the difference between Always and Sometimes may not be the same as the difference between Sometimes and Never.

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Answer: [tex]1.000\times 10^2m^2[/tex]

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division  is :

The least precise number present determines the number of significant figures in the answer.  

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

Area of square collector 1 =

Area of square collector 1 =[tex]6.00m\times 6.00m=36.0m^2[/tex]

Area of square collector 2 =[tex]length\times breadth[/tex]

Area of square collector 2 =[tex]8.000m\times 8.000m=64.00m^2[/tex]

Combined area of both collectors = Area of square collector 1 + Area of square collector 2 = [tex]36.0m^2+64.00m^2=100.0m^2=1.0\times 10^2m^2[/tex]

The combined area of both collectors is [tex]1.000\times 10^2m^2[/tex]

The combined area of both solar collectors is 1.0 × 10² m².

To find the combined area of both solar collectors, simply add the areas of the two squares. The formula for the area of a square is length multiplied by width. For the first solar collector measuring 6.00 m by 6.00 m, the area is 6.00 m x 6.00 m = 36.00 m². To find the combined area of both solar collectors, simply add the areas of the two squares. The formula for the area of a square is length multiplied by width. For the first solar collector measuring 6.00 m by 6.00 m, the area is 6.00 m x 6.00 m = 36.00 m². For the second solar collector measuring 8.000 m by 8.000 m, the area is 8.000 m x 8.000 m = 64.00 m². Adding the areas, we get 36.00 m² + 64.00 m² = 100.00 m².The correct answer, using the correct number of significant figures, is therefore 1.0 × 10² m². This answer is represented by option b.For the second solar collector measuring 8.000 m by 8.000 m, the area is 8.000 m x 8.000 m = 64.00 m². Adding the areas, we get 36.00 m² + 64.00 m² = 100.00 m².

The correct answer, using the correct number of significant figures, is therefore 1.0 × 10² m². This answer is represented by option b.

Answer:

Spring constant of the spring will be 68.6 N/m

Explanation:

It is given mass which is vertically hung m = 6.80 kg

Spring is stretched by length of 0.1 m , so x = 0.210 m

Acceleration due to gravity will be equal to [tex]g=9.8m/sec^2[/tex]

Force on the mass which is vertically hung will be equal to mg

This force will be balanced by spring force acting on the mass

And spring force is equal to F = Kx

So kx = mg

[tex]k\times 0.1=0.7\times 9.8[/tex]

k = 68.6 N /m

So spring constant of the spring will be equal to 68.6 N/m

Answer:

Explanation:

Given

Charge of [tex]Q=0.8\ nC[/tex]  

Length of side of cube [tex]a=4\ m[/tex]  

Total Flux through the cube [tex]\phi =\frac{Q}{\epsilon _0}[/tex]  

[tex]\epsilon _0=8.854\times 10^{-12}\ C^2/N-m^2[/tex]  

total Flux [tex]\phi=\frac{0.8\times 10^{-9}}{8.854\times 10^{-12}}[/tex]  

[tex]\phi =90.35\ N-m^2/C[/tex]  

As cube has 6 faces , so flux through each face will be similar

thus flux through  each face [tex]\phi'=\frac{\phi }{6}[/tex]  

[tex]\phi '=\frac{90.35}{6}=15\ N-m^2/C[/tex]    

Answer:

Explanation:

According to Boyle's law  for constant temperature of gas Pressure is inversely proportional to the volume of gas.

[tex]PV=nRT[/tex]

[tex]PV=constant[/tex]

[tex]P\propto \frac{1}{V}[/tex]

if Pressure is tripled then

[tex]P\times V_1=3P\times V_2[/tex]

[tex]V_2=\frac{V_1}{3}[/tex]

Volume becomes one-third of original volume          

Final answer:

According to Boyle's Law, tripling the pressure on a gas at constant temperature will reduce its volume to one third of the original volume.

Explanation:

The question is based on Boyle's Law which states that for a given mass of an ideal gas at constant temperature, the volume of the gas is inversely proportional to its pressure. Therefore, if the pressure acting on a gas is tripled (pressure is proportional to 3), the volume will be reduced to one third of its original value (volume is proportional to 1/3), assuming that the temperature and the amount of gas remain constant.

Answer:

2. 113 degrees F increase

Explanation:

Formula for converting °C to °F is

(°C × 9/5)+32

Where °C is the temperature value in degree Celsius. Given temperature to be 45°C, converting to °F we have;

(45°C × 9/5) + 32

= 81+32

= 113°F

Answer:

It's answer : 44 atm

Explanation:

Explanation:

Iron has tiny magnetic domains inside it. Each domain acts like a tiny magnet with its own magnetic field. These domains are randomly distributed thus resulting in zero magnetic field and iron doesn't behave like a magnet.

When a copper wire is wound around the nail and current is passed through the coil, magnetic field is generated. This magnetic field penetrates through the nail. Due to this the magnetic domains of the nail align in the same direction thus having a net magnetic field. The nail behaves like a magnet till the time current flows through the coil.

Explanation:

We know that in series connection current in all the resistors are same.

Effective resistance is sum of individual resistances.

Here three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit

Effective resistance = 3 + 5 + 22 = 30 ohms

Voltage = 28 V

We know

        Voltage = Current x Resistance

         V = IR

         28 = 30 x I

         I = 0.93 A

Current in each resistor is 0.93 A

Option C is the correct answer.

Explanation:

In both cases the conversion of one chemical element into another is obtained, modifying the number of protons in the nucleus. The difference is that artificial transmutation needs an outside cause, since an outside particle reacts with the nucleus, while in nuclear  decay not cause outside is needed.

Explanation:

A wave on a string is described is given by :

[tex]D(x,t)=2\ cm\ sin[(12.57\ rad/m)-(638\ rad/s)t][/tex]

The linear density of the string is 5 g/m.

Where

x is in meters and t is in seconds

The general equation of a wave is given by :

[tex]y=A\ sin(kx-\omega t)[/tex]

(2) The speed of the wave in terms of tension is given by :

[tex]v=\sqrt{\dfrac{T}{\mu}}[/tex]

Also, [tex]v=\dfrac{\omega}{k}[/tex]

So, [tex]\dfrac{\omega}{k}=\sqrt{\dfrac{T}{\mu}}[/tex]

[tex]T=\dfrac{\mu \omega^2}{k^2}[/tex]

[tex]T=\dfrac{5\times 10^{-3}\times (638)^2}{(12.57)^2}[/tex]

T = 12.88 N

(3) The maximum displacement of a point on the string is equal to the amplitude of the wave. So, the maximum displacement is 2 cm.

(4) The maximum speed of a point on the string is given by :

[tex]v=A\omega[/tex]

[tex]v=0.02\times 638[/tex]

v = 12.76 m/s

Hence, this is the required solution.

The net force of the cart when it is pushed to the right with a force of 15N.

Explanation:

To find the force of net, which is calculated by the  formula.

The Net Force= Addition of the force applied on the respective  direction.

The Net Force here is given by

The Net Force = 15-20 (A force towards the right and a force towards left, two opposite so subtraction).

Hence

Thus the Net Force = -5(The force towards left, so it gets a  negative value).

The net force on the cart is -5 N, which means the cart is experiencing a force of 5 N in the opposite direction of its motion.

The net force on the cart can be found by subtracting the force pulling the cart to the left from the force pushing the cart to the right. In this case, the force pushing the cart to the right is 15 N and the force pulling the cart to the left is 20 N. So, the net force on the cart is:

Net force = Force pushing to the right - Force pulling to the left

Net force = 15 N - 20 N

Net force = -5 N

The net force on the cart is -5 N, which means the cart is experiencing a force of 5 N in the opposite direction of its motion.

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Answer:

8.29 * 10^{13} N

Explanation:

Weigth is the force of gravity a body of mass experiences due to the gravity of another mass.

Force=mass*acceleration (to calculate the mass of the object);

675=m*9.8; Mass = 68.88 kg

Force= [tex]\frac{GMm}{r^{2} }[/tex]; M is the mass of the bigger object, m is the mass of the smaller object, r is the seperation in between (radius in this case) and G is the Gravitational constant.

Mass of the sun = 1.989 × 10^30 kg

G = 6.67 × 10-11 m3 kg-1 s-2

mass of the object = 68.88 kg;

Applying the formula:

Force=[tex]\frac{(6.67 * 10^{-11} ) * (68.88) * (1.989 * 10^{30} )}{(((21 *10^{3} ))/2)^{2} }[/tex]

Force = 8.29 * 10^{13} N

The weight on the surface of a neutron star that has the same mass as our Sun and a diameter of 21.0 km will be 8.29 × 10¹³ N

Given that the weight of the person on the earth is 675N.

mg = 675N

where m is the mass of the person.

m = 675/g

m = 675/9.8

m = 68.87 kg

The gravitational force on the surface of a celestial body is given by:

F = GMm/R²

where G is the gravitational constant

M is the mass of the body

m is the mass of the person

and, R is the radius of the body

F = (6.67 × 10⁻¹¹)( 2 × 10³⁰)(68.87) / (21/2 × 10³)²

F = 8.29 × 10¹³ N

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Answer:

kinetic energy in each pulse = 9.5J

Explanation:

Conventionally, overall energy = kinetic + potential

Hence kinetic energy in each pulse = half of the total energy = 0.5 x 19

energy = 9.5J

The kinetic energy is in each pulse is 19J.

The Power delivered is defined at the rate of work done, if P be the power, W be the work done and t be the time for which the work is done then:

P = W/t

W = Pt

given that P = 10w and t = 1.9s

W = 10×1.9 J

W = 19J

Now, the work done is equal to the change in Kinetic energy (KE)

ΔKE = W = 19J

Hence, the kinetic energy is 19J.

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Answer: The oscilloscope is not a plotting machine.

Explanation: The Oscilloscope is not a plotting machine is a device which is use to measure the frequency,period, peak to peak Voltage Vpp or any signal. That is alternating.

So, if you're such you wired your circuit whose output signal you want to measure very well and all connections and settings are done accurately, then you can reduce the volt/div below 0.2. You not seeing any signal at 0.2v/div shows that the amplitude of the signal coming into the Oscilloscope is not up to that.

The x-axis on an oscilloscope represents time, while the y-axis represents voltage. To view a 6 volt signal when the 'volts/div' is set at 0.2, you should adjust it to 2 volts/div or higher, as the current setting is too low to display the signal's amplitude correctly.

On an oscilloscope, the horizontal axis (or x-axis) typically represents time, allowing you to see how a signal changes over time. The vertical axis (or y-axis) represents voltage, displaying the amplitude of the signal. If you are attempting to view a 6 volt signal with the "volts/div" setting at 0.2 volts per division, the signal will be off-scale, because each division will represent only 0.2 volts, and a 6 volt signal would require 30 divisions to be fully displayed, which is beyond the scope of a standard oscilloscope screen.

To properly view the 6 volt signal, you should turn the dial to 2 volts/div or higher. This adjustment will ensure that the signal occupies fewer divisions on the screen, making it visible. If you set it to 0.02 volts/div, the signal would be even less visible because the signal would then require 300 divisions, which is impractical to display.

The acceleration of the proton is 6.7×10¹⁰ m/s² in the direction of the electric field.

Electrostatic force:

The force on a charged particle due to an electric field is given by:

F = qE

where q is the charge = 1.6×10⁻¹⁹C

and E is the electric field = 700N/C

Also, from Newton's laws of motion;

F = ma

where m is mass = 1.67×10⁻²⁷kg and a is acceleration

ma = qE

a = qE/m

[tex]a=\frac{1.6\times10^{-19}\times700}{1.67\times10^{-27}}\;m/s^2\\\\a=6.7\times10^{10}\;m/s^2[/tex]towards the direction of the electric field.

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Answer:

spring constant of the spring will be equal to 317.33 N/m

Explanation:

We have given mass of the child m = 6.80 kg

Spring is stretched by length of 0.210 m . so x = 0.210 m

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Force on the child will be equal to [tex]W=mg[/tex]

This force will be balanced by spring force

And spring force is equal to F = Kx

So kx = mg

[tex]k\times 0.210=6.80\times 9.8[/tex]

k = 317.33 N /m

So spring constant of the spring will be equal to 317.33 N/m