A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attached to a vertical wall by a string 6 meter long and 5 meter away from the wall. Find the magnitude of the horizontal force F,APPLIED TO THE LOWER block that shall be necessary so that slipping of 100 kg block occurs. (take coefficient of friction for both contacts =0.25 )

Answer:

(a) 2.88×10⁻² W/m²

(b) 8.36×10⁻³ W/m²

Explanation:

The intensity of sound from an isotropic point source, with distance L is given as

I = P/(4πL²) .................................... Equation 1

Where I = intensity of sound, P = Power from the source, L = length, π = pie.

(a)

1.4 m from the source.

I = P/(4πL²)

Given: P = 0.71 W, L = 1.4 m, π = 3.14.

Substitute into equation 1

I = 0.71/(4×3.14×1.4²)

I = 0.71/24.6176

I = 0.0288 W/m².

I = 2.88×10⁻² W/m²

(b) 2.6 m from the source.

Given: P = 0.71 W, L = 2.6 m, π = 3.14

Substitute into equation 1

I = 0.71/(4×3.14×2.6²)

I = 0.71/84.9056

I = 0.00836 W/m²

I = 8.36×10⁻³ W/m²

Answer:

[tex]m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )[/tex]

Explanation:

Then the mass of the material required to make such a sphere would be calculated as:

Total volume of the spherical shell:

[tex]V_t=\frac{4}{3} \pi.r_2^3[/tex]

And the volume of the hollow space in the sphere:

[tex]V_h=\frac{4}{3} \pi.r_1^3[/tex]

Therefore the net volume of material required to make the sphere:

[tex]V=V_t-V_h[/tex]

[tex]V=\frac{4}{3} \pi(r_2^3-r_1^3)[/tex]

Then the mass of the material used is:

[tex]m=\rho.V[/tex]

[tex]m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )[/tex]

Explanation:

This difference is because of the difference in arrangement of carbon atoms both graphite and Diamond.

Carbon atoms in graphite are arranged in layered form in an infinite array of layers. These layers are held together by a weaker force of attraction called vander waal's force of attraction such that layer's can slip over one another. Whereas in diamond carbon atoms are arranged tetrahedrally. Each carbon atom is attached to four carbon atoms with a bond angle of 109.5°. It is strong rigid three dimensional structure that results in infinite array atoms. This accounts for hardness of the diamond.

Final answer:

Diamond and graphite exhibit vastly different physical properties due to their respective carbon atom structures: diamond's strong three-dimensional covalent bonds make it extremely hard, while graphite's layered structure with weak interlayer forces makes it soft and slippery.

Explanation:

Diamond and graphite are two forms of the same element, carbon, but they have vastly different physical properties due to the way their atoms are bonded together. In diamond, each carbon atom is tetrahedrally bonded to four other carbon atoms in a strong three-dimensional network, which is what makes diamonds so hard and durable. This covalent bonding extends throughout the crystal, making it an excellent insulator but very hard to break.

Conversely, graphite is composed of layers of carbon atoms bonded in a hexagonal pattern, with weaker interlayer attractions known as London dispersion forces. This allows the layers to slide past each other easily, which is why graphite can be used as a lubricant and as the 'lead' in pencils – rubbing off onto paper with ease. The strong covalent bonds within the layers give graphite its high melting point, but the weak interactions between layers contribute to its softness.

Furthermore, graphite's structure enables it to conduct electricity parallel to the planes due to delocalized π (pi) bonds, while diamond does not conduct electricity. Graphite's black color results from the absorption of light by its delocalized electrons, whereas pure diamond is colorless.

Answer:

Yes, it will produce a diffraction pattern.

a. 3.9 mm b. 1.95 mm

Explanation:

The light shined from a single slit will produce a diffraction pattern because,  the wavefront act as wavelets which generates its own wave according to Huygens principle. This therefore causes the diffraction pattern.

Given

wavelength of green light, λ = 520 nm = 520 × 10⁻⁹ m = 5.20 × 10⁻⁷ m

width of slit, d = 0.440 mm = 0.44 × 10⁻³ m = 4.4 × 10⁻⁴ m

Distance of slit from central maximum , D = 1.65 m

Distance of first minimum from central maximum, y = ?

a. The relationship between the slit width and wavelength is given by [tex} dsinθ = mλ [/tex]where d = slit width, θ = angular distance from central maximum, λ = wavelength of light and m = ±1, ±2, ±3...

The relationship between y and D is given by [tex] tanθ = y/D [/tex]

Since θ is small, sinθ ≈ θ ≈ tanθ

so, dθ = mλ ⇒ θ = mλ/d = y/D

Therefore, y = mλD/d

Now, for the first minimum above the slit, m = +1 and for the first minimum below the slit, m = -1. So, y₁ =  λD/d and y₋₁ =  -λD/d. So, the width of the central maximum Δy is the difference between the first minima below and above the central maximum. So, Δy = y₁ - y₋₁ = λD/d -(-λD/d) = 2λD/d

Substituting the values from above, Δy= 2 × 5.20 × 10⁻⁷ × 1.65/4.4 × 10⁻⁴ =  3900 × 10⁻⁶ m = 3.9 × 10⁻³ m = 3.9 mm

b. The first order fringe is the fringe located between the first minimum and the second minimum. From dsinθ = mλ and tanθ = y/D when θ is small, sinθ ≈ θ ≈ tanθ. So, y = mλD/d. Let m= 1 and m=2 be the first and second minima respectively. So,y₁ =  λD/d and y₂ =  2λD/d. The difference Δy₁ = y₂ - y₁ is the width of the first order fringe. Therefore, Δy₁ = 2λD/d - λD/d= λD/d. Substituting the values from above, we have

λD/d= 5.20 × 10⁻⁷ × 1.65/4.4 × 10⁻⁴= 1.95 × 10⁻³ m = 1.95 mm

Answer:

0.056 miles away

Explanation:

From sound wave,

v = 2x/t .................................. Equation 1

Where v = velocity of sound in air, x = distance of echo, t = time.

making x the subject of the equation,

x = 2v/t........................... Equation 2.

Given: v = 344 m/s, t = 7.6 s.

Substituting into equation 2

x = 2(344)/7.6

x = 90.53 m.

x = 90.53/1609.344

x = 0.056 mile.

Thus the lighting strike 0.056 miles away

Answer:

option (c)

Explanation:

When an object thrown upwards, the value of acceleration acting on the object is acceleration due to gravity which is always acting towards the earth.

As it falls downwards, the acceleration is again equal to the acceleration due to gravity.

So, the ball's acceleration is constant.

Final answer:

The acceleration of the ball remains constant throughout its up and down motion since it is solely influenced by gravity, which provides an acceleration of approximately 9.81 m/s² downward

Explanation:

When a ball is thrown upwards from the ground and then falls back down, the acceleration of the ball is what remains constant throughout its motion. This is due to gravity, which acts downward on the ball with an acceleration denoted as "g". While the ball's position and speed are changing throughout the motion, its acceleration due to gravity remains constant at approximately 9.81 m/s2 (on Earth), regardless of its state of motion. Therefore, the quantity that remains constant over the course of this up and down motion is the ball's acceleration.

Answer: D. all of the above

Explanation:

The speed is important in tennis, so you can win easily, speed is important in soccer to collect the ball quickly and reach the goal, speed is necessary for swimming as the first person wins the game so, option D is correct.

A moving object's rate of change in distance traveled is measured as speed. Speed is a scalar, which implies it is a measurement with a magnitude but no direction.

A thing that moves quickly and with high speed, covering a lot of ground in a short time. On the other hand, a slow-moving object traveling at a low speed covers a comparatively small distance in the same amount of time. An object with zero speed does not move at all.

Speed shortens the time needed to complete a task or travel between two locations. The spare time can then be applied to other tasks. The Earth's orbit around the Sun is maintained by speed.

Thus, speed is important in all the games mentioned here.

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Answer: 1/2

Explanation:

The total energy consumption in the United States of America has been estimated to be about 101.3quadrillion Btu( British thermal unit). The United States of America uses a mix energy source for energy Production which includes PRIMARY, SECONDARY, RENEWABLE,FOSSIL FUELS.

Five basic energy consumption sectors have been categorized in the United States,which includes ELECTRIC POWER, INDUSTRIAL, COMMERCIAL, RESIDENTIAL AND TRANSPORTATION. Of the estimated 101.3(quads) about 1/2 of 101.3(quads) are used for the production and manufacturing of materials by the manufacturing industry.

Hi you didn't provide any images to solve the question, hence I am going to solve a different question of same concept so you can have an idea how to tackle such types of questions.(please refer to the attachment for question)

Answer:

Please refer to the attachment for answers and explanation

Explanation:

Please refer to the attachment for answers and explanation

To determine the resultant internal loadings at the cross sections, we need to consider the external and internal forces. Trigonometric principles can be used to calculate the magnitudes and directions of the loadings. More information about the frame is needed for a precise analysis.

In order to determine the resultant internal loadings acting at the cross sections at points F and G of the frame, we need to consider the external forces applied to the frame, as well as the internal forces generated within the frame due to those external forces. These internal forces include axial forces, shear forces, and bending moments.

Given that θ = 27º and t = 178 lb, we can use trigonometric principles to determine the magnitudes and directions of the internal loadings at points F and G.

For a more specific and accurate analysis, it would be helpful to have more information about the frame, such as its shape, structural elements, and boundary conditions. Without that information, it is not possible to provide a more detailed answer at this time.

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Answer:

0.5A

Explanation:

GIVEN THAT:

V = 3 V

R =6 ohms

V=IR

I =V/R

I = 3/6 =0.5 A

Answer: The person will still have a mass of 90kg on Mars

Explanation: The Truth is, the mass of a body remains constant from place to place. It is the weight which is equal to {mass of body * acceleration due to gravity{g}} that varies from place to place since it is dependent on {g}.

In this case the person will have a Weight of 90*9.8 = 882N on Earth.

{ "g" on Earth is 9.8m/s²}

And a Weight of 90*3.3 = 297N on Mars.

{ From the question "g" on Mars is {9.8m/s²}/3 which is 3.3m/s²}

From this analysis you notice that the WEIGHT of the person Varies but the MASS remained Constant at 90kg.

Answer:

The value of the angle theta = 135degree, which is option c.

Explanation :

These are the options given in the question

a) 45 degrees

b)120 degrees

c)135 degrees

d)150 degrees

e) it is impossible to deliver a negative power.

The concept of work done on an object is applied here.

work = Fd

F = ma

work = mad

Work is a form of energy transferred by an object after the application of a force that act on the object. A step by step explanation is as attached below.

Answer: A. Vb1 = -6m/s , Vb2 = 9m/s.

B. Vb1 = 4.5m/s , Vb2 = 4.5m/s

Explanation: A. In a perfectly elastic collision the objects involved moved with a different velocity after collision. Also kenitic energy is conserved. In other to get the different velocity of ball 1 (Vb1) and ball 2 (Vb2) after collision, we apply the following formula

Vb1 = {{m1 - m2}*V1}/{m1 +m2}

Vb2 = {{2m1}*V1}/{m1 + m2}

Where V1 = velocity of ball 1 before collision=15m/s

m1 = mass of ball 1

m2 = mass of ball 2.

Substituting in the above equation:

Vb1 = {{0.15kg - 0.35kg}*15}/{0.15 + 0.35}

= {{-0.2}*15}/0.5

= -3/0.5

= -6m/s

Also,

Vb2 = {{2*0.15kg}*15m/s}/{0.15kg + 0.35kg}

={0.3kg*15m/s}/0.5kg

=4.5/0.5

=9m/s

B. In a perfectly inelastic collision the object involved move with a common velocity after collision.

We have that ,

m1*V1 + m2*v2 = {m1 + m2} V¹

Where V¹ is the final velocity of both balls after a perfectly inelastic collision.

NOTE: v2 here is 0m/s since ball 2 was at rest before collision.

So we have,

0.15kg*15m/s + 0.35kg*0m/s = {0.15kg + 0.35kg}*V¹

2.25 kgm/s = 0.5kg* V¹

Making V¹ subject of formula we have,

V¹ = 2.25kgm per sec/0.5kg

=4.5m/s. vb1 = Vb2 = V¹

NOTE also that the mass of the balls from the question were given in gram hence we converted to kilogram the standard unit for mass by dividing by 1000.

Answer:

For both ball 1 and ball 2, the change in velocity is less in an inelastic collision.

Explanation:

a short simple answer

Answer:

5.5 N

Explanation:

Weigh of floating ball=5.5 N

Acceleration due to gravity=9.8 [tex]m/s^2[/tex]

We have to find the size of the buoyant force that acts on it.

We know that

Buoyant force is that force which act in upward direction and exert by fluid and opposes the weight of an immersed object.

Therefore,

Buoyant force=Weight of ball

Buoyant force=5.5 N

Hence, the size of buoyant force acts on the ball=5.5 N

Given the ball's weight of 5.5 N, the buoyant force is also 5.5 N.

To determine the buoyant force acting on a floating ball, we can use the principles of buoyancy and the given information about the ball's weight. The ball's weight in air is 5.5 N, and we know the acceleration due to gravity (g) is 9.8 m/s².

For a floating object, the buoyant force (Fb) is equal to the weight of the object when it is floating. Therefore, since the ball is floating, the buoyant force must equal the weight of the ball:

Buoyant force Fb = Weight of the ball

Given that the weight of the ball is 5.5 N, the buoyant force acting on the ball is:

Fb = 5.5 N

This force is what keeps the ball afloat in the fluid.

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Answer:

The work done by the force is 109.5 Joules.

Explanation:

It is given that,

Mass of the object, m = 3 kg                                

Speed of the object, v = 5 m/s

Force applied on the object, F = 12 N

Distance covered by the object, d = 6 m

The work done by this force is given by the sum of kinetic energy and potential energy as per work energy theorem as :

[tex]W=K+P[/tex]

[tex]W= \dfrac{1}{2}mv^2+Fd[/tex]

[tex]W=\dfrac{1}{2}\times 3\times (5)^2+12\times 6[/tex]

W = 109.5 Joules

So, the work done by the force is 109.5 Joules. Hence, this is the required solution.

Answer:

Change, increase in note frequency of the sound that comes as a result of the reduction in the vibrating length (wavelength) when the string movement is slightly restricted at its midpoint

Explanation:

When the midpoint of a vibrating guitar string is lightly touched it reduces the wavelength of the guitar string sound, halving it and such increases the the frequency inversely by a factor of 2

The relationship

f = vw/λ, for sound wave where vw is the speed of sound, frequency, f and λ is the wavelength

Frequency varies inversely with wavelength

An Octave

is the frequency vibration of sound-wave twice that of its lower note

Answer:

i believe it would be classified as A shopping

Answer:

True

Explanation:

It can cause flooding and destruction of habitat because of dammed rivers create large reservoirs upstream which can spill out to the surrounding during heavy rainfall causing flooding and destruction of natural habitat.

Answer:

The height of the water slide is 0.878 m

Explanation:

Given that,

Distance = 2.52 m

Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.

We need to calculate the time

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value in the equation

[tex]1.80=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t^2=\dfrac{1.80\times2}{9.8}[/tex]

[tex]t=\sqrt{\dfrac{1.80\times2}{9.8}}[/tex]

[tex]t=0.606\ sec[/tex]

We need to calculate the velocity

Using formula of velocity

[tex]v = \dfrac{d}{t}[/tex]

Put the value into the formula

[tex]v=\dfrac{2.52}{0.606}[/tex]

[tex]v=4.15\ m/s[/tex]

We need to calculate height

Using conservation of energy

[tex]\dfrac{1}{2}mv^2=mgh[/tex]

[tex]h=\dfrac{v^2}{2g}[/tex]

Put the value into the formula

[tex]h=\dfrac{4.15^2}{2\times9.8}[/tex]

[tex]h=0.878\ m[/tex]

Hence, The height of the water slide is 0.878 m.

Answer:

The Commemorative head of a king (Oba)

Explanation:

The commemorative head of a king is similar to the other features mentioned in the question due to their royal statuses. These features are idolized by the people in their respective societies. The 'Oba' for example is respected by the people of Benin and he makes the rules and regulations for the people. When he dies, his eldest son usually takes his position.

Answer:

The Commemorative head of a king (Oba)

Explanation:

I took the test B )

Answer:

[tex]f=571.67\ Hz[/tex]

Explanation:

Given:

Therefore we have the wavelength of the wave as the distance between the two consecutive maxima:

[tex]\lambda=1.2-0.6[/tex]

[tex]\lambda=0.6\ m[/tex]

We have the speed of sound in the air as:

[tex]v=343\ m.s^{-1}[/tex]

Therefore the frequency of sound:

[tex]f=\frac{v}{\lambda}[/tex]

[tex]f=\frac{343}{0.6}[/tex]

[tex]f=571.67\ Hz[/tex]

The frequency of the sound from the speaker is 571.67 Hz.

Given that the phase constant of speakers is the same, the position of one speaker is at origin, the position of another speaker from the origin is 10 m.

The position of maxima interference is at 0.6 m and 1.2 m. Hence the wavelength of the wave is equivalent to the difference between the two consecutive maxima interference.

[tex]\lambda = 1.2 - 0.6[/tex]

[tex]\lambda = 0.6 \;\rm m[/tex]

We know that the speed v of the sound in the air is 343 m/s. Hence the frequency of the sound is calculated as given below.

[tex]f = \dfrac {v}{\lambda}[/tex]

[tex]f = \dfrac { 343}{0.6}[/tex]

[tex]f = 571.67\;\rm Hz[/tex]

Hence we can conclude that the frequency of the sound from the speaker is 571.67 Hz.

To know more about the frequency, follow the link given below.

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Answer

given,

Electric field,E = 490 N/C

time, t = 54 ns

for electron

Mass of electron me = 9.1 x 10⁻³¹ kg

Charge of electron e = -1.6 x 10⁻¹⁹  C

electrostatic force

F = E q

F = 490 x 1.6 x 10⁻¹⁹

F = 784  x 10⁻¹⁹ N

now, using newton second law

[tex]a = \dfrac{784\times 10^{-19}}{9.1\times 10^{-31}}[/tex]

  a = 8.62 x 10¹² m/s²

using equation of motion

v = u + a t

v = 0 + 8.62 x 10¹² x 54 x 10⁻⁹

v = 4.65 x 10⁵ m/s

velocity of electron is equal to v = 4.65 x 10⁵ m/s

For Proton  

Mass mp = 1.67 x 10⁻²⁷ kg  

Charge p = 1.6 x 10⁻¹⁹ C

Electric field E = 490 V/C

from above solution

F = 784  x 10⁻¹⁹ N

now, acceleration

[tex]a = \dfrac{784\times 10^{-19}}{1.67\times 10^{-27}}[/tex]

  a = 4.69 x 10¹⁰ m/s²

using equation of motion

v = u + a t

v = 0 + 4.69 x 10¹⁰ x 54 x 10⁻⁹

v = 4.65 x 10³ m/s

velocity of electron is equal to v = 4.65 x 10³ m/s

Answer:

Explanation:

Electric field, E = 490 N/C

mass of electron, me = 9.1 x 10^-31 kg

mass of proton, mp = 1.67 x 10^-27 kg

charge of electron or proton = 1.6 x 10^-19 C

time, t = 54 ns = 54 x 10^-9 s

initial velocity, u = 0 m/s

Force on each particle, F = q E = 1.6 x 10^-19 x 490 = 7.84 x 10^-17 N

acceleration of electron = Force / mass of electron

ae = (7.84 x 10^-17) / ( 9.1 x 10^-31) = 8.6 x 10^13 m/s²

Let the velocity of electron is ve.

use first equation of motion

ve = u + ae x t

ve = 0 + 8.6 x 10^13 x 54 x 10^-9

ve = 4.65 x 10^6 m/s

acceleration of proton = Force / mass of proton

ap = (7.84 x 10^-17) / ( 1.67 x 10^-27) = 4.69 x 10^10 m/s²

Let the velocity of electron is vp.

use first equation of motion

vp = u + ap x t

vp = 0 + 4.69 x 10^10 x 54 x 10^-9

ve = 2535.1 m/s

Answer:

d. Critical transportation; situation assessment; and mass care services

Explanation:

The correct answer is option d which is Critical transportation: Situation assessment and mass care services are core capabilities for response.  

As we know that critical transportation are very important factor which control capability for responses. Due to fast transportation a life can be saved, people can be out of danger in the situation of natural calamity.

Answer:

[tex]1.06085\times 10^{-10}\ m[/tex]

Explanation:

h = Planck's constant = [tex]6.626\times 10^{-34}\ m^2kg/s[/tex]

m = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]

k = Coulomb constant = [tex]8.99\times 10^{9}\ Nm^2/C^2[/tex]

e = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]

n = 1 (ground state)

Angular momentum is given by

[tex]L=mvr[/tex]

From Bohr's atomic model we have

[tex]L=\dfrac{nh}{2\pi}[/tex]

[tex]mvr=\dfrac{nh}{2\pi}\\\Rightarrow v=\dfrac{nh}{2\pi mr}[/tex]

The centripetal force will balance the electrostatic force

[tex]\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m[/tex]

The diameter is [tex]2\times 5.30426\times 10^{-11}=1.06085\times 10^{-10}\ m[/tex]

Answer:

The acceleration of the box is 2.

Explanation:

According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.

Net force = Mass × Acceleration

So [tex]Acceleration = \frac{Net force}{Mass}[/tex]

Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.

Net force = 27-17 = 10 N.

Thus, [tex]Acceleration = \frac{10 N}{5 kg}[/tex]

So 2 [tex]m/s^{2}[/tex] is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.

Answer:

b. It deflects the electron to the right.

Explanation:

Since the sphere is positively charged and electron has negative charge, it will be attracted toward the sphere and hence,

The electron is deflected to the right as the positively charged sphere on its right

So, the 2nd option is correct.

Answer:

3.735×10⁻⁶ N

Explanation:

From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

F = (6.67×10⁻¹¹×70×200)/0.5²

F = 93380×10⁻¹¹/0.25

F = 373520×10⁻¹¹

F = 3.735×10⁻⁶ N

Hence the force between the person and the refrigerator =  3.735×10⁻⁶ N

Answer:

1. This is to allow the tube of the tire to position itself properly inside the tire.

2. Inflating,deflating and reinflating aircraft tires help to eliminate all the air between the tube and the inside of the tire.

3. It helps to test the entire tube and tire assembly for any leaks.

Explanation:

Part A. The initial speed of the egg is 17.7 m/s.

Part B. The maximum height of the egg is 15.98 m.

Part C. The magnitude of the velocity at its highest point is 0 m/s.

Part E. The magnitude and direction of the acceleration in the upward direction is 9.8 m/s2.

Given that the distance traveled by the egg is 34 m in time 5 seconds.

The distance at its initial point will be zero.

The initial speed of the egg can be calculated by the position equation of the egg.

[tex]x = x_0 + v_0t + \dfrac {1}{2}at^2[/tex]

Where x is the initial position of the egg that is 0 m, x_0 is the final position that is 34 m in time t = 5 s, v_0 is the initial speed and a is the acceleration. Since the egg is thrown vertically, hence the acceleration of the egg is similar to the gravitational acceleration.

[tex]0 = 34 + v\times 5 + \dfrac {1}{2}\times(- 9.8)\times 5^2[/tex]

[tex]v = \dfrac {122.5 - 34}{5}[/tex]

[tex]v = 17.7 \;\rm m/s[/tex]

The initial speed of the egg is 17.7 m/s.

The maximum height for the egg can be calculated by the equation given below.

[tex]v^2 = v_0^2 + 2gh[/tex]

For the highest point, the final speed v will be zero and the initial speed v_0 is 17.7 m/s. Hence,

[tex]0 = (17.7)^2 + 2\times (-9.8)\times h[/tex]

[tex]19.6 h = 313.29[/tex]

[tex]h = 15.98 \;\rm m[/tex]

The maximum height of the egg will be 15.98 m.

The velocity of the object thrown at a height will be zero at its highest point. Hence the velocity of the egg will be zero at its highest point.

Velocity [tex]v_h[/tex] = 0 m/s

The egg is thrown vertically upward, hence its acceleration is similar to the gravitational acceleration.

Acceleration a = 9.8 m/s2

To know more about the velocity and acceleration, follow the link given below.

https://brainly.com/question/2239252.