A basketball is thrown up into the air. It is released with an initial velocity of 8.5 m/s. How long does it take to get to the top of its motion?

Answers

Answer 1
It takes 0.867 seconds to get to the top of its motion

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 8.5 m/s

     Final velocity, v = 0 m/s    - At maximum height

     Time, t = ?

     Acceleration , a = -9.81 m/s²

     Substituting

                      v = u + at  

                      0 = 8.5 + -9.81 x t

                      t = 0.867 s

  It takes 0.867 seconds to get to the top of its motion

Answer 2

Answer:

0.87 s

Explanation:

initial velocity, u = 8.5 m/s

Let it takes time t to reach to maximum height. At maximum height the velocity is zero, so, v = 0

Use first equation of motion

v = u - gt

where, g be the acceleration due to gravity

0 = 8.5 - 9.8 t

t = 0.87 s

Thus, the time taken to reach at top is 0.87 s.


Related Questions

1.Are BEVs or hydrogen fuel cell vehicles a more promising transportation technology for the future?

2.Should car companies be required to produce electric cars?

Answers

Answer:

1. Yes, BEVs or hydrogen fuel cell vehicles are a more promising transportation technology for the future.

2. Yes, car companies should be require to produce electric cars.

Explanation:

BEV stands for battery electric vehicle which is a type of electric vehicle. These vehicle and hydrogen fuel vehicles are a promising transportation technology for future as traditional vehicles along with other factors have polluted the earth so much that now we have to minimize the carbon footprint. The natural resources of fuel are also getting scare. So, these batteries assisted and eco-friendly are the need of the present and are vital in playing a important role in transportation in future.Car companies should be require to produce electric cars as some companies like Tesla has already their electric car in the market lately. The countries in the scandinavian region have adopted the policy to promote and use this vehicles so company come forward to provide eco-friendly and price competitive vehicles so everyone can take the advantage.

Both BEVs and FCEVs have their roles in the future of transportation, with BEVs currently leading in light-duty vehicles and FCEVs being more suitable for heavier-duty applications. Mandating the production of electric vehicles involves several considerations, including environmental benefits, technological adoption, and infrastructure readiness.

Comparing Battery Electric Vehicles (BEVs) and Hydrogen Fuel Cell Vehicles (FCEVs)

When looking at the future of transportation technology, both Battery Electric Vehicles (BEVs) and Hydrogen Fuel Cell Vehicles (FCEVs) have their respective advantages and roles to play. BEVs are currently more prevalent and benefit from ongoing advances in battery technology that aim to increase energy density, decrease charging time, and reduce weight, securing their place in the market, especially for short to medium-range transportation. Meanwhile, FCEVs offer promise for applications where the quick refueling and longer range of conventional vehicles are required, making them particularly suitable for medium-duty and heavy-duty vehicles, such as delivery trucks and buses. The choice between the two technologies might depend on the specific needs of the transportation sector, whether it's for personal vehicles, long-distance road transport, or heavy-duty applications.

Should Car Companies Be Required to Produce Electric Cars?

The requirement for car companies to produce electric cars stems from global environmental pressures such as climate change and air quality concerns. Governments might consider mandates for electric vehicles production to reduce greenhouse gas emissions and promote fuel independence. However, the question involves not only environmental and political considerations but also practical aspects of technology adoption, economics, and consumer preferences. The impact on residential areas in terms of increased electrical demand, potential reliance on nighttime charging to utilize solar input, and consumer willingness to adopt new technologies while considering the costs of battery decline and replacement are all factors that would need to be addressed in such a transition.

A piston/cylinder contains 2 kg of water at 20◦C with a volume of 0.1 m3. By mistake someone locks the piston, preventing it from moving while we heat the water to saturated vapor. Find the final temperature and volume and the process work?

Answers

Answer:

Hi

Final temperature = 250.11 °C

Final volume = 0,1 m3.

Process work = 0

Explanation:

The specific volume in the initial state is: v = 0.1m3/2 kg = 0.05 m3/kg.

This volume is located between the volumes as saturated liquid and saturated steam at 20 °C. For this reason the water is initially in a liquid vapor mixture. As the piston was blocked the volume remains constant and the process is isometric, also known as isocoric process, so the final temperature will be the water temperature at a saturated steam of v=0.05m3/kg, which is obtained by using steam tables for water, by linear interpolation. As follows, using table A-4 of the Cengel book 7th Edition:

v=0.05 m3/kg

v1=0.057061 m3/kg

T1=242.56°C

v2=0.049779 m3/kg

T2=250.35°C

T=[tex]\frac{T2-T1}{v2-v1} x(v-v1)+T1=\frac{250.35°C-242.56°C}{0.049779m3/kg-0.057061m3/kg}x(0.05m3/kg-0.057061m3/kg)+242.56°C=250.11°C[/tex]

The process work is zero because there is no change in volume during heating:

W=PxΔv=Px0=0

where

W=process work

P=pressure

Δv=change of volume, is zero because the piston was blocked so the volume remains constant.

Final answer:

Using Charles's Law and considering the properties of water, in a locked piston, the volume remains constant as water vaporizes, despite temperature changes. The temperature is affected by specific heat and latent heat of vaporization. No work is done as the locked piston prevents expansion.

Explanation:

In this scenario, we would need to use principles from physics to solve this problem, particularly the laws of thermodynamics and the properties of gases and liquids, specifically water. Despite the piston being locked, as the water heats up and turns into vapor, the volume would increase according to Charles's Law. However, since our piston is locked and cannot move, in this case, the volume does not change and stays constant at 0.1 m³.

Next, the temperature change can be calculated from the specific heat of water and the given mass of water. However, as the water turns into vapor, we also have to account for the latent heat of vaporisation which is energy needed to change the water to vapor without changing its temperature.

As for the process work, it is zero in this case because our system is not doing work on the surroundings because the piston is locked and no expansion occurred which normally forms the basis of work done.

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If a photon has frequency = 2.00 x 1014s-1 and the speed of light = 3.00 x 108ms-1, then what is its wavelength?

Answers

Answer:

The photon has a wavelength of [tex]1.5x10^{-6}m[/tex]

Explanation:

The speed of a wave can be defined as:

[tex]v = \nu \cdot \lambda[/tex] (1)

Where v is the speed, [tex]\nu[/tex] is the frequency and [tex]\lambda[/tex] is the wavelength.

Equation 1 can be expressed in the following way for the case of an electromagnetic wave:

[tex]c = \nu \cdot \lambda[/tex] (2)              

 

Where c is the speed of light.    

Therefore, [tex]\lamba[/tex][tex]\lambda[/tex] can be isolated from equation 2 to get the wavelength of the photon.

[tex]\lambda = \frac{c}{\nu}[/tex] (3)

[tex]\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}[/tex]

[tex]\lambda = 1.5x10^{-6}m[/tex]

Hence, the photon has a wavelength of [tex]1.5x10^{-6}m[/tex]        

Summary:  

Photons are the particles that constitutes light.


A 0.50 kg croquet ball is initially at rest on the grass. When theball is struck by a mallet, the average force exerted on it is240 N. If the ball's speed after beingstruck is 3.0 m/s, how long was the malletin contact with the ball?

Answers

Answer:

time=6.25×10⁻³ seconds

or

time=6.25 Milliseconds

Explanation:

Given Data

Ball mass= 0.50 kg

Force = 240 N

Speed =3.0 m/s

To find

Time

Solution

From Newtons second Law of motion

Force=mass×acceleration

As mass and Force is given we need to Find acceleration

So

Acceleration=Force/mass

Acceleration=240/0.50

Acceleration=480 m/s²

When ball was at rest its velocity at that time was 0.Now the final velocity is given as:

Velocity=acceleration×time

As we have find the acceleration and velocity is given so we can find time easily

So

time=velocity/acceleration

time=(3.0m/s)/480 N

time=6.25×10⁻³ seconds

or

time=6.25 Milliseconds

Final answer:

Using the impulse-momentum theorem, the time the mallet was in contact with the ball can be found to be 0.00625 seconds.

Explanation:

This problem can be solved using the imulse-momentum theorem, which states that the impulse on an object is equal to the change in its momentum. Momentum is calculated as mass times velocity, and impulse is calculated as force times time. In this particular case, we can set the final momentum of the croquet ball, 0.50 kg * 3.0 m/s, equal to the impulse, 240 N * t, the duration of time the mallet was in contact with the ball.

Setting these equal to each other, we get:
240 N * t = 0.50 kg * 3.0 m/s
Solving for t, we get:
t = (0.50 kg * 3.0 m/s) / 240 N
After doing the calculations, we find the duration t to be 0.00625 seconds.

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A rock is thrown off of a 100 foot cliff with an upward velocity of 45 m/s. As a result its height after t seconds is given by the formula?

Answers

Q: A rock is thrown off of a 100 foot cliff with an upward velocity of 45 m/s. As a result its height after t seconds is given by the formula:

h(t)=100+45t−4.9t2

(a) What is its height after 3 seconds?

(b)What is its velocity after 3 seconds?

Answer:

(a) 190.9 m.

(b) 15.6 m/s upward

Explanation:

Given:

h(t) = 100 + 45t - 4.9t²

The height after 3 seconds,

t = 3 s

Substitute the value of t in to the equation above.

h(3) = 100+45(3)-4.9(3)²

h(3) = 100+135-44.1

h(3) = 190.9 m

Therefore the height after 3 seconds = 190.9 m.

(b) Velocity after 3 seconds

The velocity is obtained by differentiating h(t) with respect to time

v = dh(t)/dt

dh(t)/dt = 45-9.8t

v = 45 - 9.8t ......................................... Equation 1

t = 3 s.

Substitute the value of t into the equation above,

v = 45 - 9.8(3)

v = 45- 29.4

v = 15.6 m/s

Thus the velocity after 3 seconds = 15.6 m/s upward

Final answer:

After 3 seconds, the rock is 190.9 meters high and moving upwards with a velocity of 15.6 m/s. The computations are based on the given formula for height over time.

Explanation:

The question involves determining the height and velocity of a rock thrown off a 100-foot cliff with an upward velocity of 45 m/s after a certain time interval. Given the formula h(t) = 100 + 45t - 4.9t2, where h represents the height in meters and t represents the time in seconds, we can calculate the specific outcomes for the rock at different points in time.

(a) Height after 3 seconds

To find the height after 3 seconds, we substitute t = 3 into the equation: h(3) = 100 + 45(3) - 4.9(3)2 = 100 + 135 - 44.1 = 190.9 meters above the ground.

(b) Velocity after 3 seconds

The velocity of the rock can be found by taking the derivative of the height function, which gives v(t) = 45 - 9.8t. Substituting t = 3: v(3) = 45 - 9.8(3) = 45 - 29.4 = 15.6 m/s, directed upwards.

Automotive applications such as electronic control units mostly use semiconductors such as diodes, transistors, and power transistors. True or false?

Answers

Answer: the answer is true

Explanation:

electronic control units use semiconductors and also they widely use MOSFETS which are transistors as well.

It is true that automotive applications use semiconductors such as diodes, transistors, and power transistors. Semiconductors are the foundation of modern electronic devices and systems, including those in the automotive industry.

The statement is true. Automotive applications such as electronic control units indeed utilize semiconductors like diodes, transistors, and power transistors. Semiconductors are essential for modern electronics, as they can be combined into integrated circuits (ICs) on a single silicon chip, connecting millions of devices with conducting paths. Diodes, for example, only allow current to flow in one direction and are crafted from a p-n junction between a p-type and an n-type semiconductor.

Transistors are also semiconductor devices that have revolutionized modern technology, allowing for the miniaturization of electronic devices. They consist of three layers — the collector, base, and emitter — and can control large currents with small input signals. These components are integral to various electronic systems within vehicles for controlling functions and processing signals.

A force of 40 Newtons is applied to a mass resulting in an acceleration of 8 m/s2What force would need to be applied to this mass to cause an acceleration of 25 m/s2?

Answers

Answer:

125 N

Explanation:

Force: This can be defined as the product of the mass of a body and its acceleration. S.I unit of force is Newton (N).

Mathematically, Force can be expressed as,

F = ma................... Equation 1

Where F = force, m = mass, a = acceleration of the body.

Making m the subject of the equation,

m = F/a ............... Equation 2.

Given: F = 40 Newtons, 8 m/s²,

Substituting into equation 2

m = 40/8

m = 5 kg,

When the acceleration a = 25 m/s²

Substitute into equation 1

F = 25×5

F = 125 N.

Hence the needed = 125 N.

To cause an acceleration of 25 m/s2 on the given mass, a force of 125 Newtons would be needed.

To find the force needed to cause an acceleration of 25 m/s2 on the same mass, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. First, we can calculate the mass by dividing the force of 40 Newtons by the acceleration of 8 m/s2: 40 N = mass x 8 m/s2.

Therefore, the mass is 5 kg. Next, we can use the calculated mass and the desired acceleration of 25 m/s2 to find the force: force = mass x acceleration. Substituting the values, we have force = 5 kg x 25 m/s2 = 125 Newtons.

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In boxing, the use of 16-ounce gloves rather than 12-ounce gloves reduces the chance of injury because the force is distributed over a greater area.A. TrueB. False

Answers

Answer:

true

Explanation:

Here we have assumed that increasing the mass of a glove will increase the surface area.

Injury is caused by the application of pressure at a point on the body. The application of pressure takes place via the area of the gloves. Pressure is given by

[tex]P=\dfrac{F}{A}[/tex]

where

F = Force

A = Area to which the force is applied

So, a bigger glove will increase the surface area and reduce the pressure resulting in a lower chance of injury.

Hence, the statement is true.

You're explaining to your client that using electronic documents and signatures simplifies the home buying process. Your client is skeptical about these signatures. You describe the Uniform Electronic Transactions ACT (UETA) and tell your client?

Answers

Answer: State laws take precedence over UETA

Explanation: The UETA is an attempt to standardize acceptance of electronic documents and signatures, but state laws govern the use of these electronic items.

UETA is a legislative act that, in terms of the statute of laws, accords electronic signatures the same legal standing as handwritten ones as released by the Uniform Law Commission in 1999.

What is UETA?

Only specified types of electronic  transactions and those where the parties have consented to conduct the transaction electronically are covered by the UETA.

Any electronic sound, symbol, or procedure that is both attached to or linked with a document or contract qualifies as an electronic signature executed with the goal of signing the document.

Any electronic sound, symbol, or procedure connected to a contract with the intent to sign is considered an electronic signature. Even if an electronic signature is valid, a judge may rule that it cannot be used because the amount of assurance it provided was insufficient.

Every state  the district of Columbia, Puerto Rico, and the  Islands have accepted the UETA. Despite not having the UETA, New York has similar legislation that make electronic signatures enacted.

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A total of 27.10 KJ of heat is added to a 5.30-L sample of helium at 0.981 atm. The gas is allowed to expand against a fixed external pressure to a volume of 23.70 L.
A) calculate the work done on or by the helium gas units of joules, J.
B) what is the change in the helium a internal energy in units kilojoules, KJ?

Answers

Final answer:

The work done by a gas when it expands against a constant external pressure can be calculated using the formula W = -P∆V. For a helium gas expanding from 5.30 L to 23.70 L against an external pressure of 0.981 atm, the work done is -1.8299164 kJ. The change in internal energy is the heat added plus the work done on the system, resulting in a change of 28.93 kJ.

Explanation:

To calculate the work done by the helium gas during its expansion against a fixed external pressure, we can use the formula for work, which is:

W = -P∆V

where:

- W is the work done on or by the gas (in joules, J)

- P is the external pressure (in pascals, Pa)

- ∆V is the change in volume (in cubic meters, m3)

Firstly, we need to convert the pressure from atm to Pa and volume from L to m3:

1 atm = 101325 Pa
1 L = 0.001 m3

Thus:

P = 0.981 atm × 101325 Pa/atm = 99456.325 Pa
∆V = (23.70 L - 5.30 L) × 0.001 m3/L = 0.0184 m3

Work done, W = -P∆V = -99456.325 Pa × 0.0184 m3 = -1829.9164 J

The work done by the gas is negative, indicating that it was done on the surroundings. Converting Joules to kilojoules (1 J = 0.001 kJ), we have:

W = -1.8299164 kJ

To determine the change in internal energy, we use the first law of thermodynamics, which states:

∆U = Q - W

where:

- ∆U is the change in internal energy
- Q is the heat added to the system

Since we added 27.10 kJ of heat (Q), and work done (W) on the surroundings is -1.8299164 kJ, we can calculate the change in internal energy (∆U) as:

∆U = 27.10 kJ - (-1.8299164 kJ) = 28.9299164 kJ

The change in the helium's internal energy is 28.93 kJ.

Ocean tides are waves that have a period of 12 hours, an amplitude (in some places) of 1.50 m, and a speed of 750 km/hr. What is the distance between adjacent crests of these waves?

Answers

Answer:

distance between adjacent crests = 9000 km

Explanation:

given data

time period = 12 hours

amplitude = 1.50 m

speed = 750 km/hr

solution

we get here distance between adjacent crests that is express as

distance between adjacent crests = speed × time ..............1

put here value and we get

distance between adjacent crests = 750 × 12

distance between adjacent crests = 9000 km

Final answer:

The distance between adjacent crests of an ocean tide's waves, also known as the wavelength, can be calculated using the formula for wave speed and the given values. The frequency of the tide is 0.083 cycles per hour, and by substituting the values into the formula, we obtain a wavelength of approximately 9045 kilometers.

Explanation:

The distance between adjacent crests of waves, also known as the wavelength, can be calculated using the formula for wave speed: speed = frequency x wavelength. Since the tide has a period (time for one complete cycle) of 12 hours, this means its frequency is 1 cycle/12 hours. However, since the speed is in km/hr, we need to convert the frequency to cycles per hour. This gives us a frequency of 2 cycles/24 hours = 0.083 cycles per hour.

Now we can substitute the values into the formula: 750 km/hr = 0.083 cycles/hr x wavelength. Solving for wavelength, we get a wavelength of about 9045 kilometers.

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The traffic on the freeway is moving at a constant speed of 24 m/sm/s. What distance does the traffic travel while the car is moving the length of the ramp?

Answers

Incomplete question as there is so much information is missing.The complete question is here

A car sits on an entrance ramp to a freeway, waiting for a break in the traffic. Then the driver accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 24 m/s (54 mi/h) when it reaches the end of the 120-m-long ramp. The traffic on the freeway is moving at a constant speed of 24 m/s. What distance does the traffic travel while the car is moving the length of the ramp?

Answer:

Distance traveled=240 m

Explanation:

Given data

Initial velocity of car v₀=0 m/s

Final velocity of car vf=24 m/s

Distance traveled by car S=120 m

To find

Distance does the traffic travel

Solution

To find the distance first we need to find time, for time first we need acceleration

So

[tex](V_{f})^{2}=(V_{o})^{2}+2aS\\ So\\a=\frac{(V_{f})^{2}-(V_{o})^{2} }{2S}\\ a=\frac{(24m/s)^{2}-(0m/s)^{2} }{2(120)}\\a=2.4 m/s^{2}[/tex]

As we find acceleration.Now we need to find time

So

[tex]V_{f}=V_{i}+at\\t=\frac{V_{f}-V_{i}}{a}\\t=\frac{(24m/s)-(0m/s)}{(2.4m/s^{2} )}\\t=10s[/tex]

Now for distance

So

[tex]Distance=velocity*time\\Distance=(24m/s)*(10s)\\Distance=240m[/tex]

According to Lewin's Change Model, an organization must deliberately change old habits, learn new work methods, and accept the new work methods as parts of the job.

Answers

Answer:

True

Explanation:

The Kurt Lewin Model: Defines change as a modification of the forces that maintain the behavior of a stable system.

    Which is the product of two types of forces that help to make the change (F. Drivers) and those that prevent change from occurring (F restrictive) that want to maintain the same state of the organization.

    When both forces are balanced, the levels of behavior are maintained and a quasi-stationary equilibrium is achieved according to Lewin. To modify it you can increase the forces that cause the change or decrease the forces that prevent it or change both tactics. Lewin proposes a three-phase plan to carry out the planned change

Defrosting: involves reducing the forces that keep the organization at its current level of behavior.

Change or movement: It consists of moving towards a new state or new level within the organization with respect to behavior patterns and habits, behaviors and attitudes.

Recongelación: The organization is stabilized in a new state of equilibrium where culture, norms, policies and organizational structure are used.

According to Lewin's Change Model, organizations must deliberately change old habits, learn new work methods, and accept them as part of the job. Hence the statement is True.

True. According to Lewin's Change Model, organizations must deliberately change old habits, learn new work methods, and accept them as part of the job. This process involves transitioning through phases of change to achieve successful organizational transformation.

Polychlorinated biphenyls (PCBs) have been banned because they are an environmental hazard. Which of the following was NOT a reason for banning them?

Answers

Answer:

PCBs have high electrical resistance and are excellent insulating materials.

Explanation:

Polychlorinated biphenyls [PCBs] are industrial chemical compounds made by man, which contains carbon, hydrogen and chlorine atoms. They can be used in the production of paints and dyes, heat transfer, etc.

There has been the ban on the use of these compounds because they are said to be very stable, and yield slowly to degradation by nature. They have low and not high electrical resistance.  

A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. What is the magnitude of the impulse delivered to your roof? b. If the raindrop comes to rest in 0.37 ms, what is the magnitude of the force of the impact?

Answers

Final answer:

The magnitude of the impulse delivered to the roof is -0.01134 kg·m/s, and the magnitude of the force of the impact is -30.70 N.

Explanation:

The magnitude of impulse delivered to your roof can be calculated using the equation impulse = mass x change in velocity. In this case, the mass of the raindrop is given as 0.0014 g, which is equivalent to 0.0014 kg. The change in velocity is the final velocity (0 m/s) minus the initial velocity (8.1 m/s). Therefore, the magnitude of the impulse is 0.0014 kg x (-8.1 m/s) = -0.01134 kg·m/s.

To calculate the magnitude of the force of the impact, we can use the equation force = impulse/time. In this case, the impulse is the magnitude of the impulse calculated previously (-0.01134 kg·m/s) and the time is given as 0.37 ms, which is equivalent to 0.00037 s. Therefore, the magnitude of the force of the impact is -0.01134 kg·m/s / 0.00037 s = -30.70 N.

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In this physics problem, we calculate both the magnitude of the impulse delivered and the force of impact of a raindrop hitting a roof.

The magnitude of the impulse delivered to the roof can be calculated by multiplying the mass of the raindrop by its velocity.

The magnitude of the force of the impact can be determined using the formula for impulse, considering the time it takes for the raindrop to come to rest.

An electric power plant uses energy from burning coal to generate steam at 450∘C. The plant is cooled by 20∘C water from a nearby river. If burning coal provides 100 MJ of heat, what is the theoretical minimum amount of heat that must be transferred to the river during the conversion of heat to electric energy? A. 100 MJ. B. 90 MJ. C. 60 MJ. D. 40 MJ.

Answers

Answer:

40 MJ (D)

Explanation:

Quantity of heat (Qh) = 100 MJ

temperature of steam (Th) = 450°c = 450 + 273 = 723 K

emperature of water (TI) = 20 °c = 20 + 273 = 293 k

efficiency = (Qh-Qi)/Qh = (Th-Ti)/Th

 [tex]\frac{100x10x^{6}-Qi }{100x10^{6}} = \frac{723-293}{723}[/tex]

[tex]100x10^{6}[/tex] - Qi= 0.5947 x [tex]100 x 10 ^{6}[/tex]

[tex]100x10^{6}[/tex] - (0.5947 x [tex]100x10^{6}[/tex]) = Qi

Qi = 40.5 MJ equivalent to 40 MJ (D)

Final answer:

The theoretical minimum amount of heat that must be transferred to the river during the conversion of heat to electric energy is 0.0836 MJ, which is closest to option D: 40 MJ.

Explanation:

The theoretical minimum amount of heat that must be transferred to the river during the conversion of heat to electric energy can be calculated using the formula:

Q = m * c * ΔT

Where Q is the heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

In this case, we know the change in temperature (ΔT) is 20∘C and we need to find the heat transferred (Q). For simplicity, we will use a mass of 1 kg. The specific heat capacity of water is approximately 4.18 J/g°C.

Using the formula, we can calculate:

Q = 1 kg * 4.18 J/g∘C * 20∘C

We need to convert grams to kilograms:

Q = 1 kg * 4.18 J/g∘C * 20∘C * (1 g / 1000 kg)

Q = 0.0836 MJ

This means the theoretical minimum amount of heat that must be transferred to the river during the conversion of heat to electric energy is 0.0836 MJ, which is closest to option D: 40 MJ.

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An uncharged pith ball is suspended by a nylon fiber. When a negatively charged rubber rod is brought nearby, without touching it, the pith ballA. Becomes charged by induction.
B. Becomes polarized.
C. Is repelled by the rod.
D. Is unaffected.
E. None of the above choices are correct.

Answers

Answer:

B

Explanation:

An uncharged pith ball is suspended by a nylon fiber. When a negatively charged rubber rod is brought nearby, without touching it, the pith ball A.

Becomes polarized.

We claim the allegation has been divided inside the can. Polarization implies, in general terms, separating between opposites.  Polarization is the method of splitting contrary charges inside an object, in the case of electricity. The positive charge is distinguished from the negative charge.

The correct answer is: A. Becomes charged by induction.

When a negatively charged rubber rod is brought near an uncharged pith ball suspended by a nylon fiber, the pith ball becomes charged by induction. The rod induces a dipole moment in the pith ball, causing it to be attracted in the inhomogeneous field surrounding the rod. This procedure illustrates one of the basic ideas of electrostatics: the existence of a charged object can affect the way charges are distributed in a nearby neutral object, causing the object to acquire a charge by induction.

A race car completes a lap on a 1600 m long track with an average speed of 250 km/h. If the car's average speed on the first half of the track was 215 km/h, what was its average speed (in km/h) on the second half?

Answers

Its average speed (in km/h) on the second half is 298.76 km/hr

Explanation:

Length of track = 1600 m

Average speed = 250 km/h = 69.44 m/s

We have

      Distance = Speed x Time

      1600 = 69.44 x time

      Time = 23.04 seconds

Total time = 23.04 seconds

Half of the track = 0.5 x 1600 = 800 m

Speed on first half = 215 km/hr = 59.72 m/s

We have

      Distance = Speed x Time

      800 = 59.72 x time

      Time = 13.40 seconds

Time taken to complete remaining half = 23.04 - 13.40 = 9.64 seconds

Distance = 800 m

We have

      Distance = Speed x Time

      800 = Speed x 9.64

      Speed = 82.99 m/s = 298.76 km/hr

Its average speed (in km/h) on the second half is 298.76 km/hr

A truck with 28-in.-diameter wheels is traveling at 50 mi/h. Find the angular speed of the wheels in rad/min, *hint convert miles to inches & hours to minutes: rad/min How many revolutions per minute do the wheels make? rpm

Answers

Answer:

Angular speed ω=3771.4 rad/min

Revolution=5921 rpm

Explanation:

Given data

[tex]d=28in\\r=d/2=28/2=14in\\v=50mi/hr[/tex]

To find

Angular speed ω

Revolution per minute N

Solution

First we need to convert the speed of truck to inches per mile

as

1 mile=63360 inches

1 hour=60 minutes

so

[tex]v=(50*\frac{63360}{60} )\\v=52800in/min[/tex]

Now to solve for angular speed ω by substituting the speed v and radius r in below equation

[tex]w=\frac{v}{r}\\ w=\frac{52800in/min}{14in}\\ w=3771.4rad/min[/tex]

To solve for N(revolutions per minute) by substituting the angular speed ω in the following equation

[tex]N=\frac{w}{2\pi }\\ N=\frac{3771.4rad/min}{2\pi }\\ N=5921RPM[/tex]  

Final answer:

To find the angular speed of the wheels, convert the speed from miles per hour to inches per minute, and calculate using the formula Angular Speed = Linear Speed / Radius. The wheels make Revolutions per Minute which can be found by dividing the angular speed in radians per minute by 2π.

Explanation:

To find the angular speed of the wheels in rad/min, we need to use the formula:
Angular Speed = Linear Speed / Radius

First, let's convert the speed from miles per hour to inches per minute. There are 5,280 feet in a mile and 12 inches in a foot. So, 50 miles/hour is equal to:
(50 miles/hour) x (5,280 feet/mile) x (12 inches/foot) x (1 hour/60 minutes)

Next, we need to convert the diameter of the wheel to the radius. Since the diameter is given in inches, the radius is half the diameter:
Radius = 28 in./2 = 14 in.

Using these values, we can calculate the angular speed:

Angular Speed = (Linear Speed / Radius)

To find the number of revolutions per minute (rpm) the wheels make, we need to divide the angular speed in radians per minute by 2π (the number of radians in a full revolution):
Revolutions per Minute = Angular Speed (in rad/min) / 2π

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A golfer, driving a golf ball off the tee, gives the ball a velocity of 38 m/sec. The mass of the ball is 0.045 kg, and the duration of the impact with the golf club is 0.003 sec. What is the change in momentum of the ball?

Answers

Answer:

Explanation:

momentum (p) = mass × velocity.

Change in momentum (∆p) = final momentum - initial momentum.

∆p = 0.045×38 - 0.045×0

∆p = 1.7 kg m/s.

Momentum (p) = mass × velocity. Change in momentum (∆p) = final momentum - initial momentum.

What is Change in momentum?

The word "momentum" is frequently used in sports. A squad that is moving forward and has momentum will be difficult to stop.

A team that is genuinely moving forward and gaining momentum will be challenging to stop. A physics phrase, momentum describes the amount of motion that an item has. The momentum belongs to a sports team that is actively playing.

The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion.  ∆p = 0.045×38 - 0.045×0, ∆p = 1.7 kg m/s.

Therefore, Momentum (p) = mass × velocity. Change in momentum (∆p) = final momentum - initial momentum.

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An automobile having a mass of 2000 kg deflects its suspension springs 0.02 m under static conditions. Determine the nafural frequency of the automobile in the vertical direction by assuming damping to be negligible.

Answers

Answer:Frequency = 3.525 Hertz

Explanation:In static equilibrium, kd =mg

Where k= effective spring constant of the spring.

mg= The weight of the car.

d= static deflection.

Therefore, w =SQRTg/d

w = SQRT 9.81/0.02

w= 22.15 rad/sec

Converting to Hertz unit for frequency

1 rad/s = 0.1591

22.15rad/s=?

22.15 × 0.1591= 3.525 hertz

The natural frequency of the automobile in the vertical direction is 3.52 Hertz

Static equilibrium

Static equilibrium refers to the physical state in which the components of a system are at rest and the net force acting through the system is equal to zero.

In static equilibrium:

kd = mg

where;

k = effective spring constant of the spring.

mg = the weight of the car

d = static deflection.

also K = mω²

where ω is angular velocity

m is mass

Thus, mω²d = mg

ω²d = g

ω = √g/d

ω = g/d

ω  = √9.8/0.02

ω = 22.15 rad/sec

Converting to Hertz unit for frequency

1 rad/s = 0.1591 Hertz

22.14 rad/s = 22.14 * 0.1591

22.14 rad/s = 3.525 hertz

Therefore, the natural frequency of the automobile in the vertical direction is 3.52 Hertz

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A child is sliding on a sled at 1.3 m/s to the right. You stop the sled by pushing on it for 0.80 s in a direction opposite to its motion. Part A If the mass of the child and sled is 34 kg , what is the magnitude of the average force you need to apply to stop the sled?

Answers

Answer:

find acceleration first

a = vf - vi / t

a = 0  - 1.5 / 0.5s   (vf is zero)

a = -3 (negative sign indicates that acceleration is decreasing)

so F=ma

    F = 35 x -3

   F = -105 N (here negative sign indicates that u have to apply a force opposite to the boy's direction i.e from the left or towards the right)

Explanation:

At 25 °C, a bottle contains 2.00 L of water in its liquid state. What is the volume of the water after it freezes (at 0 °C)? The densities of liquid water and ice are 0.997 g/mL and 0.917 g/mL, respectively.

Answers

Answer:

2.175 L

Explanation:

temperature (T) = 25 degrees

volume of water (v) = 2 L = 2000 mL

density of water = 0.997 g/mL

density of ice = 0.917 g/mL

we can get the mass of the water and the use it to get the volume when it freezes to ice, this is because the mass remains the same irrespective of the change of state.

mass of water = volume x density  = 2000 x 0.997 = 1994 gvolume of ice = mass/density = 1994 / 0.917 = 2174.5 mL = 2.175 L

The different molecules that make up the air in a room have, on average the same kinetic energy. How does the speed of the different molecules that make up the air depend on their masses?

Answers

Answer:

speed of molecule ∝  1/mass of molecule.

Explanation:

The velocities of the molecules depend on their masses. That's because if the molecules are large in size, their velocity is slower. Therefore their velocity is quicker when their size is small, since the molecules can move faster.

Therefore , it can be written as

speed of molecule ∝  1/mass of molecule.

A 880 N crate rests on the floor. (a) How much work is required to move it at constant speed 4.8 m along the floor against a friction force of 180 N?

Answers

Answer:

We have to do 864 J for moving the crate

Explanation:

We have given a 880 N crate is at rest on the floor

Frictional force f = 180 N

We have to move the crate by 4.8 m

For moving the crate we have to overcome the frictional force acting the crate

We know that work done is given by [tex]Work\ done=force\times distance[/tex]

Here force will be equal to frictional force and distance is 4.8 m

So work done [tex]W=180\times 4.8=864J[/tex]

So we have to do 864 J for moving the crate

After a 0.260-kg rubber ball is dropped from a height of 19.5 m, it bounces off a concrete floor and rebounds to a height of 15.5 m. (a) Determine the magnitude and direction of the impulse delivered to the ball by the floor.

Answers

Answer:

a)impulse = 10.7296 kg-m/s (upward)

b) F = 268.24 N (upward)

Explanation:

(a)

velocity of ball before it strikes the floor:

initial gravitational potential energy = final kinetic energy

mgh = (1/2)mv²

v = sqrt(2gh)

v = sqrt[2(9.81 m/s²)(19.5 m)]

v = 19.5599 m/s

velocity of ball after striking the floor:

initial kinetic energy = final gravitational potential energy

(1/2)mv² = mgh

v = sqrt(2gh)

v = sqrt[2(9.81 m/s²)(15.5m)]

v = 17.4387 m/s

impulse = change in momentum

impulse = (0.290 kg)(17.4387 m/s - (-19.5599 m/s))

impulse = 10.7296 kg-m/s (upward)

(b)

impulse = (force exerted)(time)

10.7296 kg-m/s = F(0.04 s)

F = 268.24 N (upward)

An object with a charge of -3.2 uC and a mass of 1.0×10^(-2) kg experiences an upward electric force, due to a uniform electric field, equal in magnitude to its weight.

If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.

upward
downward
to the left
to the right

Answers

Answer:

The magnitude of the acceleration is equal to 19.6m/s² and the acceleration is directed upwards though the magnitude of the charge has doubled. This is because the electric force is directed upwards and from newton's second law of motion the charge will have acceleration in the same direction as the electric force on the charge.

Explanation:

The detailed solution can be found in the attachment below.

Thank you for reading and I hope this is helpful to you.

Final answer:

The acceleration direction and magnitude will remain the same when the charge on the object is doubled while its mass remains the same.

Explanation:

When the charge on the object is doubled while its mass remains the same, the acceleration direction and magnitude will remain the same. It will still experience an upward acceleration.

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a block of mass m is pushed up against a spring with spring constant k until the spring has been compressed a distance x from equilibrium. what is the work done on the block by the spring.

A. W=kx^2
B.W=-kx^2
C.W=0
D. None of these

Answers

Answer:d

Explanation:

Spring is compressed to a distance of x from its equilibrium position

Work done by block on the spring is equal to change in elastic potential energy

i.e. Work done by block [tex]W=\frac{1}{2}kx^2[/tex]

therefore spring will also done an equal opposite amount of work on the block in the absence of external force

Thus work done by spring on the block [tex]W=-\frac{1}{2}kx^2[/tex]

Thus option d is correct

Final answer:

The work done on a block by a spring it compresses is given by the formula for elastic potential energy, ½ kx^2, with a negative sign because the work is done against the movement of the block. Therefore, the correct answer is B.W=-kx^2.

Explanation:

In this case, the work done on the block by the spring is given by the formula for elastic potential energy, which is ½ kx2. However, this work is done on the block, meaning it loses this amount of energy, so the sign is negative. Therefore, the correct answer is B.W=-kx^2.

This negative sign indicates that the work is done against the movement. As the block is pushed onto the spring, the spring does negative work on the block by pushing back. Think of it as the block 'losing' energy to the spring while it compresses it, which is why the work done by the spring on the block is negative.

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The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at 50∘C has a total translational kinetic energy of 4000 J.A) Diatomic oxygen has a molar mass 16 times that of diatomic hydrogen. The root-mean-square speed vrms for diatomic oxygen at 50∘C is:________a) (16)(2000m/s)=32000m/sb) (4)(2000m/s)=8000m/sc) 2000m/sd) (14)(2000m/s)=500m/se) (116)(2000m/s)=125m/sf) none of the aboveB) The total translational kinetic energy of 1.0 mole of diatomic oxygen at 50∘C is:________a) (16)(4000J)=64000Jb) (4)(4000J)=16000Jc) 4000Jd) (14)(4000J)=1000Je) (116)(4000J)=150Jf) none of the aboveC) The temperature of the diatomic hydrogen gas sample is increased to 100∘C. The root-mean-square speed vrms for diatomic hydrogen at 100∘C is:______a) (2)(2000m/s)=4000m/sb) (2√)(2000m/s)=2800m/sc) 2000m/sd) (12√)(2000m/s)=1400m/se) (12)(2000m/s)=1000m/sf) none of the above

Answers

Answer:

A) d. (1/4)(2000m/s) = 500 m/s

B) c. 4000 J

C) f. None of the above (2149.24 m/s)

Explanation:

A)

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 1^-23 J/K

T = Absolute Temperature

but,

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

Comparing both equations:

(3/2)KT = (1/2) mv²

v = √(3KT)/m  _____ eqn (1)

FOR HYDROGEN:

v = √(3KT)/m = 2000 m/s  _____ eqn (2)

FOR OXYGEN:

velocity of oxygen = √(3KT)/(mass of oxygen)  

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

using eqn (2)

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

B)

K.E = (3/2)KT

Since, the temperature is constant for both gases and K is also a constant. Therefore, the K.E of both the gases will remain same.

K.E of Oxygen = K.E of Hydrogen

K.E of Oxygen = 4000 J

C)

using eqn (2)

At, T = 50°C = 323 k

v = √(3KT)/m = 2000 m/s

m = 3(1.38^-23 J/k)(323 k)/(2000 m/s)²

m = 3.343 x 10^-27 kg

So, now for this value of m and T = 100°C = 373 k

v = √(3)(1.38^-23 J/k)(373 k)/(3.343 x 10^-27 kg)

v = 2149.24 m/s

The rms speed will be "500 m/s". A further solution is provided below.

Given:

Speed of a diatomic hydrogen molecule,

2000 m/s

Mol of diatomic hydrogen,

1.0

Temperature,

50°C

Now,

The rms speed of diatomic molecule will be:

→ [tex]V_{rms} = \sqrt{\frac{5kT}{m} }[/tex]

or,

→ [tex](V_{rms})O_2 = \sqrt{\frac{5kT}{16(m)} }[/tex]

                  [tex]= \frac{1}{4} (V_{rms})H_2[/tex]

                  [tex]= \frac{1}{2} (2000)[/tex]

                  [tex]= 500 \ m/s[/tex]

Thus the above response is right.  

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Technician A says clutch slippage can best be diagnosed with the vehicle stopped, parking brake applied, placing the transmission in 4th gear, and slowly releasing the clutch pedal to see if it stalls the engine. Technician B says an excessively slipping clutch can cause friction surface warpage or hot spots. Who is correct?
Select one:

a. Technician A
b. Technician B
c. Both Technician A and Technician B
d. Neither Technician A nor Technician B

Answers

Answer:

c. Both Technician A and Technician B

Explanation:

It is true that the clutch slippage can be diagnosed with vehicle stopped  parking brake applied, placing the transmission in 4th gear, and slowly releasing the clutch pedal to see if it stalls the engine. Hence techician A is correct.

Moreover, excessive slipping clutch can cause friction surface warpage ( being bent or twisted out of shape) and hot spot( heat energy from the friction.

Therefore, both technician A and B are correct.

Both Technician A and Technician B are correct. Technician A provides a valid diagnostic technique for clutch slippage, and Technician B accurately describes the consequences of an excessively slipping clutch. Hence option c is the answer.

The question addresses two different technicians' statements about diagnosing clutch problems and the effects of clutch slipping. Technician A suggests a diagnostic method for clutch slippage, while Technician B explains a potential consequence of an excessively slipping clutch.

Technician A is correct because testing the clutch by placing the vehicle in a higher gear and releasing the clutch pedal with the parking brake engaged can indeed help diagnose if there is clutch slippage. If the engine does not stall, it indicates that the clutch is not engaging fully and is slipping. Technician B is also correct because an excessively slipping clutch can lead to damage such as friction surface warpage or the development of hot spots on the clutch components due to excessive heat generated by the friction.

The appropriate answer to the student's question is:

c. Both Technician A and Technician B

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