A baseball (m = 145 g) traveling 32 m/s moves a fielder's glove backward 25 cm when the ball is caught. What was the average force exerted by the ball on the glove?

Answers

Answer 1

Answer:

297 N

Explanation:

First, find the acceleration of the ball.

Given:

Δx = 0.25 m

v₀ = 32 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (32 m/s)² + 2a (0.25 m)

a = -2048 m/s²

Find the force exerted on the ball by the glove.

F = ma

F = (0.145 kg) (-2048 m/s²)

F = -297 N

The force exerted by the ball on the glove is equal and opposite.

-F = 297 N

Round as needed.

Answer 2

The average force exerted by the ball on the glove when it was caught is 297 N.

The given parameters:

mass of the baseball, m = 145 g = 0.145 kgspeed of the baseball, u = 32 m/sdistance moved, d = 25 cm = 0.25 m

The acceleration of the baseball is calculated as follows

[tex]v^2 = u^2 + 2as\\\\0 = 32^2 + 2(-0.25)a\\\\0 = 1024 - 0.5a\\\\0.5a = 1024\\\\a = 2048 \ m/s^2[/tex]

The average force exerted by the ball on the glove when it was caught is calculated as follows:

[tex]F = ma\\\\F = 0.145 \times 2048\\\\F = 297 \ N[/tex]

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Related Questions

The magnitudes of the vertical and horizontal components of a vector are 11 and 17 centimeters respectively. Find the magnitude of the vector and the angle from the horizontal axis.

Answers

Explanation:

let the magnitude of the vector be |A|

|A| = ✓11^2 + 17^2 =

|A| =✓410

|A| = 20.23

theta =Tan^-1(11/17) =32.91°

Explanation: edmentum answer


Based on the idea of isostasy, which of these statements is NOT correct?

A) Continental crust is less dense than oceanic crust.
B) The depth at which a crustal plate sits is a function of its mass.
C) When more weight is added to the crust, through a process like mountain building, it slowly sinks deeper into the mantle.
D) The formation ice sheets cause the Earth's surface to sink so much that when the ice melts, the crust and mantle does not rebound.

Answers

The formation ice sheets cause the Earth's surface to sink so much that when the ice melts, the crust and mantle does not rebound.

Explanation:

The above-mentioned statement is the only false statement

During the Ice ages, large continental parts were covered under thick ice sheets. This imposed a superincumbent additional load on the Earth's crust.

Isostasy refers to the balance that exists between parts of Earth's mantle and crust.  Isostatic adjustments are a common phenomenon.  As a result of isostatic adjustments, several parts of the world have risen by as much as 900 feet as an adjustment to superincumbent load since ice ages. E.g. Parts of Scandinavian countries have witnessed these activities and also undergoing this process.

Answer: d

Explanation:

Need help pls (projectiles)

Answers

A) 13.13 m (4.13 m above the top of the ramp)

B) 0.92 s,  30.0 m (14.4 m from the top of the ramp)

Explanation:

A)

The motion of the projectile consists of two independent motions:

- A uniform motion along the horizontal direction (constant horizontal velocity)

- A uniformly accelerated motion along the vertical direction (constant downward acceleration)

To find the maximum height, we just analyze the vertical motion.

The initial vertical velocity of the projectile is given by:

[tex]u_y = u sin \theta = (18)(sin 30^{\circ})=9 m/s[/tex]

Where

u = 18 m/s is the initial velocity

[tex]\theta=30^{\circ}[/tex] is the angle of projection

Since this is a uniformly accelerated motion, we can use the following suvat equation:

[tex]v_y^2-u_y^2=2as[/tex]

where:

[tex]v_y=0[/tex] is the final vertical velocity when the projectile reaches the maximum height

[tex]a=-g=-9.8 m/s^2[/tex] is the acceleration due to gravity (negative because it is downward)

s is the vertical displacement

Re-arranging, we find s:

[tex]s=\frac{v_y^2-u_y^2}{2a}=\frac{0^2-(9)^2}{2(-9.8)}=4.13 m[/tex]

However, this is the vertical displacement above the top of the ramp. We see that the ramp is [tex]d=15.6 m[/tex] long in the horizontal direction, so the height of the ramp is

[tex]h=d tan \theta=(15.6)(tan 30^{\circ})=9m[/tex]

So, the maximum height of the projectile is:

[tex]H=h+s=9+4.13 = 13.13 m[/tex]

B)

To find the time at which the projectile reaches the maximum height, we use another suvat equation:

[tex]v_y=u_y + at[/tex]

where:

[tex]v_y=0[/tex] is the vertical velocity at the maximum height

[tex]a=-9.8 m/s^2[/tex] is the acceleration due to gravity

[tex]u_y = 9 m/s[/tex] is the initial vertical velocity

Solving for t, we find the time:

[tex]t=\frac{v_y-u_y}{a}=\frac{0-9}{-9.8}=0.92 s[/tex]

The horizontal position of the projectile instead is given by the equation for uniform motion:

[tex]x(t)=v_x t[/tex]

where:

[tex]v_x = u cos \theta = (18)(cos 30^{\circ})=15.6 m/s[/tex] is the initial horizontal velocity

Substituting t = 0.92 s, we find:

[tex]x=(15.6)(0.92)=14.4 m[/tex]

So, this is the horizontal distance covered from the top of the ramp at the instant of maximum height; and therefore, the horizontal distance from the beginning of the ramp is

[tex]d=15.6+14.4=30.0 m[/tex]

What circuit that has only one path for the
current to follow?

Answers

Answer:

Series circuit

Explanation:

By definition series circuit is a closed circuit in which the flow of electric current follows only one path.

In a simple electrical circuit (which is a series circuit) where electric cell is the source of power, each component is connected in such a way that there is only one pathway current flows from the positive terminal(+) round to the negative terminal(-) via the external circuit.

Current having only one pathway to flow means that when one of the components is removed, there will be no current flow.

Explain how water freezing and thawing causes weathering and the type of weathering it would be considered.

Answers

Final answer:

Water freezing and thawing causes weathering through a process called frost or ice wedging. This leads to the physical weathering of rocks or soil. In areas with frequent freeze-thaw cycles, such as Iceland, this process can gradually break down rocks into smaller pieces.

Explanation:

Water freezing and thawing can cause weathering through a process called frost or ice wedging. When water freezes, it expands by about 9%, exerting pressure on the rocks or soil in which it is trapped. This pressure can cause the rocks to crack or break apart, leading to physical weathering. As the ice thaws, water seeps into the cracks and when it freezes again, it widens the cracks further, gradually breaking down the rock. This type of weathering is known as mechanical weathering. It is a significant process in areas with frequent freeze-thaw cycles.

Example: In regions with colder climates, such as Iceland, freezing and thawing of water can weather rocks over time. The repeated cycles of freezing and thawing cause the rocks to deteriorate and break down into smaller pieces, contributing to the formation of gravel, sand, and clay.

The truck’s motor is creating 500 N of thrust, but air resistance is placing 500 N in the opposite direction

Answers

500-500=0 it has to be it



A certain microwave has a
wavelength of 0.032 meters. Calculate the frequency of this
microwave​

Answers

Answer:

[tex]9.375\times 10^{9} Hz[/tex]

Explanation:

Frequency is mathematically defined as the quotient of speed divided by wavelength.

[tex]Frequency= \frac {v}{W}[/tex]

where

v-is the speed of light

-w is wavelength.

Given the speed of the wave  as [tex]V=300000000 \ m/s[/tex] and the wavelength [tex]\lambda= 0.032\ m[/tex], we substitute these values in the Frequency function to solve for frequency:

[tex]Frequency=\frac {300000000}{0.032}=9375000000 Hz=9.375\times 10^{9} Hz[/tex]

Hence, the wave's frequency is [tex]9.375\times 10^9\ Hz[/tex]

Microwave has the  wavelength of 0.032 meters so, the frequency is [tex]\rm 9.375\times 10^9 \; Hz[/tex] and this will be determined by using the frequency formula.

Given :

Wavelength = 0.032 m

The Formula of Frequency can be used to determine the wavelength of the microwave:

[tex]\rm Frequency = \dfrac{c}{w}[/tex]   --- (1)

where, [tex]\rm c = 3 \times 10^8\;m/sec[/tex] is the speed of light and w is the wavelength.

Now, put the values of speed of light (c) and wavelength (w) in equation (1).

[tex]\rm Frequency = \dfrac{3\times 10^8}{0.032}[/tex]

[tex]\rm Frequency = 9.375\times 10^9 \; Hz[/tex]

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The circumference of the earth is 40,000 km. The distance from the
North Pole to the equator is 1/4 of the circumference of the earth, which equals __ m.

Answers

Answer:

The distance from the North Pole to the equator is [tex]1*10^{7}[/tex]m.

Explanation:

Circumference of Earth = 40,000 km    ......................(1)

Distance from the North Pole to the Equator is =  1/4th of the Circumference of Earth  ......................  (2)

Let Distance from the North Pole to the Equator be  d ,

the equation formed will be ,

d = 1/4 * Circumference of Earth       ........(3)......... ( from equation 1 )

put the value of Circumference of Earth in equation (3),

d = 1/4 * 40,000  km

d = 10,000 km

converting km to m ,

d = 10,000 * [tex]10^{3}[/tex] m

d =  1 * [tex]10^{7}[/tex] m

The distance from the North Pole to the equator is [tex]1*10^{7}[/tex]m.

Final answer:

The distance from the North Pole to the equator is 1/4 of the Earth's circumference, which equals 10,000,000 meters.

Explanation:

The distance from the North Pole to the equator is 1/4 of the circumference of the earth. Given that the circumference of the earth is 40,000 kilometers, we can calculate this by dividing the circumference by 4. So, 40,000 km ÷ 4 = 10,000 km. To convert this into meters, we multiply by 1,000 (since there are 1,000 meters in a kilometer), thus 10,000 km × 1,000 = 10,000,000 meters. The distance from the North Pole to the equator is 1/4 of the circumference of the earth. The circumference of the earth is 40,000 km, so 1/4 of that distance would be 10,000 km.

This is may mastering physics homework and I just need help solving the question.
Luc, who is 1.80 m tall and weighs 950 N, is standing at the center of a playground merry-go-round with his arms extended, holding a 4.0 kg dumbbell in each hand. The merry-go-round can be modeled as a 4.0-m-diameter disk with a weight of 1500 N. Luc's body can be modeled as a uniform 40-cm-diameter cylinder with massless arms extending to hands that are 85 cm from his center. The merry-go-round is coasting at a steady 27 rpm when Luc brings his hands in to his chest.

Answers

Answer:

Angular speed of the disc after he fold his hands is given as

[tex]\omega_f = 27.5 rpm[/tex]

Explanation:

As we know that the moment of inertia of the solid cylinder is given as

[tex]I_1 = \frac{m_1r_1^2}{2}[/tex]

so we have

[tex]I_1 = \frac{(950/9.81)(0.20)^2}{2}[/tex]

[tex]I_1 = 1.94 kg m^2[/tex]

now moment of inertia of two dumbbell in his hand is given as

[tex]I_2 = 2(m_2 r_2^2)[/tex]

[tex]I_2 = 2(4)(0.85)^2[/tex]

[tex]I_2 = 5.78 kg m^2[/tex]

Now moment of inertia of the disc is given as

[tex]I_3 = \frac{1}{2}MR^2[/tex]

[tex]I_3 = \frac{1}{2}(1500/9.81)(2^2)[/tex]

[tex]I_3 = 305.8 kg m^2[/tex]

Now we can use angular momentum conservation as there is no external torque on it

[tex](I_1 + I_2 + I_3) \omega_i = (I_1 + I_3)\omega_f[/tex]

[tex](1.94 + 5.78 + 305.8) 27 = (1.94 + 305.8) \omega_f[/tex]

[tex]\omega_f = 27.5 rpm[/tex]

Answer: Hello above answerer, Why didn't you add I2 on the other side of the equation?

You just added I1 and I3

Explanation:

What is the acceleration of the object?

Answers

Answer:

Explanation:

Velocity is changing by a constant amount -10 m/s-in second of time.Anytime an object's velocity is changing,the object is said to be accelerating;it has an acceleration.

Answer:

[tex]\boxed{\mathrm{view \ explanation}}[/tex]

Explanation:

[tex]\displaystyle Acceleration =\frac{change \ in \ velocity}{elapsed \ time}[/tex]

[tex]\displaystyle A=\frac{V_f-V_i}{t}[/tex]

Elements have the same number of ______ as you move from left to right

Answers

Answer:

protons

Explanation:

Answer:

Electron shells

Explanation:

Infrasounds _____.

can be used to view internal organs
are sounds with frequencies below 20 Hz
are sounds with frequencies above 20,000 Hz
travel in transverse waves

Answers

Infra sounds are sounds with frequencies below 20 Hz.The popular concept that infra sounds are in audible holds false

Explanation:

Some example of Infrasounds  are- some animals such as whales, elephants and giraffes which  communicate with each other  using infrasound over long distances. Various natural phenomenon such as Avalanches, volcanoes, earthquakes, ocean waves, water falls and meteors also generate infrasonic wavesInfrasound, is sound that is lower in frequency than 20 Hz or cycles per second.Even the human body can generate mechanical vibrations at very low frequencies, which are known as the  infrasonic waves. Such low-frequency vibrations/infrasonic waves  are produced by physiological processes—such as heartbeats, respiratory movements, blood flow in vessels, and other processes.

A tuning fork vibrating at 512 Hz is held near one end of a tube of length that is open at both ends, as shown above. The column of air in the tube resonates at its fundamental frequency. The speed of sound in air is 340 m/s. Calculate the length of the tube.



Answers

Answer:

Length of the pipe is 33.2 cm

Explanation:

As we know that the frequency of the sound in open end pipe is given as

[tex]f = \frac{v}{2L}[/tex]

so here we will have

f = 512 Hz

v = 340 m/s

so now we have

[tex]512 = \frac{340}{2L}[/tex]

[tex]L = \frac{170}{512}[/tex]

[tex]L = 33.2 cm[/tex]

Final answer:

To calculate the length of a tube open at both ends with a given frequency and speed of sound, we can rearrange the formula ν = v / (2L) and solve for L, giving a length of 0.332 m for a 512 Hz tuning fork.

Explanation:

A tuning fork vibrating at 512 Hz is held near one end of a tube of length that is open at both ends. The tube resonates at its fundamental frequency. To calculate the length of the tube given the speed of sound in air is 340 m/s, we use the formula for the fundamental frequency of a tube open at both ends, which is ν = v / (2L), where ν is the frequency (512 Hz), v is the speed of sound (340 m/s), and L is the length of the tube we are looking for.

Rearranging the formula, we get L = v / (2ν). Plugging in the numbers, L = 340 m/s / (2 × 512 Hz) = 0.33203125 meters, which can be rounded to 0.332 m or 33.2 cm.


name the three basic types of playing positions used in a basketball game.

Answers

point guard, center, middle

Answer:

point guard, center, middle

Explanation:

A car accelerates from 20mi/hr to 60mi/hr. How many times greater is the car's kinetic energy at the higher speed compared to the kinetic energy at the slower speed

Answers

Answer:

9 times

Explanation:

Kinetic energy is:

KE = ½ mv²

When we triple the velocity, the kinetic energy increases by a factor of 9.

9KE = ½ m(3v)²

The kinetic energy of the car at 60 m/hr is 9 times greater than the kinetic energy at 20 m/hr.

What do you mean by kinetic energy?

Kinetic energy is a form of energy that an object possesses by virtue of its motion and is dependent on the mass and velocity of the object.

The kinetic energy of an object is given by the equation:

KE = (1/2)mv²

Where

KE = is the kinetic energy,

m = is the mass of the object,

v = its velocity.

Here in this question,

The kinetic energy of an object is proportional to the square of its velocity, so if a car accelerates from 20 km/hr to 60 km/hr, its kinetic energy at the higher speed will be:

KE(higher) = 1/2 ×m × v(higher)²

And at the lower speed, the kinetic energy will be:

KE(lower) = 1/2 ×m × v(lower)²

Where

m = the mass of the car.

Now for ratio, we have to divide the two equations:

KE(higher) / KE(lower) = [1/2× m ×v(higher)²] / [1/2 × m × v(lower)²]

The mass of the car cancels out, leaving us with:

KE(higher) / KE(lower) = (v(higher)²) / (v(lower)²)

Now, we get:

KE(higher) / KE(lower) = (60²) / (20²) = 9

Therefore, the kinetic energy of the car which is moving at a speed of 60 m/hr is 9 times greater than the kinetic energy of the car which is moving at 20 m/hr.

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How much force is required to accelerate a 50 kg with a mass at 4 m/s2?

Answers

Answer:200N

Explanation:

Mass=50kg

Acceleration=4m/s^2

Force=mass x acceleration

Force=50 x 4

Force=200N

what is the resistance of a conductor

Answers

Opposition for the current flow

Explanation:

Resistance is defined as the ability pf the conductor to oppose the flow of electrons through it. It is usually represented in Ohm.Resistance is an important parameter in a circuit design and it should be properly designed.Resistance of a conductor depends upon the material nature, length of the conductor and area of cross section. In conductor, Resistance is low. It is due to that charges flow through the conductor freely.

2 characteristics of constant speed

Answers

Answer:

it has no acceleration

Explanation:

Does reflection occur when a wave bounces off a surface that cannot pass through

Answers

Answer: yes

Explanation: bc

Which of the following materials offer the least electrical resistance? Pure water, wood, salt water, glass

Answers

Salt water offers the least electrical resistance.

Explanation:

Least electrical resistance indicates that any material which readily allows the electric current through itself, and shows more conductivity.

Here pure water doesn't contain any ions, so it is a bad conductor.

Wood and glass are also bad conductors of electricity.

Salt water contains ions, which conducts electricity which means it shows least electrical resistance.

Answer:

salt water

Explanation:

What are the advantages of parallel circuits? Check all that apply.
If one bulb goes out, the other bulbs go out.
If one bulb goes out, the other bulbs stay lit.
If there is a break in one branch of the circuit, current can still flow through the other branches.
If there is a break in one branch of the circuit, current cannot flow at all.
Parallel circuits are simple to design and build,
O Parallel circuits are complicated to design and build.

Answers

The correct answer is option (1) and (2). The advantages of parallel circuits include If one bulb goes out, the other bulbs stay lit and If there is a break in one branch of the circuit, current can still flow through the other branches.

Parallel circuits offer several advantages, and you should check the statements that accurately reflect these benefits.

Here are the advantages of parallel circuits:

1. If one bulb goes out, the other bulbs stay lit.

Correct. In a parallel circuit, each component is connected across the same voltage source. Therefore, if one component fails, the others continue to function.

2. If there is a break in one branch of the circuit, current can still flow through the other branches.

Correct. In a parallel circuit, each branch operates independently. A break in one branch does not affect the operation of the other branches.

3. Parallel circuits are simple to design and build.

Incorrect. While parallel circuits offer certain advantages in terms of reliability and consistent voltage, they are not necessarily simpler to design compared to series circuits. The complexity can increase with the number of branches and components.

4. Parallel circuits are complicated to design and build.

Correct. Parallel circuits can be more complex to design and build than series circuits, especially as the number of branches increases. The design must ensure proper connections and consider the current distribution across each branch.

5. If one bulb goes out, the other bulbs go out.

Incorrect. This statement applies to series circuits, not parallel circuits. In a series circuit, if one component fails, the entire circuit is interrupted.

6. If there is a break in one branch of the circuit, current cannot flow at all.

Incorrect. In a parallel circuit, a break in one branch does not stop current from flowing through the other branches. Each branch operates independently of the others.

The complete question is:

What are the advantages of parallel circuits? Check all that apply.

1. If one bulb goes out, the other bulbs go out.

2. If one bulb goes out, the other bulbs stay lit.

3. If there is a break in one branch of the circuit, current can still flow through the other branches.

4. If there is a break in one branch of the circuit, current cannot flow at all.

5. Parallel circuits are simple to design and build,

6. Parallel circuits are complicated to design and build.


Two equal and opposite charges separated by a distance, d, experience an attractive force, F. If each charge is doubled in magnitude, what should be the new distance between them so that the force remains unchanged?

Answers

If the each charge is doubled in magnitude and force remains unchanged then the distance between the charged particle is four times the original distance.

Explanation:

The force between two charged objects are shown by Coulomb's law.

In the scalar form, this law is represented as:

[tex]F = k \frac{q_1 q_2}{d^2}[/tex]

where,

k = coulomb's constant

q₁ and q₂ are the magnitude of charged objects

d = distance between the charges.

According to the question,

Case1:

charge on object 1 = +q₁

Charge on object 2 = -q₂

Distance between the charges = d

[tex]Force, F = k\frac{+q_1 X -q_2}{d^2} \\\\F = k\frac{-q_1q_2}{d^2}[/tex]

Case 2:

Charge on object 1 = +2q₁

Charge on object 2 = -2q₂

Force between the objects is same

New distance, dₓ = ?

If both the forces are equal then,

[tex]k\frac{-q_1q_2}{d^2} = k\frac{+2q_1 X -2q_2}{d_x^2} \\\\[/tex]

On simplifying the equation we get,

[tex]\frac{-1}{d^2} = \frac{-4}{d_x^2} \\\\d_x^2 = 4d^2[/tex]

So, if the each charge is doubled in magnitude and force remains unchanged then the distance between the charged particle is four times the original distance.

Final answer:

If the charges are doubled and the force is to remain the same, the new distance between the charges should be the initial distance multiplied by the square root of 2.

Explanation:

The force experienced by two equal and opposite charges separated by a distance d can be calculated using Coulomb's Law: F = k*q1*q2/d^2, where F is the force, k is a constant, q1 & q2 are the charges, and d is the distance between them. If the magnitude of each charge is doubled, the equation becomes F = k*2q1*2q2/d'^2, where d' is the new distance. If we want the force to remain unchanged, we have the equation: k*q1*q2/d^2 = k*2q1*2q2/d'^2. Solving for d', we get d' = sqrt (2) * d. Therefore, the new distance between the charges should be sqrt (2) times the initial distance to keep the force the same when the magnitude of the charges is doubled.

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If an object's mass is decreasing while a constant force is applied to the object, would its acceleration decrease, increase, or remain the same?

Answers

Answer:

increase

Explanation:

We need to find what change takes place to the acceleration of the object in the given situation.

The acceleration of the object would increase.

m = Mass of the object

a = Acceleration of the object

Force is given by

[tex]F=ma[/tex]

Acceleration would be

[tex]a=\dfrac{F}{m}[/tex]

It is given that force is constant so

[tex]a\propto \dfrac{1}{m}[/tex]

This means that acceleration is inversely proportional to mass.

Here, the mass is decreasing so the acceleration will increase.

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Suppose a truck has a momentum of 40,120 kg • meters per second and a mass of 1,180 kg. What is the truck’s velocity?

4.7 × 107 meters per second
47 × 107 meters per second
34 meters per second
3.4 meters per second

Answers

34 meters per second because 1180 kg times 34 Mps is 40120 kg/mps

Final answer:

To find the velocity of a truck given its momentum and mass, divide the momentum by the mass; the truck has a velocity of 34 meters per second.

Explanation:

The question is asking us to calculate the velocity of a truck given its momentum and mass. The formula to find velocity when momentum and mass are known is velocity = momentum / mass.

Plug in the values to get the velocity: velocity = 40,120 kg·m/s ÷ 1,180 kg = 34 m/s. Therefore, the velocity of the truck is 34 meters per second.

To find the velocity of a truck given its momentum and mass, divide the momentum by the mass; the truck has a velocity of 34 meters per second.

1. Identify whether the following statements describe a change in acceleration. Explain your response.

a. A car stopped at a stop sign.

b. A boat traveling east at 10 knots.

c. An airplane traveling north 600 miles per hour.

d. A person running at 5 meters/second along a curving path.

Answers

Answers:

a. Change in acceleration

b. Not change in acceleration.

c. Not change in acceleration.

d. Change in acceleration

Explanation:

Let's begin by explaining what acceleration is:

Acceleration [tex]a[/tex] is initially defined as the variation of Velocity [tex]\Delta V[/tex] in time [tex]\Delta t[/tex]:  

[tex]a=\frac{\Delta V}{\Delta t}[/tex]  

However, we cannot forget acceleration is a vector quantity as well (like velocity) and as a vector it has magnitude and direction.

So, when one of these aspects changes (or both) acceleration changes as well.

In other words: A change in acceleration implies the change in velocity, or a change in direction, or both.

Having this clear, we can identify the statements that describe a change in acceleration:

a. A car stopped at a stop sign.

Change in acceleration, since the car changed its velocity.

b. A boat traveling east at 10 knots.

Not a change in acceleration, since the boat is travelling at a constant velocity and is not changing its direction.

c. An airplane traveling north 600 miles per hour.

Not a change in acceleration, since the airplane is travelling at a constant velocity and is not changing its direction.

d. A person running at 5 meters/second along a curving path

Change in acceleration, since the person is changing its direction in the curving path.

Compare the magnitude of the electromagnetic and gravitational force between two electrons separated by a distance of 2.00 m. Assume the electrons have a mass of 9.11 × 10–31 kg and a charge of 1.61 × 10–19 C. Round to two decimal places

Answers

Answer:

1) 5.83

2) 1.38

3) 4.22

Explanation:

The electrostatic force exerted tow electrons on each other is equal to  5.83  × 10⁻²⁹ N. The gravitational force is 1.38  × 10⁻⁷¹ N.

What is coulomb's law?

According to this law, the force of attraction between two charged particles can be written as the product of their charges on them and is the inverse of the square of the distance by which they are separated.

The magnitude of the electrostatic force between charges is given by:

[tex]\displaystyle F = k\frac{q_1q_2}{r^2}[/tex]

where k has a value of 8.99 × 10⁹ N.m²/C².

Given the charge on one electron, q₁ =  q₂ = 1.61 × 10⁻¹⁹

The distance between these two electrons, r = 2.00 m

The magnitude of electric force between the electrons will be:

F = 8.99 × 10⁻⁹ × (1.61 × 10⁻¹⁹)²/ (2.00)²

F = 5.83  × 10⁻²⁹ N

The gravitational force between two electrons is equal to:

[tex]\displaystyle F = G\frac{m_1m_2}{r^2}[/tex]

F' = 6.674 × 10⁻¹¹ × (9.1 × 10⁻³¹)²/ (2.00)²

F' = 1.38  × 10⁻⁷¹ N

F/F' = 4.23 × 10⁴² N

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g of potassium reacts with 16 g of oxygen to produce 94 g of potassium oxide

Answers

Answer:

78g

Explanation:

Given parameters:

Mass of oxygen gas = 16g

Mass of potassium oxide = 94g

Unknown:

Mass of reacting potassium = ?

Solution:

To solve this problem, we need to obtain a balanced reaction equation. Then determine the number of moles of the reactant and use it to find that of the other one.

Balanced equation:

                      4K +   O₂   →    2K₂O

  Number of moles of reacting oxygen;

       Number of moles = [tex]\frac{mass}{molar mass}[/tex]

molar mass of  O₂ = 2 x 16 = 32g/mole

     Number of moles = [tex]\frac{16}{32}[/tex]  = 0.5mole

From the reaction equation;

          4 mole of K reacted with 1 mole of O₂;

           x mole of K will react with 0.5 mole of O₂

Therefore, 4 x 0.5 = 2 moles of potassium.

Mass of potassium = number of moles x molar mass

              Molar mass of potassium = 39g

Mass of potassium = 2 x 39 = 78g

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 StartFraction N over C EndFraction. If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

Answers

Answer:

0.027 J

Explanation:

The electric potential energy of the charge is given by:

[tex]U=qEd[/tex]

where:

q is the magnitude of the charge

E is the strength of the electric field

d is the distance of the charge from the source of the field

In this problem, we have:

[tex]q=4.5\cdot 10^{-5}C[/tex] is the charge

[tex]E=2.0\cdot 10^4 V/m[/tex] is the strength of the field

d = 0.030 m is the distance of the charge

So, its electric potential energy is

[tex]U=(4.5\cdot 10^{-5})(2.0\cdot 10^4)(0.030)=0.027 J[/tex]

Answer:

.027 J

Explanation:

If the vector below is multiplied by 2, what will be its end point?

Answers

Answer:

If the scalar is negative, then multiplying a vector by it changes the vector’s magnitude and gives the new vector the opposite direction. For example, if you multiply by –2, the magnitude doubles but the direction changes. We can summarize these rules in the following way: When vector A is multiplied by a scalar c

Explanation:

Answer: (4, -2)

Explanation:

The vector shown in the image is (2, -1)

 

    2. Now, the scalar multiplication for vectors works in the next way:

    3. for a scalar c and a vector (x,y)

    4. c*(x,y) = (c*x, c*y)

     5. In our case, the scalar is 2, and the vector is (2, -1)

     6.  2*(2, - 1) = (2*2, -1*2) = (4, -2)

one cubic foot of water can store 312btu. a home requires 100,000 what is the volume​

Answers

Volume of water required to store 100,000 Btu of thermal energy is [tex]320.51foot^{3}[/tex] .

Explanation:

The complete question is : One cubic foot of water can store 312 Btu of thermal energy. On a cold winter day a well-constructed home may require 100,000 Btu of nighttime space heating. What is the volume of water required to store this energy? In this question , it's given that One cubic foot of water can store 312 Btu of thermal energy or 312 Btu takes 1 cubic foot of water ,So

1 Btu takes  [tex]\frac{1}{312}[/tex] cubic foot of water

Therefore, 100,000 Btu takes:

⇒ [tex]volume = \frac{1}{312}(100,000)[/tex] [tex]foot^{3}[/tex]

⇒ [tex]volume = \frac{100,000}{312}[/tex] [tex]foot^{3}[/tex]

⇒ [tex]volume = 320.51[/tex] [tex]foot^{3}[/tex]

Volume of water required to store 100,000 Btu of thermal energy is [tex]320.51foot^{3}[/tex] .

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