A ball of mass 100g falls from a height of 3m on to a horizontal surface and rebounds to a height of 2m. calculate the change in momentum and the kinetic energy of the ball it strikes the surface​

Answers

Answer 1

The change in momentum is equal to 1.3928 kg.m/s².

The kinetic energy of the ball as it strikes the surface = 2.94 Joules

Explanation:

Given:

Mass of the ball = 100 g = 100 × 10⁻³ kg = m = 0.1 kg

Height from which ball falls = h = 3 m

Height to which the ball rebounds = h' = 2 m

g= acceleration due to gravity = g = 9.8 m/s²

1. A ball dropped from a height of 3 m, hits the horizontal surface and bounces back. This will cause a change in momentum.

The velocity of the ball before hitting the surface and after hitting the surface is different; causing a change in momentum (Δp).

Since momentum (p) = mass (m) × velocity (v) : [tex]p=m\times v[/tex]

Δp = [tex]m\times V_\ after[/tex] [tex]-\ m\times V_\ before[/tex] = [tex]m\times (V_\ after[/tex] [tex]\ -\ V_\ before[/tex] [tex])[/tex] ...........................(1)

Velocity (v) is given by [tex]v = \sqrt{2gh}[/tex]

[tex]V_\ before[/tex] = [tex]\sqrt{2\times g\times h} = \sqrt{2\times 9.8\times 3} = \sqrt{58.8} = 7.668\ m/s^2[/tex]

[tex]V_\ after[/tex] = [tex]\sqrt{2\times g\times h'} = \sqrt{2\times 9.8\times 2} = \sqrt{39.2} = 6.2609\ m/s^2[/tex]

[tex]V_\ before[/tex] is a decreasing quantity (Ball dropped from 3 m) until it becomes equal to [tex]V_\ after[/tex] and hence is a negative vector (negative in sign and opposite in direction to [tex]V_\ after[/tex].)

[tex]V_\ before[/tex] = (-7.668 m/s²)

From (1), for m = 0.1 kg, Δp becomes;

Δp = [tex]m\times (V_\ after[/tex][tex]\ -\ V_\ before[/tex][tex])[/tex] =  [tex]0.1( 6.2609 - ( - 7.668)) = 0.1\times 13.9289 = 1.3928\ kg.m/s[/tex]

2. As a ball falls to the surface, its gravitational potential energy is transformed into kinetic energy. This kinetic energy keeps on increasing with increase in momentum until it strikes the surface.

K.E of ball just before it strikes the surface from 3 m height = [tex]K.E = mgh[/tex]

[tex]K.E = 0.1\times 9.8\times 3 = 2.94\ J[/tex]


Related Questions

Based on the diagram which of the following statements is true of a helium atom

Answers

Answer: Option 2

Explanation:

Option 1 is wrong because there are 2 protons and 2 neutrons in nucleus.

Option 3 is wrong because there are two electrons moving around nucleus.

Option 4 is wrong because electrons are negatively charged and are moving around the nucleus.

Option 5 is wrong because there equal amount of protons and electrons with 2 each.

what is the potential energy of the ball when it gets to its maximum height just before falling back to the ground​

Answers

Answer:

I will say that the the potential energy will be at its maximum.

Explanation:

potential energy deals with gravity and gravity deals with height, so when a object is in its maximum height it will have the maximum potential energy.  

"Your friend has a job as a pizza delivery person. She carries a few pizzas, weighing 20 N, up four flights of stairs , a height of 30 m. How much work does she do?" If you could explain how to do this that would be great!

Answers

Answer:

600J

Explanation:

work done=newtons×distance

Two birds collide in midair. Before the collision their combined momentum was 88kg•m/sto the west. What is their combined momentum after the collision

Answers

Answer:

88 kg•m/s to the west

Explanation:

Momentum is conserved, so momentum before collision = momentum after collision.

Answer:

88 kg•m/s to the west

Explanation:

aye pecks and so u guys feel more secure

If the difference in electronegativity values between two atoms is more than 2.0, nonpolar covalent bonds generally form.

ITS FALSE

Answers

It’s False I think :))

A figure skater in a tight spin has a rotational inertia of 5.6kgm^2, and an angular velocity of 16 rad/s a) What is her angular momentum? b) what was her angular velocity when she went into the spin if her rotational inertia was 9.8kgm^2 before she tucked?

Answers

The angular momentum is 89.6 kg-m^2/s.

The angular velocity is 9.142 rad/s.

Explanation:

Momentum is the product of rotational inertia to the angular velocity.

Angular momentum = m *v = 5.6 * 16 = 89.6 kg-m^2 / s.

Angular velocity is the rate of velocity at which an object is rotating around a center or a specific point in a given time period. It is also known as rotational velocity. Angular velocity is measured in radian per second (rad/s).

angular velocity = angular momentum / rotational inertia

                          = 89.6 / 9.8 = 9.142 rad / s.

You pull your t-shirt out of the washing machine and note that 2850 particles have become attached, each of which could be either an electron or a proton. Your t-shirt has a net charge of − 5.50 X 10 -18 C. How many electrons are attached to your t-shirt? Enter the number



Answers

The number of electrons attached to your t-shirt is 1442.

What is charge?

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively).

Unlike charges attract one another while like charges repel one another. Neutral refers to an object that carries no net charge.

Let the total number of electrons is = n.

Total number of proton is = 2850 - n.

Then, total charge on the t-shirt = ( n - (2850- n) ×(-1.6×10⁻¹⁹) C.

= (2n - 2850) ×(-1.6×10⁻¹⁹) C.

So,

(2n - 2850) ×(-1.6×10⁻¹⁹) C = − 5.50×10⁻¹⁸

(2n - 2850) = 34

2n = 2884

n = 1442

Hence, The number of electrons attached to your t-shirt is 1442.

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Final answer:

The number of electrons attached to your t-shirt is 34.

Explanation:

To determine the number of electrons attached to your t-shirt, we need to consider the net charge of the t-shirt and the charge of an electron. The net charge of your t-shirt is −5.50 × 10-18 C. The charge on an electron is -1.6022 × 10-19 C. To find the number of electrons, we divide the net charge of the t-shirt by the charge per electron:

Number of electrons = Net charge / Charge per electron

Number of electrons = -5.50 × 10-18 C / -1.6022 × 10-19 C = 34.28

Since we cannot have a fraction of an electron, the number of electrons attached to your t-shirt is 34.

What does the impulse-momentum theorem state? A. Impulse equals change in momentum B. Impulse and momentum change force. C. Impulse and momentum are conserved. D. Force equals change in momentum

APEX physical science

Answers

Impulse equals change in momentum.

If a bicyclist has a mass of 70 KG and a velocity of 25M/S, what is the momentum of the bicyclist?

Answers

Answer:

1750 kgm/s

Explanation:

The equation for momentum is p = mv = 70 * 25 = 1750.

The momentum of the bicyclist with the given value of mass travelling at the given velocity is 1750kgm/s.

What is Momentum?

Momentum is simply the product of the mass of an object and its velocity.

Its is expressed as;

P = m × v

Where m is the mass of the object and v is its velocity.

Given the data in the question;

Mass of bicyclist m = 70kgVelocity v = 25m/sMomentum P = ?

We substitute the given values into the expression above.

P = m × v

P = 70kg × 25m/s

P = 1750kgm/s

Therefore, the momentum of the bicyclist with the given value of mass travelling at the given velocity is 1750kgm/s.

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A skydiver jumped out of a plane, determine distance he descended after 5 seconds. Gravity is pulling him down at 10 m/s^2 (air resistance is negligible).

Answers

Answer: 125 m

Explanation:

This problem is related to vertical motion and can be solved with the following equation:

[tex]y-y_{o}=V_{o}t-\frac{1}{2}gt^{2}[/tex] (1)

Where:

[tex]y-y_{o}=\Delta y[/tex] is the difference between the final height [tex]y[/tex] and initial height [tex]y_{o}[/tex]. Let's take into account the initial height is greater than the final height, since the skydiver is descending.

[tex]V_{o}=0 m/s[/tex] Is the skydiver's initial velocity, assuming the plane was not moving at that moment

[tex]t=5 s[/tex] is the time

[tex]g=10 m/s^{2}[/tex] is the acceleration due gravity

Solving the equation:

[tex]\Delta y=-\frac{1}{2}gt^{2}[/tex] (2)

[tex]\Delta y=-\frac{1}{2}(10 m/s^{2})(5 s)^{2}[/tex] (3)

[tex]\Delta y=-125 m[/tex] (4) Here, the negative sign only indicates the position of the skydiver, and remember the initial height is greater than the final height.

In fact, the distance is positive: 125 m

Which type of graph most clearly show how a part or percentage relate to the whole

Answers

Circle graph is the type of graph which most clearly shows the part or percentage related to the whole.

Explanation:

Graphs are the easiest tool to show the change in a given dependent variable with respect to independent variable. The influence or the effects will be seen in the graphs.

There are different kinds of graph like circle graph, bar graph, line graph. Each of these have their own method of showing the change in the dependent variable. Among them, circle graph is the one which will help to show the percentage of each variable related to the whole.

The circle graph, or pie chart, excels in highlighting proportional relationships within a dataset. Its circular format provides an intuitive view of component distribution and significance. Here option C is correct.

A circle graph, also known as a pie chart, is particularly effective in illustrating the proportional relationship between individual components and the entire set. Graphs serve as a valuable tool for visualizing the fluctuations of a dependent variable in relation to an independent one.

Various types of graphs, such as bar graphs, line graphs, and circle graphs, offer distinct approaches to representing these changes. Among these options, the circle graph stands out for its ability to clearly depict the percentage contribution of each variable relative to the whole.

Its circular format allows for an intuitive understanding of the distribution and relative significance of different components within the dataset. By utilizing this visual representation, one can easily grasp the relative importance of each element and how they collectively constitute the entirety of the data. Here option C is correct.

Complete question:

Which type of graph is particularly effective in illustrating the proportional relationship between individual components and the entire set?

A) Bar graph

B) Line graph

C) Circle graph (Pie chart)

D) Scatter plot

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Att=0 a car has a speed of 30 m/s. Att-6 s, its speed is 14 m/s.
What is its average acceleration during this time interval?

Answers

The average acceleration during this time interval is [tex]-2.67 \mathrm{m} / \mathrm{s}^{2}[/tex]

Explanation:

Average acceleration can be measured as the ratio of change in speed to change in time. As the initial speed at initial time is 30 m/s at t = 0 and then at t = 6 s, the speed is decreased to 14 m/s. Then the average acceleration will be

[tex]Average acceleration =\frac{14-30}{6-0} =-2.67m/s^{2}[/tex]

So the average acceleration is negative which indicates that there is deceleration occurrence in the system.

What are the formulas for Calculating Kinetic Energy and Potential Energy?

Answers

Answer:

KE = .5(m)(v²) and PE = mgh

Explanation:

m = mass, v = velocity, g = gravity (9.8 on earth), h = height.

Answer:

[tex]\boxed{\bold { \large { \boxed {KE=\frac{1}{2} mv^2 \ , \ PE=mgh}}}}[/tex]

Explanation:

Kinetic energy formula

[tex]\displaystyle KE=\frac{1}{2} mv^2[/tex]

Potential energy formula

[tex]\displaystyle PE=mgh[/tex]

[tex]\displaystyle KE \Rightarrow \sf kinetic \ energy \ (J)[/tex]

[tex]\displaystyle PE \Rightarrow \sf potential \ energy \ (J)[/tex]

[tex]\displaystyle m \Rightarrow \sf mass \ (kg)[/tex]

[tex]\displaystyle v \Rightarrow \sf velocity \ (m/s)[/tex]

[tex]\displaystyle g \Rightarrow \sf acceleration \ of \ gravity\ (m/s^2)[/tex]

[tex]\displaystyle h \Rightarrow \sf height \ (m)[/tex]

The snowblower driver figured that he moved 1250 kg of snow. If the plow pushes with a force of 40000 Newton’s, how fast did the snow accelerate? (Assume no friction)

Answers

The acceleration of snow is 32 m/[tex]s^{2}[/tex].

Explanation:

According to Newton's second law of motion, the force acting on any object is directly proportional to the product of mass and acceleration acting on the object.

So if the object is a snowblower driver with mass 1250 kg and the force acting on it is 40000 N, then the acceleration of the snow can be determined from the ratio of force to mass.

Force = Mass × Acceleration

Acceleration = [tex]\frac{Force}{Mass}[/tex] = [tex]\frac{40000}{1250}=32 m/s^{2}[/tex]

Thus, the acceleration of the snow is 32 m/[tex]s^{2}[/tex].

50 points !! I need help asap.......Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts of potential and kinetic energy the bowling ball has:
• as it sits on top of a building that is 40 meters tall.
• as it is half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second.
• as it is just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.


1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?
Answer:
2. Does the bowling ball have more potential energy or kinetic energy as it is half way through its fall? Why?
Answer:
3. Does the bowling ball have more potential energy or kinetic energy just before it hits the ground? Why?
Answer:
4. What is the potential energy of the bowling ball as it sits on top of the building?
Answer:
5. What is the potential energy of the ball as it is half way through the fall, 20 meters high?
Answer:
6. What is the kinetic energy of the ball as it is half way through the fall?
Answer:
7. What is the kinetic energy of the ball just before it hits the ground?
Answer:


Answers

1) At the top of the building, the ball has more potential energy

2) When the ball is halfway through the fall, the potential energy and the kinetic energy are equal

3) Before hitting the ground, the ball has more kinetic energy

4) The potential energy at the top of the building is 784 J

5) The potential energy halfway through the fall is 392 J

6) The kinetic energy halfway through the fall is 392 J

7) The kinetic energy just before hitting the ground is 784 J

Explanation:

1)

The potential energy of an object is given by

[tex]PE=mgh[/tex]

where

m is the mass

g is the acceleration of gravity

h is the height relative to the ground

While the kinetic energy is given by

[tex]KE=\frac{1}{2}mv^2[/tex]

where v is the speed of the object

When the ball is sitting on the top of the building, we have

[tex]h=40 m[/tex], therefore the potential energy is not zero[tex]v=0[/tex], since the ball is at rest, therefore the kinetic energy is zero

This means that the ball has more potential energy than kinetic energy.

2)

When the ball is halfway through the fall, the height is

[tex]h=20 m[/tex]

So, half of its initial height. This also means that the potential energy is now half of the potential energy at the top (because potential energy is directly proportional to the height).

The total mechanical energy of the ball, which is conserved, is the sum of potential and kinetic energy:

[tex]E=PE+KE=const.[/tex]

At the top of the building,

[tex]E=PE_{top}[/tex]

While halfway through the fall,

[tex]PE_{half}=\frac{PE_{top}}{2}=\frac{E}{2}[/tex]

And the mechanical energy is

[tex]E=PE_{half} + KE_{half} = \frac{PE_{top}}{2}+KE_{half}=\frac{E}{2}+KE_{half}[/tex]

which means

[tex]KE_{half}=\frac{E}{2}[/tex]

So, when the ball is halfway through the fall, the potential energy and the kinetic energy are equal, and they are both half of the total energy.

3)

Just before the ball hits the ground, the situation is the following:

The height of the ball relative to the ground is now zero: [tex]h=0[/tex]. This means that the potential energy of the ball is zero: [tex]PE=0[/tex]The kinetic  energy, instead, is not zero: in fact, the ball has gained speed during the fall, so [tex]v\neq 0[/tex], and therefore the kinetic energy is not zero

Therefore, just before the ball hits the ground, it has more kinetic energy than potential energy.

4)

The potential energy of the ball as it sits on top of the building is given by

[tex]PE=mgh[/tex]

where:

m = 2 kg is the mass of the ball

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

h = 40 m is the height of the building, where the ball is located

Substituting the values, we find the potential energy of the ball at the top of the building:

[tex]PE=(2)(9.8)(40)=784 J[/tex]

5)

The potential energy of the ball as it is halfway through the fall is given by

[tex]PE=mgh[/tex]

where:

m = 2 kg is the mass of the ball

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

h = 20 m is the height of the ball relative to the ground

Substituting the values, we find the potential energy of the ball halfway through the fall:

[tex]PE=(2)(9.8)(20)=392 J[/tex]

6)

The kinetic energy of the ball halfway through the fall is given by

[tex]KE=\frac{1}{2}mv^2[/tex]

where

m = 2 kg is the mass of the ball

v = 19.8 m/s is the speed of the ball when it is halfway through the  fall

Substituting the values into the equation, we find the kinetic energy of the ball when it is halfway through the fall:

[tex]KE=\frac{1}{2}(2)(19.8)^2=392 J[/tex]

We notice that halfway through the fall, half of the initial potential energy has converted into kinetic energy.

7)

The kinetic energy of the ball just before hitting the ground is given by

[tex]KE=\frac{1}{2}mv^2[/tex]

where:

m = 2 kg is the mass of the ball

v = 28 m/s is the speed of the ball just before hitting the ground

Substituting the values into the equation, we find the kinetic energy of the ball just before hitting the ground:

[tex]KE=\frac{1}{2}(2)(28)^2=784 J[/tex]

We notice that when the ball is about to hit the ground, all the potential energy has converted into kinetic energy.

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Answer:

Quest ions

(Score for Question 1: ___ of 7 points)

1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?

Answer: The bowling ball has more potential energy as it sits on top of the building because the force necessary to take the object from greater height will be more than from a lower height. Potential energy is stored energy, so when an object's height changes, its potential falls and becomes lower.

(Score for Question 2: ___ of 7 points)

2. Does the bowling ball have more potential energy or kinetic energy as it is half way through its fall? Why?

Answer: The potential and kinetic energy are the same as it is half way through its fall. The height is 20m half way through the fall, that also means that the potential energy is half of when the ball was at the top of the building.  

E= PE + KE,  

E= PE at the top,  

E= PE half way + KE half way = PE at the top / 2 + KE half way = E / 2 + KE half way,  

PE half way= PE at the top / 2 = KE half way = E / 2,

So when the ball is half way the kinetic energy and potential energy are equal, and each is half of the total energy.

(Score for Question 3: ___ of 7 points)

3. Does the bowling ball have more potential energy or kinetic energy just before it hits the ground? Why?

Answer: The bowling ball has more kinetic energy just before it hits the ground because it’s moving faster, and the faster something moves, the more kinetic energy it has.

(Score for Question 4: ___ of 4 points)

4. What is the potential energy of the bowling ball as it sits on top of the building?  

Answer:  

PE= mgh

Given:

mass= 2 kg,

gravity= 9.8m/s2,

height (where it’s located) = 40m,

PE= (2) (9.8) (40) = 748J

(Score for Question 5: ___ of 4 points)

5. What is the potential energy of the ball as it is half way through the fall, 20 meters high?  

Answer:

PE= mgh

Given:

mass= 2 kg,

gravity= 9.8m/s2,

height (where it’s located) = 20m,

PE= (2) (9.8) (20) = 392J

(Score for Question 6: ___ of 3 points)

6. What is the kinetic energy of the ball as it is half way through the fall?  

Answer:  

KE= ½mv2  

Given:

m= 2kg

v (the speed of the ball when it is halfway through the fall) = 19.8m/s

KE= ½ (2) (19.8)2 = 392J

(Score for Question 7: ___ of 3 points)

7. What is the kinetic energy of the ball just before it hits the ground?  

Answer:

KE= ½mv2  

Given:

m= 2kg

v (the speed of the ball when it is halfway through the fall) = 28m/s

KE= ½ (2) (28)2 = 784J

The mass of the Sun is 1.99 % 1030 kg. Jupiter is 7.79 * 108
km away from the Sun and has a mass of 1.90 X 1027 kg.
The gravitational force between the Sun and Jupiter to
three significant figures is
X 104 N.

Answers

Answer:

Force = [tex]4.16\times 10^{29}\ N[/tex]

Explanation:

Given:

Mass of Sun (M) = [tex]1.99\times 10^{30}\ kg[/tex]

mass of Jupiter (m) = [tex]7.79\times 10^8\ kg[/tex]

Distance between Sun and Jupiter (d) = [tex]1.90\times 10^{27}\ kg[/tex]

The gravitational force between the two is given as:

[tex]F_g=\frac{GMm}{d^2}[/tex]

Where, [tex]G=6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}[/tex]

Now, plug in all the given values and solve for [tex]F_g[/tex]. This gives,

[tex]F_g=\frac{6.674\times 10^{-11}\times 1.99\times 10^{30}\times1.90\times 10^{27} }{(7.79\times 10^8)^2}\\\\F_g=4.16\times 10^{29}\ N[/tex]

Therefore, the gravitational force between the Sun and Jupiter to three significant figures is [tex]4.16\times 10^{29}\ N[/tex]

Answer:

C. 4.16

Explanation:

Right on ED2021

Matching:
The west wind drift circles the globe,near Antarctica I impeded it is the only ocean current that is a...

A. Warm water current
B. Cold water current
C. Circumpolar

Answers

C. Circumpolar

Explanation:

Antarctic  circumpolar current (ACC) is an ocean current that flows from west to east around Antarctica, estimated to be over 100 times larger than the waters flowing in the world's rivers.It connects waters of the atlantic, indian and pacific oceans. The current flow is more is several circular fronts extending from the surface of the sea to the sea floor. It transports and store heat a characteristics that majorly influence both world and regional climate.

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explain why a moving object cannot come to a stop instantaneously (in zero seconds)

Answers

Answer: The pressure from the air and force of who or what used effort to make it move. For example you roll a ball it doesn't stop unless it runs out of the force which in this case would be energy.

Explanation:

Knowledge

Complete the formula for the kinetic energy equation of a moving object

Answers

Answer:

Let the mass of an object starting from rest be m and the velocity with which it travels be v

Kinetic energy of the object will be K.E = mv^2/2

If the object's velocity increases/decreases then kinetic energy would be K.E = m(v^2-u^2)/2 where u is the initial velocity and v is the final velocity

Hope this helps!

a hockey puck sliding on the ice has ______.

A) kinetic energy only
B) potential energy only
C) no kinetic or potential
D) some kinetic and potential

Answers

A kinetic energy only. As it something that is touching and moves against within the touched object hope this helps :) xx

Answer: kinetic energy only

Explanation: kinetic energy only since it's moving

An iceberg at its melting point
(0°C) absorbs 2.40*10^7 J of heat
from the sun. What mass of ice
melts to 0°C water as a result?
(Unit = kg)​

Answers

The mass of the iceberg is 71.9 kg

Explanation:

The amount of thermal energy needed to completely melt a substance at its melting point is given by

[tex]Q=\lambda m[/tex]

where

[tex]\lambda[/tex] is the latent heat of fusion

m is the mass of the substance

In this problem, we have a block of ice at its melting point (zero degrees). The amount of heat given to the block is

[tex]Q=2.40\cdot 10^7 J[/tex]

And the latent heat of fusion of ice is

[tex]\lambda = 334 J/g[/tex]

So, we can re-arrange the equation to find m, the amount of ice that will melt:

[tex]m=\frac{Q}{\lambda}=\frac{2.40\cdot 10^7}{334}=71856 g = 71.9 kg[/tex]

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1500 Joules of work are done lifting a 500 N weight. How high was the weight raised as a result of this work ?

Answers

Work in general  =  (force) x (distance)

Work to lift a weight = (weight of the weight) x (distance lifted)

1500 J = (500 N) x (height)

Divide each side by  500 N :

Height = (1500 J) / (500 N)

Height = 3 meters

Final answer:

Using the work-energy principle, the 500 N weight was raised to a height of 3 meters with 1500 Joules of work done.

Explanation:

To determine how high the 500 N weight was raised using 1500 Joules of work, we can use the work-energy principle, which states that work done (W) is equal to the change in potential energy (PE).

The formula for work when lifting an object vertically is:

W = F × d, where:

W is the work done in joules (J),

F is the force in newtons (N),

d is the distance in meters (m).

Here, we are given that a 500 N weight is lifted, and we have the amount of work 1500 J. We can rearrange the formula to solve for distance (d):

d = W / F

Substituting the given values, we get:

d = 1500 J / 500 N = 3 meters

Therefore, the weight was raised up to 3 meters high as a result of the 1500 J of work.

How big is the moon?

Answers

Answer:

1,079.4 mi

Explanation:

I searched it up. -w-"

Lol

Final answer:

The Moon has a diameter of 3476 kilometers, about a quarter of Earth's, and is roughly 384,000 kilometers away from Earth. In a scaled model, Earth is like a grape and the Moon is a pea over a foot away, fitting into a backpack. Both the Sun and Moon appear similarly sized in the sky from Earth.

Explanation:

The Moon's diameter is approximately 3476 kilometers, which is about one fourth the size of the Earth. On average, the Moon is situated roughly 384,000 kilometers away from Earth, which is about 30 Earth's diameters. If we were to imagine a scale model of our celestial neighborhood, where we reduced every dimension by a factor of one billion, Earth would be the size of a grape (approximately 1.3 centimeters in diameter), while the Moon would be a tiny pea, orbiting at a distance of 40 centimeters, just over a foot away. This scaled-down Earth-Moon system could comfortably fit inside a standard backpack, providing a tangible representation of their proportions and distances relative to each other.

It is an interesting coincidence that, from our perspective on Earth, the Sun and Moon appear to be roughly the same size in the sky. This is because although the Sun's diameter is about 400 times greater than that of the Moon, it is also approximately 400 times farther from Earth. Consequently, both have an angular size of about 1/2 degree, leading to phenomena like solar eclipses, where the Moon can completely cover the Sun.


A 3.00 watt electric motor is plugged into an electrical outlet It takes the motor 30 00 seconds to lift a mass of 254.9 g a distance of
10.00 cm. In that time, the motor has used 90.00 J of energy Assuming no energy leaves the system, how much heat has been
added to the system by the end of those 30 seconds?​

Answers

Answer:

89.75 J

Explanation:

The motor uses 90.00 J of electrical energy.  Any of that energy that isn't used to do work is converted to heat.

The amount of work done is:

W = mgh

W = (0.2549 kg) (9.81 m/s²) (0.1000 m)

W = 0.2501 J

So the heat generated is:

Q = 90.00 J − 0.2501 J

Q = 89.75 J

You hang a tv on your wall. What kind of energy does it have?

Kinetic energy
Potential energy

Answers

Answer:

potential, not moving

Explanation:

A TV hung on a wall has potential energy due to its elevated position, which could be converted to kinetic energy if it falls.

When you hang a TV on your wall, it possesses potential energy because of its position above the ground. Potential energy is the stored energy an object has as a result of its position relative to other objects; in this case, the Earth's surface.

If the TV were to fall, the potential energy would be transformed into kinetic energy, energy due to the motion of the object, as it accelerates towards the ground until it impacts the floor, at which point that kinetic energy would then be transferred to the ground and to the TV in the form of other energy forms such as sound and heat.

I need to find the current resistance and voltage for each in this complicated circuit plz help

Answers

Explanation:

The 11Ω, 22Ω, and 33Ω resistors are in parallel.  That combination is in series with the 4Ω and 10Ω resistors.

The net resistance is:

R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)

R = 20Ω

Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:

V = IR

120 V = I (20Ω)

I = 6 A

So the voltage drops are:

V = (4Ω) (6A) = 24 V

V = (10Ω) (6A) = 60 V

That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:

V = 120 V − 24 V − 60 V

V = 36 V

So the currents are:

I = 36 V / 11 Ω = 3.27 A

I = 36 V / 22 Ω = 1.64 A

I = 36 V / 33 Ω = 1.09 A

If we wanted to, we could also show this using Kirchhoff's laws.

Does velocity of a wave in a medium changes with the wavelength?

Answers

The velocity of a wave in a medium changes with the wavelength

Explanation:

Wave

It is the periodic disturbance in a medium.

Types of Wave

There are two types of wave in general depending upon their propagation through a substance.

• Mechanical  

• Electromagnetic  

Mechanical Wave

It is the kind of wave which needs medium to travel.

For example: Sound Wave  

Electromagnetic Wave

Is that which can travel through medium as well as through vacuum. For example: Light

Characteristics of Wave

There are certain characteristics that each sound possesses. Let’s see.  

 Oscillation: It is the complete movement of particle about its mean position.

Amplitude: Is the maximum displacement of particle from its mean position in either direction (cm).It is denoted by ‘A’.

Frequency: It is the number of sound waves produced per second (Hertz).It is denoted by υ(nu)

Time Period: The time taken to complete one oscillation (sec).It is denoted by ‘T’.

Wavelength: The distance between two consecutive crest or trough (cm).It is denoted by λ(lambda).

Velocity of Wave: The speed with which sound travel (m/sec).It is denoted by ‘v’.

Relation between time period, frequency and velocity of wave  

We have: frequency =velocity /wavelength  

                υ=c/λ

Velocity of wave depends upon :

frequency of wave

Wavelength of wave

Therefore , with change in wavelength , the velocity of a wave in medium changes .

Calculate your average walking speed when you step 0.80m in o.50s

Answers

Answer: 1.6 m/s

Explanation: Avg.Speed = total Distance/ Total time

Avg Speed = 0.80 / 0.50

. = 1.6 m/s

Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts of potential and kinetic energy the bowling ball has:
• as sits on top of a building that is 40 meters tall.
• as it is half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second.
• as it is just about to hit the ground from a fall off a building that is 40 meters tall and traveling 28 meters per second.

1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?
2. Does the bowling ball have more potential energy or kinetic energy as it is half way through its fall? Why?
3. Does the bowling ball have more potential energy or kinetic energy just before it hits the ground? Why?
4. What is the potential energy of the bowling ball as it sits on top of the building?
5. What is the potential energy of the ball as it is half way through the fall, 20 meters high?
6. What is the kinetic energy of the ball as it is half way through the fall?
7. What is the kinetic energy of the ball just before it hits the ground?

Answers

Answer:

number 1 is that the bowling ball has more gravitational potential energy as it sits on top of the building.

Answer:

#2 would be : The bowling ball now has more kinetic energy because it is moving and picking up speed. The potential energy has already been wasted because it has been used as the ball falls.

:)

An object is dropped from a bridge. It is recorded to take 3.4 seconds to reach the ground. How high is the bridge? Assume the acceleration of gravity is 10m/sec2

Answers

Answer:

The height of bridge is [tex]17\ m[/tex]

Explanation:

Given the time taken to reach the ground is [tex]3.4\ second[/tex]

And acceleration of gravity [tex]10\ m/s^2[/tex]

Also the initial velocity of the object [tex]u=0\ m/s[/tex]

The object is falling under the condition of free fall.

So, we can use the following formula for computing the distance when the object is under free fall.

Where [tex]S[/tex] is the height, [tex]t[/tex] is time of fall, and [tex]g[/tex] is acceleration of gravity.

[tex]S=\frac{gt^2}{2}\\\\S=\frac{10\times3.4}{2}\\S=17\ m[/tex]

The height of the bridge is calculated to be 57.8 meters considering the object takes 3.4 seconds to reach the ground when dropped from rest.

To calculate the height of the bridge from which an object is dropped and takes 3.4 seconds to reach the ground, we can use the formula for the distance covered under acceleration due to gravity:

[tex]s = ut + \frac{1}{2} at^2[/tex]

where:
s = distance (height of the bridge in this case)
u = initial velocity (0 m/s, since the object is dropped)
a = acceleration due to gravity (10 m/s^2)
t = time taken to reach the ground (3.4 seconds)

Now, substituting the known values:


s = 5 * 11.56
s = 57.8 meters

Therefore, the height of the bridge is 57.8 meters.

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