A 65 kg students is walking on a slackline, a length of webbing stretched between two trees. the line stretches and sags so that line makes a 20 degree angle relative to the horizontal. what is the tension in the line?

Radiation transfers energy through electromagnetic waves, not by moving matter.

The statement that 'radiation transfers energy by moving matter' is false.

Radiation transfers energy through electromagnetic waves, which do not require the movement of matter. Atoms and molecules emit electromagnetic radiation as their electrons move about and collide or vibrate in place. This radiation carries energy and can be absorbed by other material.

For example, in a hot material, the individual particles vibrate or move rapidly from collisions, resulting in more energetic waves being emitted. On the other hand, cool material generates lower-energy waves due to low-energy atomic and molecular motions.

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José's lack of pain is likely due to the release of endorphins, which are natural pain relievers produced by the body during intense physical activity.

José's lack of pain after a long and bruising football game is most likely due to the release of endorphins. Endorphins are neurotransmitters produced by the central nervous system and the pituitary gland. Known as the body's natural pain relievers, they are released in response to stress or discomfort to inhibit the transmission of pain signals in the brain and produce a feeling of euphoria.

This phenomenon is often referred to as a 'runner's high' and can occur during and after intense physical activity.

Explanation :  

The angular velocity of the planet in the elliptical orbit will vary. Its shows that the planet  travel slower when farther from the sun, then faster when closer to the sun.

1. Yes, Earth experiences the strongest gravitational force when it is closest to the Sun.

2. Yes,  Earth moves the greatest distance in thirty days when it is closest to the Sun.

3. Yes,  Earth travels with the slowest tangential speed when it is farthest from the Sun.

4. Yes,  Earth sweeps out the same area in the same time frame anywhere in its orbit

Kepler's second law : Kepler describe the motion of the planets around the sun. the line joining the planet and the sun sweeps out  the same area in the same time.

The characteristics of Earth’s orbit  that that agree and follow the pattern of Kepler’s second law are;

Earth experiences the strongest gravitational force when it is closest to the Sun.

Earth moves the greatest distance in thirty days when it is closest to the Sun.

Earth travels with the slowest tangential speed when it is farthest from the Sun.

Earth sweeps out the same area in the same time frame anywhere in its orbit

Therefore, Earth usually have strongest gravitational force as it moves close to the sun.

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The mass of a soccer ball traveling at a velocity of 50 m/s and has a kinetic energy of 500 J is 0.4kg.

The mass of a soccer ball can be calculated using the following formula:

K.E = ½mv²

Where;

According to this question, a soccer ball is traveling at a velocity of 50 m/s and has a kinetic energy of 500 J. The mass of the kinetic energy is as follows:

500 = ½ × m × 50²

500 = ½ × 2500m

500 = 1250m

m = 500/1250

m = 0.4kg

Therefore, the mass of a soccer ball traveling at a velocity of 50 m/s and has a kinetic energy of 500 J is 0.4kg.

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The statement which best describes the effect of scientific advances on society is that they are inspired by the needs of society. Thus, the correct option for this question is B.

Scientific advancement may be defined as the generation or discovery of knowledge that advances the understanding of science or technology. It is also known as technological advancement. This mechanism stimulates when technologies or applied sciences become more precise, accurate, efficient, or more powerful or capable.

According to the context of this question, scientific advancement allows us to develop new technologies, solve practical problems, and make informed decisions both individually and collectively.

This is because its products are so useful, and the process of science is intertwined with those applications. This proves that it plays a major role in society. New scientific knowledge may lead to new applications.

Therefore, the correct option for this question is B.

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A. The component waves have different frequencies.

Answer:

1. Disagree; inertia is a property of matter to behave this way, not some kind of force.

Explanation:

Newton's first law of motion states that a body will remain in rest or in uniform motion while no external force is applied on it. What makes things to preserve their states of motion in inertia. It can be easy to understand remembering that the mass of the objects is the measure of their inertia. Since the mass is a property of matter so is the inertia.

To calculate the acceleration of the elevator, we can use Newton's second law, Fnet = ma, where Fnet is the net force acting on the person and m is the mass of the person. The acceleration of the elevator is equal to 0.34 times the person's weight divided by the person's mass.

When the elevator starts to move, the scale briefly reads only 0.66 of the person's regular weight. To calculate the acceleration of the elevator, we can use Newton's second law, Fnet = ma, where Fnet is the net force acting on the person and m is the mass of the person. In this case, the net force is equal to the difference between the weight of the person and the scale reading, so we have Fnet = w - Fs. The scale reading is given as 0.66 of the person's weight, so Fs = 0.66w. Plugging this into the equation, we get Fnet = w - 0.66w = 0.34w. Since Fnet = ma, we can write 0.34w = ma. Dividing both sides by the mass, we get a = 0.34w/m. Therefore, the acceleration of the elevator is equal to 0.34 times the person's weight divided by the person's mass.

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Final answer:

The best way to remember kinematics for your physics exam is to follow a step-by-step approach, including examining the situation, identifying knowns and unknowns, and using appropriate kinematic equations.

Explanation:

Steps to Remember Kinematics for a Physics Exam:

Examine the situation to determine the physical principles involved.

Identify the knowns and unknowns in the problem.

Find an appropriate kinematic equation(s) to solve the problem.

For example, if time is not given, you can use the kinematic equation that does not involve time.

Remember to draw a simple sketch of the situation and assign positive/negative directions.

Practice applying these steps to different kinematic problems to improve your understanding and retention.

Answer:

The more energy a wave carries the higher its amplitude.

Explanation:

The energy of a wave is defined by the equation:

[tex]E=\frac{1}{2} m\omega^2 A^2[/tex]

Where [tex]E[/tex] is energy, [tex]m[/tex] is mass, [tex]\omega[/tex] is angular velocity, and [tex]A[/tex] is amplitude.

The previous equation indicates that the energy is directly proportional to the amplitude; if the energy of a wave increases so does the amplitude, and if the energy of a wave decreases the amplitude also decreases.

Thus the answer is:

The more energy a wave carries the higher its amplitude.

10 m/s² to the left.

Given:

Question:

What the acceleration of the bear is?

This is the case for implementing Newton's second law, i.e., 'the resultant force is proportional to the acceleration'. If we also use SI units then 'the resultant force is equal to the product of the mass and the acceleration'.

[tex]\boxed{\boxed{ \ F_{net} = m \cdot a \ }}[/tex]

Let's calculate the net force.

Referring to the horizontal axis marked a positive to the right, then

[tex]\boxed{ \ F_{net} = 15 - 17 = - 2 \ N \ }[/tex]

A negative sign indicates that the bear is moving to the left.

We continue to calculate the bear's acceleration. Remember, the mass that is applied is the mass of the bear that is accelerating.

[tex]\boxed{ \ F_{net} = m \cdot a \rightarrow a = \frac{F_{net}}{m_{bear}} \ }[/tex]

[tex]\boxed{ \ a = \frac{2 \ kg.ms^{-2}}{0.2 \ ms^{-2}} \ }[/tex]

Thus, the magnitude and direction of the acceleration is [tex]\boxed{\boxed{ \ a = 10 \ m/s^2 \ to \ the \ left \ }}[/tex]

Keywords: two children, a 200 g stuffed bear, the 25 kg boy pulls to the right, a 15 n force, the 20 kg girl, left, a 17 n, what the acceleration, newton's second law, the magnitude and direction

The acceleration of the bear is [tex]\boxed{10{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}}[/tex] and its direction of motion is towards left side.

Further explanation:

The net force acting on the bear is equal to the difference between force applied by the girl on the bear and force applied by boy on the bear.

Given:

The mass of the bear is [tex]200{\text{ g}}[/tex].

The force applied by the boy on the bear, towards right side, is [tex]15{\text{ N}}[/tex].

The force applied by the girl on the bear, towards left side, is [tex]17{\text{ N}}[/tex].

The mass of the boy is [tex]25{\text{ kg}}[/tex].

The mass of the girl is [tex]20{\text{ kg}}[/tex].

Formula and concept used:

From the Newton’s law of motion,

[tex]\sum F=ma[/tex]  

Here, [tex]\sum F[/tex] is the net force acting on the object, [tex]m[/tex] is the mass of object  and [tex]a[/tex] is the acceleration.

The weight of the boy and the girl will not affect the net force applied by them on the bear.

The net force applied on the bear is equal to the difference between force applied by the girl and force applied by the boy because the forces applied by the boy and girl are parallel to each other but opposite in the direction.

Therefore, from the vector law, the resultant of the parallel vectors acting  opposite in direction is equal to the difference between their magnitudes.  The direction of the resultant can be specified as the direction of the vector on larger magnitude.

The expression for the net force on the bear is:

[tex]\boxed{ma={F_g} - {F_b}}[/tex]                                                                            …… (1)

Here, [tex]{F_g}[/tex] is the force applied by the girl, [tex]{F_b}[/tex] is the force applied by the boy, [tex]m[/tex] is the mass of bear  and [tex]a[/tex] is the acceleration of the bear.

Thus, the acceleration of the bear is [tex]\boxed{10{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}}[/tex] and its direction of motion is towards left side.

Calculation:

Substitute the value of [tex]{F_g}[/tex], [tex]{F_b}[/tex] and [tex]m[/tex] in equation (1).

[tex]\begin{aligned}\frac{{200}}{{1000}}a&=17 - 15 \\0.2a&=2 \\a&=10{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}} \\ \end{aligned}[/tex]

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Answer detail:

Grade: College

Subject: Physics

Chapter: Dynamics of motion

Keywords:

Two children fighting, force on the bear, acceleration, newton's law, boy, girl, pulling bear towards left, 10m/s2, 10m/s^2, 10.0m/s2 , 10.0m/s^2, mass, net force, weight, magnitude and direction.

Final answer:

A person with a near point of 56.6cm is farsighted and needs convex lenses to correct their vision.

A person with a far point of 56.6cm is nearsighted and requires diverging lenses.

Explanation:

To correct for vision where a person has a near point of 56.6cm, they are likely farsighted. Farsightedness is corrected using convex lenses that converge the light before it hits the eye. This increases the eye's focusing power to bring nearby objects into clear vision.

For a person with a far point of 56.6cm, they are suffering from myopia, or nearsightedness. They require diverging lenses, typically negative diopter lenses, to spread out the light before it reaches the eye. This extends the far point of their vision, allowing them to see distant objects more clearly.

If the eyeglasses are held 1.50 cm from the eyes, we would need to consider the vertex distance in the lens formula to calculate the required lens power. The formula to determine the lens power needed, in diopters (D), is 1/f, where f is the focal length in meters. Since the eyeglasses are not in direct contact with the eye, the formula to find the effective focal length f' when considering vertex distance d is f' = f - d.

The rocket’s acceleration is [tex]21m/s^2[/tex]

Acceleration is the rate of change of the velocity of an object with respect to time. Acceleration is vector quantities as it has both magnitude and direction.

It is given by

[tex]a = \frac{v_f-v_0}{t}[/tex]

Where,

[tex]a =[/tex] average acceleration

[tex]v_f=[/tex] final velocity

[tex]v_0=[/tex] starting velocity

[tex]t =[/tex] elapsed time

The force acting on an object perpendicular to the surface is called thrust. It is vector quantity and SI Unit of thrust is Newton.

[tex]\mathbf{T}=\mathbf{v} \frac{\mathrm{d} m}{\mathrm{d} t}[/tex]

Where,

[tex]T=[/tex] thrust

[tex]v=[/tex] velocity

[tex]dm=[/tex] change of mass

[tex]dt=[/tex] change in time

Given,

Mass of rocket, [tex]m = 5*10^5Kg[/tex]

Thrust,[tex]T = 1.5*10^7N[/tex]

Air resistance [tex]F_a= 4.5*10^6N[/tex]

The net upward force will be

[tex]F_n= T-F_a\\F_n= 1.5*10^7-4.5*10^6\\F_n= 1.05*10^7N[/tex]

Using

[tex]F = ma\\a = \frac{F}{m}\\a = \frac{1.05*10^7}{5*10^5}\\a = 21 m/s^2[/tex]

Thus the acceleration is [tex]21m/s^2[/tex].

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To calculate the rocket's acceleration, subtract air resistance from the engine's thrust to get the net force and then divide it by the rocket's mass according to Newton's second law. The acceleration is found to be 21 [tex]m/s^2[/tex].

To determine the rocket's acceleration, we must apply Newton's second law of motion, which states that force equals mass times acceleration (F = ma). In this scenario, we have two forces to consider: the rocket engine's thrust and the air resistance acting against it. The net force is calculated by subtracting the air resistance from the engine's thrust.

Firstly, we must find the net force acting on the rocket. To do this, we subtract the air resistance from the thrust:

Net Force = Thrust - Air Resistance
[tex]Net Force = 1.50 X 10^7 N - 4.50 X 10^6 N\\Net Force = 10.5 X 10^6 N[/tex]

Now, using Newton's second law, we set up the equation for acceleration (a = F/m), where F is the net force and m is the mass of the rocket:

Acceleration (a) = Net Force (F) / Mass (m)
[tex]Acceleration (a) = \frac{10.5 X 10^6 N}{5.00 X 10^5 kg}\\Acceleration (a) = 21 \ m/s^2[/tex]

Thus, the acceleration of the rocket is 21 meters per second squared.

The label which belongs in the area marked Z having characteristics as

are producers.

Autotrophs, also called as primary producers are organisms that acquire their energy from sunlight and materials from nonliving sources. Algae, and some bacteria are important autotrophs in running waters.

Heterotrophs obtain energy and materials by taking living or dead plants or animals matter.

Producers create their own food using sunlight and absorb water from the soil.

Thus, the category labelled as producers.

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Answer : The maximum acceleration will be 3.0 [tex] m/sec^{2} [/tex].

Explanation : We can calculate the force using the formula given below;

F = m . a ;

(F - Force; m - mass and a - acceleration);

given in the problem; mass (1) - 1200 kg; acceleration (1) - 4 [tex] m/sec^{2} [/tex]

So, on substituting we get,

F = [tex] m_{1} a_{1} [/tex] = 1200 X 4 = 4800 N; we get F = 4800 N

Now, when mass 400 kg is added then mass (2) will be 1600 kg and acceleration has to be found;

Here, the force remains the same; so it can be equated;

[tex] m_{1} a_{1} [/tex] = [tex] m_{2} a_{2} [/tex];

So, 1200 X 4 = (1200 + 400) x [tex] a_{2} [/tex]

Therefore, the answer will be [tex] a_{2} [/tex] = 3.0 [tex] m/sec^{2} [/tex]

The ball will rise to a maximum height of [tex]\boxed{h=\dfrac{v^2}{2g}}[/tex].

Explanation:

The kinetic energy of a body is the energy associated with the body by virtue of its motion whereas the potential energy of the body is the amount of energy stored in a body by virtue of its position.

The amount of kinetic energy stored in a body is given by:

[tex]\boxed{K=\dfrac{1}{2}mv^2}[/tex]                                                ...... (1)

Here, [tex]K[/tex] is the kinetic energy, [tex]m[/tex] is the mass and [tex]v[/tex] is the speed of the body.

The potential energy stored in a body as it reaches its maximum height is given as:

[tex]\boxed{P=mgh}[/tex]                                                      ...... (2)

Here, [tex]P[/tex] is the potential energy stored, [tex]g[/tex] is the acceleration due to gravity and [tex]h[/tex] is the height attained by the body.

According to the conservation of energy, the energy can neither be created nor destroyed. It can only be converted from one form to another.

[tex]\text{kinetic energy}=\text{potential energy}[/tex]

Substitute the values of kinetic energy and potential energy and simplify the expression for the maximum height.

[tex]\begin{aligned}\dfrac{1}{2}mv^{2}=&mgh_{max}\\h_{max}=&\dfrac{v^2}{2g}\end{aligned}[/tex]

Therefore, the maximum height attained by the ball as it rises up is [tex]\boxed{h_{max}=\dfrac{v^2}{2g}}[/tex].

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Answer Details:

Grade: Senior School

Subject: Physics

Chapter: Conservation of Energy

Keywords:

Ball is launched, ground level, conservation of energy, kinetic, potential energy, motion, maximum height, in contact with hill, vertical height, in terms of v and g.

Using the conservation of energy, the maximum vertical height hmax a ball can reach when launched up a frictionless hill is given by the equation hmax = v²/2g. The ball's initial kinetic energy is converted into potential energy at the maximum height, at which point its speed is momentarily zero.

To determine the maximum vertical height hmax that the ball will reach, we can invoke the law of conservation of energy. This fundamental principle asserts that the total energy of an isolated system remains constant, expressing that energy can be converted from one form to another, but not created or destroyed.

At the initial moment before the launch, the ball has kinetic energy but no potential energy (since it's at ground level). The kinetic energy is given by the formula 1/2mv², where m is mass, and v is initial speed.

At the moment when the ball has climbed to maximum height (hmax), it comes momentarily at rest, so its kinetic energy is zero and all converted to the potential energy. The potential energy at this position is given by m*g*hmax, where g is the acceleration of gravity.

Forming an equation using the law of conservation of energy, we equate the initial kinetic energy and the final potential energy as: 1/2mv² = m*g*hmax. Solving for hmax we have: hmax = v²/2g.

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The normal force on a car traveling inside a vertical circular track differs at the top and bottom. At the top, the normal force is in the same direction as gravity, and at the bottom, it supports the car's weight against gravity plus provides the centripetal force. To find the normal force at the bottom, one must use the equations for circular motion taking into account the gravitational force.

To determine the normal force on the car at the bottom of the track (point A), we must consider that the car is in circular motion, and at the top and bottom of the track, the forces acting on the car are different due to its position relative to the center of the circular path.

At the top of the track, the normal force and the weight of the car both act downwards. Since the car is in circular motion and is not accelerating vertically, the net force must be equal to the centripetal force required to keep the car moving in a circle. This can be represented by the equation N + mg = mv2/r at point B, where N is the normal force, m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car and r is the radius of the circular path.

At the bottom of the track, the normal force acts upwards while the weight of the car acts downwards. The normal force at the bottom must be greater than at the top because it must support the car's weight in addition to providing the centripetal force. So, the equation at point A is N - mg = mv2/r.

From the information provided, we know that the normal force at the top is 6.00 N, the mass of the car is 0.800 kg, and the gravitational acceleration is 9.8 m/s2. By writing out both equations for the normal force at the top and bottom, and substituting the known values, we can solve for the unknown normal force at the bottom of the track.

Answer:

A). The nuclear regulatory commission.

Explanation:

I am taking the test rnn.

Flvs

Momentum is a property of matter related to mass and velocity. It has a directional component, aligning with the velocity of the object. Additionally, it has importance in physics principles and displays wave properties on a subatomic level.

Momentum is a property of matter that is intrinsically connected to both the object's mass and velocity. From the formula of momentum, p=mv, we can see that momentum is directly proportional to mass and also velocity. Thus, the greater an object's mass or the faster it moves, the greater its momentum.

Momentum is a vector quantity, meaning it also has a direction aligning with the velocity of the object. Many concepts in physics such as Newton's second law of motion, can be restated in terms of momentum. Furthermore, momentum conservation is a fundamental principal used to analyze matters from simple collisions to complex particle physics.

Also, on a microscopic scale, momentum is observed to have wave properties that are integral to understanding the behaviours of subatomic particles.

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Answer:

gravity

Explanation: Because when you are jumping

Final answer:

The use of the mnemonic ROY G BIV to remember the colors of the rainbow in the order of wavelength illustrates the concept of color vision in physics.

Explanation:

The use of the mnemonic ROY G BIV to remember the colors of the rainbow in the order of wavelength illustrates the concept of color vision in physics. Visible light consists of different wavelengths, and our eyes perceive these wavelengths as different colors. The mnemonic helps us remember the order of colors in the rainbow from longest to shortest wavelength: red, orange, yellow, green, blue, indigo, and violet.

For example, red light has a longer wavelength than orange light, and violet light has a shorter wavelength than green light. The mnemonic ROY G BIV is a helpful tool for remembering this sequence of colors and their corresponding wavelengths.

ΔU = -Wint

Consdier the work of of interaction is W =m*g*h - equation -1

and the Potential energy U.

Final Potential energy Uf =0 , And the Initial Potential Energy Ui =m*g*h

Now we will write the equation for a Change in Potential energy ΔU,

ΔU = Uf - Ui

= 0-m*g*h

  ΔU = -m*g*h --Equation 2

Now compare the both equation

Wint = -ΔU

we can rewrite the above equation

ΔU = -W.

So our Answer is ΔU = -W. .