Final answer:
The force exerted by the toy locomotive on the caboose is 3.08 N, which is calculated by adding the force required to overcome friction and the force necessary for acceleration according to Newton's second law.
Explanation:
To determine the magnitude of the force exerted by the toy locomotive on the caboose, we can use Newton's second law, which states that the force is equal to the mass times the acceleration (F = ma).
However, we also need to account for the frictional force acting on the caboose. The total force required to accelerate the caboose includes the force to overcome friction and the force needed for acceleration:
Step 1: Calculate the force needed to overcome friction, which is already given as 0.48 N.
Step 2: Determine the force needed to accelerate the caboose using the formula F = ma, where m is the mass of the caboose (1.0 kg) and a is the acceleration (2.6 m/s2).
Step 3: Add the force to overcome friction to the force required for acceleration to get the total force exerted by the locomotive on the caboose.
Step 2 in detail: F = ma = 1.0 kg × 2.6 m/s2 = 2.6 N.
Step 3 in detail: The total force exerted by the locomotive on the caboose is 2.6 N (to accelerate) + 0.48 N (to overcome friction) = 3.08 N.
Therefore, the force exerted by the toy locomotive on the caboose is 3.08 N.
What is not a factor that affects the viscosity of magma?
Answer:
Age
Depth
Explanation:
Viscosity is referred to as a measure of a material's resistance to flow
Rise in temperature or heat, burial, exposure to existing magmas, dissolved gases, exposure to mantle plumes, decreasing pressure, and high water content, crystal composition are factors that affect the viscosity of magma;
However, age and depth are two of the factors that do not affect the viscosity of magma/lava
Answer:
The question is incomplete because it lacked the options. These are the options..
a. composition
b. age
c. temperature
d. dissolved gases
Answer is B. Age.
Explanation:
Viscosity is simply described or explained as the resistance to flow.
Magma is known to be the molten rock material under the Earth's crust. It known to come out from the rock or mountain through the vent during volcano eruption.
All the other options except the age, that is , composition, temperature and dissolved gases contribute to the viscosity of the magma.
Magma with higher SiO and, increase in temperature tends to increase viscosity of the magma.
Examine the false statement. Bernoulli's principle indicates that increasing the velocity of a fluid will cause its pressure to increase. Which answer choice rewords the false statement so that it becomes true?
Explanation:
Bernoulli's principle indicates that as the velocity of a fluid increases (liquid or gas) at a certain amount, the pressure of the fluid decreases inside it.Therefore, the given statement is not true. The total mechanical energy of the moving fluid including the gravitational potential energy, the energy-related to the pressure of the fluid and the kinetic energy of the liquid when it is in motion remains constant.The statement can become true by changing 'increase' to 'decrease'. Hence, when the velocity of a fluid increases, its pressure decreases as per Bernoulli's Principle.
Explanation:The false statement can be rewritten to say 'Bernoulli's Principle indicates that an increase in the velocity of a fluid will cause its pressure to decrease.
This principle is utilized in various applications such as the lift on an aircraft wing and the functioning of a curve ball in baseball. It states that, in an inviscid flow of a non-conducting fluid, an increase in the speed of the fluid occurs simultaneously with a decrease in pressure or a decrease in the fluid potential energy.
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What should be the angle of incidence for sunlight on a plane mirror so that the rescue pilot sees the reflected light?
Answer:
The incidence angle is 27°
Explanation:
As the complete question is not given, the complete question is given here
The angle between the Sun and a rescue aircraft is 54 degrees. What should be the angle of incidence for sunlight on a plane mirror so that the rescue pilot sees the reflected light?
From the question, the total angle between the Sun and the aircraft is 54 degrees which is the sum of the incidence and the reflected angle so
[tex]\theta_{total}=\theta_{incidence}+\theta_{reflection}=54[/tex]
Also from the law of reflection
[tex]\theta_{incidence}=\theta_{reflection}[/tex]
So now the equation becomes
[tex]\theta_{total}=\theta_{incidence}+\theta_{reflection}=54\\\theta_{total}=\theta_{incidence}+\theta_{incidence}=54\\2\theta_{incidence}=54\\\theta_{incidence}=27\\[/tex]
So the incidence angle is 27°
The angle of incidence for sunlight on a plane mirror should be set so that the angle of reflection directs the light towards the rescue pilot. The mirror's orientation is crucial, and light reflects at the same angle relative to the normal. Practical adjustments have to be made based on the positions of the sun and pilot.
Explanation:For sunlight to be reflected from a plane mirror to a rescue pilot, the angle of incidence should be such that the angle of reflection directs the light towards the pilot. Since the angle of reflection is equal to the angle of incidence, the mirror must be tilted to reflect the light into the pilot's eyes.
According to the law of reflection, light incident on a mirror will reflect off at the same angle relative to the normal (an imaginary line perpendicular to the surface of the mirror). Hence, for the rescue pilot to see the reflected light, the angle of incidence must be adjusted accordingly based on the position of the sun and the pilot's location in the sky.
It is important to note that if we wish to maximize the reflection towards the pilot, utilizing the mirror's orientation is key. At very high angles of incidence, approaching 90 degrees, almost all the light is reflected, according to physical principles. However, such angles may not be practical when trying to target a specific viewer such as a pilot.
An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.235 V/m imposed along its entire length. The temperature of the wire is 55.0°C. Assume one free electron per atom. Given that at 20 degrees, rhoo = 2.82x10-8 Ωm and α = 3.9x10-3 /C. Determine:
a) the resistivity of the wire.
b) the current density in the wire.
c) the total current in the wire.
d) the potential different that must exist between the ends of a 2m length of wire if the given electric field is to be produced.
Answer with Explanation:
We are given that
Diameter of coil=d=0.115mm
Radius, r=[tex]\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m[/tex]
Using [tex]1mm=10^{-3} m[/tex]
Electric field=E=0.235V/m
T=55 degree C
[tex]T_0=20^{\circ} C[/tex]
[tex]\rho_0=2.82\times 10^{-8}\Omega m[/tex]
[tex]\alpha=3.9\times 10^{-3}/C[/tex]
(a).We know that
[tex]\rho=\rho_0(1+\alpha(T-T_0))[/tex]
Substitute the values
[tex]\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))[/tex]
[tex]\rho=3.2\times 10^{-8}\Omega m[/tex]
(b).Current density,[tex]J=\frac{E}{\rho}[/tex]
Using the formula
[tex]J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2[/tex]
c.Total current,I=JA
Where [tex]A=\pi r^2[/tex]
[tex]\pi=3.14[/tex]
Using the formula
[tex]I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2[/tex]
I=0.076A
d.Length of wire=l=2m
[tex]V=El[/tex]
Substitute the values
[tex]V=0.235\times 2=0.47 V[/tex]
Volume of a Cube The volume V of a cube with sides of length x in. is changing with respect to time. At a certain instant of time, the sides of the cube are 7 in. long and increasing at the rate of 0.2 in./s. How fast is the volume of the cube changing (in cu in/s) at that instant of time?
Answer:
Therefore the volume of cube is change at the 29.4 cube in./s at that instant time.
Explanation:
Formula
[tex]\frac{dx^n}{dx} =nx^{n-1}[/tex]Cube :
The volume of a cube is = [tex]side^3[/tex]
The side of length is x in.
Then volume of the cube is (V) = [tex]x^3[/tex]
∴ V = [tex]x^3[/tex]
Differentiate with respect to t
[tex]\frac{d}{dt}(V)=\frac{d}{dt} (x^3)[/tex]
[tex]\Rightarrow \frac{dV}{dt} =3x^2\frac{dx}{dt}[/tex]....(1)
Given that the side of the cube is increasing at the rate of 0.2 in/s.
i.e [tex]\frac{dx}{dt} = 0.2[/tex] in/s.
And the sides of the cube are 7 in i.e x= 7 in
Putting [tex]\frac{dx}{dt} = 0.2[/tex] and x= 7 in equation (1)
[tex]\therefore \frac{dV}{dt} =3 \times 7^2 \times 0.2[/tex] cube in./s
=29.4 cube in./s
Therefore the volume of cube is change at the 29.4 cube in./s at that instant time.
To find the rate at which the volume of the cube is changing, differentiate the volume formula with respect to time. For a cube with sides of 7 in length growing at 0.2 in/s, the rate of volume change is 6.3 in³/s.
The volume of a cube is determined by the formula V = x³, where x is the length of the side of the cube.
Given that the sides of the cube are 7 in long and increasing at 0.2 in/s, we can calculate how fast the volume is changing by differentiating the volume formula with respect to time. By taking the derivative of V = x³, we find that the rate of change of the volume at that instant of time is 6.3 in³/s.
Handle forces f1 and f2 are applied to the electric drill. Replace this force system by an equivalent resultant force and couple moment acting at point o. Express the results in cartesian vector from.
Answer:
The resultant force is F=6i-j-14k while the resultant Moment is about point O (M_o) is 1.3i +3.3 j -0.45k.
Explanation:
As the complete question is not given, the complete question is attached herewith
The coordinates of the points from the Free-body diagram are given as
0=(0,0,0) m
A=(0.15,0,0.3) m
B=(0,-0.25,0.3) m
the position vector of OA is
roa=(0.15-0)i +(0-0)j +(0.3–0)k
= 0.15i +0j +0.3k
the position vector of OB is
rob =(0-0)i +(-0.25 - 0); +(0.3–0)k
= 0i -0.25j +0.3K
Now
The equivalent resultant force is expressed as,
F = F1+ F2
Substitute 6i - 3j -10k for F1, and 2j -4K for F2.
F =6i -3j -10k +2j - 4k
= 6i - 1j -14k
So the resultant force is F=6i-j-14k.
Resultant couple moment at point O is expressed as,
[tex]M_o=r_{OA}\times F_1+r_{OB}\times F_2\\M_o=\left|\begin{array}{ccc}i&j&k\\0.15&0&0.3\\6&-3&-10\end{array}\right|+\left|\begin{array}{ccc}i&j&k\\0&-0.25&0.3\\0&2&-4\end{array}\right|\\M_o=0.9 i+3.3j-0.45 k+0.4 i+0 j+0k\\M_o=1.3 i+3.3 j-0.45 k[/tex]
The moment of the resultant force about point O (M_o) is 1.3i +3.3 j -0.45k.
If the activation energy for a given compound is found to be 103 kJ/mol, with a frequency factor of 4.0 × 1013 s-1, what is the rate constant for this reaction at 398 K?
Answer: The Rate constant is 1.209
Explanation:
in the attachment
Explanation:
Below is an attachment containing the solution.
You are standing on a cliff that is 75 m above the ocean and you see a ship that is 350 m from the bottom of the cliff. Find the angle of depression from you to the ship.
Answer:
tan 75/350
Explanation:
the cliff is the height 75 and the length is 350 the other side is added to form a triangle . the tan rule is then used.
Narrow belts of high-speed winds that blow in the upper troposphere and lower stratosphere are known as
Explanation:
Jet streams are the winds that flow in the upper levels of the atmosphere.These are relatively narrow bands of strong wind.These high-speed winds blow from west to east in jet streams.Sometimes, the flow of wind shifts from north to south.Jet streams follow the boundaries between hot and cold air.An infinitely long line of charge has linear charge density 5.00 10-12 C/m. A proton (mass 1.67 10-27 kg, charge +1.60 10-19 C) is 18.0 cm from the line and moving directly toward the line at 1.20 103 m/s. How close does the proton get to the line of charge?
Answer: 16.57cm
Explanation:
Given
λ = 5*10^-12C/m
Mass, m = 1.67*10^-27kg
v = 1.2*10^3
Ri = 18cm
K = ?
Rf = ?
K = mv²/2
K = (1.67*10^-27)*(1.2*10^3)²/2
K = 1.2*10^-21J
Recall, Vf - Vi = K/e
Vf - Vi = 1.2*10^-21/1.6*10^-19
Vf - Vi = 7.5*10^-3
Vf - Vi = 0.0075
Also, Vf - Vi = (λ/2πE)[In(Rf/Ri)]
In Rf/Ri = (-0.0075*2*π*8.85*10^-12)/5*10^-12
In Rf/Ri = -0.083
Rf = Ri (exp -0.083)
Rf = 18 (exp -0.083)
Rf = 16.57 cm
the proton gets as close as 16.57cm to the line of charge
To practice Problem-Solving Strategy 21.1 Conservation of energy in charge interactions. An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of −3.45×10−3 V . The charge and the mass of an alpha particle are qα = 3.20×10−19 C and mα = 6.68×10−27 kg , respectively.
Answer:
Explanation:
kinetic energy of alpha particle
= Q X V ( Q is charge on the particle and V is potential difference )
= 3.2 x 10⁻¹⁹ x 3.45 x 10⁻³
= 11.04 x 10⁻²² J
1/2 m v² = 11.04 x 10⁻²²
1/2 x 6.68 x 10⁻²⁷ x v² = 11.04 x 10⁻²²
v² = 3.305 x 10⁵
v = 5.75 x 10² m /s
Final answer:
To find the speed of the alpha particle after it has moved through a potential difference, we can use the conservation of energy. Using the given values for charge and potential difference, we can calculate the speed using the formula for change in kinetic energy. The speed of the alpha particle is approximately 1.91x10^5 m/s.
Explanation:
To find the speed of the alpha particle after it has moved through a potential difference of -3.45x10^-3 V, we can use the conservation of energy.
The potential difference is given by ΔV = qΔV, where q is the charge of the alpha particle and ΔV is the potential difference. Plugging in the values, we get ΔV = (3.20x10^-19 C)(-3.45x10^-3 V).
The change in kinetic energy is given by ΔKE = (1/2)mv^2, where m is the mass of the alpha particle and v is its velocity. Setting ΔV equal to ΔKE, we can solve for v. Plugging in the values, we get (1/2)(6.68x10^-27 kg)v^2 = (3.20x10^-19 C)(-3.45x10^-3 V).
Solving for v, we find that the speed of the alpha particle is approximately 1.91x10^5 m/s.
A series RLC circuit containing a resistance of 12Ω, an inductance of 0.15H and a capacitor of 100uF are connected in series across a 100V, 50Hz supply. Calculate the total circuit impedance, the circuit’s current, and the power factor.
Answer:
Impedance = 19.44ohms
Current = 5.14A
Power factor = 0.62
Explanation:
Impedance in an RLC AC circuit is defined as the total opposition to the flow of current in the resistor, inductor and capacitor.
Impedance Z = √R²+(Xl-Xc)²
Where R is the resistance = 12Ω
Inductance L = 0.15H
Capacitance C = 100uF = 100×10^-6F
Since Xl = 2πfL and Xc = 1/2πfC where f is the frequency.
Xl = 2π×50×0.15
Xl = 15πΩ
Xl = 47.12Ω
Xc = 1/2π×50×100×10^-6
Xc = 100/π Ω
Xc = 31.83Ω
Z =√12²+(47.12-31.83)²
Z = √144+233.78
Z = 19.44Ω
Impedance = 19.44ohms
To calculate the circuit current, we will use the expression V=IZ where V is the supply voltage = 100V
I = V/Z = 100/19.44
I = 5.14Amperes
To calculate the power factor,
Power factor = cos(theta) where;
theta = arctan(Xl-Xc)/R
theta = arctan(47.12-31.83)/12
theta = arctan(15.29/12)
theta = arctan1.27
theta = 51.78°
Power factor = cos51.78°
Power factor = 0.62
Answer:
The circuit impedance [tex]=19.4 \Omega[/tex]
The circuit's current [tex]=5.14 A[/tex]
Circuit Power Factor [tex]=0.62[/tex]
Explanation:
Given:
Resistance [tex]R=12 \Omega[/tex]
Inductance [tex]=0.15H[/tex]
Capacitance [tex]=100uF[/tex]
Voltage [tex]=100V[/tex]
Step 1:
To calculate the inductive reactance, [tex]$X_{L}$[/tex].
[tex]X_{L}=2 \pi f L=2 \pi \times 50 \times 0.15=47.13 \Omega[/tex]
To calculate the Capacitive reactance,
[tex]X_{C}=\frac{1}{2 \pi f C}[/tex]
[tex]=\frac{1}{2 \pi \times 50 \times 100 \times 10^{-6}}[/tex]
[tex]=31.83 \Omega[/tex]
Step 2:
Circuit impedance,
[tex]$$Z=\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}}$$[/tex]
where R is the resistance,
[tex]$$&Z=\sqrt{12^{2}+(47.13-31.83)^{2}}[/tex]
[tex]&Z=\sqrt{144+234}=19.4 \Omega\end{aligned}$$[/tex]
Step 3:
Circuits Current, I
[tex]$I=\frac{V_{S}}{Z}[/tex]
[tex]=\frac{100}{19.4}[/tex]
[tex]=5.14 \ A[/tex]
Step 4:
Voltages across the Circuit, [tex]$\mathrm{V}_{\mathrm{R}}, \mathrm{V}_{\mathrm{L}}, \mathrm{V}_{\mathrm{C}}$[/tex]
[tex]V_{R}=I \times R=5.14 \times 12=61.7$ volts[/tex]
[tex]V_{L}=I \times X_{L}=5.14 \times 47.13=242.2$ volts[/tex]
[tex]V_{C}=\ I \times X_{C}=5.14 \times 31.8=163.5$ volts[/tex]
Step 5:
Circuits Power factor
[tex]$=\frac{R}{Z}=\frac{12}{19.4}=0.619$[/tex]
Therefore,
The circuit impedance [tex]=19.4 \Omega[/tex]
The circuit's current [tex]=5.14\ A[/tex]
Power Factor [tex]=0.62[/tex]
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https://brainly.com/question/15058220https://brainly.com/question/15170590A propeller blade at rest starts to rotate from t = 0 s to t = 5.0 s with a tangential acceleration of the tip of the blade at 3.00 m/s2. The tip of the blade is 1.5 m from the axis of rotation. At t = 5.0 s, what is the total acceleration of the tip of the blade?
Answer:
Explanation:
Given that
Tangential acceleration (at) =3m/s²
The propeller blade starts from rest i.e. wo=0rad/sec
And also the change in time ∆t=5sec
Also radius of blade (r)=1.5m
We have the tangential acceleration, so we need the centripetal acceleration
Which is given as
ac=v²/r
Then we need to get the final velocity using equation of motion
v=u+at
Where (a) is the tangential acceleration = 3m/s²
And the is final time at t=5sec
v=0+3×5
v=0+15
v=15m/s
Then, ac=v²/r
ac=15²/1.5
ac=150m/s²
Then, the total acceleration is given as
a=√(at)²+(ac)²
Since at=3m/s² and ac=150m/s²
Then,
a=√3²+150²
a=√22509
a=150.03m/s²
The total acceleration is 150.03m/s²
A sample of radioactive waste has a half-life of 10 years and an activity level of 2 curies. After how many years will the activity level of this sample be 0.25 curie?
To find out after how many years the activity level of a sample with a half-life of 10 years decreases from 2 curies to 0.25 curie, we calculate that it takes 30 years.
The question asks, "A sample of radioactive waste has a half-life of 10 years and an activity level of 2 curies. After how many years will the activity level of this sample be 0.25 curie?" To solve this problem, we follow the basic principle of half-lives, which states that the amount of a radioactive substance decreases to half its initial amount after one half-life period.
In this example, the activity decreases from 2 curies to 0.25 curies. To go from 2 curies to 1 curie, it takes one half-life (10 years). To go from 1 curie to 0.5 curies takes another half-life (adding up to 20 years in total). Finally, to decrease from 0.5 curies to 0.25 curies requires a third half-life period, adding another 10 years, for a total of 30 years.
Therefore, it will take 30 years for the activity level of the sample to reduce to 0.25 curie.
A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.5 A when an additional 1.6 Ω resistor is added in series with R1. What is the value of R1? Assume the internal resistance of the source of emf is zero. Answer in units of Ω.
Answer:
R1 = 4.8Ω
Explanation:
The loop circuit has an initial voltage of V = IR
I = 2 A , R1 = R
V = 2R1
with the current reduced to 1.5A with an additional 1.6Ω resistor
the total resistance of the circuit is 1.6 + R1
the voltage of the two scenarios has to be equal , since the same voltage flows through the circuit
therefore V = 2R1
from Ohms law V = IR
2R1= 1.5 (1.6 + R1)
2R1 = 2.4 + 1.5R1
collecting like terms
2R1 - 1.5R1 = 2.4
0.5R1 = 2.4
R1 = [tex]\frac{2.4}{0.5}[/tex]
R1 = 4.8Ω
Answer:
4.8 Ω
Explanation:
From Ohm's Law,
Using,
I = E/(R+r)................. Equation 1
E = I(R+r)................. Equation 2
Where I = current, E = emf, R = external resistance, r = internal resistance
Given: I = 2 A, R = R1, r = 0 Ω
Substitute into equation 2
E = 2(R1)
E = 2R1.
When an additional 1.6 Ω resistor is added in series,
E = 1.5(R1+1.6)
2R1 = 1.5R1+2.4
2R1-1.5R1 = 2.4
0.5R1 = 2.4
R1 = 2.4/0.5
R1 = 4.8 Ω
A box of mass m = 17.5 kg is pulled up a ramp that is inclined at an angle θ = 23.0 ∘ angle with respect to the horizontal. The coefficient of kinetic friction between the box and the ramp is μ k = 0.295 , and the rope pulling the box is parallel to the ramp. If the box accelerates up the ramp at a rate of a = 2.29 m/s 2 , calculate the tension F T in the rope. Use g = 9.81 m/s 2 for the acceleration due to gravity.
Answer:
T = 153.77 [N]
Explanation:
To solve this type of problems, we must make a free body diagram, with the forces acting on the box. Then performing a sum of forces on the Y axis equal to zero we can find the value of the normal force. After finding the friction force, we performed a sum of forces equal to the product of mass by acceleration (newton's second law). We can find the T-Force value.
To calculate the tension in the rope, we can use Newton's second law. Using the given values of mass, angle, coefficient of kinetic friction, and acceleration, we can set up an equation and solve for FT. The tension in the rope is approximately 173.5 N.
Explanation:To calculate the tension in the rope, we can use Newton's second law. The only external forces acting on the mass are its weight and the tension in the rope. Using the given information, we can set up the equation FT - mgsinθ - μkmgcosθ = ma, where FT is the tension, m is the mass, θ is the angle, μk is the coefficient of kinetic friction, a is the acceleration, and g is the acceleration due to gravity.
Substituting the given values, we have FT - (17.5 kg)(9.81 m/s2)sin(23.0°) - (0.295)(17.5 kg)(9.81 m/s2)cos(23.0°) = (17.5 kg)(2.29 m/s2).
Solving for FT, we find that the tension in the rope is approximately 173.5 N.
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Chang drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 12 hours. When Chang drove home, there was no traffic and the trip only took 8 hours. If his average rate was 20 miles per hour faster on the trip home, how far away does Chang live from the mountains?
Answer:
Chang live 480 miles from the mountains
Explanation:
Constant Speed Motion
An object is said to have constant speed if it takes the same time t to travel the same distances x. The speed is calculated as
[tex]\displaystyle v=\frac{x}{t}[/tex]
From that equation, we can solve for x
[tex]x=v\cdot t[/tex]
and for t
[tex]\displaystyle t=\frac{x}{v}[/tex]
Let's assume the distance from the mountains and Chang's house is x. We know he took t1=12 hours in heavy traffic at an average speed v1, thus we can set
[tex]x=v_1\cdot t_1[/tex]
In his way back home Chang took t2=8 hours at a speed v2, thus:
[tex]x=v_2\cdot t_2[/tex]
Since the distance is the same
[tex]v_1\cdot t_1=v_2\cdot t_2[/tex]
The speed back is 20 mph more than the speed to the mountain:
[tex]v_2=v_1+20[/tex]
Replacing in the above equation
[tex]v_1\cdot t_1=(v_1+20)\cdot t_2[/tex]
[tex]v_1\cdot t_1=v_1\cdot t_2+20\cdot t_2[/tex]
[tex]v_1\cdot 12=v_1\cdot 8+20\cdot 8[/tex]
Solving for v1
[tex]v_1\cdot 4=160[/tex]
[tex]v_1=40\ mph[/tex]
Now we can compute the value of x
[tex]x=40\cdot 12[/tex]
[tex]\boxed{x=480 \ miles}[/tex]
Chang lives 480 miles from the mountains
Kalb Enterprises is trying to develop a good brand name for its revolutionary accounting software program. They turn to an external consultant to help them. The consultant gives them a list of characteristics of a "good" brand name. Which characteristic would NOT be on their list
Answer:
The correct answer is Can be pronounced in many ways.
Explanation:
Typically a consultant is hired to solve a major business problem, carry out a major change and increase sales. The consultant, with experience of other companies, with methodology resources listens to the client's need, - the current situation and design an effective plan to implement, thus creating a positive impact on the business in a short time.
Light is incident on the surface of a metal. If the wavelength of the incident photons becomes smaller, the maximum kinetic energy of the photoelectrons emitted from the surface __________
Answer:
Light is incident on the surface of a metal. If the wavelength of the incident photons becomes smaller, the maximum kinetic energy of the photo electrons emitted from the surface ___will decrease_______
Explanation:
when light is incident on the surface of a metal and electrons are emitted from the surface due to heating is called photoelectric effect.
Einstein proposed the statement that light has a particle nature which exist in the form of small small packets known as photons.
He said that when light is incident on the surface of a metal then electrons are emitted due to head=ting effect of the surface and electrons emitted are called photo electrons.
This theory of photoelectric effect states that energy of photo electrons is directly proportional to amplitude of the light and it's frequency. That's why if wavelength/amplitude of incident photons becomes smaller then the maximum kinetic energy of photo electrons emitted from the surface will decrease
How high does a rocket have to go above the Earth’s surface so that its weight is reduced to 58.8 % of its weight at the Earth’s surface? The radius of the Earth is 6380 km and the universal gravitational constant is 6.67 × 10−11 N · m 2 /kg2 . Answer in units of km
Final answer:
To determine the height a rocket needs to go above the Earth's surface so that its weight is reduced to 58.8% of its weight at the Earth's surface, we can use the concept of gravitational force.
Explanation:
To determine the height a rocket needs to go above the Earth's surface so that its weight is reduced to 58.8% of its weight at the Earth's surface, we can use the concept of gravitational force. The force of gravity between two objects is given by the equation: F = (G * m1 * m2) / r^2, where G is the universal gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the objects. We can set up a ratio of the weight of the rocket at a certain height to its weight at the Earth's surface:
Weight at height / Weight at surface = (G * m1 * m2) / (r + h)^2 / (G * m1 * m2) / r^2
By substituting the given values, such as the radius of the Earth and the weight reduction percentage, we can solve for h, which represents the height the rocket needs to reach. The final answer should be in units of kilometers, which can be obtained by converting the radius of the Earth from meters to kilometers.
A wheel of radius 0.4 m rotates with a constant angular velocity of 50 rad/s. What are the magnitudes of the tangential velocity
Answer:
Therefore the magnitude of tangential velocity is 20 m/s.
Explanation:
Tangential velocity:The tangential velocity is the straight line velocity of at any point of rotating object.
It is denoted by [tex]v_t[/tex]
[tex]v_t= \omega r[/tex]
ω= angular velocity
r = radius of rotating object.
Angular velocity: Angular velocity is ratio of angle to time.
Here ω= 50 rad/s and r = 0.4 m
Tangential velocity=(50 ×0.4)m/s
=20 m/s
Therefore the magnitude of tangential velocity is 20 m/s.
What is the term that describes how a plant responds to gravity
Answer:
The term is geotropism (also known as gravitropism)
The spacing between two closely spaced oppositely charged parallel plates is decreased. What happens to the electrostatic potential difference between the plates, assuming they form an isolated system: (a) it increases, (b) it decreases, (c) it stays the same, or (d) you can’t tell from the information given?
Explanation:
If the spacing between two closely spaced oppositely charged parallel plates is decreased the electrostatic potential difference between the plates will decrease. An electrostatic potential that is also referred to as the electric field potential or potential drop is the amount of work required to replace a unit of charge from a reference point to a specific point inside the electric field without any change in acceleration. Therefore, if the distance will decrease between oppositely charged plates there will be more affinity to attract which will reduce the amount of work done thus decreasing the electric potential∴ The Correct option is (b)
A 360-N child is in a swing that is attached to a pair of ropes 1.90 m long. Find the gravitational potential energy of the child–Earth system relative to the child's lowest position at the following times.
Answer:
684J
Explanation:
So basically the formula for gravitational potential energy is Mass X Gravity X height. That is G.p.e = mgh
We don't have the mass but since we have the height, we multiply directly with the height since the quantity of weight is already given.
so G.p.e = 360 X 1.9 = 684J
Note that; The answer is in joules because g.p.e is work done.
Hope that was helpful!!
Is it easier to balance a long rod with a mass attached to it when the mass is closer to your hand or when the mass is farther away?
Answer:
Yes, It is easier to balance a long rod with a mass attached to it when the mass is farther from your hand.
Explanation:
There it is illustrated how we can hold a long rod while the hand is further away from the surface.
Rotational inertia depends on whether the mass is closer to or further to the rotation point.
The more the mass is, the greater the acceleration of the rotation.
The explanation for this is that the mass variance is directly proportional to the roational inertia height.
When the mass attached to a long rod is closer to your hand, the rod is easier to balance. This is because the center of gravity and mass concentration is closer to the axis of rotation, which reduces the force needed to maintain balance.
Explanation:In the context of balancing a long rod with a mass attached to it, it's crucial to consider the concept of the center of gravity, and moment of inertia. The center of gravity is the point at which the weight of an object is concentrated. When the mass is closer to your hand, the center of gravity is also closer, making the rod easier to balance as less torque-force is required.
This is analogous to two people carrying a load – whoever is closer to the center of gravity carries more of the weight, making it easier for them. Furthermore, the moment of inertia, a measure of an object's resistance to changes to its rotation, also plays a role. Objects with their mass concentrated closer to the axis of rotation have a lower moment of inertia and are thus easier to rotate or balance. This is reflective of the rod's behavior – when the mass is closer to your hand (essentially the axis of rotation), balancing it becomes easier.
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A proton with charge 1.602 x 10^-19 C moves at a speed of 300 m/s in a magnetic field at an angle of 65 degrees. If the strength of the magnetic field is 19 T, what would be the magnitude of the force the charge experiences? (1 point) 8.28 x 10^-16 N 13.78 x 10^-15 N 5.09 x 10^-14 N 7.75 x 10^-17 N Where are the magnetic field lines of a permanent magnet the strongest? (1 point) Near both the North and South Poles In the center of the magnet Far away from the North Pole Far away from the South Pole Look at the picture of a positive charge moving in a magnetic field. Using the right hand rule, which direction will the force be that the charge experiences? (1 point) The force will be pointing to the left of the positive charge The force will be into the screen, pointing away from you The force will be out of the screen, pointing towards you The force will be pointing to the right of the positive charge An alpha particle travelling at 2155 m/s enters a magnetic field of strength 12.2 T. The particle is moving horizontally and the magnetic field is vertical. If an alpha particle contains two protons, each with a charge of 1.602 x 10^-19 C and the particle has a mass of 6.64 x 10^-22 kg, what is the radius of the circular path the particle will travel in? (1 point) 0.366 m 0.918 m 0.106 m 0.672 m What is the cyclotron frequency of an electron entering a magnetic field of strength 0.0045 T? The charge of an electron is -1.602 x 10^-19 C and the mass of an electron is 9.31 x 10^-31 kg (1 point) 2.87 x 10^8 Hz 5.19 x 10^7 Hz 1.23 x 10^8 Hz 3.44 x 10^9 Hz If a charged particle is travelling in a helical shape as it moves through a magnetic field, but then the particle gains the opposite charge, what happens to it's travelling path? (1 point) The path remains helical, but it reverses in direction The path changes from helical to a spherical shape The path changes from helical to a triangular shape Nothing happens A conducting loop is placed in a magnetic field. What must be true for there to be a current induced in the loop? (1 point) There must be a source of charge The magnetic field must be changing Potential energy must change into kinetic energy The loop must be surrounded by insulating material A rectanglular loop of length 15 cm and width 8 cm is placed in a horizontal plane. A magnetic field of strength 5.5 T passes through the plane at 18 degrees above the horizontal. What is the flux through the loop? (1 point) 0.018 Tm^2 0.231 Tm^2 0.098 Tm^2 0.063 Tm^2 A conducting coil with 100 loops is placed in a magnetic field. The radius of each loop is 0.075 m. The magnetic field passes through the coil at an angle of 60 degrees. If the magnetic field increases at a rate of 0.250 T/s, what is the emf produced in the coil after 1 second? (1 point) 0.22 V 1.78 V 0.63 V 1.01 V A transformer coil has 20 turns on one end and 200 turns on the other end. An emf of 300 V comes into the 20 turn end. How much emf comes out of the 200 turn end of the transformer? (1 point) 3000 V 6000 V 13000 V 9000 V Describe, in your own words, the Right Hand Rule (3 points) According to Lenz's Law, the induced emf in any conducting wire will always be in what direction? Hint: How does the induced emf relate to the changing magnetic field? (3 points) Name at least two circumstances in which a charge will NOT experience a force from a magnetic field. Assume both the charge and field are strong enough to sense each other (2 points) According to Faraday's Law, given a loop of wire in a magnetic field, what two possible things can change to change the flux through the wire? (2 points) Briefly describe how an electromagnet works (3 points)
Answer:
did you get the answer?
Explanation:
Answer:
did you get anything?
Explanation:
Suppose there was a star with a parallax angle of 1 arcsecond. How far away would it be?
Answer: 3.26 light years
Explanation:
Each star has a parallax of one arcsecond at a distance of one parsec, which is equivalent to 3.26 light years.
so the parallax of 1 arcsecond will be at a distance of 1/1 × 3.26 light years
A star with a Parallax Angle of 1 arcsecond is 1 parsec or about 3.26 light-years away. This method of determining star distance is fundamental in astronomy.
The distance of a star from us can be determined using its parallax angle.
The unit of measurement is the parsec, which stands for 'parallax-second'.
If a star has a parallax angle of one arcsecond (which is essentially a measurement of the angular shift in the star's position due to the Earth's orbit around the Sun), it's defined to be 1 parsec away from us.
A parallax angle of 1 arcsecond, therefore, means that the star is 1 parsec away.
Because 1 parsec equals 3.26 light-years, such a star would actually be about 3.26 light-years distant from Earth.
This method of calculating the distance of stars using their parallax angles was revolutionized by the Hipparcos spacecraft and is critical in the field of astronomy.
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You are a crane operator using a wrecking ball to demolish an old building. You can choose to use a 100-kg ball or a 150-kg ball. Answer the questions in terms of momentum and it's properties.
Answer:
The answer to the question is
The two balls, although of different masses, could be made to have the same demolishing force by setting the velocity of the 100 kg ball to 1.5 times the velocity of the 150 kg ball.
That is if V₁ is the velocity of the 150 kg ball and V₂ is the velocity of the 100 kg ball then V₂ = 1.5×V₁ for the demolishing effect of the two balls to be equal.
Explanation:
To answer the we are required to explain the meaning of momentum and state its properties
Momentum is a physical property of an object in motion. It indicates the amount of motion inherent in the object. An object in motion is said to have momentum
The types of momentum possessed by an object can be classified into either
1, Linear momentum or
2. Angular momentum
An object moving with a velocity, v has linear momentum while a spinning object has an angular momentum
The momentum is given by the formula
P = m × V
Where m = mass and
V = velocity
Newtons second law of motion states that, the force acting on an object is equivalent to the rate of change of momentum produced and acting in the direction of the force
Properties of momentum
From the above statements it means that the two balls can be made equivalent by having the appropriate amount of speed. That iis the two balls can have the same momentum thus for equal momentum effect, we have
150 kg × V₁ = 100 kg × V₂
or V₂ = 1.5×V₁
A woman is sitting on a spinning seat of a piano stool with her arms folded. Ignore any friction in the spinning stool. What happens to her angular velocity and angular momentum when she extends her arms outward?
Answer:
The angular velocity of the woman will decrease when she extends her arms outwards.
Explanation:
We know that the angular momentum of a body is the product of its angular velocity and the moment of inertia.
So, mathematically:
[tex]L=I.\omega[/tex]
where:
[tex]I=[/tex] moment of inertia (second moment of mass that depends upon the radial distance of the mass from the center of rotation)
[tex]\omega=[/tex] angular velocity
When the woman extends her arms she increases the radial distance of her mass form the axis of rotation thus increasing the moment of inertia of her body. As the angular momentum in this case remains constant so proportionately the angular velocity of her body increases.
[tex]I'\times \omega'=I\times \omega[/tex]
The angular velocity will increase and angular momentum remains constant, when she extends her arms outward.
The given problem is based on the concept of angular momentum. The angular momentum of a body is the product of its angular velocity and the moment of inertia. So, mathematically:
[tex]L = I \times \omega[/tex]
Here,
I is the moment of inertia.
[tex]\omega[/tex] is the angular velocity.
Note: - The moment of inertia (I) depends on the radial distance and mass of object.
So in the given problem, when the woman extends her arms she increases the radial distance of her mass and form the axis of rotation. Thereby increasing the moment of inertia of her body. As the angular momentum in this case remains constant so proportionately the angular velocity of her body increases.
Thus, we can conclude that the angular velocity increases and angular momentum remains constant, when she extends her arms outward.
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Which molecules of the adaptive defense system provide humoral immunity by circulating freely in the blood and lymph
Answer: Antibody molecules
Explanation:
The immune system is categorised into two functional systems:
-Innate (natural) immune system and
-Acquired (adoptive) immune system.
The acquired immune system plays a major role against all the microbes capable of producing diseases and they are classified into two namely: Humoral and cell mediated immunity. The humoral immunity involves the B cells and the production of antibodies which are specific to invading antigens of disease causing organisms.
Antibodies are molecules of the adaptive defence system that provides humoral immunity by circulating freely in the blood and lymph.