Answer:
10.28571 hp
Explanation:
[tex]W_{shaft}[/tex] = Shaft output power = 104 hp
[tex]\eta[/tex] = Average efficiency = 91%
Electric work done rate is given by
[tex]W_{el}=\dfrac{W_{shaft}}{\eta}[/tex]
The rate of heat supply is given by
[tex]Q=W_{el}-W_{shaft}\\\Rightarrow Q=W_{shaft}(\dfrac{1}{\eta}-1)\\\Rightarrow Q=104(\dfrac{1}{0.91}-1)\\\Rightarrow Q=10.28571\ hp[/tex]
The heat supply by the motor to the engine compartment at full load is 10.28571 hp
Geographic Information Systems consists of a system of satellites that orbit the earth on precisely paths, broadcasting highly accurate time and location information is known as:_______
Answer: Global Positioning System (GPS)
Explanation:
Geographic Information Systems consists of a system of satellites that orbit the earth on precisely paths, broadcasting highly accurate time and location information is known as Global Positioning System (GPS). The Global Positioning System consists of various satellites that orbit the Earth and make it possible for people with ground receivers to pinpoint their geographic location. The signals also allow the electronic receiver to calculate the current local time to high precision, which allows time synchronisation.
Integration Management, one of the 10 PMBOK Guide Knowledge Areas, represents the processes and activities to identify, define, combine, unify, and coordinate the various processes and project management activities. True or false?
Answer: TRUE
Explanation: INTEGRATION MANAGEMENT is one of the ten PROJECT MANAGEMENT BODY OF KNOWLEDGE (PMBOK) guide knowledge area can be defined as coordinating responsibilities,resources(financial or non-financial), stakeholders(project team and end users) and any other project aspects. Integration management also involves conflicts resolution between different units of a project, making prudent and best decision between competing activities or needs and analysing the resources available to ensure that it meets the required specifications.
A nerve signal is transmitted through a neuron when an excess of Na+ ions suddenly enters the axon, a long cylindrical part of the neuron. Axons are approximately 10.0 μm in diameter, and measurements show that about 5.60×1011 Na+ions per meter (each of charge +e) enter during this process. Although the axon is a long cylinder, the charge does not all enter everywhere at the same time. A plausible model would be a series of nearly point charges moving along the axon. Let us look at a 0.100 mm length of the axon and model it as a point charge.
1) What electric field (magnitude and direction) does the sudden influx of charge produce at the surface of the body if the axon is 5.00 cm below the skin? Note that distance to the skin is much greater than the length of the charged axon so that the axon charge is effectiely point-like.,
2) If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a 0.100 mm length of the axon? Answer in C
3) the field is directed away from the axon or the field is directed into the axon
The electric field produced at the surface of the body due to the sudden influx of charge in the axon can be calculated using Coulomb's law. If the charge that enters each meter of the axon is distributed uniformly along it, the total charge that enters a 0.100 mm length of the axon can be calculated. The electric field produced by the influx of Na+ ions is directed away from the axon.
Explanation:1) The electric field produced at the surface of the body due to the sudden influx of charge in the axon can be calculated using Coulomb's law. The formula for electric field is E = k * (Q / r^2), where k is the electrostatic constant, Q is the charge, and r is the distance. By substituting the given values, we can find the magnitude and direction of the electric field.
2) If the charge that enters each meter of the axon is distributed uniformly along it, we can calculate the total charge that enters a 0.100 mm length of the axon by multiplying the charge per meter by the length in meters.
3) Since the excess of Na+ ions enter the axon, the electric field produced by them will be directed away from the axon.
Learn more about Electric field here:https://brainly.com/question/8971780
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On the scale of the cosmic calendar, in which the history of the universe is compressed to 1 year, how long has human civilization (i.e., since ancient Egypt) existed?
A. About half the year
B. About a month about a month about a month
C. A few hours
D. A few seconds
E. Less than a millionth of a second
Answer:
D. A few seconds
Explanation:
Cosmic Calendar is a way of visualizing the history/timeline of the whole universe in just one year. It starts with Big Bang happening on January 1st midnight. The current moment is taken on the December 31st just before the midnight. Every second on this calendar accounts for around 435 years.
The earliest remains of life are thought to have surfaced on September 14. The primitive humans arrived at 22:24 on December 31st. The ancient Egyptian civilization arrived only at 23:59:48 on December 31st. So seen at a cosmic scale the human civilization is just 12 seconds old.
An electric dipole is formed from two charges, , spaced 1.0 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (x,y) = (0,10) in cm is 360 N/C. a. Calculate the dipole moment and charge q. b. Calculate the electric field strength at the point (x,y) = (10, 0) in cm.
Answer:
q = 3.703*10^-9
dipole moment = 3.703*10^-11
E @ (10,0) = 331.977 N/C
Explanation:
Given:
Coordinates
+ q = (0,-0.5) cm
- q = (0,0.5) cm
E = 360 N/C @ (0,10)
Solution:
[tex]Electric Field Strength @ (0,10) = \frac{k*q}{R^2}\\[/tex]
Note: +q (away from charge) and -q (towards the charge)
[tex]E = k*q*(\frac{1}{R^2_{1}} - \frac{1}{R^2_{2} })\\ 360 = (9*10^9)*q*(\frac{1}{0.095^2} - \frac{1}{0.105^2 })\\\\q =1.99 *10^-9[/tex]
Dipole moment = q.(space between two charges)
= (3.703*10^-9 * 0.01)
= 3.703*10^-11
Electric Field Strength @ (10,0)
[tex]E = 2*k*q*(\frac{1}{R^2})*cos(Q)\\ \\Q = arctan(\frac{10}{0.5}) = 87.138 degrees\\R = \sqrt{10^2 + 0.5^2} = 10.01249 cm\\E = 2* (9*10^9)*(3.703*10^-9)*\frac{cos (87.138)}{0.1001249^2}\\E = 331.977 N/C[/tex]
Answer:
a. dipole moment = 2.003 × 10⁻¹³ Cm, charge = 2.003 × 10⁻¹¹ C b. 8.96 N/C
Explanation:
a. The electric field due to a dipole is given by
E = p/2πεy³ where p = dipole moment and y = distance of dipole to point of electric field = 10 cm = 0.10 m. E = electric field strength at (0,10) = 360 N/C
So, E = p/2πεy³
p = 2πεy³E = 2π × 8.854 × 10⁻¹² × (0.10 m)³ × 360 N/C = 2.003 × 10⁻¹³ Cm
Also, p = qd where q = charge and d = distance of charges apart = 1.0 cm = 0.01 m
q = p/d = 2.003 × 10⁻¹³ Cm/0.01 m = 2.003 × 10⁻¹¹ C
b. The electric field at point (10,0)
E = qx/[πε√(d² + 4x²)]³ which is the electric field at an axis perpendicular to the dipole where x = 10 cm = 0.10 m
E = 2.003 × 10⁻¹¹ C × 0.10/π × 8.854 × 10⁻¹²√(0.01² + 4×(0.1)²)³ = 8.96 N/C.
An object is released from rest on a planetthat has no atmosphere. The object fallsfreely for 2.03 m in the first second.What is the magnitude of the accelerationdue to gravity on the planet?
Answer:
4.06 m/s
Explanation:
It's pretty easy
since it has no atmosphere, so there won't be air/wind resistance that will slow it down.
Distance = ut + (1/2) g t^2
Distance = 2.03
U = initial velocity = 0
t = time = 1sec
g = x
2.03 = x(1^2)/2
4.06 = x
x = g = 4.06.
A dragster and driver together have mass891.3 kg.The dragster, starting from rest,attains a speed of 25.2 m/s in 0.62 s.Find the average acceleration of the drag-ster during this time interval.
Answer:
40.645 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s². Mathematically,
a = (v-u)/t................................. Equation 1
Where a = acceleration, v = velocity, u = initial velocity, t = time.
Given: v = 25.2 m/s, u = 0 m/s, t = 0.62 s.
Substituting into equation 1
a = (25.2-0)/0.62
a = 25.2/0.62
a = 40.645 m/s²
Hence the average acceleration of the drag-star = 40.645 m/s²
An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remainder of the race. Find the runner's speed (in m/s) at the following times.
Answer:
The runner's speed at the following times would remain 8.64 m/s.
Explanation:
Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.
In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.
First equation of motion: Vf = Vi + a×t
Vf stands for final velocity
Vi stands for initial velocity
a stands for acceleration
t stands for time
In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.
The acceleration (a) is given as 2.4 m/s²
The time (t) is given as 3.6 s
Now put the values of Vi, a and t in first equation of motion
Vf = Vi + a×t
Vf = 0 + 2.4×3.6
Vf = 2.4×3.6
Vf = 8.64 m/s
So,the runner's speed at the following times would remain 8.64 m/s.
In the equation: v3 *t/A where v is the speed, t is the time and A is the area. Which of the following represents the dimensions of the result. Select one: a. length*time b. length2 /time c. length/time2 d. 1/time
Answer:
option C
Explanation:
given,
[tex] \dfrac{v^3t}{A}[/tex]
where v is the speed
t is the time
A is the area
we know v = m/s
dimension of v = [LT⁻¹]
v³ = [L³ T⁻³]
t = s
dimension of t = [T]
unit of area = m²
dimension of A = [L²]
dimension of the given equation
[tex]\dfrac{v^3t}{A}= \dfrac{[L^3T^{-3}][T]}{[L^2]}[/tex]
[tex]\dfrac{v^3t}{A}= \dfrac{[L]}{[T^2]}[/tex]
=[tex]\dfrac{Length}{time^2}[/tex]
hence, the correct answer is option C
Final answer:
In the equation [tex]v^3[/tex] * t / A, where v is speed, t is time, and A is the area, the result has the dimensions of length/time squared (L/[tex]T^2[/tex]), which represents an acceleration. The correct answer is c. [tex]length/time^2[/tex].
Explanation:
The equation given is [tex]v^3[/tex] * t / A. To determine the dimensions of the result, we need to assess each variable's dimensional formula. The velocity (v) has the dimension of length/time (L/T). Time (t) is already in the dimension of time (T). The area (A) has the dimension of length squared ([tex]L^2[/tex]).
Combining these, we have the dimensions for velocity cubed as [tex](L/T)^3[/tex], which gives us [tex]L^3/T^3[/tex]. This is multiplied by the time (T), resulting in [tex]L^3/T^2[/tex]. When we divide this by the area ([tex]L^2[/tex]), the result simplifies to L/T, which is the dimension of velocity. However, because we are dividing by area and not velocity, the final dimension is L/[tex]T^2[/tex], which is option c: [tex]length/time^2[/tex].
What is the length of the shadow cast on the vertical screen by your 10.0 cm hand if it is held at an angle of θ=30.0∘ above horizontal?
Answer:
Length of shadow cast by hand= 5.0 cm
Explanation:
With the hand inclined at an angle θ=30.0∘ above horizontal, it can be imagined to form part of a right angled triangle that has the following parts
vertical screen=vertical part of the triangle where we cast the shadow of the hand
The hand=the hypotenuse side
The horizontal = side to which the hand makes the 30.0° angle
By trigonometric relationship
Sin θ°= Opposite/hypotenuse
Sin θ° = (Shadow cast by hand)/(Length of hand)
Sin 30° = ( length of shadow cast by hand)/10cm
or 0.5 = (length of shadow cast by hand)/10cm
Length of shadow cast by hand= 0.5 × 10cm = 5.0 cm
A motorcycle, which has an initial linear speed of 6.3 m/s, decelerates to a speed of 1.9 m/s in 4.6 s. Each wheel has a radius of 0.68 m and is rotating in a counterclockwise (positive) direction.a) the constant angular acceleration (in rad/s2) andb) the angular displacement (in rad) of each wheel?
Answer:
Explanation:
Given
initial velocity of motorcycle [tex]u=6.3\ m/s[/tex]
final velocity [tex]v=1.9\ m/s[/tex]
time taken [tex]t=4.6\ s[/tex]
radius of wheel [tex]r=0.68\ m[/tex]
using v=u+at
where a=acceleration
[tex]1.9=6.3+a\times 4.6[/tex]
[tex]a=-0.956\ m/s^2[/tex]
angular acceleration [tex]\alpha =\frac{a}{r}[/tex]
[tex]\alpha =\frac{-0.956}{0.68}=-1.406\ rad/s^2[/tex]
[tex]Displacement=average\ velocity\times time[/tex]
[tex]Displacement=\frac{u+v}{2}\times t[/tex]
[tex]Displacement=\frac{1.9+6.3}{2}\times 4.6=18.86\ m[/tex]
Angular displacement [tex]\theta =\frac{Linear\ displacement}{radius}[/tex]
Angular displacement [tex]\theta =\frac{18.86}{0.68}=27.73\ rad[/tex]
Answer:
Explanation:
initial velocity, u = 6.3 m/s
final speed, v = 1.9 m/s
time, t = 4.6 s
radius, r = 0.68 m
(a)
initial angular velocity, ωo = u / r = 6.3 / 0.68 = 9.26 rad/s
final angular velocity, ω = v / r = 1.9 / 0.68 = 2.79 rad/s
Let α be the angular acceleration
Use first equation of motion
ω = ωo + αt
2.79 = 9.26 + α x 4.6
α = - 1.41 rad/s²
(b) Let Ф be the angular displacement
Use third equation of motion
ω² = ωo² + 2 αФ
2.79² = 9.26² - 2 x 1.41 x Ф
Ф = 27.6 rad
Wo baseballs are fired into a pile of hay. If one has twice the speed of the other, how much farther does the faster baseball penetrate?
Answer:
Explanation:
Given
Two baseballs are fired into a pile of hay such that one has twice the speed of the other.
suppose u is the velocity of first baseball
so velocity of second ball is 2u
suppose [tex]d_1[/tex] and [tex]d_2[/tex] are the penetration by first and second ball
using [tex]v^2-u^2=2 ad[/tex]
where v=final velocity
u=initial velocity
a=acceleration
d=displacement
here v=0 because ball finally stops
[tex]0-u^2=2ad_1----1[/tex]
for second ball
[tex]0-(2u)^2=2ad_2----2[/tex]
divide 1 and 2 we get
[tex]\frac{u^2}{4u^2}=\frac{d_1}{d_2}[/tex]
as deceleration provided by pile will be same
[tex]\frac{1}{4}=\frac{d_1}{d_2}[/tex]
[tex]d_2=4d_1[/tex]
thus faster ball penetrates 4 times of first ball
Final answer:
The faster baseball will penetrate farther into the pile of hay due to the greater change in kinetic energy caused by its higher speed.
Explanation:
In this scenario, we can analyze the problem using the concept of work and energy. When the slower baseball and the faster baseball are both fired into the pile of hay, the work done by air resistance on each baseball will be different. The work done by air resistance is equal to the change in kinetic energy of the baseball. Since the faster baseball has twice the speed of the slower baseball, it will experience a greater change in kinetic energy and therefore penetrate farther into the pile of hay.
You are in a spaceship moving in a straight line at constant speed. You cannot see out of the ship. Assuming perfectly uniform motion, what can you do to prove you are moving?
Answer:
There is no experiment to prove that you are in motion
Explanation:
A frame of reference which has constant velocity is known as an inertial frame of reference. Motion is relative. One can detect one's motion only when one observes change in position with respect to a fixed body.
Thus, if you are in a spaceship moving at a constant speed in a straight line and unable to look outside, you would not be able to prove that you are moving. Everything within the spaceship would have same speed. If you will throw any object within the spaceship, then the parameters measured by you would also not show that the spaceship is in motion.
The resistance to the motion of electrons through different types of materals is n decreasing order, dry so·most so uderground water, and ron ore. How can this knowledge and the measurement of the charge reaching the detector per unit time help identity what type of material is under Check all that apply.
a. More electrons will reach the detector from iron than from dry soil.
b. The electrons reaching the detector are affected very little by what's under the surface.
c. The detector will get more electric charge if the resistance to flow is less, and resistance is related to the type of material
d. The electrons reaching the detector will carry water with them if water is under the surface
Answer:
a and d
Explanation:
The ground's resistance is influenced by the form of substances under the earth. Other materials like metals have far less resistance and more electrical conductivity. Therefore more electrons will enter the detectors in the earth that has iron. Therefore, choice a and d is are correct.
Final answer:
Electrons passing through various materials to reach a detector are influenced by the resistance and resistivity of those materials. Iron ore, which has lower resistance, allows more electrons to reach the detector compared to dry soil or underground water. Thus, by measuring the charge reaching the detector per unit time, one can infer the type of material based on the known resistivity of different materials.
Explanation:
The question you've asked relates to how the measurement of electric current reaching a detector can be used to identify the type of material underground by considering the effect of materials' resistance on the flow of electrons. To answer the question, we need to understand some key principles:
Resistance is a measure of how much a material impedes the flow of charge.
The resistance to the flow of electrons through materials is in the decreasing order of dry soil, underground water, and iron ore, meaning iron ore has the lowest resistance among them.
Resistivity of materials affects the quantity of charge reaching the detector per unit time. The lower the resistivity, the higher the conductivity, and thus more charge will reach the detector because there is less opposition to the flow.
Now, evaluating the statements given:
(a) More electrons will reach the detector from iron than from dry soil. This is true because iron ore has a lower resistance compared to dry soil.
(b) The electrons reaching the detector are affected very little by what's under the surface. This is not true; the material significantly affects the electron flow.
(c) The detector will get more electric charge if the resistance to flow is less, and resistance is related to the type of material. This is a correct statement and aligns with the principles of conductivity.
(d) The electrons reaching the detector will carry water with them if water is under the surface. This statement is false, as electrons do not carry water with them.
Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 seconds. Compute the power developed by the student.
Answer:
140 watt
Explanation:
We are given that
Force applied by student ,F=28 N
Weight pulled by students=70 N
Displacement,s=15 m
Time=3 s
We have to find the power developed by the student.
Work done=w=[tex]F\times s[/tex]
Work done by the student=[tex]28\times 15=420 J[/tex]
Power=[tex]\frac{work\;done}{time}[/tex]
Using the formula
Power=[tex]\frac{420}{3}=140watt[/tex]
Hence, the power developed by the students=140 watt
To determine the power developed by the student pulling the weight, we use the equation P = Fv, with a force of 28.0 N and a velocity of 5.0 m/s, which yields a power of 140.0 Watts.
Explanation:To calculate the power developed by the student pulling the weight, we can use the formula for power when the force is applied along the direction of the displacement: P = Fv, where P is power, F is force, and v is velocity. Power is the rate at which work is done or energy is transferred over time. In this case, the student does work by applying a force to pull the weight across the tabletop.
The student pulls the weight for a distance of 15.0 meters in 3.0 seconds, which means the velocity (v) of the weight is v = distance/time = 15.0 m / 3.0 s = 5.0 m/s. We are given the force (F) as 28.0 Newtons. Therefore, the power (P) developed by the student is:
P = Fv = 28.0 N × 5.0 m/s = 140.0 Watts.
A 0.5 kg ball is dropped from rest at a point 1.2m above the floor. The ball rebounds straight upward to a height of 0.7m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor.
Answer:
4.281 kgm/s upward
Explanation:
Impulse:This can be defined product of force and time. The S.I unit of impulse is Ns.
From Newton's second law of motion,
Impulse = Change in momentum.
I = mΔv....................... Equation 1.
Where m = mass of the ball, Δv = change in velocity of the ball
and Δv = v -u
Where u = velocity of the ball before it hit the floor, v = velocity of the ball after if hit the floor
I = m(v-u) -------------- Equation 2
But
the initial kinetic energy of the ball = potential energy at the initial height (1.2 m above)
1/2mu² = mgh₁
Where h₁ = initial height. or height of the ball before collision
making u the subject of the equation,
u = √(2gh₁)........................ Equation 3
Where h₁ = 1.2 m g = 9.81 m/s²
Substitute into equation 3
u = √(2×1.2×9.81)
u =√(23.544)
u = -4.852 m/s.
Note: u is negative because the ball was moving downward at the first instance.
Similarly,
v = √(2gh₂)............................. Equation 3
h₂ = height of the ball after collision
Given: h₂ = 0.7 m, g = 9.81 m/s²
Substitute into equation
v = √(2×9.81×0.7)
v = √13.734
v = 3.71 m/s.
Also given: m = 0.5 kg,
Substituting into equation 2
I = 0.5(3.71-(4.852)
I = 0.5(8.562)
I = 4.281 kgm/s. Upward.
Thus the impulse = 4.281 kgm/s upward
A spaceship is traveling toward Earth while giving off a constant radio signal with a wavelength of 1 meter (m). What will the signal look like to people on Earth?
Answer:
Less than 1 m
Explanation:
When objects are getting closer to each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the blue shift of waves. Here, the wavelength reduces.
In the opposite case the when objects are getting farther from each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the red shift. Here, the wavelength increases.
In this case the spaceship is getting close to Earth hence the wavelength will be lower than 1 m.
Explaining how a radio signal from a spaceship appears redshifted to observers on Earth.
Redshift: When a spaceship traveling towards Earth emits a radio signal with a wavelength of 1 meter, it will appear redshifted to people on Earth, meaning the wavelength will increase due to the Doppler effect caused by the relative motion between the spaceship and Earth.
Doppler Effect: This change in wavelength can help observers determine the speed and direction of the spaceship based on how much the signal is redshifted.
Frequency and Wavelength: As the signal travels towards Earth, its wavelength will change, affecting how it is perceived by observers on Earth in terms of frequency and color.
A circular-motion addict of mass 90 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.3 m/s. (a) What is the period of the motion?
Answer:
9.97sec
Explanation:
To solve for the period we can derive the formula as follows
ω=2πf
ω=2π/T
v=rω
v=2πr/T
T=2πr/v
[tex]T=\frac{2*3.142*10}{6.3}[/tex]
T=9.97sec
Four parallel-plate capacitors are constructed using square plates, and each has a dielectric inserted between the plates.?
Rank the capacitance of each capacitor in order from highest to lowest.
A = side length (L/2) ; distance between plates (d) ; dielectric current (k)
B = side length (L) ; distance between plates (d/2) ; dielectric current (4k)
C = side length (2L) ; distance between plates (d) ; dielectric current (2k)
D = side length (L) ; distance between plates (2d) ; dielectric current (2k)
Final answer:
The capacitance of the parallel-plate capacitors can be ranked from highest to lowest as follows: C, A, B, D.
Explanation:
The capacitance of a parallel-plate capacitor depends on the area of the plates (A) and the distance between them (d). The larger the area of the plates, the greater the charge they can store, so the capacitance is greater for a larger A. Similarly, the closer the plates are together, the stronger the attraction between the charges, so the capacitance is greater for a smaller d.
Based on this information, we can rank the capacitance of each capacitor:
Capacitor C: It has the largest side length and the same distance between plates as capacitor A, so it will have the highest capacitance.Capacitor A: It has a smaller side length and the same distance between plates as capacitor B, so it will have a lower capacitance than C, but higher than B and D.Capacitor B: It has a larger side length and half the distance between plates compared to capacitor A, so it will have a lower capacitance than A and C, but higher than D.Capacitor D: It has the smallest side length and double the distance between plates compared to capacitor A, so it will have the lowest capacitance.In solar thermal electric generation, the sun’s energy is concentrated by ___ to heat the fluid in a pipe that is used to generate electricity.
Answer:
Mirrors
Explanation:
In Solar thermal power generation system, mirrors are used to collect and focus sunlight onto a fluid pipe to produce high temperature required to generate electricity.
There are two main components: mirrors capture and focus light onto a receiver. The heat transfer fluid is circulated in the receiver. Steam is produced which is converted to mechanical energy in a turbine. It powers a generator and electricity is produced.
In solar thermal electric generation, concave mirrors are used to concentrate sunlight onto a pipe in a system known as a parabolic trough. The heat is transferred via heat exchanger to produce steam, which generates electricity through a steam turbine-generator setup.
In solar thermal electric generation, the sun's energy is concentrated by concave mirrors or reflectors to heat the fluid in a pipe that is used to generate electricity. These mirrors are often part of a system known as a parabolic trough or concentrating collector, which has the approximate shape of a section of a cylinder, specifically one-quarter of a full cylinder. The mirrors focus sunlight onto a blackened pipe containing a special fluid.
Once this fluid is heated, it is then pumped through a heat exchanger where its thermal energy is transferred to water to produce steam. This steam drives a turbine connected to a generator, producing electricity through a conventional steam cycle. This entire process is a part of larger solar thermal power plants, which utilize solar collectors with two components: mirrors to collect and focus sunlight, and a receiver to collect the heat transferred to the fluid.
A 430 g soccer ball lying on the ground is kicked and flies off at 25 m/s. If the duration of the impact was .01 s, what was the average force acting on the ball?
Explanation:
Force is given by rate of change of momentum.
Mass of soccer ball = 430 g = 0.43 kg
Initial velocity = 0 m/s
Final velocity = 25 m/s
Change in momentum = 0.43 x 25 - 0.43 x 0
Change in momentum = 10.75 kg m/s
Time taken = 0.01 s
Rate of change of momentum = Change in momentum ÷ Time
Rate of change of momentum = 10.75 ÷ 0.01
Rate of change of momentum = 1075 N
Force = 1075 N
The average force acting on the ball is 1075 N in the direction of travel of ball.
A 12-kg lead brick falls from a height of 1.9 m. (c) The brick falls onto a carpet, 2.0 cm thick. Assuming the force stopping it is constant, find the average force the carpet exerts on the brick.
Answer:
F = -11199.63 N
Explanation:
given,
mass of the brick = 12 Kg
height of the fall, h = 1.9 m
thickness of the carpet = 2 cm = 0.02 m
average force = ?
velocity of brick just before hitting mat
[tex] v = \sqrt{2gh}[/tex]
[tex]v =\sqrt{2\times 9.81\times 1.9}[/tex]
v = 6.11 m/s
velocity of brick just before hitting ground= 6.11 m/s
final velocity = 0 m/s
using equation of motion for acceleration calculation.
v² = u² + 2 a s
0² = 6.11² + 2x a x 0.02
[tex]a = -\dfrac{6.11^2}{0.04}[/tex]
a =-933.3025 m/s²
now, average force is equal to
F = m a
F = 12 x (-933.3025)
F = -11199.63 N
negative sign represent the decelerating force.
The positions of a satellite in elliptical orbit are indicated. Rank these quantities from greatest to least: Gravitational Force A) Speed B ) KE C) PE D) momentum
Answer:
A,B,C,D,E
Explanation: Ranking the quantities from greatest to least, we have:
A.) Gravitational Force
B) Speed
C) KE
D) PE
E) momentum
The gravitational force is the greatest at periapsis and the least at apoapsis. The speed of the satellite orbits is greatest at periapsis and the least at apoapsis. The potential energy is highest at apoapsis and lowest at periapsis, while the kinetic energy is highest at periapsis and lowest at apoapsis.
The gravitational force is the greatest when the satellite is closest to the large mass (periapsis) and the force is the least when the satellite is farthest away (apoapsis).
The speed of the satellite is greatest at periapsis and least at apoapsis. This is because the gravitational force is strongest at periapsis, causing the satellite to accelerate and increase its speed.
The potential energy (PE) is highest when the satellite is farthest away (apoapsis) and lowest when the satellite is closest to the large mass (periapsis). The kinetic energy (KE) is highest when the satellite is closest to the large mass (periapsis) and lowest when the satellite is farthest away (apoapsis).
The momentum of the satellite remains constant throughout the elliptical orbit.
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You are not harmed by contact with a charged metal ball, even though its voltage may be very high. Is the reason similar to why you are not harmed by the hotter- than-1000°C sparks from a fireworks sparkler?
Final answer:
You are not harmed by a charged metal ball or by fireworks sparks because the actual exposure (amount of charge and duration for the ball, and size and duration for the sparks) is insufficient to cause injury.
Explanation:
The reason you are not harmed by contact with a charged metal ball, even if its voltage may be very high, is similar to why you are not harmed by the hotter-than-1000°C sparks from a fireworks sparkler. In both cases, it is the amount of charge and the duration of the contact that determine the danger of the electric shock, not just the voltage alone. For the metal ball, even though the voltage is very high, the resulting current is usually very low because the charge moves to the outer surface and is quickly neutralized by surrounding materials. Consequently, the exposure to the charge is so brief that it doesn't cause harm. Similarly, with the sparks from a sparkler, they may be extremely hot, but they are small and lose their heat quickly upon contact with the skin, so they don't transfer enough energy to cause a burn.
Humans require organ systems to carry out life processes. Single-celled organisms do not have organ systems and yet they are able to carry out life processes. This is because
Human organ systems lack the organelles found in single-celled organisms
A human cell is more efficient than the cell of a single-celled organism
It is not necessary for single-celled organisms to maintain homeostasis
Organelles present in single-celled organisms act in a manner similar to organ systems
Answer: is Organelles present in single-celled organisms act in a manner similar to organ systems
Explanation:
Multicellular organisms organ system play a critical role for the smooth functioning of whole body. Millions of cells combined to make an organism. The role of organ system in whole body is to provides oxygen and nutrients to the cells and eliminates the toxic material such as carbon dioxide. Organ systems like, respiratory system, digestion system, and cardiovascular play an important role in the human body to perform various functions for its survival.
Unlike multicellular organisms the unicellular only consists of single cell e.g. prokaryotic organisms and eukaryotic organisms namely, Amoeba, Euglena, salmonella, Fungi etc. Single celled organisms are able to carry out all processes mandatory for the sustenance of life with the help of single cell only e.g. respiration and digestion.They can survive with the help of single cell. Unlike multicellular organisms unicellular do not require multiple number of cell for its survival.
Organelles present in single-celled organisms act very similar to organ systems in multicellular organisms.
Organelles:
They are the small bio-molecular system that carry out the vital processes inside a cell.
For example-
Mitochondria produce energy in the cell.Nucleus is the information center that run the whole cell like a human brain.Lysosomes digest the objects inside the cell, work as digestive system inside the body.Therefore, organelles present in single-celled organisms act very similar to organ systems in multicellular organisms.
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Multicellular organisms
organ system play a critical role for the smooth functioning of whole body. Millions of cells combined to make an organism. The role of organ system in whole body is to provides oxygen and nutrients to the cells and eliminates the toxic material such as carbon dioxide. Organ systems like, respiratory system, digestion system, and cardiovascular play an important role in the human body to perform various functions for its survival.
Unlike multicellular organisms the unicellular only consists of single cell e.g. prokaryotic organisms and eukaryotic organisms namely, Amoeba, Euglena, salmonella, Fungi etc. Single celled organisms are able to carry out all processes mandatory for the sustenance of life with the help of single cell only e.g. respiration and digestion.They can survive with the help of single cell. Unlike multicellular organisms unicellular do not require multiple number of cell for its survival
If an atom has 13 protons and is currently electrically neutral, what must happen to give the same atom a positive charge of +2e?
The atom must lose 2 electrons
Explanation:
An atom consists of three types of particles:
- Protons, in the nucleus, with positive electric charge [tex]+e[/tex]
- Neutrons, in the nucleus, with no electric charge
- Electrons, orbiting around the nucleus, with negative electric charge [tex]-e[/tex]
As a result, the net electric charge of an atom is given by the number of protons minus the number of electrons:
Q = #p - #e
For a neutral atom, the number of protons and electrons is the same, so the net charge is zero.
In order for an atom to have a positive charge of +2, it means that there must be 2 protons more than the number of electrons. Since atoms exchange electrons (and not protons), this means that the atom must have "lost" 2 electrons.
In this problem, we have an atom with 13 protons: this means that initially it also has 13 electrons. However, later the atom lost 2 electrons, and as a result, the final charge is +2e.
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How high will a 1.30-kg rock go from the point of release if thrown straight up by someone who does 80.0 J of work on it? Neglect air resistance.
Explanation:
The work done on the stone is kinetic energy.
Kinetic energy = 80 J
We have
Kinetic energy = 0.5 x Mass x Velocity²
Mass = 1.30 kg
80 = 0.5 x 1.30 x Velocity²
Velocity = 11.09 m/s
We have equation of motion v² = u² + 2as
Initial velocity, u = 11.09 m/s
Acceleration, a = -9.81 m/s²
Final velocity, v = 0 m/s
Substituting
v² = u² + 2as
0² = 11.09² + 2 x -9.81 x s
s = 6.27 m
Height it will go is 6.27 m
To find the height a 1.30-kg rock will reach when thrown vertically upwards after 80.0 J of work is done on it, convert the work into potential energy and use the formula PE = mgh. The rock will reach a height of about 6.14 meters.
Work-energy principle: The work done on an object when thrown vertically upwards is stored as potential energy at the highest point of the rock's trajectory. In this case, with 80.0 J of work done on a 1.30-kg rock, the rock will reach a height determined by the conversion from work to potential energy.
Calculating the height: By converting the work done into potential energy and using the formula PE = mgh, where PE is the potential energy, m is the mass, g is the acceleration due to gravity (9.81 m/s^2), and h is the height, you can calculate the height the rock will reach.
Answer: The rock will reach a height of approximately 6.14 meters from the point of release.
What is the purpose of family?
How many different types of families currently exist in our society today? What are their differences and similarities? ASAP!!! I'll give you brainliest answer
Answer:
Purpose of family:
Basically main role of a family towards the society is its continuity by both reproduction and interaction with each other. The main contribution of family to the society is society's continuation.
Types of families:
The family further divided into six types nowadays. Namely,
Nuclear FamilySingle ParentExtended FamilyChildless FamilyStep family Grandparent FamilyDefining each Family and their pros and cons :
1). Nuclear Family: The most basic kind of family is nuclear family based on two parents and their biological or adopted children. Number of children is variable, some have one and others have more than one. The main aim of the nuclear family is to up bring their kids and teach them how to socialize in the society.
Pros of nuclear family:
Both parents work and more likely financially stable Children gets more balanced parentingConcerned about educationFocus more on health issues both mental and physicalMore socialize in the societyCons of nuclear family:
Higher level of stress factor due to increased number of dependentsHave higher rates of disputesChildren become egotistical due to over possessive parents2). Single Parent: Consists of either a mother or a father living with one or more than one child. Parents may initially married, separated or departed, or passed away (one of them). Like other family structures single parents also have some pros and cons.
Pros of single parent:
Close relationship with each other due to less family membersMore responsible as duties are not being further divided.Both children and parents are strong and independentCons of single parent:
Less income due to sole parentMay relay on financial helpQuality living may compromise due to sole earningChildren become mentally unstable by living alternatively with parents (in divorced cases).3). Extended Family: Basically extended families are joint families, in which grandparents, parents and children live together to support each other both financially and socially.
Pros of extended family:
More tolerance level among childrenCare and Respects for people older in age is practicedHave emotional supportHave social supportCons of extended family:
Face more financial crises due to large number of members in a familyIntervening in personal matters with each other Low privacy4).Childless Family: Partners who have no any children either by choice or due to infertility.
Pros of childless family:
More financially strongNo one to take care of More free to do basic thing like travelling, shopping and fun activitiesHave more chance to fulfill desired goalCons of childless family:
Develop fear of isolation by the time Society pressure (not having kids)Develop sense of lacking something important (infertile couples)5). Step family:
When two families start living to gather, like two divorced people get married and living together with their children (from 1st partner).
Pros of step family:
Child gets advantage by living with both parentsFinancially stable due to two source of incomesCons of step family:
Feeling of living forcefully with second parentCouple fight often due to each other's children conflictchildren develop leas tolerance6) Grandparent Family: In which grandchildren are raised by their grandparents.
Pros of grandparent family:
Children have strong relationship with their elderlyMore protective environment for childrenCons of grandparent family:
Less financially tableDifficult to raise children due to old age and related health issueBig age gapSimilarities and Differences:
By considering the pros and cons of different family structure we come to the point that many of them have some similarities like financial stability, strong bonding, and more socialization. Likewise there are few differences as well as some families share strong bond while other suffers from isolation. Some are more financially stable and others are less. Some have children while other are childless. Some children have both parents while other have single or step patent. Some of them have high tolerance while other has less. Some live quality life whiles other compromise on their needs and wants.
A rubber ball with a mass of 0.145 kg is dropped from rest. From what height (in m) was the ball dropped, if the magnitude of the ball's momentum is 0.800 kg · m/s just before it lands on the ground?
Answer:
1.55 m
Explanation:
Momentum: This can be defined as the product of mass of a body and it velocity. the S.I unit of momentum is kgm/s.
Mathematically,
Momentum can be represented as,
M = mv................................. Equation 1
Where m = mass of the body, v = velocity of the body, M = momentum.
Making v the subject of the equation,
v = M/m........................................... Equation 2
Given: M = 0.80 kg.m/s, m = 0.145 kg.
Substituting into equation 2,
v = 0.8/0.145
v = 5.52 m/s.
Using the equation of motion,
v² = u² + 2gs ....................... Equation 3.
Where v = final velocity of the rubber ball, u = initial velocity of the rubber ball, s = distance, g = acceleration due to gravity.
Given: v = 5.52 m/s, u = 0 m/s, g = 9.81 m/s².
Substituting into equation 2
5.52² = 0² + 2(9.81)s
30.47 = 19.62s
s = 30.47/19.62
s = 1.55 m.
Thus the ball was dropped from a height of 1.55 m
Intensive properties can be: Select the correct answer below:
1. physical properties
2. chemical properties
3. either physical or chemical properties
4. none of the above answer
Answer: The answer is 3 either physical or chemical properties
Explanation:
because all properties of matter are either physical or chemical
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Intensive properties, which are characteristic of a substance and do not depend on the amount of material, can be either physical or chemical properties. For example, boiling point and density are physical intensive properties, whereas flammability is a chemical intensive property.
Explanation:The correct answer is 3, intensive properties can be either physical or chemical properties. In chemistry, intensive properties are those that do not depend on the amount of the material present. They are characteristic of the substance and help us identify it. Examples of intensive properties include density, boiling point, or color. These can be either physical properties like boiling point and density, which do not alter the chemical composition of the substance, or chemical properties like flammability, which do involve a chemical reaction.
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