6/15=2/c need to solve

Final answer:

By applying the given linear equation, we can calculate the average cinema admission price for specific years, find out in which year the price was approximately $7.88, and predict when it might reach $10.04.

Explanation:

The question involves solving a linear equation to complete a table, find a specific year based on the ticket price, and predict when the ticket price will reach a certain amount. To complete these steps, we apply the equation y=0.28x+5.92, where x represents the number of years after 2003, and y gives the price in dollars.

For a, plug in the values of x (2, 5, 8) into the equation to find y.

For b, set y=7.88 and solve for x (years after 2003) by rearranging the equation.

For c, with a target price of $10.04, use the equation again to solve for x.

When x=2, y=6.48.

When x=5, y=7.32.

When x=8, y=8.16.

For a ticket price of $7.88, solve for x: x =  (7.88 - 5.92) / 0.28 = 7 years after 2003, which is 2010.

To predict when the ticket price reaches $10.04, solve for x: x =  (10.04 - 5.92) / 0.28 = 14.71, rounding to 15 years after 2003, which is 2018.

By setting up and solving a system of two equations based on the problem, we find that the larger country is 86,673 square kilometers in area and the smaller is 86,300 square kilometers.

This problem can be solved by using a system of two equations in two variables. Let's denote areas of two countries as x (for the bigger country) and y (for the smaller country).

The information from the problem provides us with two equations:
1) x + y = 172,973 (since combined area of two countries is 172,973 square kilometers),
2) x - y = 373 (since Country A is larger by 373 square kilometers).

Solving these equations will give the areas of the individual countries. Countries' areas can be found by adding the two equations together to eliminate y, you get 2x = 173,346, so x = 86,673 square kilometers.

Then, you can substitute x into the first equation: 86,673 + y = 172,973, from which y = 172,973 - 86,673 = 86,300 square kilometers.

So, the larger country's area is 86,673 square kilometers and the smaller country's area is 86,300 square kilometers.

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Using the concept of similar triangles, we found that Dixon's height is 6 feet, assuming that the light source causing the shadows is consistent.

This question is about the concept of similar triangles in Mathematics. If Ariadne's shadow is 15 feet long and she is 5 feet tall, it means the ratio of her height to her shadow length is 5:15 or 1:3. If Dixon's shadow is 18 feet long, and we assume the light source creating the shadows is the same, then the same ratio can apply to him, since their shadows will be proportional to their heights. Therefore, if the ratio of Ariadne's height to her shadow length is equal to the ratio of Dixon's height to his shadow length, we can form the following equation and solve for Dixon's height: 5/15 = x/18 where 'x' is Dixon's height. Solving this equation, we find that Dixon's height is 6 feet.

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Answer:

[tex]\displaystyle \int {\frac{sin(x)}{2x}} \, dx = \frac{1}{2}\sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n + 1}}{(2n + 1)^2(2n)!}} + C[/tex]

General Formulas and Concepts:

Calculus

Integration

Sequences

Series

Taylor Polynomials

Power Series

Integration of Power Series:

Step-by-step explanation:

*Note:  

You could derive the Taylor Series for sin(x) using Taylor polynomials differentiation but usually you have to memorize it.

We are given the integral and are trying to find the infinite series of it:

[tex]\displaystyle \int {\frac{sin(x)}{2x}} \, dx[/tex]

We know that the power series for sin(x) is:

[tex]\displaystyle sin(x) = \sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n + 1}}{(2n + 1)!}[/tex]

To find the power series for  [tex]\displaystyle \frac{sin(x)}{2x}[/tex], divide the power series by 2x:

[tex]\displaystyle \frac{sin(x)}{2x} = \sum^{\infty}_{n = 0} \bigg[ \frac{(-1)^nx^{2n + 1}}{(2n + 1)!} \cdot \frac{1}{2x} \bigg][/tex]

Simplifying it, we have:

[tex]\displaystyle \frac{sin(x)}{2x} = \sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n}}{2(2n + 1)!}[/tex]

Rewrite the original integral:

[tex]\displaystyle \int {\frac{sin(x)}{2x}} \, dx = \int {\sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n}}{2(2n + 1)!}} \, dx[/tex]

Integrate the power series:

[tex]\displaystyle \int {\frac{sin(x)}{2x}} \, dx = \sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n + 1}}{2(2n + 1)(2n + 1)!}} + C[/tex]

Simplify the result:

[tex]\displaystyle \int {\frac{sin(x)}{2x}} \, dx = \frac{1}{2}\sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n + 1}}{(2n + 1)^2(2n)!}} + C[/tex]

And we have our final answer.

Topic: AP Calculus BC (Calculus I + II)  

Unit: Power Series

Answer:

152.4 cm

Step-by-step explanation:

Wesly is 5 feet and 3 inches tall. Since there are 12 inches in one foot, 5 feet has 60 inches. This means Wesly is 63 inches tall. If one inch is 2.54 cm then 60(2.54) is Wesly's height in centimeters. 60(2.54) = 152.4

To find tan x/2, given that tan x=3 and x terminates in π < x < (3π/2), we can use the half-angle formula for tangent. The value of tan (x/2) is ±1/√2.

To find tan x/2, given that tan x=3 and x terminates in π < x < (3π/2), we can use the half-angle formula for tangent. The half-angle formula for tangent is tan(x/2) = ±√((1-cosx) / (1+cosx)). Since tan x=3, we need to find the value of cos x first.

Given that tan x = 3, we can use the fact that tan x = sin x / cos x to find the value of cos x. Rearranging the equation, we have cos x = sin x / tan x = 1 / 3. Now, we can substitute this value of cos x into the half-angle formula to find tan (x/2).

tan (x/2) = ±√((1-cos x) / (1+cos x))
tan (x/2) = ±√((1-1/3) / (1+1/3))
tan (x/2) = ±√((2/3) / (4/3))
tan (x/2) = ±√(2/4)
tan (x/2) = ±√(1/2)
tan (x/2) = ±1/√2

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If we modify the number of balls on a display it would alter the number of balls on the other displays based on an underlying mathematical rule or pattern.

The number of balls on the display could potentially represent a mathematical relationship or pattern. If we increase or decrease the number of balls on one display, it would change the number of balls on the other displays in a way that reflects this pattern.

For example, let's assume that the pattern is such that each display has twice the number of balls as the one before it. So if the first display has 1 ball, the second has 2, the third has 4, and so on. If you change the number of balls on the first display to 2, then the number of balls on the 6th display would increase according to the rule, and would become 2^6=64 instead of 1^6=32.

However, the relationship or pattern between the displays would need to be known in order to accurately predict how changing the number of balls on one display would affect the others.

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The equivalent value of the expression k = ( 2F/p )

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

F = ( 1/2 ) kp

On simplifying , we get

Multiply by 2 on both sides , we get

2F = kp

Divide by p on both sides , we get

k = 2F/p

Hence , the expression is k = 2F/p

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the area of the region between the curves [tex]\(y = x\) and \(y = x^2\) for \(x\) in \([-2, 1]\) is \( \frac{29}{6} \)[/tex] square units.

To find the area of the region between the curves [tex]\(y = x\) and \(y = x^2\)[/tex]for x in the interval [-2, 1], we need to set up the integral and integrate with respect to x.

First, let's graph the curves [tex]\(y = x\) and \(y = x^2\) over the interval \([-2, 1]\)[/tex] to visualize the region.

Now, let's find the points of intersection between the curves [tex]\(y = x\) and \(y = x^2\).[/tex]

Setting [tex]\(y = x\) equal to \(y = x^2\)[/tex], we get:

[tex]\[ x = x^2 \][/tex]

[tex]\[ x - x^2 = 0 \][/tex]

[tex]\[ x(1 - x) = 0 \][/tex]

This equation gives us two solutions: x = 0 and x = 1. So, the curves intersect at x = 0 and x = 1.

Now, to find the area of the region between the curves, we integrate the difference of the curves from [tex]\(x = -2\) to \(x = 0\), and from \(x = 0\) to \(x = 1\)[/tex], and then add the absolute value of these results:

[tex]\[ \text{Area} = \int_{-2}^{0} (x - x^2) \, dx + \int_{0}^{1} (x^2 - x) \, dx \][/tex]

Let's solve these integrals separately:

1. [tex]\[ \int_{-2}^{0} (x - x^2) \, dx \][/tex]

[tex]\[ = \left[ \frac{x^2}{2} - \frac{x^3}{3} \right]_{-2}^{0} \][/tex]

[tex]\[ = \left[ \left(\frac{0^2}{2} - \frac{0^3}{3}\right) - \left(\frac{(-2)^2}{2} - \frac{(-2)^3}{3}\right) \right] \][/tex]

[tex]\[ = \left[ 0 - \left(\frac{4}{2} - \frac{-8}{3}\right) \right] \][/tex]

[tex]\[ = \left[ 0 - \left(2 + \frac{8}{3}\right) \right] \][/tex]

[tex]\[ = -2 - \frac{8}{3} \][/tex]

[tex]\[ = -\frac{6}{3} - \frac{8}{3} \][/tex]

[tex]\[ = -\frac{14}{3} \][/tex]

2. [tex]\[ \int_{0}^{1} (x^2 - x) \, dx \][/tex]

[tex]\[ = \left[ \frac{x^3}{3} - \frac{x^2}{2} \right]_{0}^{1} \][/tex]

[tex]\[ = \left[ \left(\frac{1^3}{3} - \frac{1^2}{2}\right) - \left(\frac{0^3}{3} - \frac{0^2}{2}\right) \right] \][/tex]

[tex]\[ = \left[ \left(\frac{1}{3} - \frac{1}{2}\right) - (0 - 0) \right] \][/tex]

[tex]\[ = \left( \frac{1}{3} - \frac{1}{2} \right) \][/tex]

[tex]\[ = \frac{1}{3} - \frac{1}{2} \][/tex]

[tex]\[ = \frac{2}{6} - \frac{3}{6} \][/tex]

[tex]\[ = -\frac{1}{6} \][/tex]

Now, we add the absolute values of these results:

[tex]\[ \text{Area} = \left| -\frac{14}{3} \right| + \left| -\frac{1}{6} \right| \]\\[/tex]

[tex]\[ \text{Area} = \frac{14}{3} + \frac{1}{6} \]\\[/tex]

[tex]\[ \text{Area} = \frac{28}{6} + \frac{1}{6} \]\\[/tex]

[tex]\[ \text{Area} = \frac{29}{6} \][/tex]

Therefore, the area of the region between the curves [tex]\(y = x\) and \(y = x^2\) for \(x\) in \([-2, 1]\) is \( \frac{29}{6} \)[/tex] square units.

The probable question maybe:

What is the area of the region between the curves [tex]\(y = x\) and \(y = x^2\)[/tex]for x in the interval [-2, 1]?

Final answer:

To find the probability of the sum of two dice being greater than 4 given the second die is a 3, first identify the sample space for the first die as {1, 2, 3, 4, 5, 6}. Then, calculate the favorable outcomes where the first die, added to 3, results in a number greater than 4, which are {2, 3, 4, 5, 6}. The probability is 5/6, rounded to approximately 0.8333.

Explanation:

Sample Space and Probability Calculation

When two dice are rolled one after another, and the second die results in a 3, we consider the outcomes of the first die only. As the first die is also a fair, six-sided die with faces numbered from 1 to 6, the sample space for the first die is S = {1, 2, 3, 4, 5, 6}.

The question asks for the probability of the sum being greater than 4 given that the second die is a 3. This means we are looking for the sum to be 5 or more. We can calculate the possible outcomes where the first die, when added to 3, results in a total greater than 4.

Therefore, the outcomes in the sample space that result in a sum greater than 4 are {2, 3, 4, 5, 6}. The probability of this event, given the second die is a 3, is the number of favorable outcomes divided by the total number of possible outcomes of the first die. There are 5 favorable outcomes and 6 possible outcomes, so the probability is 5/6 or approximately 0.8333 when rounded to four decimal places.

To construct the sample space, we need to consider all possible outcomes of rolling two dice. The probability of the sum of the dots on the dice being greater than 4 given that the second die is a 3 is 5/36.

To construct the sample space, we need to consider all possible outcomes of rolling two dice. Since each die has six sides numbered 1 to 6, the sample space will consist of 36 outcomes. We can represent the outcomes as pairs of numbers, where the first number represents the result of the first die and the second number represents the result of the second die. For example, (1, 1) represents both dice landing on 1, (1, 2) represents the first die landing on 1 and the second die landing on 2, and so on.

To determine the probability of the sum of the dots on the dice being greater than 4 given that the second die is a 3, we need to identify the outcomes where the second die is 3 and the sum is greater than 4. These outcomes are (2, 3), (3, 3), (4, 3), (5, 3), and (6, 3). There are a total of 5 outcomes that satisfy these conditions. Since the sample space has 36 outcomes, the probability is 5/36. To find the probability that the sum of the dots on two dice is greater than 4 given the second die is a 3, we list the possible outcomes for the first die as {1, 2, 3, 4, 5, 6}. The favorable outcomes are those that, when added to 3, result in a number greater than 4: {2, 3, 4, 5, 6}. This results in a probability of 5/6.

Answer:

497.2 miles

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

To begin solving this problem we first need to calculate how much gas Tyler has in his jeep after stopping at the gas station. We calculate this by multiplying the total bill by the price per gallon of gas, and then we add the amount that was left in the tank.

[tex](22/1.25)+5 = 22.6gallons[/tex]

After stopping at the gas station Tyler has 22.6 gallons of gas in his jeep. Since he gets 22 miles per gallon we multiply this by the amount of gallons in his car to calculate the distance they can travel.

[tex]\frac{22.miles}{gallon} * 22.6gallons = 497.2miles[/tex]

Tyler and his friends can travel 497.2 miles with the amount of gas they have.

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