Final answer:
The possible locations of the third vertex of the triangle with a perimeter of 12 units, given two vertices at (4, 0) and (8, 0), are (12, 0) and (0, 0). The vertex at (0, 0) will produce a triangle with the largest area equals to 8 square units.
Explanation:
Possible Locations of Third Vertex:
To find the possible locations of the third vertex of the triangle, we need to consider the perimeter of the triangle. Given that the perimeter is 12 units and two vertices are located at (4, 0) and (8, 0), we can deduce that the third vertex must lie on the line segment between these two points.
Calculating the Third Vertex:
Since the distance between the two given vertices is 8 - 4 = 4 units, the remaining distance to achieve a perimeter of 12 units would be 12 - 4 = 8 units.
Therefore, the possible locations of the third vertex are (4 + 8, 0) = (12, 0) or (8 - 8, 0) = (0, 0).
Determining the Largest Area:
To determine which vertex would produce a triangle with the largest area, we need to consider the base and the height of the triangle. Since both the possible vertices lie on the x-axis, the base would be the same for both triangles, which is 4 units.
The height of the triangle can be determined by finding the distance between the base and the y-coordinate of the third vertex. If the third vertex is (12, 0), the height would be 0 units. If the third vertex is (0, 0), the height would be 4 units.
Therefore, the triangle with the third vertex at (0, 0) would produce the largest area, which is equal to 1/2 * base * height = 1/2 * 4 * 4 = 8 square units.
The possible locations of the third vertex of the triangle form a line segment parallel to the x-axis and symmetric about the y-axis, extending from (4, 3) to (8, -3) or from (4, -3) to (8, 3). The triangle with the largest area will be the one where the third vertex is directly above or below the midpoint of the line segment joining the first two vertices, at either (6, 3) or (6, -3).
Given two vertices of a triangle at (4, 0) and (8, 0), the distance between them is the length of the line segment joining them, which is 8 - 4 = 4 units. Since the perimeter of the triangle is 12 units, the sum of the lengths of the other two sides must be 12 - 4 = 8 units.
Let's denote the third vertex as (x, y). The distance from (4, 0) to (x, y) is one side of the triangle, and the distance from (8, 0) to (x, y) is the other side. Using the distance formula, we have:
[tex]\[ \sqrt{(x - 4)^2 + y^2} + \sqrt{(x - 8)^2 + y^2} = 8 \][/tex]
To simplify the problem, we can look for points where the sum of the distances to the two fixed points is 8 units. Since the two given vertices are on the x-axis, the third vertex must be such that its x-coordinate is between 4 and 8 (inclusive) to form a triangle.
For the y-coordinate, we know that the sum of the distances from the third vertex to the two fixed points is 8 units. If we consider the case where y = 0, the third vertex would be on the x-axis, which would not form a triangle. Therefore, y must be non-zero.
Let's consider the two sides of the triangle formed by the third vertex and the two fixed points. The lengths of these sides can be thought of as the radii of two circles, one centered at (4, 0) and the other at (8, 0), both with a radius of 4 units (since each circle's radius is half the sum of the lengths of the two sides not on the x-axis).
The third vertex must lie on the intersection of these two circles. Since the circles are of equal radius and their centers are 4 units apart, they will intersect in two points, which will be equidistant from the line segment joining the first two vertices.
To find these points, we can set up the following system of equations based on the distance formula:
[tex]\[ (x - 4)^2 + y^2 = 16 \][/tex]
[tex]\[ (x - 8)^2 + y^2 = 16 \][/tex]
The line segment joining these two points, (6, 3) and (6, -3), represents all possible locations of the third vertex. This line segment is parallel to the x-axis and symmetric about the y-axis, and it extends from (4, 3) to (8, -3) or from (4, -3) to (8, 3), depending on which side of the x-axis the third vertex is located.
To find the vertex that produces the largest area, we note that for a given base length (which is fixed at 4 units in this case), the area of a triangle is maximized when the height is maximized. The height is maximized when the third vertex is directly above or below the midpoint of the base, which is at (6, 0). Therefore, the third vertex should be at either (6, 3) or (6, -3) to produce the triangle with the largest area. The area of this triangle is 1/2 * base * height = 1/2 * 4 * 3 = 6 square units.
We have found all possible locations of the third vertex because any point outside the line segment joining (6, 3) and (6, -3) would result in a perimeter greater than 12 units, and any point inside would result in a perimeter less than 12 units. Thus, the line segment from (4, 3) to (8, -3) or from (4, -3) to (8, 3) represents the complete set of solutions for the third vertex that satisfy the given perimeter constraint.
PLEASE SHOW WORK PLEASE
Answer:
part 1) [tex]13[/tex]
part 2) [tex]\frac{119}{45}[/tex]
part 3) [tex]2[/tex]
part 4) [tex]\frac{1,958,309}{128}[/tex]
part 5) [tex]4\ yd^2[/tex]
Step-by-step explanation:
The complete question in the attached figure
we know that
Applying PEMDAS
P ----> Parentheses first
E -----> Exponents (Powers and Square Roots, etc.)
MD ----> Multiplication and Division (left-to-right)
AS ----> Addition and Subtraction (left-to-right)
Part 1) we have
[tex]\frac{2}{3}(6)+\frac{3}{4}(12)[/tex]
Remember that when multiply a fraction by a whole number, multiply the numerator of the fraction by the whole number and maintain the same denominator
so
[tex]\frac{12}{3}+\frac{36}{4}[/tex]
[tex]4+9=13[/tex]
Part 2) we have
[tex]2\frac{1}{3}(3\frac{2}{5}:3)[/tex]
Convert mixed number to an improper fraction
[tex]2\frac{1}{3}=2+\frac{1}{3}=\frac{2*3+1}{3}=\frac{7}{3}[/tex]
[tex]3\frac{2}{5}=3+\frac{2}{5}=\frac{3*5+2}{5}=\frac{17}{5}[/tex]
substitute
[tex]\frac{7}{3}(\frac{17}{5}:3)[/tex]
Solve the division in the parenthesis (applying PEMDAS)
[tex]\frac{7}{3}(\frac{17}{15})[/tex]
[tex]\frac{119}{45}[/tex]
Part 3) we have
[tex]\frac{7}{8}:(1\frac{1}{4}:4)[/tex]
Convert mixed number to an improper fraction
[tex]1\frac{1}{4}=1+\frac{1}{4}=\frac{1*4+1}{4}=\frac{5}{4}[/tex]
substitute
[tex]\frac{7}{8}:(\frac{5}{4}:4)[/tex]
Solve the division in the parenthesis (applying PEMDAS)
[tex]\frac{7}{8}:(\frac{5}{16})[/tex]
Multiply in cross
[tex]\frac{80}{40}=2[/tex]
Part 4) we have
[tex]18:(\frac{2}{3})^2+25:(\frac{2}{5})^7[/tex]
exponents first
[tex]18:(\frac{4}{9})+25:(\frac{128}{78,125})[/tex]
Solve the division
[tex](\frac{162}{4})+(\frac{1,953,125}{128})[/tex]
Find the LCD
LCD=128
so
[tex]\frac{32*162+1,953,125}{128}[/tex]
[tex]\frac{1,958,309}{128}[/tex]
Part 5) Find the area of triangle
The area of triangle is equal to
[tex]A=\frac{1}{2}(b)(h)[/tex]
substitute the given values
[tex]A=\frac{1}{2}(6)(1\frac{1}{3})[/tex]
Convert mixed number to an improper fraction
[tex]1\frac{1}{3}=1+\frac{1}{3}=\frac{1*3+1}{3}=\frac{4}{3}[/tex]
substitute
[tex]A=\frac{1}{2}(6)(\frac{4}{3})=4\ yd^2[/tex]
Scura makes sun block and their annual revenues depend on how much they sell. Let x be the quantity of 5 oz. bottles of sun block that they make and sell each year measured in 1000 's of bottles. Thus if x=10 then they make and sell 10000 bottles of sun block each year. If x=25 then they make and sell 25000 bottles of sun block each year.
a. If x=50 how many bottles of sun block does Scura make and sell?
b. What is x equal to if Scura produces and sells 45000 bottles of sunblock?
Answer:
a) 50,000 bottles
b) x = 45
Step-by-step explanation:
We are given the following in the question:
The annual revenue of sun block depends on how much they sell.
Let x be the quantity of 5 oz. bottles of sun block that they make and sell each year measured in 1000 's of bottles.
For x = 10,
10,000 bottles were made and sell each year.
For x = 25,
25,000 bottles of sun block were made and sell each year.
a) x = 50
[tex]\text{Number of bottles} = 50\times 1000 = 50,000[/tex]
Thus, 50,000 bottles of sun block does Scura make and sell.
b) Scura produces and sells 45000 bottles of sunblock
We have to find the value of x
[tex]x = \displaystyle\frac{\text{Number of bottles}}{1000} = \frac{45000}{1000} = 45[/tex]
Thus, x = 45 if Scura produces and sells 45000 bottles of sunblock.
For Scura's Sunblock Sales, if x=50, they sell 50,000 bottles, and when Scura sells 45,000 bottles of sunblock, x equals 45.
Explanation:Answer to Scura's Sunblock Salesa. If x=50, then according to the relationship given where x represents thousands of bottles, Scura makes and sells 50,000 bottles of sun block.
b. To determine what x is equal to when Scura produces and sells 45,000 bottles of sunblock, we take the total number of bottles and divide by 1000, since x is measured in 1000s. So, x=45 when Scura produces and sells 45,000 bottles of sunblock.
You have a right circular cone of height 1530 mm and volume 2.2 x 104 in3 . Calculate the base diameter of the cone.
Answer:
37.35 in
Step-by-step explanation:
The volume of a cone is given by the formula ...
V = (π/3)r²h
where r is the radius of the base and h is the height. We want to find the diameter of the base, so we can rewrite this in terms of diameter and solve for d. Please note that the height is given in millimeters, not inches, so a conversion is necessary.
V = (π/3)(d/2)²h
12V/(πh) = d²
d = 2√(3V/(πh)) = 2√(3(2.2×10^4 in^3)/(π·1530 mm/(25.4 mm/in))
= 2√(1.6764×10^6/(π·1.53×10^3) in^2)
d ≈ 37.35 in
The base diameter of the cone is about 37.35 inches.
The diameter of the base of the cone is found to be approximately 18.28802 inches after substituting the given values into the volume formula for a cone and solving for radius, and then doubling to get diameter.
Explanation:The volume V of a right circular cone is given by the formula V = 1/3πr²h, where r represents the radius of the cone's base and h is the cone's height. The diameter of the base of a cone is double the radius, so we will be solving for diameter instead of radius.
We were given V = 2.2 x 104 in³ and h = 1530 mm. Firstly it is important to note that 1 mm is equal to approximately 0.0393701 in, so h becomes approximately 60.2362205 in. Now we substitute these values into the equation and solve for r as follows: 2.2 x 104 = 1/3πr²*60.2362205. Solving for r we get r = approximately 9.14401 in.
We obtain the diameter by doubling the radius, so the diameter d = 2r = 18.28802 in.
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By the fourth quarter of 2015, U.S. households had accumulated $12.5 trillion in housing equity, which represents about 14 percent of their net worth. What proportion of U.S. households own their home
Answer:
two-thirds
Step-by-step explanation:
In 2015, there was a campaign for the accumulation of households in the United States of America. Most of the citizens tried their best possible to acquire property in terms of buildings and other facilities. In the last quarter of the year, approximately two-thirds of the home in the United States of America were owned by households.
one pound of grapes cost $1.55 which equation correctly shows a pair of equivalent ratios that can be used to find the cost of 3.5 lb of grapes
Answer:
[tex]$ \frac{\textbf{1.55}}{\textbf{1}} \hspace{1mm} \textbf{=} \hspace{1mm} \frac{\textbf{x}}{\textbf{3.5}} $[/tex]
Step-by-step explanation:
Let us assume that the total cost of the grapes = x $.
Given that it costs 1.55 $ for one pound. We are asked to determine how much it would cost for 3.5 pounds.
note that for one pound you pay 1.55 so how much should you pay for 3.5 pounds? Clearly, the cost increases with the increase in weight of the item.
This is equal to [tex]$ \frac{1.55}{1} \times 3.5 = x $[/tex]
[tex]$ \iff \frac{1.55}{1} = \frac{x}{3.5} $[/tex]
Hence, the answer.
The price-demand equation for gasoline is 0.1 x + 4 p = 85 where p is the price per gallon in dollars and x is the daily demand measured in millions of gallons.a. What price should be charged if the demand is 40 million gallons?b. If the price increases by $0.4 by how much does the demand decrease?
Answer:
a. The price that should be charged if the demand is 40 million gallons is $20.25.
b. The demand decreases by 16 millions of gallons.
Step-by-step explanation:
We know that the price-demand equation for gasoline is given by
[tex]0.1 x + 4 p = 85[/tex]
where
p is the price per gallon in dollars and
x is the daily demand measured in millions of gallons.
a. To find what price should be charged if the demand is 40 million gallons you must
Solve for p,
[tex]0.1x\cdot \:10+4p\cdot \:10=85\cdot \:10\\x+40p=850\\40p=850-x\\p=\frac{850-x}{40}[/tex]
We know that the demand is 40 million gallons (x = 40). So,
[tex]p=\frac{850-40}{40}=\frac{81}{4}=20.25[/tex]
b. To find how much does the demand decrease when the price increases by $0.4 you must
Solve for x,
[tex]0.1x\cdot \:10+4p\cdot \:10=85\cdot \:10\\x+40p=850\\x=850-40p[/tex]
We know that the price increases by $0.4. So,
[tex]-40\left(0.4\right)=-16[/tex]
The demand decreases by 16 millions of gallons.
When the demand is 40 million gallons, the price per gallon should be $20.25. The impact of a $0.4 price increase on the demand can be calculated by substitifying p in the equation, solving for x, and subtracting the original x value.
Explanation:The subject of this question is algebra, specifically dealing with the use of equations representing real-world scenarios. In this case, the equation represents price-demand dynamics for gasoline.
a. To find the price that should be charged when the demand is 40 million gallons, substitute x with 40 in the equation, which gives 0.1 * 40 + 4p = 85. By simplifying this, we get 4 + 4p = 85. Further solving for p, we get 4p = 81, therefore p = 81 / 4, which is $20.25 per gallon.
b. When the price increases by $0.4, substitute p with p + 0.4 in the equation. This gives 0.1x + 4(p + 0.4) = 85. Solving this for x, and then subtracting the original x value, gives us the decrease in demand due to the increase in price.
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Find the sample space for the experiment.
A sales representative makes presentations about a product in three homes per day. In each home, there may be a sale (denote by S) or there may be no sale (denote by F).
Answer:
The sample space = {SSS, SSF, SFS, SFF, FSS, FSF, FFS, FFF}
Step-by-step explanation:
When we say sample space, we mean the list of all possible outcome from an event. For this even of sales representative presenting at homes., only two outcome is possible. Whether:
1. the home(s) buys his product (S)
2. the home(s) did not buy his product (F).
Thus from three (3) homes, that will be:
==> [tex]2^{3}[/tex] = 2*2*2 = 8 possible outcomes.
The sample space for the experiment where a sales representative makes presentations at three homes with each home resulting in either a sale (S) or no sale (F) consists of 8 possible outcomes: SSS, SSF, SFS, SFF, FSS, FSF, FFS, and FFF.
Explanation:To find the sample space for the experiment where a sales representative makes presentations about a product in three homes per day, and in each home, there may be a sale (denoted by S) or there may be no sale (denoted by F), we have to consider all the possible outcomes. Each home has two possible outcomes, meaning that the total sample space consists of 23 = 8 possible combinations for the three presentations.
The sample space S can be written as:
SSS (Sale in all three homes)SSF (Sale in the first two homes, no sale in the third)SFS (Sale in the first and third homes, no sale in the second)SFF (Sale in the first home, no sale in the second and third)FSS (No sale in the first home, sale in the second and third)FSF (No sale in the first and third homes, sale in the second)FFS (No sale in the first two homes, sale in the third)FFF (No sale in all three homesEach combination represents one possible outcome for the day's sales presentations.
Find the sample space for the experiment.
You toss a six-sided die twice and record the sum of the results.
Answer:
S ={(1+1=2), (1+2=3), (1+3=4), (1+4=5), (1+5=6), (1+6=7),
(2+1=3), (2+2=4),(2+3=5),(2+4=6),(2+5=7),(2+6=8),
(3+1=4), (3+2=5),(3+3=6),(3+4=7),(3+5=8),(3+6=9),
(4+1=5), (4+2=6),(4+3=7),(4+4=8),(4+5=9),(4+6=10),
(5+1=6), (5+2=7),(5+3=8),(5+4=9),(5+5=10),(5+6=11),
(6+1=7), (6+2=8),(6+3=9),(6+4=10),(6+5=11),(6+6=12)}
Step-by-step explanation:
By definition the sample space of an experiment "is the set of all possible outcomes or results of that experiment".
For the case described here: "Toss a six-sided die twice and record the sum of the results".
Assuming that we have a six sided die with possible values {1,2,3,4,5,6}
The sampling space denoted by S and is given by:
S ={(1+1=2), (1+2=3), (1+3=4), (1+4=5), (1+5=6), (1+6=7),
(2+1=3), (2+2=4),(2+3=5),(2+4=6),(2+5=7),(2+6=8),
(3+1=4), (3+2=5),(3+3=6),(3+4=7),(3+5=8),(3+6=9),
(4+1=5), (4+2=6),(4+3=7),(4+4=8),(4+5=9),(4+6=10),
(5+1=6), (5+2=7),(5+3=8),(5+4=9),(5+5=10),(5+6=11),
(6+1=7), (6+2=8),(6+3=9),(6+4=10),(6+5=11),(6+6=12)}
The possible values for the sum are 2,3,4,5,6,7,8,9,10,11,12
This histogram shows the times, in minutes, required for 25 rats in a animal behavior experiment to successfully navigate a maze. What percentage of the rats navigated the maze in less than 5.5 minutes? 34% 60% 68% 70% 84%
Answer:
The question is lacking the image of the histogram, but the file attachment to this answer contains the complete question and histogram image.
The percentage of the rats that navigated the maze in less than 5.5 minutes is 84%
Step-by-step explanation:
First of all let us compute the total frequency which represents the total number of rats in the experiment.
from the information given in the question, we are told that the total number of rats involved in the experiment are 25 rats and this makes up the total frequency.
To calculate the percentage of rats that navigated the maze in less than 5.5 minutes, you will first of all need to identify the 5.5 minute point on the histogram and add all the frequencies below that point. This gives the total number of rat that navigated in less than 5.5 minutes. These frequencies from 0 to <5.5 are; 3, 8, 6, and 4. And the total is given as the sum of these frequencies shown below:
Total number of rats that navigated in less than 5.5 minutes = 3 + 8 + 6 + 4 = 21. Hence, a total of 21 rats navigated the maze in less than 5.5 minutes.
Now to find the percentage of the number of rats that navigated in less than 5.5 minutes, we have to find out what percentage of 25 (total number of rats) is 21 (number of rats that navigated in less than 5.5 minutes). This is calculated thus:
[tex]\frac{21}{25}[/tex] × 100 = 0.84 × 100 = 84 %.
Therefore 84% of the total number of rats navigated the maze in less than 5.5 minutes in the experiment.
To find the percentage of rats that navigated the maze in less than 5.5 minutes, locate the bar on the histogram that represents that interval and calculate the percentage based on the number of rats in that interval compared to the total number of rats.
Explanation:The histogram shows the times required for 25 rats to navigate a maze. To find the percentage of rats that navigated the maze in less than 5.5 minutes, we need to look at the data on the histogram. The histogram is divided into various time intervals, and the bars represent the number of rats that fall into each interval. You need to locate the bar that corresponds to the interval less than 5.5 minutes and calculate the percentage of rats represented by that bar.
Let's say the bar for the interval less than 5.5 minutes represents 10 rats. To calculate the percentage, we divide the number of rats in that interval (10) by the total number of rats (25) and multiply by 100:
(10/25) x 100 = 40%
Therefore, 40% of the rats navigated the maze in less than 5.5 minutes.
Driving under the influence of alcohol (DUI) is a serious offense. The following data give the ages of a random sample of 50 drivers arrested while driving under the influence of alcohol. This distribution is based on the age distribution of DUI arrests given in the Statistical Abstract of the United States46 16 41 26 22 33 30 22 36 3463 21 26 18 27 24 31 38 26 5531 47 27 43 35 22 64 40 58 2049 37 53 25 29 32 23 49 39 4024 56 30 51 21 45 27 34 47 35(b) Make a frequency table using seven classes.Class Limits... Class Boundaries...Midpoint...Frequency...RelativeFrequency...CumulativeFrequency
Answer:
Explanation below.
Step-by-step explanation:
For this case we have the following dataset:
46, 16, 41, 26, 22 ,33, 30, 22 ,36, 34,
63, 21, 26, 18, 27, 24, 31, 38, 26, 55,
31, 47, 27, 43 ,35, 22 ,64,40, 58, 20,
49, 37, 53, 25, 29, 32, 23, 49, 39, 40,
24, 56, 30, 51, 21, 45, 27, 34, 47, 35
So we have 50 values. The first step on this case would be order the dataset on increasing way and we got:
16, 18, 20, 21, 21, 22, 22, 22, 23, 24,
24, 25, 26, 26, 26, 27, 27, 27, 29, 30
30, 31, 31, 32, 33, 34, 34, 35, 35, 36,
37, 38, 39, 40, 40, 41, 43, 45, 46, 47,
47, 49, 49, 51, 53, 55, 56, 58, 63, 64
We can find the range for this dataset like this:
[tex] Range = Max-Min = 64-16 =48[/tex]
Then since we need 7 classes we can find the length for each class doing this:
[tex] W = \frac{48}{7}=6.86[/tex]
And now we can define the classes like this and counting how many observations lies on each interval we got the frequency:
Class Frequency Midpoint RF CF
________________________________________________
[16-22.86) 8 19.43 (8/50)=0.16 0.16
[22.86-29.71) 11 26.29 (11/50)=0.22 0.38
[29.71-36.57) 11 33.14 (11/50)=0.22 0.6
[36.57-43.43) 7 40.0 (7/50)=0.14 0.74
[43.43-50.29) 6 46.86 (6/50)=0.12 0.86
[50.29-57.14) 4 53.72 (4/50)=0.08 0.94
[57.14-64] 3 60.57 (3/50)=0.06 1.0
________________________________________________
Total 50 1.00
RF= Relative frequency. CF= Cumulative frequency
The relative frequency was calculated as the individual frequency for a class divided by the total of observations (50)
The mid point is the average between the limits of the class.
And the cumulative frequency is calculated adding the relative frequencies for each class.
(Pitman 3.4.9) Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up first on the nth toss. If we play this game repeatedly, how much money do you expect to win or lose per game over the long run?
Answer:
Let's make a couple of assumptions to clarify the situation. First, the coin flipping is fair, that is, each flip is independent of all the others and for each flip, the probabilities of heads and tails are both 1/2. Second, you have enough money to pay me no matter how many tails are flipped before the first head.
Under those assumptions, the expected amount of money I will win in infinite.
In decision theory, utility is often used to make decisions rather than money. If my utility is proportional to expected monitory payoff, I should pay whatever I can scrape up, my total assets. For some reason, economists often assume utility functions have deminishing returns, and eventually flatten out.
In that case, the expected amount of utility payoff will be lower than the maximum utility. What does that mean for this game? It means it won't matter to me whether I get some large quantity of money like a trillion dollars, or any larger quantity of money, like a quadrillion dollars. All my needs are met by a trillion dollars. That's 240 dollars. So I certainly shouldn't pay more than $40 to play the game. As the utility function starts to flatten out earlier, perhaps $30 would come out to be a fair payment.
Let R be the event that a randomly chosen person lives in the city of Raleigh. Let O be the event that a randomly chosen person is over 50 years old. Place the correct event in each response box below to show: Given that the person lives in Raleigh, the probability that a randomly chosen person is over 50 years old.
Answer:
P(O|R)
Step-by-step explanation:
The conditional probability notation of two events A and B can be written as either P(A|B) or P(B|A).
The '|' sign is read as 'given'. So, P(A|B) is read as the probability of event A given event B which implies that it is the probability that event A will occur given that event B has already occurred.
In the question,
Event R = Person lives in the city of Raleigh
Event O = Person is over 50 years old
The statement says, 'given that the person lives in Raleigh' which means that event R has already occurred and we need to find the probability of event O (the randomly chosen person is over 50 years old).
Hence, this statement can be given in conditional probability notation as
P(O|R)
The question pertains to conditional probability (P(O|R)) and requires specific data to calculate the probability that a randomly chosen person is over 50 years old given they live in Raleigh.
Explanation:The student is asking about the concept of conditional probability, which in this case refers to the probability of a randomly chosen person being over 50 years old, given that they live in Raleigh. To express this mathematically, we say P(O|R), which means the probability of event O occurring given that event R has occurred.
To find this probability, one would typically use information from a study or a survey giving population counts or percentages of those over 50 within the city of Raleigh population. Without specific data, one cannot provide a precise probability value.
However, the concept is important in probability theory and widely applied across different domains.
A certain college graduate borrows 7277 dollars to buy a car. The lender charges interest at an annual rate of 11%. Assuming that interest is compounded continuously and that the borrower makes payments continuously at a constant annual rate k dollars per year.
1. Determine the payment rate that is required to pay off the loan in 5 years.
2. Also determine how much interest is paid during the 5-year period?
Answer:
a. $1773.82
b. $1592.1
Step-by-step explanation:
1. If he pays k dollar in the first year, then the amount that he owned without interest is
7277 - k
The amount that he owned including interest of 11% in the 2nd year is
(7277 - k)*1.11 or 7277*1.11 - 1.11k
After 2nd year and paying k then the amount he owned (without interest is)
(7277 - k)*1.11 - k
With interest
[(7277 - k)*1.11 - k]1.11 or [tex]7277*1.11^2 - 1.11^2k - 1.11k[/tex]
So after 5 years
[tex]7277*1.11^5 - (1.11^5 + 1.11^4 + 1.11^3 + 1.11^2 +1.11)k[/tex]
[tex]12262.17 - 6.91 k[/tex]
Since he's dept-free after 5 year then
[tex]12262.17 - 6.91 k = 0[/tex]
[tex]k = 12262.17 / 6.91 = 1773.82[/tex] dollar
2. The total amount he would have to pay over 5 years is 5k = 5*1773.82 = 8869.1
So the interest we has to pay over 5 years is the total subtracted by the principal, which is 8869.1 - 7277 = 1592.1 dollar
In a data set with mean of 12 and standard deviation of 4, at least what percent of data falls between 4 and 20?
Answer:
At least 95% of data falls between 4 and 20.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 12
Standard deviation = 4
At least what percent of data falls between 4 and 20?
4 = 12 - 2*4
So 4 is two standard deviations below the mean
20 = 12 + 2*4
So 20 is two standard deviations above the mean
By the Empirical Rule, at least 95% of data falls between 4 and 20.
Solve, graph, and give interval notation for the compound inequality:
7 (x + 2) −8 ≥ 13 AND 8x − 3 < 4x − 3
Answer:
The answer to your question is below
Step-by-step explanation:
Inequality 1
7(x + 2) - 8 ≥ 13
7x + 14 - 8 ≥ 13
7x + 6 ≥ 13
7x ≥ 13 - 6
7x ≥ 7
x ≥ 7/7
x ≥ 1
Inequality 2
8x - 3 < 4x - 3
8x - 4x < - 3 + 3
4x < 0
x < 0 / 4
x < 0
Interval notation (-∞ , 0) U [1, ∞)
See the graph below
The summary statistics for the hourly wages of a sample of 130 system analysts are given below. The coefficient of variation equals a.30%. b.0.30%. c.54%. d.0.54%.
Answer:
addition tioin multiplication
Step-by-step explanation:
Using the given data, the coefficient of variation is 30% which matches option b.
To calculate the coefficient of variation (CV), you use the formula :CV = (Standard Deviation ÷ Mean) × 100%From the given data :Mean (μ) = 60Variance (σ²) = 324The standard deviation (σ) is the square root of the variance :σ = √324 = 18Plugging these values into the CV formula :CV = (18 ÷ 60) × 100% = 0.30 × 100% = 30%Therefore, the coefficient of variation is 30%.Complete Question :
The hourly wages of a sample of 130 system analysts are given below. mean = 60 range = 20 mode = 73 variance = 324 median = 74. The coefficient of variation equals a. 0.30%. b. 30% O c. 5.4% d. 54%.
Kurt is designing a table for a client. The table is a rectangular shape with a length 26 inches longer than its width. The perimeter of the table is 300 inches. What is the area of the table in square inches? The area (A) of a rectangle is A=length×width.
Answer: area = 5,456
Answer:
5456 sq. inches
Step-by-step explanation:
Let width = w,
Then length = w + 26
Perimeter = 2[length + width]
2[(w +26) + w] = 2[2w + 26] = 4w + 52
Perimeter given is 300
So, 4w + 52 = 300
4w = 248
w = 248/4 =62
length = 62 + 26 = 88
Area = length × width
Area = 88 × 62 = 5456 sq. inches
Find the sample space for the experiment.
You toss a coin and a six-sided die.
Answer:
For the first case we are going to assume that the order matters, on this case 6, H is not the same as H,6
The sampling space denoted by S and is given by:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T),(4,T),(5,T),(6,T),
(H,1), (H,2),(H,3), (H,4),(H,5),(H,6),
(T,1), (T,2),(T,3), (T,4), (T,5),(T,6)}
If we consider that (5,H) is equal to (H,5) "order no matter" then we will have just 12 elements in the sampling space:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T) , (4,T), (5,T),(6,T)}
Step-by-step explanation:
By definition the sample space of an experiment "is the set of all possible outcomes or results of that experiment".
For the case described here: "Toss a coin and a six-sided die".
Assuming that we have a six sided die with possible values {1,2,3,4,5,6}
And for the coin we assume that the possible outcomes are {H,T}
For the first case we are going to assume that the order matters, on this case 6, H is not the same as H,6
The sampling space denoted by S and is given by:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T),(4,T),(5,T),(6,T),
(H,1), (H,2),(H,3), (H,4),(H,5),(H,6),
(T,1), (T,2),(T,3), (T,4), (T,5),(T,6)}
If we consider that (5,H) is equal to (H,5) "order no matter" then we will have just 12 elements in the sampling space:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T) , (4,T), (5,T),(6,T)}
In a recent baseball season, Ron was hit by pitches 21 times in 602 plate appearances during the regular season. Assume that the probability that Ron gets hit by a pitch is the same in the playoffs as it is during the regular season. In the first playoff series, Ron has 23 plate appearances. What is the probability that Ron will get hit by a pitch exactly once?
Answer:
the probability that Ron will get hit by a pitch exactly once is 36.71%
Step-by-step explanation:
The random variable X= number of times Ron is hits by pitches in 23 plate appearances follows ,a binomial distribution. Where
P(X=x) = n!/(x!*(n-x)!)*p^x*(1-p)^x
where
n= plate appearances =23
p= probability of being hit by pitches = 21/602
x= number of successes=1
then replacing values
P(X=1) = 0.3671 (36.71%)
The probability that Ron will get hit by a pitch exactly once in his 23 playoff plate appearances, given his regular season hit rate, is approximately 0.37 or 37%.
Explanation:The subject of this problem is probability; it's asking us to calculate the chances of a specific event happening. It is given that during the regular season, Ron was hit by pitches 21 times out of 602 plate appearances. Thus, the probability of him getting hit by a pitch is 21/602, or approximately 0.035.
In the playoffs, he has 23 plate appearances. We want to find the probability that he gets hit exactly once. This is a binomial probability problem, using the formula:
P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))
Where n is the number of trials (plate appearances), k is the number of successes we want (getting hit by the pitch), p is the success probability, and C(n, k) is the combination operator. Substituting the given values:
P(X=1) = C(23, 1) * (0.035^1) * ((1-0.035)^(23-1))
Performing this calculation gives a pitch hitting probability of about 0.37 or 37%, which means Ron is likely to be hit by one pitch during the 23 plate appearances in the playoffs.
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A survey of an urban university showed that 750 of 1,100 students sampled attended a home football game during the season. Using the 90% level of confidence, what is the confidence interval for the proportion of students attending a football game?
a. 0.7510 and 0.8290
b. 0.6592 and 0.7044
c. 0.6659 and 0.6941
d. 0.6795 and 0.6805
Answer:
b. 0.6592 and 0.7044
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence interval [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
A survey of an urban university showed that 750 of 1,100 students sampled attended a home football game during the season. This means that [tex]n = 1100, p = \frac{750}{1100} = 0.6818[/tex]
90% confidence interval
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6818 - 1.645\sqrt{\frac{0.6818*0.3182}{1100}} = 0.6592[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6818 + 1.645\sqrt{\frac{0.6818*0.3182}{1100}} = 0.7044[/tex]
So the correct answer is:
b. 0.6592 and 0.7044
Suppose that a recent poll of American households about car ownership found that for households with a car, 39% owned a sedan, 33% owned a van, and 7% owned a sports car. Suppose that three households are selected randomly and with replacement. What is the probability that at least one of the three randomly selected households own a sports car
Answer:
The probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Step-by-step explanation:
Let X = number of household owns a sports car.
The probability of X is, P (X) = p = 0.07.
Then the random variable X follows a Binomial distribution with n = 3 and p = 0.07.
The probability function of a binomial distribution is:
[tex]P(X=x) = {n\choose x}p^{x}[1-p]^{n-x}\\[/tex]
Compute the probability that of the 3 households randomly selected at least 1 owns a sports car:
[tex]P(X\geq 1)=1-P(X<1)\\=1-P(X=0)\\=1- {3\choose 0}(0.07)^{0}[1-0.07]^{3-0}\\=1-0.8044\\=0.1956[/tex]
Thus, the probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is used to measure the glucose concentration in the blood sample five times. The measured glucose concentrations are 104.5 , 96.2 , 102.2 , 98.3 , and 101.8 mg/dL. Calculate the absolute error and relative error for each measurement made by the glucose monitor. A. 104.5 mg/dL absolute error = 2.5 mg / dL relative error = 0.025 B. 96.2 mg/dL absolute error = −5.8 mg / dL relative error = 0.057 C. 102.2 mg/dL absolute error = 0.2 mg / dL relative error = 0.020 D. 98.3 mg/dL absolute error = −3.7 mg / dL relative error = 0.036 E. 101.8 mg/dL absolute error = −0.2 mg / dL relative error =
Answer:
The Absolute Error is the difference between the actual and measured value.
[tex]Absolute \:error = |Actual \:value - Measured \:value|[/tex]
The Relative Error is the Absolute Error divided by the actual measurement.
[tex]Relative \:error = \frac{Absolute \:error}{Actual \:value}[/tex]
We know that the actual value is 102.0 mg/dL.
To find the absolute error and relative error for each measurement made by the glucose monitor you must use the above definitions.
a) For a concentration of 104.5 mg/dL the absolute error and relative error are
[tex]Absolute \:error = \left|102-104.5\right|\\Absolute \:error =\left|-2.5\right|\\Absolute \:error =2.5[/tex]
[tex]Relative \:error = \frac{2.5}{102.0}=0.0245[/tex]
b) For a concentration of 96.2 mg/dL the absolute error and relative error are
[tex]Absolute \:error = \left|102.0-96.2\right|\\Absolute \:error =\left|5.8\right|\\Absolute \:error =5.8[/tex]
[tex]Relative \:error = \frac{5.8}{102.0}=0.0569[/tex]
c) For a concentration of 102.2 mg/dL the absolute error and relative error are
[tex]Absolute \:error = \left|102.0-102.2\right|\\Absolute \:error =\left|-0.2\right|\\Absolute \:error =0.2[/tex]
[tex]Relative \:error = \frac{0.2}{102.0}=0.00196[/tex]
d) For a concentration of 98.3 mg/dL the absolute error and relative error are
[tex]Absolute \:error = \left|102.0-98.3\right|\\Absolute \:error =\left|3.7\right|\\Absolute \:error =3.7[/tex]
[tex]Relative \:error = \frac{3.7}{102.0}=0.0363[/tex]
e) For a concentration of 101.8 mg/dL the absolute error and relative error are
[tex]Absolute \:error = \left|102.0-101.8\right|\\Absolute \:error =\left|0.2\right|\\Absolute \:error =0.2[/tex]
[tex]Relative \:error = \frac{0.2}{102.0}=0.00196[/tex]
A survey was conducted from a random sample of 8225 Americans, and one variable that was recorded for each participant was their answer to the question, "How old are you?" The mean of this data was found to be 42, while the median was 37. What does this tell you about the shape of this distribution?
a. It is skewed left.
b. It is symmetric.
c. There is not enough information.
d. It is skewed right
Answer:
d. skewed right
Step-by-step explanation:
The shape of the given distribution is rightly skewed. For a symmetric distribution mean and median are equal and if mean is greater than median then the distribution is rightly skewed and if mean is less than median then the distribution is skewed left.
In the given distribution mean is greater than median and so the given distribution is skewed right.
9. An automobile dealer believes that the average cost of accessories in new automobiles is $3,000 over the base sticker price. He selects 50 new automobiles at random and finds that the average cost of the accessories is $3,256. The standard deviation of the sample is $2,300. Test his belief at -0.0s. Use the classical method
Answer:
There is no enough evidence to claim that the average cost of accesories is different from $3,000.
Step-by-step explanation:
The significance level for this test is α=0.05.
The classical method is based on regions of rejection of acceptance, according to the sample parameter. In this case, the standard deviation of the population is unknown.
The null and alternative hypothesis are:
[tex]H_0: \mu=3000\\\\ H_a: \mu\neq 3000[/tex]
This is a two-tailed test, with significance level of 0.05.
The t-value for this sample is:
[tex]t=\frac{x-\mu}{s/\sqrt{N}} =\frac{3256-3000}{2300/\sqrt{50}}=\frac{256}{325}=0.787[/tex]
The degrees of freedom are:
[tex]df=n-1=50-1=49[/tex]
For df=49 and α=0.05 (two-tailed test), the critical values are [tex]|t|>2.009[/tex], so the value t=0.787 is within the acceptance region.
The null hypothesis can not be rejected.
Patricia serves the volleyball to Amy with an upward velocity of 17.5ft/s. The ball is 5 feet above the ground when she strikes it. How long does Amy have to react, before the volleyball hits the ground? Round your answer to two decimal places.
Answer:
1.33 s
Step-by-step explanation:
Given:
Δy = -5 ft
v₀ = 17.5 ft/s
a = -32 ft/s²
Find: t
Δy = v₀ t + ½ at²
-5 = 17.5 t + ½ (-32) t²
0 = -16t² + 17.5t + 5
0 = 32t² − 35t − 10
t = [ 35 ± √((-35)² − 4(32)(-10)) ] / 64
t = (35 ± √2505) / 64
t = 1.33
Amy has 1.33 seconds to react before the volleyball hits the ground.
Amy has to react to the volleyball based on its initial upward velocity and the height at which it was hit, using gravitational equations to calculate the time before it hits the ground.
Explanation:Patricia serves the volleyball to Amy with an upward velocity of 17.5ft/s. The ball is 5 feet above the ground when she strikes it. To determine how long Amy has to react before the volleyball hits the ground, we can use the equations of motion under gravity. Assuming the acceleration due to gravity (g) is 32.2ft/s2 (downward), the time (t) for the volleyball to reach the ground can be found by solving the quadratic equation derived from the formula:
h = v0t - (1/2)gt2
where h is the height above the ground (5 feet), v0 is the initial velocity (17.5ft/s), and t is the time in seconds. One can use the quadratic formula to solve for t. However, to provide a concrete example and simplify the calculation for the purpose of this answer, we would use a calculator or other computational tools to solve for t numerically, remembering to consider the positive root that makes physical sense. One would typically find a time in the range of a second or slightly more for this scenario.
The probability that a new car battery functions for more than 10,000 miles is .8, the probability that it functions for more than 20,000 miles is .4, and the probability that it functions for more than 30,000 miles is .1. If a new car battery is still working after 10,000 miles, what is the probability that (a) its total life will exceed 20,000 miles
Answer:
There is a 50% probability that its total life will exceed 20,000 miles.
Step-by-step explanation:
To solve this question, we use the following formula:
[tex]P(A|B) = \frac{P(A \cap B)}{P(B)}[/tex]
In which P(A|B) is the probability of A happening, given that B has happened, [tex]P(A \cap B)[/tex] is the probability of A and B happening, and P(B) is the probability of B happening.
In this problem, we want:
The probability of the total life of the car battery exceeding 20,000 miles, given that it exceeded 10,000 miles.
[tex]P(A \cap B)[/tex] is the probability of exceeding 20,000 and 10,000 miles. It is the same as the probability of exceeding 20,000 miles(If it exceeded 20,000 miles, necessarily it will have exceeded 10,000 miles). So [tex]P(A \cap B) = 0.4[/tex]
P(B) is the probability of exceeding 10,000 miles. So [tex]P(B) = 0.8)[/tex]
So
[tex]P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.4}{0.8} = 0.5[/tex]
There is a 50% probability that its total life will exceed 20,000 miles.
Final answer:
If a new car battery is still working after 10,000 miles, the probability that its total life will exceed 20,000 miles is 0.5 or 50%.
Explanation:
The question pertains to conditional probability, which is the probability of an event occurring given that another event has already occurred. Here, we are asked to find the probability that a new car battery will exceed 20,000 miles given that it has already functioned for more than 10,000 miles. This question essentially requires us to calculate conditional probability.
Given:
Probability that a new car battery functions for more than 10,000 miles (P(A)) = 0.8Probability that it functions for more than 20,000 miles (P(B)) = 0.4To find the conditional probability that its total life will exceed 20,000 miles given it has already worked for over 10,000 miles (P(B|A)), we use the formula:
P(B|A) = P(B & A) / P(A)
However, since any battery that has functioned for more than 20,000 miles must have also functioned for more than 10,000 miles, P(B & A) = P(B), hence:
P(B|A) = 0.4 / 0.8 = 0.5
Therefore, if a new car battery is still working after 10,000 miles, the probability that its total life will exceed 20,000 miles is 0.5 or 50%.
An 18-meter-tall cylindrical tank with a 4-meter radius holds water and is half full. Find the work (in mega-joules) needed to pump all of the water to the top of the tank. (The mass density of water is 1000 kg/m3. Let g = 9.8 m/s2.
Final answer:
To find the work needed to pump all of the water to the top of the tank, we need to calculate the potential energy at the half-full level and the top of the tank. By using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height, we can calculate the potential energy for each level and find the difference. The work needed is approximately 41 million mega-joules.
Explanation:
To calculate the work needed to pump all the water to the top of the tank, we need to find the potential energy of the water at the half-full level and the potential energy of the water at the top of the tank. The potential energy of an object is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Given that the tank is half full, the height of the water column is 18/2 = 9 meters. The radius of the tank is 4 meters, so the volume of the water is πr^2h = π(4^2)(9) = 144π cubic meters. The mass of the water is density × volume = 1000 × 144π = 144,000π kg.
The potential energy at the half-full level is PE = mgh = 144,000π × 9 × 9.8 = 12,931,200π joules. The potential energy at the top of the tank is PE = mgh = 144,000π × 18 × 9.8 = 25,862,400π joules. Therefore, the work needed to pump all the water to the top of the tank is the difference in potential energy = 25,862,400π - 12,931,200π = 12,931,200π joules. To convert to mega-joules, divide by 1,000,000, so the work needed is approximately 41 million mega-joules.
Use the graph to fill in the blank with the correct number. f(−2) = ________ X, Y graph. Plotted points negative 3, 0, negative 2, 2, 0, 1, and 1, negative 2. Numerical Answers Expected! Answer for Blank 1:
The given points
[tex](-3, 0)[/tex]
[tex](-2, 2)[/tex]
[tex](0, 1)[/tex]
[tex](1, -2)[/tex]
Imply that
[tex]f(-3)=0[/tex]
[tex]f(-2)=2[/tex]
[tex]f(0)=1[/tex]
[tex]f(1)=-2[/tex]
Answer:
f(2) = -1.
Step-by-step explanation:
A certain museum has five visitors in two minutes on average. Let a Poisson random variable denote the number of visitors per minute to this museum. Find the variance of (write up to first decimal place).
Answer:
The variance is 2.5.
Step-by-step explanation:
Let X = number of visitors in a museum.
The random variable X has an average of 5 visitors per 2 minutes.
Then in 1 minute the average number of visitors is, [tex]\frac{5}{2} =2.5[/tex]
The random variable X follows a Poisson distribution with parameter λ = 2.5.
The variance of a Poisson distribution is:
[tex]Variance=\lambda[/tex]
The variance of this distribution is:
[tex]V(X)=\lambda=2.5[/tex]
Thus, the variance is 2.5.
The following data represent the social ambivalence scores for 15 people as measured by a psychological test. (The higher the score, the stronger the ambivalence.) 8 12 11 15 14 10 8 3 8 7 21 12 9 19 11 (a) Guess the value of s using the range approximation. s ≈ (b) Calculate x for the 15 social ambivalence scores. Calculate s for the 15 social ambivalence scores. (c) What fraction of the scores actually lie in the interval x ± 2s? (Round your answer to two decimal places.).
Answer:
a) 4.5
b) x = 11.2, s = 4.65
c) 93.33%
Step-by-step explanation:
We are given he following data in the question:
8, 12, 11, 15, 14, 10, 8, 3, 8, 7, 21, 12, 9, 19, 11
a) Estimation of standard deviation using range
Sorted data: 3, 7, 8, 8, 8, 9, 10, 11, 11, 12, 12, 14, 15, 19, 21
Range = Maximum - Minimum = 21 - 3 = 18
Range rule thumb:
It states that the range is 4 times the standard deviation for a given data.[tex]s = \dfrac{\text{Range}}{4} = \dfrac{18}{4} = 4.5[/tex]
b) Mean and standard deviation
Formula:
[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]
where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{168}{15} = 11.2[/tex]
Sum of squares of differences = 302.4
[tex]S.D = \sqrt{\dfrac{302.4}{14}} = 4.65[/tex]
c) fraction of the scores actually lie in the interval x ± 2s
[tex]x \pm 2s = 11.2 \pm 2(4.65) = (1.9,20.5)[/tex]
Since 14 out of 15 entries lie in this range, we can calculate the percentage as,
[tex]\dfrac{14}{15}\times 100\% = 93.33\%[/tex]