4x2+3x=0 please solve this by using quadratic formula

A function assigns the values. The temperature that will model most accurately predict the time spent cooling will be 300.

A function assigns the value of each element of one set to the other specific element of another set.

For the given function [tex]f(t)=349.2 (0.98)^t[/tex], the value of t which will lie within the given function range will be the value function that will model most accurately predict the time spent on cooling. Therefore, let's substitute the values and check,

A.) t = 0

[tex]f(t)=349.2 (0.98)^t\\\\0=349.2 (0.98)^t[/tex]

As the value of t will lie at infinite, therefore, this will not give an accurate prediction of the model.

B.) f(t) = 100

When the value of the function will be 100 then the value of t will be 61.6, therefore, this can not be the most accurate prediction.

C.) f(t) =300

When the value of the function will be 300 then the value of t will be 7.5, therefore, this is the most accurate prediction.

D) f(t) = 400

When the value of the function will be 400 then the value of t will be -6.724, therefore, this can not be the most accurate prediction.

Thus, the temperature that will model most accurately predict the time spent cooling will be 300.

Learn more about Function:

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Answer:

option B

Step-by-step explanation:

Step 1

A + B = C

[tex]A=\left[\begin{array}{ccc}8&-3\\3&y+2\end{array}\right][/tex][tex]+B=\left[\begin{array}{ccc}3x&z+4\\w&1/2y\end{array}\right][/tex]

=

[tex]C=\left[\begin{array}{ccc}x&2z\\4&y\end{array}\right][/tex]

Step 2

[tex]\left[\begin{array}{ccc}8+3x&-3+z+4\\3+w&y+2+y/2\end{array}\right][/tex][tex]=\left[\begin{array}{ccc}x&2z\\4&y\end{array}\right][/tex]

Step 3

4 equations are form

Equation 1

8 + 3x = x

8 = -2x

x = -4

Equation 2

-3 + z + 4 = 2z

1 + z = 2z

1 = z

z = 1

Equation 3

3 + w = 4

w = 1

Equation 4

y + 2 + y/2 = y

2 + y/2 = 0

4 + y = 0

y = -4

Step 4

[tex]\left[\begin{array}{ccc}3(-4)&1+4\\1&1(-4)/2\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}-12&5\\1&-2\end{array}\right][/tex]

Answer:

B

Step-by-step explanation:

I got 100% on EDGE 2020 Unit test

Answer:

the person above me is correct

Step-by-step explanation:

by the way its 8 because 24 words divided by 4 weeks is 8.

The unit rate describing Alan's vocabulary acquisition is 6 words per week.

The unit rate that describes the situation where Alan learned 24 new vocabulary words in 4 weeks is 6 words per week.

To find the unit rate, divide the total number of words learned by the total number of weeks. In this case, 24 words / 4 weeks = 6 words per week.

Answer:

D

Step-by-step explanation:

Substitute x = g(x) into f(x)

f(2x + 3) = (2x + 3)² ← expand factors

f(g(x)) = (2x)² + 6x + 6x + 3² = 4x² + 12x + 9 → D

Answer:

Step-by-step explanation:

A

The vertex form: f(x) = a(x-h)^2 + k

f(x) = x^2 + 16x + 60 = (x^2 + 16x) + 60

We want to get a perfect square in the brackets, so we solve for our b^2 coefficient.

b^2 = (16/2)^2 = 64

f(x) = (x^2 + 16x + 64 - 64) + 60. Note we subtracted 60 right away to end up with an equivalent expression and not some other function.

f(x) = (x+8)^2 - 4, as you can see it matches the general vertex form.

The vertex form shows when the profit is minimal. The point (h, k) or f(h).

B. The x-intercepts or when the function is equal to 0, or the profit is 0 in the context of the problem.

f(x) = x^2 + 16x + 60 set = 0

x^2 + 16x + 60 = 0

[tex]x_{12} = \frac{-16 \pm \sqrt{256 - 4(1)(60)}}{2} = \frac{-16 \pm \sqrt{16}}{2} = \frac{-16 \pm 4}{2} = -8 \pm 2[/tex]

Answer:

the vertex is either the maximum or minimum value

since the leading coefinet is negative (the number in front of the x² term), the parabola opens down and is a maximum

so

A.

a hack version is to use the -b/(2a) form

if  you have f(x)=ax²+bx+c, then the x value of the vertex is -b/(2a)

so

given

f(x)=-1x²+16x-60

the x value of the vertex is -16/(2*-1)=-16/-2=8

the y value is f(8)=-1(8)²+16(8)-60=

-1(64)+128-60=

4

the vertex is (8,4)

so you selll 8 candels to make the max profit which is $4

B.

x intercepts are where the line crosses the x axis or where f(x)=0

solve

0=-x²+16x-60

0=-1(x²-16x+60)

factor

what 2 numbers multiply to get 60 and add to get -16

-6 and -10

0=-1(x-6)(x-10)

set each factor to 0

0=x-6

x=6

0=x-10

10=x

x intercepts are at x=6 and 10

that is where you make 0 profit

I hope u get what ur looking for and I wish u give me brainlist But I know u won't cuz everyone say that . But thank you so much if u put for me and It would be a very appreciated from you and again thank you so much

Thank you

sincerely caitlin

Answer: A and D are both correct

Step-by-step explanation:

just took this test

In the straightedge and compass construction of the equilateral triangle above, the reasons can be used to prove that AC ≅ BC are:

A. AB and AC are radii of the same circle A, and AB and BC are radii of the same circle, so AB ≅ AC and AB ≅ BC, and AC ≅ BC

D. AB and AC are radii of the same circle and AB and BC are radii of the same circle, so AB ≅ AC and AB ≅ BC. AC and BC are both congruent to AB, so AC ≅ BC.

In Mathematics and Euclidean Geometry, an equilateral triangle can be defined as a special type of triangle that has equal side lengths and all of its three (3) interior angles are equal.

Since lines AB and AC are radii of the same circle and line AB and line BC are radii of the same circle, we can logically deduce that line AB would be congruent with line AC and line AB would be congruent with line BC.

This ultimately implies that line AC and line BC are both congruent to line AB, so based on the transitive property of equality, we have;

AC ≅ BC.

The answer is: The third option, the functions cos(θ) and sin(θ) will have negative values for 180°<θ<270°.

To answer the question we must remember where the trigonometric functions have positive and negative values. We can remember it by considerating where the coordinates of any point are positive or negative along the coordinate plane (x and y).

The primary trigonometric functions are:

[tex]sin(\alpha)\\cos(\alpha)[/tex]

Where,

[tex]Tan(\alpha)=\frac{sin(\alpha)}{cos(\alpha)}[/tex]

Also, we need to remember the quadrants of the coordinate plane.

First quadrant: I, 0°<θ<90°

We can find the first quadrant between 0° and 90° , taking the values from 0 to the positive numbers for the x-axis and the y-axis, the points located on this quadrant, will always have positive coordinates, meaning that the functions sine, cosine and tangent will always have positive values.

Second quadrant: II, 90°<θ<180°

We can find the second quadrant between 90° and 180°, taking the values from 0 to the negative numbers for the a-axis, and from 0 to the positive numbers, the points located on this quadrant, will have negative coordinates along the x-axis and positive coordinates along the y-axis, meaning that the function cosine and tangent will always have negative values, while the sine function will always have positive values.

Third quadrant: III, 180°<θ<270°

We can find the third quadrant between 180° and 270°, taking values from 0 to the negative numbers for both x-axis and y-axis, where the points located on this quadrant, will always have negative coordinates along the x-axis and the y-axis, meaning that both functions sine and cosine will always have negative values, while the tangent function will have positive values.

Fourth quadrant: IV, 270°<θ<360°

We can find the fourth quadrant between 270° and 360°, taking values from 0 to the positive numbers for the x-axis, and from 0 to the negative numbers for the y-axis, the points located at this quadrant will always have positive coordinates along the x-axis and negative coordinates along the y-axis, meaning that the sine and tangent function will always have negative values, while the cosine function will always have positive values.

Hence, the answer to the question is the third option, the functions cos(θ) and sin(θ) will have negative values for 180°<θ<270°.

Have a nice day!

Final answer:

For angles between 180° and 270°, the trigonometric functions cosθ and sinθ have negative values while tanθ is positive.

Explanation:

The primary trigonometric functions under consideration are sin, cos, and tan. The question pertains to angles that fall in the third quadrant, specifically for 180° < θ < 270°.

According to the unit circle and trigonometric properties, cosθ and sinθ have negative values in this range.

This is because in the third quadrant, the x-coordinates (cosine values) and the y-coordinates (sine values) are both negative, while the division of two negative values (sinθ/cosθ for tanθ) gives a positive result for tanθ.

Hence, the correct answer is that cosθ and sinθ may have negative values for the specified range of θ.

The mathematical expectation for the number of spaces moved in one turn is:

           A.    3 spaces forward.

Th result or the sample space on spinning a spinner twice is:

           (1,1)    (1,4)    (1,6)    (1,8)

           (4,1)   (4,4)    (4,6)  (4,8)

           (6,1)   (6,4)    (6,6)  (6,8)

           (8,1)   (8,4)    (8,6)   (8,8)

Total number of outcomes= 16

The number of outcomes whose sum is even= 10

( Since the outcomes are: {(1,1) , (4,4) , (4,6) , (4,8) , (6,4) , (6,6) , (6,8) , (8,4) , (8,6) , (8,8)}  )

The number of outcomes whose sum is odd= 6

( Since, the outcomes are: { (1,4) , (1,6) , (1,8) , (4,1) , (6,1) , (8,1) }

Probability(sum even)=10/16

Probability(sum odd)=6/16

Hence, the expectation is:

 [tex]E(X)=\dfrac{10}{16}\times (+6)+\dfrac{6}{16}\times (-2)\\\\\\E(X)=\dfrac{60-12}{16}\\\\\\E(X)=\dfrac{48}{16}\\\\\\E(X)=+3[/tex]

                 Hence, the answer is:

              A.  3 spaces forward.

The last ones answer is six

Answer:

The x intercepts are x=-4 and x=2

axis of symmetry x=-1

vertex (-1,-9)

D: {x: all real numbers}

R: {y: y≥ -9}

Step-by-step explanation:

f(x) = x^2+2x-8

y= x^2+2x-8

Factor the equation

What 2 numbers multiply to -8 and add to 2

4*-2 = -8

4+-2 =2

y = (x+4) (x-2)

The x intercepts are found when we set y =0

0=  (x+4) (x-2)

Using the zero product property

x+4=0   x-2 =0

x=-4 and x=2

The x intercepts are x=-4 and x=2

The axis of symmetry is halfway between the x intercepts.  It is symmetric must be in the middle of the x intercepts

1/2 (-4+2) = 1/2(-2) = -1

The axis of symmetry is at x=-1

To find the vertex, it is along the axis of symmetry.  Substitute x=-1 into the equation

y = (x+4) (x-2)

y = (-1+4) (-1-2)

  =3*-3

  =-9

The vertex is (-1,-9)

The domain is the values that x can take

x can be any number

D: {x: all real numbers}

The range is the values that y can take

since the parabola opens upward, the vertex is the minimum,Y must be greater than or equal to -9

R: {y: y≥ -9}

Answer:

  B) x^2/12 +y^2/16 = 1

Step-by-step explanation:

The distance from focus to covertex is the same as the distance from the center to the vertex: 4. So, the Pythagorean theorem tells you ...

  a^2 + 2^2 = b^2

  a^2 +4 = 4^2 = 16

  a^2 = 16 -4 = 12

So, the standard-form equation ...

  x^2/a^2 +y^2/b^2 = 1

looks like this when the values are filled in:

  x^2/12 +y^2/16 = 1

That is 99 degrees if you have the triangle facing the other way

the measure of angle KJL is [tex]\( 40^\circ \)[/tex].

Given information

[tex]\( m(KP) = 2 \cdot m(IP) \)\\\( m(IVK) = 120^\circ \)[/tex]

Using the fact that the sum of angles in a circle is [tex]\( 360^\circ \)[/tex], we have:

[tex]\[ m(KP) + m(IP) + m(IVK) = 360^\circ \][/tex]

Substituting the given values:

[tex]\[ 2 \cdot m(IP) + m(IP) + 120^\circ = 360^\circ \][/tex]

Solving for [tex]\( m(IP) \)[/tex]:

[tex]\[ 3 \cdot m(IP) = 360^\circ - 120^\circ \]\[ 3 \cdot m(IP) = 240^\circ \]\[ m(IP) = \frac{240^\circ}{3} \]\[ m(IP) = 80^\circ \][/tex]

Finding [tex]\( m(KP) \)[/tex]:

[tex]\[ m(KP) = 2 \cdot m(IP) = 2 \cdot 80^\circ = 160^\circ \][/tex]

Using the angle formed by a tangent and a secant theorem, we can find [tex]\( m(\angle KJL) \)[/tex]:

[tex]\[ m(\angle KJL) = \frac{1}{2} (m(KP) - m(IP)) \][/tex]

Substituting the known values:

[tex]\[ m(\angle KJL) = \frac{1}{2} (160^\circ - 80^\circ) \]\[ m(\angle KJL) = \frac{1}{2} (80^\circ) \]\[ m(\angle KJL) = 40^\circ \][/tex]

Therefore, the measure of angle KJL is [tex]\( 40^\circ \)[/tex].

The complete question is:

given:  [tex]\( m(KP) = 2 \cdot m(IP) \)\\[/tex] and [tex]\( m(IVK) = 120^\circ \)[/tex]

find: m∠KJL.

ANSWER

D. 13

EXPLANATION

The given function is:

[tex]f(x) = \frac{2x + 1}{x -4} [/tex]

Let

[tex]y = \frac{2x + 1}{x -4} [/tex]

Interchange x and y.

[tex]x= \frac{2y + 1}{y-4} [/tex]

Solve for y.

[tex]x(y - 4)=2y + 1[/tex]

[tex]xy - 4x=2y + 1[/tex]

[tex]xy - 2y = 1 + 4x[/tex]

[tex](x - 2)y = 1 + 4x[/tex]

[tex]y = \frac{1 + 4x}{x - 2} [/tex]

[tex] {f}^{ - 1}(x) = \frac{1 + 4x}{x - 2} [/tex]

We put x=3,

[tex]{f}^{ - 1}(3) = \frac{1 + 4 \times 3}{3- 2}[/tex]

[tex]{f}^{ - 1}(3) = \frac{13}{1} = 13[/tex]

Answer: 47+B(.85) = A

Step-by-step explanation:

One bagel = $0.85

Sold 47 today

One bagel(.85) = profit

A = profit

B = additional bagels

47+B(.85) = A

Answer:

The measure of angle BCD is [tex]68.5\°[/tex]

Step-by-step explanation:

step 1

Find the value of x

In this problem

[tex]m<ABD+m<BCD+m<EDF=180\°[/tex] -----> is a straight line

substitute the values

[tex](3x+4)+(6x-8)+(7x-20)=180\°[/tex]

[tex](16x-24)=180\°[/tex]

[tex]16x=180\°+24\°[/tex]

[tex]x=12.75\°[/tex]

step 2

Find the measure of angle BCD

[tex]m<BCD+=(6x-8)\°[/tex]

substitute the value of x

[tex]m<BCD+=(6(12.75)-8)=68.5\°[/tex]

Answer:

Step-by-step explanation:

First you assume some complex number of the form [tex]a + bi[\tex] is the square root of [tex]3 - 4i[\tex].

Then, by the definition, that number squared is 3 - 4i.

And you end up with the following equation:

[tex](a+bi)^2 = 3 - 4i\\a^2 + 2abi - b^2 = 3 - 4i\\(a^2 - b^2) + (2ab)i = 3 - 4i[/tex]

Then you assume the real part of the left is equal to 3 and the complex part [tex]2abi[\tex] is equal to [tex]-4i[\tex].

You end up with a system of equations:

[tex]a^2 - b^2 = 3\\2ab = -4[/tex]

Then you simplify the 2nd equation to [tex]ab = -2[\tex], then you rewrite b in terms of a [tex]b = \frac{-2}{a}[\tex].

You plug your new definition into the first equation and you end up with:

[tex]a^2 - (\frac{-2}{a})^2 = 3\\a^2 - \frac{4}{a^2} = 3[/tex]

You multiply the whole equation by [tex]a^2[\tex] as it is not equal to 0.

[tex]a^4 - 4 = 3a^2\\a^4 - 3a^2 -4 = 0[/tex]

We let [tex]t = a^2[\tex] and we end up with:

[tex]t^2 -3t - 4 = 0\\t_{12} = \frac{3 \pm \sqrt{9 - 4(1)(-4)} }{2} = \frac{3 \pm \sqrt{25}}{2} = \frac{3 \pm 5}{2}\\t_1 = 4\\t_2 = -1[/tex]

We then go back to the definition of [tex]t[\tex]:

[tex]t = a^2\\a^2 = 4 \mid a^2 = -1[/tex]

But since a is a real number we only use the first result:

[tex]a^2 = 4\\a_{12} = \pm 2[/tex]

We then solve for [tex]b[\tex]:

[tex]ab = -2\\b_1 = \frac{-2}{a_1}\\b_2 = \frac{-2}{a_2}\\b_{12} = \pm 1[/tex]

We then write the newly achieved complex number:

[tex]a_1 + b_1i = \sqrt{3-4i} \mid a_2 +b_2i = \sqrt{3-4i} \\2-i = \sqrt{3-4i} \mid -2 + i = \sqrt{3-4i}[/tex].

Use which equation you please to find the magnitude of:

[tex]|X| = \sqrt{2^2 + 1^2} = \sqrt{5}[/tex] - the magnitude.

And to find the phase/angle.

[tex]\theta = arcsin(\frac{b}{\sqrt{a^2+b^2} } ) = arcsin(\frac{1}{\sqrt{5}}) = 26.565^o[/tex]

Answer:

983497

step-by-step explanation:

The sum formula of arithmetic sequence is given by:

[tex]S_n = \frac{n}{2}(2a_1 +(n - 1)d[/tex]

a_1 is the first term, n is the nth term and d is the common difference

From the given information

[tex]d = - 1 -( - 5) = - 1 + 5 = 4[/tex]

[tex]a_1 = - 5 \: and \: n = 703[/tex]

By substitution we obtain:

[tex]S_{703}= \frac{703}{2}(2( - 5) +(703- 1)4)[/tex]

[tex]S_{703}= \frac{703}{2}( - 10 + 2808)[/tex]

[tex]S_{703}= \frac{703}{2}(2798)[/tex]

[tex]S_{703}=98397[/tex]

Answer:

S = 983,497

Step-by-step explanation:

We are given the following sequence and we are to find the sum of the first 703 terms of this sequence:

[tex]-5, -1, 3, 7, ...[/tex]

Finding the common difference [tex]d[/tex] = [tex]-1-(-5)[/tex] = [tex]4[/tex]

[tex]a_1=-5[/tex]

[tex]a_n=?[/tex]

[tex]a_n=a_1+(n-1)d[/tex]

[tex] a_n = - 5 + ( 7 0 3 - 1 ) 4 [/tex]

[tex] a _ n = 2803 [/tex]

Finding the sum using the formula [tex]S_n = \frac{n}{2}(a_1+a_n)[/tex].

[tex]S_n = \frac{703}{2}(-5+2803)[/tex]

S = 983,497

Answer:

slope=-1/4

Step-by-step explanation:

point 1: -4,-1

point 2: 0,-2

y1-y2/x1-x2

1/-4

-1/4

Answer:

Sanjay watched television last weekend for 180 minutes.

Step-by-step explanation:

Sanjay watched 3 television shows and one movie on television last week.

Time duration of 1 television shows = 30 mins

Time duration of 3 television shows = 3* 30 = 90 mins

Time duration of movie = 90 mins

Total number of minutes Sanjay watched television last weekend = Time duration of 3 television shows + Time duration of movie

= 90 + 90

= 180 min

So, Sanjay watched television last weekend for 180 minutes.

Answer:

10 kgs of 25% copper alloy and 40 kgs of 70% copper alloy

Step-by-step explanation:

Let a be kg of 25% copper alloy, and

b be kg of 70% copper alloy

We can write two equations:

1. a + b = 50

2. 0.25a+0.7b=0.61(50)

We can write #1 as b = 50 - a, and then plug it into #2. We have:

0.25a+0.7b=0.61(50)

0.25a+0.7(50 -  a) = 0.61(50)

0.25a + 35 - 0.7a = 30.5

-0.45a = 30.5 - 35

-0.45 a = -4.5

a = -4.5 / - 0.45

a = 10

Also, b = 50 - a, so b = 50 - 10 = 40

The metalworker should use 10 kgs of 25% copper alloy and 40 kgs of 70% copper alloy to make it.

Answer:

40

Step-by-step explanation:

Answer:

B) 3/4

Step-by-step explanation:

3 /4

Set A interquartile range = 4

Difference between medians is 3.

Therefore,  3 /4

The difference between the median of set A and set B as a multiple of interquartile range of set A is 3/4.

Set A interquartile range is 4

Difference between their medians is 3

The interquartile range is a measure of the “middle fifty” in a data set in which a range is a measure of the beginning and end are in a set, an interquartile range is a measure of the bulk of the values lie.

Difference between the median = Median / Interquartile range of A

                                                       = 3/4

Thus, the difference between the median set A and set B as multiple of interquartile range is 3/4.

Learn more about the Interquartile range from:

https://brainly.com/question/14469535

#SPJ2

Do what? I can't see a question

repost and let me know once it’s up because I can’t see the picture

Good luck,

:)

Answer:

c. 1 and 3

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot each equation.

Please see the attached image below, to find more information about the graph s

The equations are:

1) y = sin (3x + π/6)

2) y = cos (3x - π/6)

3) y = cos (3x - π/3)

Looking at the graphs, we can see that the identical ones

are equations one and three

Correct option:

c. 1 and 3

The correct option is:

             option: c     c.   1 and 3

The first trignometric function is given by:

     [tex]y=\sin (3x+\dfrac{\pi}{6})[/tex]

and also we know that:

[tex]\sin \theta=\cos(\dfrac{\pi}{2}-\theta)[/tex]

This means that:

[tex]\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{2}-(3x+\dfrac{\pi}{6})\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{2}-3x-\dfrac{\pi}{6})\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{2}-\dfrac{\pi}{6}-3x)\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{2\pi}{6}-3x)\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{3}-3x)\\\\\\\sin (3x+\dfrac{\pi}{6})=cos (-(3x-\dfrac{\pi}{3}))[/tex]

As we know that:

[tex]\cos (-\theta)=cos(\theta)[/tex]

Hence, we have:

[tex]\sin (3x+\dfrac{\pi}{6})=\cos (3x-\dfrac{\pi}{3})[/tex]

Also,  by the graph we may see that the graph of 1 and 2 function do not match.

Hence, they are not equivalent.

Answer:

Domain = Range =  All real numbers

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

f(x)=2x+cos x

From the plot, we can see the answer is

Option a.

Domain = Range = (-∞,∞)

Answer: a

Step-by-step explanation:

right on edg

4x➕6(503-x)=2296

Distribute the 6 into the parentheses

Let x represent the students

503-x will represent the non-students

4x➕3018➖6x=2296

Then combine like terms

-2x➕3018=2296

Now since you move your constant your sign has to change as well,

-2x=2296➖3018

Then subtract

-2x=-722

Then divide both sides by -2

You are left with x=361

This represents the students

503➖361= 142 which equal the non-students

Therefore your answer is:

361=students

142=non-students

Hope this helps! :3

Answer:

361 students and 503-361=142 non students

Step-by-step explanation:

Let x = number of students. And 503-x = the number of non students. Therefore, 4x+6(503-x)=2296

Answer:

4a + 2b + 1/4 c.

Step-by-step explanation:

1/4(16a+8b+c)

= 1/4 * 16a + 1/4 * 8b + 1/4 * c

= 4a + 2b + 1/4 c.

Final answer:

To apply the distributive property to the expression 1/4(16a+8b+c), we distribute the 1/4 to each term inside the parentheses and simplify the expression.

Explanation:

To apply the distributive property to the expression 1/4(16a+8b+c), we distribute the 1/4 to each term inside the parentheses. This means multiplying 1/4 by 16a, 1/4 by 8b, and 1/4 by c. The distributive property states that a (b + c) = ab + ac. So, the expression becomes:

1/4(16a) + 1/4(8b) + 1/4(c)

Since 1/4 times any number equals the number divided by 4, we can simplify further:

(16a/4) + (8b/4) + (c/4)

Which simplifies to:

4a + 2b + c/4

Answer:

The answer is -8.

Step-by-step explanation:

Answer:

The length of QS and TV is 8 units

Step-by-step explanation:

we know that

If triangle QRS is congruent with triangle TUV

then

QS=TV

QR=TU

RS=UV

In this problem

we have

QS=3v+2

TV=7v-6

so

QS=TV

3v+2=7v-6

Solve for v

7v-3v=2+6

4v=8

v=2

Find the length of QS

substitute the value of v

QS=3(2)+2=8 units

so

TS=8 units

Final answer:

Triangle QRS is congruent to triangle TUV, so side QS is equal to side TV. By setting the expressions for QS and TV equal and solving for 'v', we find that both lengths are 8 units.

Explanation:

To solve the problem of finding the length of QS and TV given that triangle QRS is congruent to triangle TUV, and being given the expressions QS = 3v + 2 and TV = 7v - 6, we must recognize that congruent triangles have corresponding sides of equal length. Thus, we can set the expressions for QS and TV equal to each other:

3v + 2 = 7v - 6

We then solve for 'v' by subtracting 3v from both sides:

2 = 4v - 6

Next, we add 6 to both sides:

8 = 4v

Divide both sides by 4 to find 'v':

v = 2

Now that we have the value of 'v', we can substitute it back into the expressions for QS and TV to find their lengths:

QS = 3(2) + 2 = 8

TV = 7(2) - 6 = 8

Therefore, the length of QS and TV is 8 units each.

Answer:

[tex]f(x)=3^x[/tex]

Step-by-step explanation:

Given that the function is represented by the graph below, which  begins in the second quadrant near the x−axis and increases slowly while crossing the ordered pair 0, 1. When the graph enters the first quadrant, it begins to increase quickly throughout the graph

Because it passes through (0,1) it is of the form

[tex]y=a^x[/tex]

Also for negative x large it is very near x axis, So a must be positive then only it increases faster in the I quadrant.  Range is only posiitve real numbers

So the function is

[tex]f(x) =3^x[/tex]

Answer:

Option A

Option C

Step-by-step explanation:

A relationship is defined as a function if and only if each element of the "domain" set is assigned only one element of the "range" set. That is, there is only one output value y assigned to each input value x.

The relation x = 3 is not a function because there are infinite output values y, assigned to the same input element x.

(3, 2), (3, 5) (3, 9) (3,10000)

Then the option A is true

Option C is also true, the equation of the line shown is

[tex]x = 3[/tex]

The rest of the options are false because x = 3 is not a function