4 Sodium metal, Na, reacts with water to form a solution of
sodium hydroxide, NaOH, and gives off hydrogen gas, H.
Write a balanced symbol equation, including state symbols,
for this reaction.

Answer:

Shorter showers

Explanation:

A 5 to 10 minute shower will only take about 10 or 20 gallons of water. Or you could take a bath and not fill the bathtub up very much.

It's completely up to you which one you chose to use. Many people take 30 to 60 minute showers. Based on that math, that could take up to 120 gallons of water.  

That shows that simply shortening your shower time, you will save gallons of water!

~CaityConcerto

Answer:

Fe=625.026g

Molar mass of Al2O3=102g

Molar mass of Fe=168g

102g of Al2O3-168g of Fe

379.48g of Al2O3-xg of Fe

Cross multiply

102x = 168×379.49

102x=63752.64

X= 625.026g

Therefore,the mass of Fe is 625.027g

Explanation:

20.06 g of Hg  and 1.6 g of O₂

Explanation:

To Find:

Number of Mercury and oxygen that can be obtained from 21.7 g of HgO

First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,

2 HgO (s) → 2Hg(l) + O₂ (g)

21.7 g of HgO  = [tex]\frac{21.7 g}{216.59 g / mol}[/tex]  

                         = 0.1 mol of HgO.

As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .

So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)

                                                 = 20.06 g of Hg

Amount of oxygen produced = 0.05  mol × 32 g/ mol = 1.6 g of O₂

Thus it is clear that 20.06 g of Hg  and 1.6 g of O₂  is obtained from 21.7 g of HgO

Final answer:

From 21.7g of mercury (II) oxide, approximately 20.059 g of mercury and 1.6 g of oxygen can be produced through the decomposition reaction. This calculation uses the stoichiometry of the reaction and the molar masses of the substances involved.

Explanation:

To determine how much mercury and oxygen could be obtained from 21.7g of mercury (II) oxide, we need to consider the decomposition reaction of mercury (II) oxide under standard state conditions:

2HgO(s, red) → 2Hg(l) + O2(g)

By using the molar mass of mercury (II) oxide (216.59 g/mol), we can convert the mass of mercury (II) oxide to moles:

21.7 g HgO × (1 mol HgO / 216.59 g HgO) = 0.1 mol HgO

Following the stoichiometry of the reaction, 0.1 moles of HgO will produce 0.1 moles of Hg and 0.05 moles of O2, since 2 moles of HgO decompose to produce 1 mole of O2. We can then calculate the mass of mercury and oxygen produced:

0.1 mol Hg x (200.59 g Hg/mol) = 20.059 g of Hg

0.05 mol O2 x (32 g O2/mol) = 1.6 g of O2

Therefore, 21.7g of mercury (II) oxide will produce approximately 20.059 g of mercury and 1.6 g of oxygen.

Answer:

3%

Explanation:

We have heard about the clean water crisis, but how can that happen if earth mostly covered in water? Even though 70% of the earth is covered in water, most of those water is at ocean and has a high concentration of salt. We can't drink those water because the salt will take more water from our bodies. Freshwater only makes up about 2.5-3% water bodies while the ocean makes up 97% of the rest. Out of 3% freshwater, we have, only 1% of them that easily accessible.

Some policies they might do is to put limits on water usage, like making sure that people don't use too much water in baths and when they are tending to their gardens.

Reduce the use of water can conserve water levels.

In conclusion, reduce the use of water can conserve water levels.

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Answer:

The volume of the sample of the gas is found to be 12.90 L.

Explanation:

Given pressure of the gas = P = 1.10 atm

Number of moles of gas = n = 0.6000 mole

Temperature = T = 288.15 K

Assuming the volume of the gas to be V liters

The ideal gas equation is shown below

[tex]\textrm{PV} =\textrm{nRT} \\1.10 \textrm{ atm}\times V \textrm{ L} = 0.6000 \textrm{ mole}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 288.5\textrm{K} \\\textrm{V} = 12.90 \textrm{ L}[/tex]

Volume occupied by gas = 12.90 L

Answer:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

The coefficient of H2O is 2

Explanation:

Ba(OH)2 + HClO4 —> Ba(ClO4)2 + H2O

Now let us balance the equation as shown below:

There are 2 atoms of Cl on the right and 1 atom on the left. It can be balanced by putting 2 in front of HClO4 as shown below:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + H2O

Now, there are a total of 4 atoms of H on the left and 2 on the right. It is balanced by putting 2 in front of H2O as shown below

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

Now, the equation is balanced. From the balanced equation, the coefficient of H2O is 2

The balanced molecular equation for the reaction of barium hydroxide (Ba(OH)₂) with perchloric acid (HClO₄) is:

Ba(OH)₂ + 2HClO₄ -> Ba(ClO₄)₂ + 2H₂O

In this equation, the coefficient of H₂O is 2.

A balanced equation is a chemical equation in which the number of atoms of each element is equal on both sides of the equation. It represents a chemical reaction by showing the reactants on the left side and the products on the right side, with appropriate coefficients to balance the equation.

In a balanced equation, the total mass and the total charge of the reactants are equal to the total mass and total charge of the products. This ensures that the law of conservation of mass and the law of conservation of charge are satisfied.

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The electrical current in a circuit is measured in amperes (amps). According to Ohm's Law, current (I) equals voltage (V) divided by resistance (R). Understanding these units helps grasp the flow of electricity in circuits.

The electrical current in a circuit is measured in amperes (often abbreviated as amps and symbolized by 'A'). According to Ohm's Law, the electric current (I) can be calculated by dividing the voltage (V) by the resistance (R). These relationships and units help in understanding the flow of electric current in circuits:

Answer: 120.15

Explanation:

Answer:

120.15

Explanation:

Look at the periodic table

Answer:

96 grams are required.

Explanation:

Given data:

Mass of K₂SO₄ required = ?

Mass of K₂SO₄ from = 1200 g of 8%

Solution:

Formula:

m/m% = mass required / mass given

Now we will put the values:

8%= x / 1200 g

8/100 = x / 1200 g

0.08 = x / 1200 g

0.08 × 1200 g= x

x = 96 g

So 96 gram of 1200 g is required.

Answer:

Explanation:

Atomic mass is the sum of number of protons and neutrons while atomic number is the number of protons or electrons.

A neutral atom has equal number of protons and electrons that's why atomic number could be either number of protons or electrons.

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Mercury                Hg                  80            200          80                120

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 200 - 80

number of neutrons = 120

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Tungsten                 W              74                 184             74            110

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 184 - 74

number of neutrons = 110

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Sodium                 Na              11                 23             11                  12

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 23 - 11

number of neutrons = 12

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Antimony               Sb              51                122             51                  71

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 122 - 51

number of neutrons = 71

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Silver                   Ag               47                108             47                61

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 108 - 47

number of neutrons = 61

Answer:

(13) billions

Big bang

expanding

quickest

nebula

hydrogen

giants

less,sun

fuel

helium

energy

supernova

white

smaller

neutron

planets/homes

Catalyst increase the rate of reaction

Catalyst decrease the activation energy needed to start a reaction

They are not used up in the reaction

Catalyst are not very specific

Explanation:

From the basic chemistry it is known Catalysts are substance that accelerates the rate of reaction without altering the nature of reaction.

Catalysts decreases the energy required for activation, in order to make collisions quicker.

Then, Catalyst just alters the rate of reaction alone and doesn't takes part in the chemical reaction.

Some catalysts are specific. But in general most of the catalysts are not specific in nature.

The mixture is a solution

Its a solution because two substances mixed

Final answer:

To calculate the standard reduction potential for each metal and organize them into a standard reduction table, we can use the formula Ecell = Ered - Eox. The standard potential for Q is -0.38V and for G is +0.72V.

Explanation:

To calculate the standard reduction potential for each metal, we can use the formula Ecell = Ered - Eox. Given the reduction potentials for Q and G, we can assume the reduction potential for Q is +0.38V and the reduction potential for G is -0.72V. Since Q is oxidized when connected to the standard hydrogen electrode, its standard potential is negative (-0.38V). On the other hand, since G is reduced when connected to the standard hydrogen electrode, its standard potential is positive (+0.72V).

Organizing the metals into a standard reduction table:

MetalStandard Reduction Potential (E°)Q-0.38VG+0.72V

Metal B has the highest standard reduction potential (0.85 V), and metal E follows closely (0.63 V). B-E galvanic cell would yield the highest potential due to their strong reduction tendencies.

To calculate the standard reduction potential for each metal, you can use the Nernst equation:

[tex]E_{\text {cell }}^{\circ}=E_{\text {cathode }}^{\circ}-E_{\text {anode }}^{\circ}[/tex]

where [tex]E_{\text {cell }}^{\circ}[/tex] is the standard cell potential, [tex]E_{\text {cathode }}^{\circ}[/tex] is the standard reduction potential of the cathode, and [tex]E_{\text {anode }}^{\circ}[/tex] is the standard oxidation potential of the anode.

First, let's assign oxidation numbers and write the balanced half-reactions for each cell:

1. [tex]\mathrm{A}(\mathrm{s})+\mathrm{B}^{2+}(\mathrm{aq}) \rightarrow \mathrm{A}^{2+}(\mathrm{aq})+\mathrm{B}(\mathrm{s})[/tex]

Reduction half-reaction: [tex]\mathrm{B}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{B}(\mathrm{s})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0.85

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

2. [tex]\mathrm{B}^{2+}(\mathrm{aq})+\mathrm{C}(\mathrm{aq}) \rightarrow \mathrm{B}(\mathrm{s})+\mathrm{C}^{2+}(\mathrm{aq})[/tex]

Reduction half-reaction: [tex]\mathrm{C}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{C}^{2+}(\mathrm{aq})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = −0.24

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

3. [tex]2 \mathrm{D}^{+}(\mathrm{aq})+\mathrm{C}(\mathrm{s}) \rightarrow 2 \mathrm{D}(\mathrm{s})+\mathrm{C}^{2+}(\mathrm{aq})[/tex]

Reduction half-reaction: [tex]\mathrm{C}(\mathrm{s})+2 e^{-} \rightarrow \mathrm{C}^{2+}(\mathrm{aq})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0

[tex]E_{\text {anode }}^{\circ}[/tex] = 0.58

4. [tex]\mathrm{B}(\mathrm{s})+\mathrm{B}^{2+}(\mathrm{aq}) \rightarrow \mathrm{B}^{2+}(\mathrm{aq})+\mathrm{B}(\mathrm{s})[/tex]

Reduction half-reaction: [tex]\mathrm{B}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{B}(\mathrm{s})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

5. [tex]\mathrm{B}(\mathrm{s})+\mathrm{E}^{2+}(\mathrm{aq}) \rightarrow \mathrm{B}^{2+}(\mathrm{aq})+\mathrm{E}(\mathrm{s})[/tex]

Reduction half-reaction:  [tex]\mathrm{E}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{E}(\mathrm{s})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0.63

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

Now, let's calculate the standard reduction potentials for each metal:

[tex]\begin{aligned}& E_{\mathrm{B}}^{\circ}=0.85-0=0.85 \\& E_{\mathrm{C}}^{\circ}=-0.24-0=-0.24 \\& E_{\mathrm{D}}^{\circ}=0-0.58=-0.58 \\& E_{\mathrm{B}}^{\circ}=0 \\& E_{\mathrm{E}}^{\circ}=0.63-0=0.63\end{aligned}[/tex]

The two metals that would produce the highest cell potential in a galvanic cell are the ones with the highest standard reduction potentials. In this case, metals B and E have the highest reduction potentials, so a galvanic cell composed of B and E would have the highest cell potential. The reason is that a higher standard reduction potential indicates a stronger tendency to be reduced, and therefore, a higher cell potential in a galvanic cell.

Answer:

C. It lists only the substances that are changed.

Explanation:

Balanced Chemical equation:

HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)

Ionic equation:

H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.  This'e why it is written in net ionic equation.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

Final answer:

A net ionic equation lists only the substances that change during a reaction, excluding spectator ions that do not participate in the chemical process. Therefore, the correct answer is C: It lists only the substances that are changed.

Explanation:

A net ionic equation is a chemical equation that shows only the species that actually participate in the reaction. These species are the ions that undergo a chemical or physical change during the reaction, which is different from the spectator ions that do not participate in the reaction. Spectator ions are present in the solution before and after the chemical reaction and do not undergo any change, so they are not included in the net ionic equation.

Correctly answering the student's question, a net ionic equation provides information about option C: It lists only the substances that are changed. This type of equation demonstrates the actual chemical change between the ionic compounds, excluding all the spectator ions that remain unchanged during the reaction process.

287.39 grams of Al2(SO4)3 is formed if 250g H2SO4 completely reacted with aluminum.

Explanation:

Balanced chemical equation:

2Al + 3H2SO4->Al2(SO4)3+H2

Data given:

atomic mass of Al2(SO4)3 = 342.14 gram/mole

mass of H2SO4 given = 250 gram

atomic mass of one mole of H2SO4 = 98.079 grams/mole

number of moles = [tex]\frac{mass}{atomic mass of one mole}[/tex]

number of moles = [tex]\frac{250}{98.079}[/tex]

number of moles = 2.54 moles

from the equation it can be seen as

3 moles of H2SO4 will react to give 1 mole Al2(SO4)3

2.54 moles of H2SO4 will react to give x moles of Al2(SO4)3.

[tex]\frac{1}{3}[/tex]= [tex]\frac{x}{2.54}[/tex]

x = 0.84 moles of Al2(SO4)3 is formed.

to calculate mass of the Al2(SO4)3 = Number of moles x atomic weight of one mole

= 0.84  x  342.14

= 287.39 grams of Al2(SO4)3 is formed.

Answer:

C5H12 + 8O2 —> 5CO2 + 6H2O

The coefficients are 1, 8, 5,6

Explanation:

The equation for the reaction is given below:

C5H12 + O2 —> CO2 + H2O

Now let us balance the equation. This is illustrated below:

There are 5 atoms of C on the left side and 1atom on the right side. It can be balance by putting 5 in front of CO2 as illustrated below:

C5H12 + O2 —> 5CO2 + H2O

There are 12 atoms of H on the left side and 2atoms on the right. It can be balance by putting 6 in front of H2O as illustrated below:

C5H12 + O2 —> 5CO2 + 6H2O

There are a total of 16 atoms of O on the right side and 2atoms on the left side. It will be balance by putting 8 in front of O2 as illustrated below:

C5H12 + 8O2 —> 5CO2 + 6H2O

Now we see clearly that the equation is balanced as the number of atoms of the different elements on both sides of the equation are the same.

The coefficients are 1, 8, 5,6

Answer:

M = 0.43× 10⁵ g/mol

Explanation:

Given data:

Mass of protein = 1.30 g

Volume of water = 100.0 mL ( 100/1000 =0.1 L)

Pressure of solution = 0.0074 atm

Temperature = 298 K

Molar mass of protein = ?

Solution:

Formula:

PV = nRT

n = PV / RT

n = 0.0074 atm ×0.1 L / 0.0821 atm. L / mol.K × 298 K

n = 0.00074 / 24.5 /mol

n = 3.0 × 10⁻⁵ mol

Molar mass of protein:

Number of moles = mass /  molar mass

3.0 × 10⁻⁵ mol = 1.30 g/ M

M = 1.30 g/  3.0 × 10⁻⁵ mol

M = 0.43× 10⁵ g/mol

Answer:

that's because....

group 1 (e.g Na, K) those tend to lose one electron to gain noble gas electron configuration.

they can achieve that by just losing one electron from their outer shell.

as you go down the group 1, element gets bigger in size, which means there is more space between nucleus (which is in center of atom) and electron of outer shell. the more far away they are the less attraction force between them.

so its easier for potassuim to lose one electron than for lithuim.

so that means potassium will easily give up 1 electron to react with non metal or other element therefore it is more reactive than lithuim

but in case of non metal, the opposite happens but simple to understand.

as you go down the group 7 (halogen- Cl, Br, I) element will get bigger therefore force between nucleus and outer electron is getting smaller. they have to gain 1 electron in order to fill the outer shell (to gain noble gas electron configuration.)

as florine is more smaller in size than clorine it is more reactive because florine has more tendency to pull extra electron from metal or other element towards its side. so it easily gain 1 electron to react.

Answer:

hope it's helpful to you .

your 9th question is wrong but I did it correctly

it's not BaS2 it's BaS

The student's inquiry involved balancing a series of chemical equations, a fundamental concept in stoichiometry. Each balanced equation ensures that there is the same number of each element's atoms on the reactant side as on the product side, in accordance with the law of conservation of matter.

The questions you've posed involve stoichiometry, a field in chemistry that quantifies the relationships of different substances in a chemical reaction. Balancing chemical equations involves ensuring the conservation of atoms (each element in reactants should be equal to the count of the same element in products). Here are the balanced equations:

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Answer: A

Explanation:

Balancing a chemical reaction, we must take into consideration every element both at the reactant and products side.

Since we were told propane reacts with oxygen to produce steam and carbon dioxide, we already have an idea of how the equation would be just remaining balancing the stoichiometry of the equation.

C3H8 + 5O2 =====》 3CO2 + 4H20

From the equation above,

3 atoms of carbon is present at reactant side and 3 carbon is also at the product side.

8 Hydrogen at reactant = 4 * 2 Hydrogen at product.

10 Oxygen at reactant = 3*2 + 4 oxygen at product

The equation must be balanced because law of conservation of matter must take place in every chemical reaction, matter can neither be created nor destroyed but can change form.

Answer:

A

Explanation:

Propane burns in oxygen to produce carbon dioxide and steam. The chemical equation is written with chemical symbols below:

C3H8 + O2  CO2 + H2O

There are three carbon atoms on the left side, but only one on the right, so we need to put a 3 in front of the carbon dioxide molecule to give three carbons on each side:

C3H8 + O2  3CO2 + H2O

There are eight hydrogen atoms on the left side and two on the right side, so we need to place a 4 in front of the water molecules on the right side:

C3H8 + O2  3CO2 + 4H2O

There are 2 oxygen atoms on the left side and 10 on the right side, so we need to place a 5 in front of the oxygen molecule on the left side:

C3H8 + 5O2  3CO2 + 4H2O

The equation has been balanced.

Answer:

A charge of -3

Explanation:

If you look on a periodic table you will find that phosphorus is 3 elements away from the nearest noble gas argon. This means that phosphorus would prefer a charge of -3!

Answer:typically it will be -3

Explanation:

It prefers to take up 3 electrons and thereby become phosphide with a -3 charge. since it is a nonmetal it will take up electrons making it negative as an ion. In order to fill up its last shell, to become stable, to form an octet it will need 3 added electrons which will give it that -3 charge. An atom of phophorus will be neutral, An ion of phsphorus will have a -3 charge.

Answer:

d

Explanation:

The light is an electromagnetic radiation which can be perceived by our human eye. The beam of light travel fastest in air. The correct option is D.

The light is defined as an electromagnetic radiation which help us to see the objects. It is composed of small packets of energy called photons. The light always moves in a straight line. Light travels at a faster rate than sound waves.

The speed of light is found to be 3 × 10⁸ m/s. Light does not require a physical medium for the propagation. It is known as a transverse wave which travels without the use of medium.

According to Einstein's theory of relativity, nothing can travel faster than light. When light is incident on any surface, the particles of light collide with the surface and thereby reflection and refractions occur.

Thus the correct option is D.

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Answer:

Explanation:

The answer choices are:

In a simple parallel circuit, each component (resistor) is connected directly to the battery forming different branches or pathways to the current.

Thus, the ends of each resistor receives the total potential difference or voltage from the battery, which is what the statement B. asserts. Hence, statement B is true.

On the other hand, the current will split among the different pathways, following Ohm's law: the greater the resistance of the resistor the lower the current. Thus, the statement A is false.

For a parallel circuit, the total resistance decreases as more resistors are added, which means that, again following Ohm's law, the current will increase, contradicting the statement C. Thus, the statement C is false.

It is in the series circuit that 'the sum of the voltage drops will equal the total voltage"; in a parallel circuit the voltage drop is the just one and the same for each resistor. Thus, the statement D is false,too.