3x+4y= -23. x=3y+1. X___. Y___

Answers

Answer 1

X=-5

Y=-2

Explanation:

3x+4y= -23. X=3y+1. X___. Y___

Related Questions

Angles of elevation and depression-SOMEONE HELP ME

Answers

If the angle of depression is 28° the complementary angle in the triangle is 62°. With this you can use soh-cah-toa to find the x value.

cos62 = 350/x; multiply both sides by x

cos62 x = 350; divide both sides by cos62

x = 350 / cos62

x = 745.519

x = 746 ft

Hope this helps you!

Jay on started off his penny collection with 1 penny. He then adds 5 pennies to his collection each day. How could you change the above scenario to make it a geometric series rather than an arithmetic series?

Answers

Answer:

By doubling each day

Step-by-step explanation:

Jay is increasing  daily a fixed amount of pennies to his collection.  That's an arithmetic series, because to obtain the next term you have to do an addition.

To get a geometric series or progression you have to find the next term through multiplication.

So, if he wants to convert his series into a geometric series, he'd have to double his contribution to his collection each day (as an example).

What’s the value of y

Answers

Answer:

  y = 60°

Step-by-step explanation:

The measure of angle y is half the measure of the subtended arc, so is ...

  y = 120°/2 = 60°

Find the measure of AED

Answers

Answer:

D) 155°

Step-by-step explanation:

The marked vertical angles are equal in measure, so ...

5x = 3x+10

2x = 10

x = 5

5x = 25 . . . . measure of angle AEB

Angle AED is the supplement of angle AEB, so is ...

180° -25° = 155°

Picture below, help fast please!

Answers

Answer:

[tex]x=21,y=25[/tex]

Step-by-step explanation:

The given equation is:

[tex]\frac{(5-3i)(x+iy)}{(4-5i)}=(2+i)^2-(3-4i)^2[/tex]

Apply difference of two squares on the RHS.

[tex]\frac{(5-3i)(x+iy)}{(4-5i)}=[(2+i)+(3-4i)][(2+i)-(3-4i)[/tex]

Simplify the RHS.

[tex]\frac{(5-3i)(x+iy)}{(4-5i)}=(5-3i)(5i-1)[/tex]

Expand the RHS

[tex]\frac{(5-3i)(x+iy)}{(4-5i)}=(10+28i)[/tex]

Cross multiply to get:

[tex](5-3i)(x+iy)=(10+28i)(4-5i)[/tex]

Expand both sides

[tex](5x+3y)+(5y-3x)i=180+62i[/tex]

Comparing the complex parts, we obtain:

[tex]5y-3x=62...(1)[/tex]

Comparing the real number parts we get;

[tex]5x+3y=180...(2)[/tex]

Solving equations (1) and (2) simultaneously; we get:

[tex]x=21,y=25[/tex]

What is the value of the expression....

Answers

The right answer is Nine.

Answer:

The answer is 9.

Step-by-step explanation:

If you substitute a and b with the numbers given, the equation you'll have to solve is: 2(5)+2-3.

2(5)=10 and 2-3=-1

Once you subtract 10-1, the answer would be 9.

You need 20 liters of 20% acid solution. You have jugs of 10% solution and 25% solution. How many liters of each should you combine to get the needed solution?

Answers

Answer:

6.(6) and 13.(3) liters.

Step-by-step explanation (this way is not the shortest one):

1. the basic rule is: the mas/volume of pure substance after and before combination is the same.

2. There is 4 liters of pure substance in 20*0.2 acid solution (20*0.2=4);

3. if 'x' is the volume of pure substance in 10%-solution; and if 'y' is the volume of pure substance in 20%-solution, then their sum of volumes is 4. It means, x+y=4 - this is the 1-st equation for system.

4. the volume of 10%-solution is x/0.1=10x; the volume of 20%-solution is y/0.25=4y; their sum is 20 litres. It means, 10x+4y=20 - this is the 2-d equation of the system.

5. to calculate the volumes of the pure substance:

[tex]\left \{ {{x+y=4} \atop {10x+4y=20}} \right.  \ =>\ \left \{ {{x=\frac{2}{3} } \atop {y=\frac{10}{3} }} \right.[/tex]

6. to calculate the volume of 10%-solution: 2/3 *10=20/3≈6.(6) litres;

to calculate the volume of 25%-solution: 10/3 *4=40/3≈13.(3) litres.

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