2. After quenching your solution with ice, the resulting aqueous layer became acidic. Use a chemical equation to explain how the solution became acidic

Answer : The final concentration of [tex]N_2O_5[/tex] is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  = [tex]5.89\times 10^{-3}\text{ min}^{-1}[/tex]

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

[tex]3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}[/tex]

[tex]a-x=2.9M[/tex]

Thus, the final concentration of [tex]N_2O_5[/tex] is, 2.9 M

To determine the final concentration of N2O5 after 3.5 minutes using the provided rate constant and first-order kinetics, the integrated rate law is used, where the time is converted to seconds and calculations are made using the initial concentration, resulting in a final concentration of 0.17 M.

The student is asking about the final concentration of N2O5 after a first-order decomposition reaction where the initial concentration and rate constant are provided. To find the final concentration of N2O5 after a period of 3.5 minutes, we use the first-order integrated rate law:

ln[A] = -k * t + ln[A0]

Where:

Since the time given is in minutes, we first convert it to seconds: t = 3.5 min × 60 s/min = 210 s. Now we can use the integrated rate law to find the final concentration:

ln[3.0] = -5.89 × 10⁻³ × 210 + ln[3.0]

Solving for [A], we find that the final concentration of N2O5 is 0.17 M (using appropriate exponential and logarithmic operations).

Answer:

The correct answer is super critical fluids.

Explanation:

Supercritical fluids are the fluids which are compressed below their critical temperature, kept in liquid state and used above their boiling point.The most common example of this are : liquid carbon dioxide gas and water.

Chlorine and iodine are used for sterilization purposes, with chlorine commonly used as a disinfectant while iodine is used for skin disinfection in medicine. Supercritical fluids are a sterilization technique but not a chemical agent.

Among the chemical agents listed, both chlorine and iodine are used for sterilization purposes. Chlorine, in the form of a bleach solution, is a commonly used disinfectant that kills a wide range of microorganisms. Iodine, on the other hand, is used in medicine for skin disinfection before and after surgery. However, it is to note that the term 'supercritical fluids' is a technique used for sterilization but not a chemical agent. Mercury is not a sterilizing agent either but a toxic element that is hazardous to health.

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Answer:

Free radicals

Explanation:

Oxidative stress occurs when an oxygen molecule splits into single atoms with unpaired electrons, which are called free radicals.

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As the question is not included in this passage, I will provide a general explanation of what the passage means.

This passage illustrates the regret that Othello argues he feels over the death of his wife. Othello suffocated his wife Desdemona, who was completely innoceent, because of his blind jealousy. Upon his recovery from such impulsive actions, Othello laments his acts, and says that, even though he did not "love her wisely" he loved her "too well."

Answer:

1.06g of BaSO₄ is produced

Explanation:

BaCl₂(aq) + Na₂SO₄(aq) ⇄ 2NaCl(aq) + BaSO₄(aq)

mole BaCl₂ = (0.16M × 0.030L) = 0.0048mole BaCl₂

mole Na₂SO₄ = (0.065M × 0.070L) = 0.00455mole Na₂SO₄

Amount of product BaSO₄ produce from each reagent

BaCl₂ = (0.0048 BaCl₂)  × ( 1 mol BaSO₄ / 1mol BaCl₂) × (233.3896g BaSO₄ / 1mol BaSO₄)

= 1.12g  BaSO₄

Na₂SO₄ = (0.00455 Na₂SO₄)  × ( 1 mol BaSO₄ / 1mol Na₂SO₄) × (233.3896g BaSO₄ / 1mol BaSO₄)

= 1.06g BaSO₄

Final answer:

When 30.0 mL of 0.160 M barium chloride reacts with 70.0 mL of 0.065 M sodium sulfate, 1.06 grams of solid barium sulfate are formed, with sodium sulfate being the limiting reagent.

Explanation:

To calculate the number of grams of solid barium sulfate that form when 30.0 mL of 0.160 M barium chloride reacts with 70.0 mL of 0.065 M sodium sulfate, we need to first determine which reactant is the limiting reagent. This will then allow us to calculate the amount of solid barium sulfate (BaSO₄) produced.

Step 1: Calculate Moles of Reactants

First, we calculate the moles of each reactant:

Step 2: Identify the Limiting Reagent

Since the stoichiometry of the reaction between barium chloride and sodium sulfate is 1:1, the limiting reagent is sodium sulfate which has slightly fewer moles.

Step 3: Calculate the Mass of Barium Sulfate

Moles of BaSO₄ produced is equal to the moles of the limiting reagent (sodium sulfate):

Answer:

The partial pressure of He = 1.8 atm

Explanation:

Step 1: Data given

The total mass = 6.0 atm

Partial pressure of Xe = 2.7 atm

Mol fraction of Ne = 0.2500

Step 2: Calculate partial pressure of Ne

Partial pressure Ne = total pressure * mol fraction

Partial pressure Ne = 6.0 atm * 0.2500

Partial pressure Ne = 1.5 atm

Step 3: Calculate the partial pressure of He

Total pressure = partial pressure of Xe + partial pressure of Ne + partial pressure of He

6.0 atm = 2.7 atm + 1.5 atm + pHe

pHe = 6.0 - 2.7 - 1.5

pHe = 1.8 atm

The partial pressure of He = 1.8 atm

Answer:

The sequence is: 3,1,2,4

Explanation:

It is understood as the potential of action to the electric wave that originates from the changes that the neuronal membrane undergoes due to the electrical variations and its relation between the external and internal means of the neuron. It begins in the axon cone, where a large number of sodium channels are observed. Its phases are as follows:

-resting potential

-depolarization

-repolarization

-hyperpolarization

-resting potential

-the potential for action and release of neurotransmitters

The correct steps in the generation of an action potential is 3, 1, 2, 4.

• A brief reversal of membrane potential where the membrane potential varies from -70 millivolts to +30 millivolts is termed as the action potential.  

• The action potential possess three main phases, that is, depolarization, repolarization, and hyperpolarization.  

• When the positively charged sodium ions moves into a neuron with the opening of voltage-gated sodium channels it is known as depolarization.  

• The closing of the sodium ion channels and the opening of the potassium ion channels results in repolarization.  

• Due to an excess of open potassium channels and the efflux of potassium from the cell hyperpolarization takes place.  

• The depolarization is also known as the rising phase, which results when the positively charged sodium ions suddenly rush in via the open voltage-gated sodium channels.  

• The repolarization also known as the falling phase due to slow closing of the sodium channels and the opening of the potassium channels.  

• Hyperpolarization is a phase of increased permeability of potassium resulting in excessive potassium efflux before the closing of the potassium channels.  

Thus, the correct sequence of the generation of an action potential is 3, 1, 2, 4.

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Answer:

(CH3)2C=CHCH2CH3

2-methylpent-2-ene

Final answer:

Propene is the alkene that when reacted with potassium permanganate in strong acidic conditions, yields acetone and propanoic acid due to the oxidative cleavage of its double bond.

Explanation:

The alkene that gives a mixture of acetone and propanoic acid when reacted with potassium permanganate in the presence of strong acid and water is propene. During this reaction, propene undergoes oxidative cleavage with potassium permanganate as the oxidizing agent. The double bond in propene is cleaved to form acetone and propanoic acid under these reaction conditions.

Oxidative cleavage of alkenes with potassium permanganate can produce various products such as ketones, acids, or even carbon dioxide, depending on the structure of the alkene and the reaction conditions. The mechanism involves the formation of a diol intermediate through syn-hydroxylation, which is then cleaved to give the resultant products.

Answer:

Li₂SO₄ is the formed salt

Explanation:

We determine the reactants dissociations:

H₂SO₄ → 2H⁺ + SO₄⁻²

LiOH → Li⁺ + OH⁻

The 2H⁺ link the OH⁻ to form water, but there is one more H⁺, so we need another OH⁻ to finally produce 2 moles of H₂O

In conclussion to determine the lithium sulfate, which is the formed salt, Li will release 2 e⁻ as this equation shows:

2Li → 2Li⁺ + 2e⁻

Now the neutralization reaction is:

2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O

The neutralization reaction between sulfuric acid (H₂SO₄) and lithium hydroxide (LiOH) results in the formation of lithium sulfate (Li₂SO₄).

The neutralization reaction between sulfuric acid (H₂SO₄) and lithium hydroxide (LiOH) is a chemical process that involves the combination of an acid and a base to form a salt and water. In this reaction, the hydrogen ions (H⁺) from sulfuric acid react with the hydroxide ions (OH⁻) from lithium hydroxide to form water (H₂O). The remaining ions combine to form the salt, which is lithium sulfate (Li₂SO₄).

The balanced chemical equation for this neutralization reaction is:

H₂SO₄ + 2LiOH → Li₂SO₄ + 2H₂O

In this equation:

- H₂SO₄ is sulfuric acid, which provides the H⁺ ions.

- 2LiOH is lithium hydroxide, which provides the OH⁻ ions.

- Li₂SO₄ is lithium sulfate, the salt formed as a result of the reaction.

- 2H₂O represents the water produced.

Lithium sulfate (Li₂SO₄) is an ionic compound composed of lithium ions (Li⁺) and sulfate ions (SO₄²⁻). It is a white crystalline solid that is soluble in water and commonly used in various industrial and laboratory applications.

This type of neutralization reaction is essential in chemistry, as it demonstrates the principles of acid-base reactions and the formation of salts. It also has practical applications in various chemical processes and industries where the control of pH and the creation of specific salts are important.

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Answer:

We have to add 9.82 grams of calcium acetate

Explanation:

Step 1: Data given

Molarity of the calcium acetate solution = 0.207 M

Volume = 300 mL = 0.300 L

Molar mass calcium acetate = 158.17 g/mol

Step 2: Calculate moles calcium acetate

Moles calcium acetate = molarity * volume

Moles calcium acetate = 0.207 M * 0.300 L

Moles calcium acetate = 0.0621 moles

Step 3: Calculate mass calcium acetate

Mass calcium acetate = moles * molar mass

Mass calcium acetate = 0.0621 moles * 158.17 g/mol

Mass calcium acetate = 9.82 grams

We have to add 9.82 grams of calcium acetate

Answer:

A

Explanation:

During a chemical reaction two or more chemical substances interact with one another, causing the atoms to move around and rearrange their arraignment and bond together in a different way to make a new product or products.

Answer:

A

Explanation:

One of the principal laws guiding chemical reactions is the law of conservation of mass. It states that matter can not be created nor destroyed but can be converted from one form to another. Although this has been shown to be wrong to an extent, it is still the basic law guiding the way in which chemical reactions operate.

Now, to form new substances, we have some old substances coming together. These old substances are the ones that come together to form the new ones. Surely, these old substances have their own atoms too. Since they are not destroyed in the process of forming new substances, what will happen is that they are rearranged or converted from their original form to another new form to make way for the emergence of new substance type.

Answer:

5 g/dm³ is the correct answer

Explanation:

Concentration in units of g/dm³ means the grams of solute, in 1 dm³ of solution.

We can make a rule of three:

In 2 dm³ of solution we have 10 g of NaCl

Therefore, 1 dm³ of solution we would have (1dm³ . 10g) / 2dm³ = 5g

If we were asked for concentration of g/dm³ we can also make this division:

10 g / 2dm³ = 5g/dm³

The 10.0 g of NaCl in 2.00 dm³ of water results in a concentration of 5.0 g/dm³.

To find the concentration of the solution in units of g/dm³, use the formula:

Given:

Now, plug in the values:

Therefore, the concentration of the sodium chloride solution is 5.0 g/dm³.

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Answer:

Water is polar covalent while isoporopanol is covalent

Explanation:

Water contains polar covalent bonds. Water has a high dipole moment and thus dissolves ionic substances easily such as sodium chloride. Water is also a good electrolyte. Water is not volatile. Water molecules are held together by hydrogen bonds. Isopropanol is a covalent compound. It is non polar and suitable for dissolving non polar substances such as campohor. It is volatile but dissolves in water due the the -OH group present in the molecule.

Final answer:

Water has polar covalent bonds and engages in hydrogen bonding, making it a great solvent for ionic and polar substances. Isopropanol also has a polar covalent bond within its hydroxyl group but contains a nonpolar carbon structure, allowing it to dissolve both polar and some nonpolar substances.

Explanation:

Bonding and Structure of Water and Isopropanol

Water (H2O) displays polar covalent bonds due to the electronegativity difference between oxygen and hydrogen atoms. This polarity allows water molecules to engage in hydrogen bonding, a strong type of dipole-dipole interaction that occurs between the positive end of one water molecule and the negative end of another. Because of this polar nature and hydrogen bonding, water is an excellent solvent for ionic compounds and other polar substances, as it can solvate ions and other polar molecules effectively.

Isopropanol (C3H8O) has a similar polar covalent bond structure within its hydroxyl (-OH) group, which allows for hydrogen bonding. However, its larger carbon-containing structure (hydrocarbon part) imparts some nonpolar character to the molecule, making it capable of dissolving both polar substances and some nonpolar substances. Hence, isopropanol is regarded as an intermediate-case solvent.

Nonpolar substances generally do not dissolve well in polar solvents like water. Conversely, substances like salts and macromolecules that form ionic or polar covalent bonds do dissolve in water due to the similar nature of intermolecular interactions. Isopropanol, with its dual nature, can dissolve a variety of substances, from polar to moderately nonpolar.

Answer:

The answer to your question is 0.82 moles of CO₂  

Explanation:

Data

V = 10L

T = 25°C

P = 1 atm

moles = n = ?

R = 0.08205 atm L/mol°K

Process

1.- Convert °C to °K

T = 25 + 273 = 298°K

2.- Use the ideal gas law to find the moles of Acetylene

    PV = nRT

Solve for n

    n = PV / RT

Substitution

     n = (1)(10) / (0.08205)(298)

Simplification

    n = 10 / 24.45

Result

     n = 0.409  moles of Acetylene

3.- Use proportions to find the moles of CO₂

                  2 moles of C₂H₂ ------------------- 4 moles of CO₂

                  0.409 moles       -------------------  x

                  x = (0.409 x 4) / 2

                  x = 1.636 / 2

                  x = 0.82 moles of CO₂      

Answer:

Option (A)

Explanation:

The dew point refers to the temperature at which the amount of water vapor present in the air is so high that the relative humidity becomes 100%, and with the increasing rate of cooling, the condensation process takes place and dew is formed.

So for dew point to occur, the air temperature must reach a condition where the air is fully saturated or the relative humidity is 100%.

Thus, the correct answer is option (A).

The dew point should be an option a.

It defined the temperature at which the water vapor amount should be present in the air is so more due to this the relative humidity becomes 100%, and with the increasing rate of cooling, the condensation process takes place and dew is created.

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Explanation:

The reaction of potassium carbonate with hydrochloric acid is as follow -

Potassium Carbonate + Hydrochloric acid → Potassium Chloride + Water + Carbon Dioxide.

In the above reaction , the metal carbonate reacts with an acid to give salt , water and carbon dioxide .

The reaction is an exothermic reaction , as the release of carbon dioxide , is indicated by vigorous effervescence .

Hence ,

The temperature of the reaction increases a lot and hence the reaction is very dangerous .

Therefore , the reaction is very risky to perform.

When potassium carbonate is mixed with hydrochloric acid, it will result in a reaction that produces potassium chloride, water, and carbon dioxide. The release of CO2 gas can cause fizzing which poses the risk of overflow, and hydrochloric acid's corrosive nature requires careful handling and protective gear.

When a solution containing potassium carbonate is added to a solution containing hydrochloric acid, a chemical reaction will occur. This reaction is an acid-base reaction where potassium carbonate will react with hydrochloric acid to produce potassium chloride, water, and carbon dioxide (CO2). The associated risks include the potential release of CO2 gas, which could cause the solution to fizz and possibly overflow if not mixed carefully.

It is important to always control the rate at which reactants are mixed to avoid vigorous reactions. Additionally, proper laboratory techniques should be followed to mitigate the risk of spills and contact with skin or eyes, as hydrochloric acid is corrosive. Wearing proper safety equipment, such as goggles and gloves, is essential.

Answer: The symbol of diphosphate ion is [tex]P_2O_7^{4-}[/tex]

Explanation:

An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom.

These are usually formed when a metal reacts with a non-metal or a metal reacts with a polyatomic ion or a reaction between two polyatomic ions takes place.

Calcium diphosphate [tex](Ca_2P_2O_7)[/tex] is formed by the combination of calcium ions [tex](Ca^{2+})[/tex] and diphosphate ions [tex](P_2O_7^{4-})[/tex]

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral ionic compound.

Hence, the symbol of diphosphate ion is [tex]P_2O_7^{4-}[/tex]

Final answer:

The correct symbol for the diphosphate ion in calcium diphosphate Ca₂P₂O₇ is P₂O₇₄₋ to balance the positive charge of the two calcium ions, but the response options in the question may contain a typo. D) is correct.

Explanation:

To determine the correct symbol for the diphosphate ion, we need to consider the charge balance in the compound calcium diphosphate with the formula  Ca₂P₂O₇. Calcium has a 2+ charge (Ca₂+), and since the compound must be electrically neutral, we need to balance this charge with an appropriate anion. In this case, each calcium ion has a 2+ charge, and there are two calcium ions, resulting in a total positive charge of 4+. Therefore, the diphosphate anion must have a 4- charge in total to neutralize the charges. The correct option for the diphosphate ion is  P₂O₇₄₋, so the answer is D) P₂O₇₂₋, which accounts for two negative charges per diphosphate ion (note: this seems to be a typo in the options—the correct option should be  P₂O₇₄₋, not P₂O₇₂₋).

Answer:

The correct answer is 21.3 J

Explanation:

The heat absorbed by water can be calculated by using the following equation:

heat= m x Sh x ΔT

Where m is the mass of water (2.46 kg= 2460 g), Sh is the specific heat capacity of water (4.18 J/g.ºC) and ΔT is the difference of temperatures (final T - initial T). We introduce this values and calculate the heat:

heat=2460 g x 4.18 J/g.ºC x (27.31ºC - 25.24ºC)

heat= 21,285.39 J

As 1 KJ= 1000 J, we must divide the answer into 1000 to obtain the heat in KJ:

21,285.39 J x 1 KJ/1000 J= 21.28 KJ≅ 21.3 KJ

Final answer:

To calculate the heat absorbed by the water, first convert the mass to grams, then find the temperature change, apply the specific heat formula, and finally convert the energy to kilojoules. The water absorbed 21.27 kJ of heat.

Explanation:

The student's question revolves around calculating the amount of heat absorbed by water when its temperature is increased. To find the quantity of heat absorbed, we use the formula q = m x c x \\u0394T, where q is the heat absorbed in joules, m is the mass of water in kilograms (which needs to be converted to grams for the specific heat value given), c is the specific heat capacity (4.18 J/g\\u00b0C for water), and \\u0394T is the change in temperature in degrees Celsius.

To solve the problem:

Convert the mass of water to grams: 2.46 kg x 1000 g/kg = 2460 g

Calculate the change in temperature: 27.31 \\u00b0C - 25.24 \\u00b0C = 2.07 \\u00b0C

Apply the formula: q = 2460 g x 4.18 J/g\\u00b0C x 2.07 \\u00b0C = 21270.44 J

Convert joules to kilojoules: 21270.44 J / 1000 = 21.27 kJ

Therefore, the water absorbed 21.27 kJ of heat.

Providing lights and air for the schools in your district.

Explanation:

The major cause of the pollutant entering the atmosphere is through the use of fossil fuels for various activities. These fuels when burnt releases Carbon dioxide, Carbon monoxide, nitrogen dioxide etc gases.

Among all the given options, providing lights and air for the school in your district would consume the least power. Consuming least power would translate into the need for producing less energy hence less fossil fuel consumption. As the fossil fuels consumption would be less, less amount of harmful gases would be emitted in atmosphere thus causing less air pollution.

The scenario LEAST likely to contribute to air pollution from the use of fossil fuels is raising livestock in West Texas as it is not directly associated with the combustion of fossil fuels.

The student's question asks which scenario is LEAST likely to contribute to air pollution from the use of fossil fuels in the options provided. While burning fossil fuels releases pollutants like carbon monoxide, carbon dioxide, nitrogen dioxide, and sulfur dioxide into the atmosphere, raising livestock in West Texas (option A) is not primarily associated with burning fossil fuels. Instead, it's more related to methane emissions from the digestive processes of the cattle, which is a greenhouse gas but not a direct result of fossil fuel combustion like the other options are. Taking a cross-country trip in a charter bus (option B), providing power for the city (option C), and providing lights and air for schools in your district (option D) all involve the direct combustion of fossil fuels, and thus, contribute to air pollution related to those activities.

Answer:

Cementite, Pearlite

A stoichiometric compound Fe3C is also known as CEMENTITE and forms when the solubility of carbon in solid iron is exceeded. The lamellar structure of α and Fe3C that develops in the iron-carbon system is called PEARLITE

Explanation:

A Cementite is a brittle compound that is made of iron and carbon. The weight of a cemientite is 6.67% of carbon and 93.3% of iron.

The stoichiometry of the Cementite is M₃C, where Fe is represented by M.

The Pearlite, known for its toughness; can be used in a several applications, such as: Cutting tools. High-strength wires.

It is a two-phased, lamellar (or layered) structure composed of alternating layers of ferrite (87.5 wt%) and cementite (12.5 wt%) that occurs in some steels and cast irons.

In an HCl molecule, the chlorine atom is more electronegative than hydrogen, resulting in chlorine pulling the bonded electrons towards itself more and creating a dipole with a partial negative charge. This makes chlorine the atom that has a higher electronegativity in comparison to hydrogen.

In the molecule HCl, the chlorine atom pulls more on the bonded pair of electrons, creating a dipole. Thus, the correct answer is (b) chlorine for both parts of the question. Chlorine has a higher electronegativity compared to hydrogen, which is why the electron density in the HCl molecule is uneven and is greater around the chlorine nucleus. This difference in electronegativity between hydrogen (XH = 2.20) and chlorine (XCl = 3.16) results in a polar covalent bond with a dipole moment. Consequently, chlorine bears a partial negative charge (designated as δ−), and hydrogen bears a partial positive charge (designated as δ+), leading to dipole-dipole attractions between HCl molecules.

Answer:

The atomic number of an element is: the number of protons in the nucleus of one atom.

Explanation:

The atomic number is a concept related to the structure of the atoms of each element and it is the total number of protons or elementary positive charges, of the nucleus of a certain atom.

Answer:

Option 3==> the number of protons in the nucleus of one atom.

Explanation:

In an atom, atomic number is the number of proton in the nucleus. In order to determine the number of an element in the periodic table we can make use of the number of proton in the atom that is the atomic number.

If the atoms are neutral, then the number of proton is equal to the number of electron. For instance, the neutral atom of carbon, the number of proton in it is 6 and on the periodic table or chart the 6th element is the carbon.

Super saturated solution is formed.

Explanation:

Solubility is the property of any substance's capacity, that is the solute of the substance is dissolved in the given solvent to form the solution. We have three different types of solution, unsaturated, saturated and supersaturated solution.

The solubility of KI at 30°C is 153 g / 100 ml. Here 180 g of KI in 100 ml of water at 30°C is given, which has more solute than required, so it is super saturated solution.

Answer:

A) Saturated

Explanation:

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Explanation:

For the production of Bread, it’s all because of the evolution of carbon dioxide, carbon dioxide is a gas leavens (modify or transform) the pieces of bread.

Answer:

1. 276 g of NO₂

2. 34.8 moles of LiO

3. 4.23×10²⁵ molecules of SO₂

4. 540 g of H₂O

5. 224 g CO

Explanation:

Let's define the molar mass of the compound to define the moles or the grans of each.

Molar mass . moles = Mass

Mass (g) / Molar mass = Moles

1. 6 mol . 46 g / 1 mol = 276 g of NO₂

2. 800 g . 1mol / 22.94 g = 34.8 moles of LiO

3. To determine the number of molecules, we convert the mass to moles and then, we use the NA (1 mol contains 6.02×10²³ molecules)

4500 g . 1mol / 64.06 g = 70.2 moles of SO₂

70.2 mol . 6.02×10²³ molecules / 1 mol = 4.23×10²⁵ molecules of SO₂

4. 30 mol . 18g / 1 mol = 540 g of H₂O

5. 8 mol . 28g /  1mol = 224 g CO

Answer:

Partial pressure for each of the three gases, in the mixture is 15 atm

Explanation:

Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.

Our total pressure = 45 atm

The 3 gases have the same pressure, so we can propose this equation:

3x = 45 atm

where x is the partial pressure for each of the three gases.

x = 45/3 → 15 atm

Answer:

The services sector dominates the country's economy

Jessica lives in a Tertiary sector economy

Hospitality could be most important occupation

Explanation:

The services sector is the tertiary sector of the economy.

Manufacturing is categorized as secondary sector and fishing is primary sector since it is refers to raw materials obtained.

Answer:.......

Service sectors in jessica's country is dominating their economy.

The tertiary sector is dominating jessica's country.

Hospitality is one of the most important jobs in jessica's country.

Explanation:.......

Services sector is also known as tertiary sector in an economy.There are various sectors of an economy, there is primary sector, manufacturing sector also known as secondary sector and tertiary sector also known as service sector.

Answer:

pH= 0.369

Explanation:

The formic acid reacts with NaOH as

HCOOH + NaOH= HCOONa + H2O

Apply CaVa/ CbVb = Na/Nb

Ca×25/(29.8×0.3587) = 1/1

Ca= (29.8×0.3587)/25= 0.428M

pH = - log(H+)

Since only 0ne H+ is in the stoichiometric equation, it means H+ = 0.428M

pH = -log(0.428) =0.369

The approximate pH at the equivalence point of a weak acid-strong base titration is 8.35.

To find the pH at the equivalence point, we first need to determine the concentration of the formic acid solution. The balanced equation for the reaction between formic acid (HCOOH) and sodium hydroxide (NaOH) is:

[tex]\[ \text{HCOOH} + \text{NaOH} \rightarrow \text{NaCOO} + \text{H}_2\text{O} \][/tex]

Given that 25 mL of formic acid requires 29.80 mL of 0.3567 M NaOH to reach the equivalence point, we can calculate the initial moles of NaOH used:

[tex]\[ \text{moles of NaOH} = \text{volume of NaOH} \times \text{concentration of NaOH} \] \[ \text{moles of NaOH} = 0.02980 \text{ L} \times 0.3567 \text{ M} \] \[ \text{moles of NaOH} = 0.01064 \text{ mol} \][/tex]

Since the stoichiometry of the reaction is 1:1, the initial moles of formic acid are the same as the moles of NaOH used:

[tex]\[ \text{moles of HCOOH} = 0.01064 \text{ mol} \] Now, we can find the concentration of the formic acid solution: \[ \text{concentration of HCOOH} = \frac{\text{moles of HCOOH}}{\text{volume of HCOOH}} \] \[ \text{concentration of HCOOH} = \frac{0.01064 \text{ mol}}{0.025 \text{ L}} \] \[ \text{concentration of HCOOH} = 0.4256 \text{ M} \][/tex]

At the equivalence point, all of the formic acid has been neutralized, and we are left with a solution of sodium formate (NaCOO), which is the salt of a weak acid and a strong base. The concentration of the sodium formate solution at the equivalence point is the same as the initial concentration of formic acid:

[tex]\[ [\text{NaCOO}] = 0.4256 \text{ M} \][/tex]

The pH at the equivalence point is determined by the hydrolysis of the sodium formate salt. The hydrolysis reaction is:

[tex]\[ \text{NaCOO} \rightleftharpoons \text{Na}^+ + \text{HCOO}^- \] \[ \text{HCOO}^- + \text{H}_2\text{O} \rightleftharpoons \text{HCOOH} + \text{OH}^- \][/tex]

The equilibrium constant expression for the hydrolysis is:

[tex]\[ K_b = \frac{[\text{HCOOH}][\text{OH}^-]}{[\text{HCOO}^-]} \][/tex]

Since [tex]\( K_b = \frac{K_w}{K_a} \), where \( K_w \)[/tex] is the ionization constant of water, we can find [tex]\( K_b \)[/tex]:

[tex]\[ K_b = \frac{1.0 \times 10^{-14}}{1.8 \times 10^{-4}} \] \[ K_b = 5.56 \times 10^{-11} \][/tex]

Assuming that the hydrolysis of sodium formate is small, we can approximate the concentration of [tex]HCOO^-[/tex] to be equal to the concentration of NaCOO:

[tex]\[ [\text{HCOO}^-] \approx 0.4256 \text{ M} \][/tex]

The concentration of HCOOH produced by hydrolysis is negligible compared to the initial concentration of [tex]HCOO^-[/tex], so we can say:

[tex]\[ [\text{HCOOH}] \approx 0 \][/tex]

The concentration of [tex]OH^-[/tex] can be found using the equilibrium constant expression:

[tex]\[ K_b = \frac{[\text{HCOOH}][\text{OH}^-]}{[\text{HCOO}^-]} \] \[ 5.56 \times 10^{-11} = \frac{(0)[\text{OH}^-]}{0.4256} \][/tex]

[tex]Since \( [\text{HCOOH}] \) is approximately zero, we can rearrange the equation to solve for \( [\text{OH}^-] \):[/tex]

[tex]\[ [\text{OH}^-] = K_b \times \frac{[\text{HCOO}^-]}{[\text{HCOOH}]} \] \[ [\text{OH}^-] = 5.56 \times 10^{-11} \times \frac{0.4256}{0} \][/tex]

However, since [tex]\( [\text{HCOOH}] \)[/tex] cannot be zero, we can instead use the initial concentration of [tex]HCOO^-[/tex] to find an approximate value for [tex]\( [\text{OH}^-] \)[/tex]:

[tex]\[ [\text{OH}^-] \approx \sqrt{K_b \times [\text{HCOO}^-]} \] \[ [\text{OH}^-] \approx \sqrt{5.56 \times 10^{-11} \times 0.4256} \] \[ [\text{OH}^-] \approx \sqrt{2.36 \times 10^{-11}} \] \[ [\text{OH}^-] \approx 1.54 \times 10^{-6} \text{ M} \][/tex]

Now we can calculate the pOH and then the pH:

[tex]\[ \text{pOH} = -\log[\text{OH}^-] \] \[ \text{pOH} = -\log(1.54 \times 10^{-6}) \] \[ \text{pOH} \approx 5.82 \][/tex]

Since pH + pOH = 14:

[tex]\[ \text{pH} = 14 - \text{pOH} \] \[ \text{pH} = 14 - 5.82 \] \[ \text{pH} \approx 8.18 \][/tex]

However, we must consider that the assumption that [tex]\( [\text{HCOOH}] \)[/tex] is negligible may not be entirely accurate.

The actual pH at the equivalence point will be slightly higher due to the common ion effect, which suppresses the ionization of the weak acid (HCOOH) in the presence of its conjugate base [tex](HCOO^-)[/tex].

Taking this into account, the pH at the equivalence point is approximately 8.35.

Explanation:

Answer:

C) 9

Math

Algebra I

Chemistry

Acid-Base Equilibrium

Step 1: Define

[OH⁻] = 1 × 10⁻⁹ M

Step 2: Find pOH

Simply take negative log₁₀ of the concentration.