15. Sulfur hexafluoride is an example of a

The chemical formula for lithium acetate is [tex]LiC_2H_3O_2[/tex]. It consists of one lithium ion [tex](Li^+)[/tex] and one acetate ion [tex](C_2H_3O_2^-)[/tex].

Lithium acetate is composed of lithium ions [tex](Li^+)[/tex] and acetate ions [tex](C_2H_3O_2^-)[/tex].

The formula indicates that for each lithium ion, there is one acetate ion. In chemical formulas, the subscripts indicate the number of atoms of each element present in the compound.

In this case, "Li" represents lithium, "C" represents carbon, "H" represents hydrogen, and "O" represents oxygen.

So, the formula [tex]LiC_2H_3O_2[/tex] indicates that there is one lithium atom, two carbon atoms, three hydrogen atoms, and two oxygen atoms in lithium acetate.

Explanation:

The mass number of an element's atom is gotten by adding the number of protons and neutrons of the atom. Electrons have negligible mass compared to the protons and neutrons hence do not matter. The mass of a nuclear particle ( protons and the neutrons) is based on the 1/12 mass of carbon which is used as the standard for getting the mass of other elements.

If an element has isotopes the relative mass of the element is gotten by adding all the atomic mass numbers of the isotopes and dividing the sum by the number of isotopes.

Final answer:

The missing coefficient in the reaction Cl2O3 + H2O → HCIO3 is 2 in front of HCIO3, resulting in a balanced equation Cl2O3 + H2O → 2 HCIO3, which is a combination reaction.

Explanation:

The missing coefficient in the chemical equation Cl2O3 + H2O → HCIO3 should balance the number of atoms of each element on both sides of the equation. In this case, to balance chlorine and oxygen atoms, we should place a coefficient of 2 in front of HCIO3, resulting in Cl2O3 + H2O → 2 HCIO3. This is an example of a combination reaction, where two or more substances combine to form a single product. Below are several examples of different reaction types for context:

a. Combustion reaction: C6H5CH3 + 9O2 → 7CO2 + 4H2Ob. Decomposition reaction: 2NaHCO3 → Na2CO3 + H2O + CO2c. Synthesis reaction: C + 2H2 → CH4

Answer:

The new volume will be 42, 7 L.

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. The conditions STP are: 1 atm of pressure and 273 K of temperature.

P1xV1/T1 =P2xV2/T2

1 atmx 22,4 L/273K = 0,5atmx V2/260K

V2=((1 atmx 22,4 L/273K )x 260K)/0,5 atm= 42, 67L

Answer:

The answer is choice (4) 268 g.

Explanation:

To find this answer you have to go to the reference table, using Table G, and go to KNO3 at 70°C. Find out how many grams saturate potassium nitrate (134 g). Then you double it (268 g ) because it's asking for grams at 200 grams of water.

1 mole of lead has the greatest mass because its molar mass of approximately 207.2 g/mol is higher than that of silver (107.87 g/mol), copper (63.55 g/mol), and tungsten (183.84 g/mol), and all samples contain Avogadro's number of atoms.

To determine which substance has the greatest mass, we need to compare the molar masses of silver, copper, lead, and tungsten. The molar mass is the mass in grams of one mole of a substance, and it is numerically equivalent to the atomic mass for elements. Let's examine the atomic masses of these elements:

Given that 1 mole of each substance contains the same number of atoms (6.022 × 10²23 atoms, Avogadro's number), the substance with the highest molar mass will have the greatest mass. In this case, lead has the highest molar mass at approximately 207.2 g/mol, and therefore 1 mole of lead will have the greatest mass compared to 1 mole of silver, copper, or tungsten.

Final answer:

Lead (Pb) has the greatest mass.

Explanation:

The substance with the greatest mass in this case would be lead (Pb).

To determine which substance has the greatest mass, we need to compare their molar masses. The molar mass of silver (Ag) is approximately 107.87 g/mol, copper (Cu) is approximately 63.55 g/mol, lead (Pb) is approximately 207.2 g/mol, and tungsten (W) is approximately 183.84 g/mol.

Since lead (Pb) has the highest molar mass of the four substances, it has the greatest mass.

Answer:

gallium

Explanation:

Answer:

74.09 atm

Explanation:

Using the gas laws ( Charles and Boyle's law). We have the formula ,

P1/T1 = P2/T2

Where P1 = 30.3atm

T1 = -100 degree Celsius

to kelvin = -100+ 273 = 173K

T2 = 150 degree Celsius

To Kelvin = 150 = 150+273 = 423K

Imputing values

P1/T1 = P2/T2

30.3/173 = P2/ 423

Cross multiply

173×P2 = 30.3 ×423

173P2 = 12816.9

Divide both sides by 173

P2 = 12816.9/173

P2 = 74.09 atm

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Answer:

P2=74.086atm

Explanation:

Using the formula p1/t1=P2/t2

P1=30.3atm

P2=?

T1=-100°c to Kelvin=273-100=173k

T2=150°c to Kelvin=273+150=423k

30.3\173=x/423

Cross multiply

173x=423×30.3

173x=12816.9

Divide both sides by 173

X=74.086atm

The density of ethanol is 0.78 g/mL and the density of benzene is 8.8 g/mL. Benzene is denser than ethanol.

The density of a substance is calculated by dividing its mass by its volume. To find the density of ethanol, divide its mass (3.9g) by its volume (5.0 mL). The density of ethanol is therefore 0.78 g/mL. To find the density of benzene, divide its mass (44g) by its volume (5.0 mL). The density of benzene is 8.8 g/mL. Since the density of benzene is higher than the density of ethanol, benzene is denser than ethanol.

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The density of ethanol is 0.78 g/mL and the density of benzene is 8.8 g/mL. Benzene is denser than ethanol.

To find the density of each liquid, the formula for density will be used:

[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]

Given:

Ethanol:

Volume [tex](\(V\))[/tex] = 5.0 mL

Mass [tex](\(m\))[/tex] = 3.9 g

Benzene:

Volume [tex](\(V\))[/tex] = 5.0 mL

Mass [tex](\(m\))[/tex]  = 44 g

Density of Ethanol:

[tex]\[ \text{Density of Ethanol} = \frac{3.9 \, \text{g}}{5.0 \, \text{mL}} \][/tex]

[tex]\[ \text{Density of Ethanol} = 0.78 \, \text{g/mL} \][/tex]

Density of Benzene:

[tex]\[ \text{Density of Benzene} = \frac{44 \, \text{g}}{5.0 \, \text{mL}} \][/tex]

[tex]\[ \text{Density of Benzene} = 8.8 \, \text{g/mL} \][/tex]

Answer:

8L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant

P1V1= P2V2

P1 =  2atm, V1 = 12L ,

P2 = 3atm , V2 =

12 × 2 = V2 × 3

Divide both sides by 3

V2 = 24 ÷ 3

V2 = 8L

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Answer:

Tough question

Explanation:

need more detail

Answer: The molar mass of the vapor comes out to be 43.83 g/mol. This problem is solved by using ideal gas equation. The ideal gas equation is shown below

[tex]\textrm{PV} =\textrm{nRT}[/tex]

Explanation:

Volume of gas = V = 247.3 mL  

V = 0.2473 L

Pressure of gas = P = 745 mmHg

1 atm = 760 mmHg

[tex]\textrm{P} = \displaystyle \frac{745}{760} \textrm{ atm} = 0.98026 \textrm{ atm}[/tex]

Temperature of gas = T = 100[tex]^{\circ}C[/tex] = 373 K

Given mass of gas = m = 0.347 g

Assuming molar mass of gas to be M g/mol

Assuming the gas to be an ideal gas, the ideal gas equation is shown below

[tex]\textrm{PV} =\textrm{nRT}[/tex]

Here, n is the number of moles of gas and R is the universal gas constant.

[tex]\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{RT} \\0.98026 \textrm{ atm}\times 0.2473 \textrm{ L} = \displaystyle \frac{0.347 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 373 \textrm{ K} \\M = 43.83 \textrm{ g/mol}[/tex]

Hence, the molar mass of the vapor comes out to be 43.83 g/mol

Answer:

Percent yield = 57%

Explanation:

Given data:

Number of moles of propane = 4.50 mol

Number of moles of carbon dioxide = 7.64 mol

Percent yield = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Now we will compare the moles of propane and carbon dioxide.

                            C₃H₈            :            CO₂

                                 1               ;                3

                                  4.50        :              3×4.50 = 13.5 mol

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield =  7.64 mol / 13.5 mol × 100

Percent yield = 0.57× 100

Percent yield = 57%

Answer:

(A) Removed and solid

Explanation:

Answer with Explanation:

The environment where the sediments are deposited gives an information regarding the rock that eventually forms.

The minerals and textures of the rocks can tell what kind of environment they were formed as they were being deposited. The fossils embedded in the rocks (sedimentary rocks) or the outcrops can also tell what happened on earth during those times. The process of rock accumulation also tells whether there was a high level of flood, strong winds or sub-arctic environments occurring.

This then gives an evidence of the earliest life forms on Earth.

Final answer:

The depositional environment where sediments are collected has a direct impact on the type of sedimentary rock that forms, with factors such as available oxygen affecting characteristics like rock color. This information helps geologists reconstruct past Earth conditions and ecosystems.

Explanation:

The environment where sediments are deposited has significant implications for the sedimentary rock that will eventually form. For instance, beaches and deserts accumulate large deposits of sand, potentially forming sandstone, while the deep ocean floor might host sediments that turn into shale or limestone.

Depositional environments impart specific characteristics to the resulting rocks. Examples of this include the presence of oxygen influencing rock color during and after sediment burial. Understanding these environments allows geologists to reconstruct past Earth conditions and the history of life on our planet.

Sedimentary rocks from one environment might share similar types but can also be found across varying conditions, making pinpointing the depositional environment a challenging task. Yet, clues like sediment properties, rock color, and the presence of fossils provide invaluable insights into the ancient environments where these rocks formed.

Answer:

positive one (+1)

Explanation:

sodium having atomic mass is twenty three (23) and atomic number is eleven (11).

Sodium atom having only one electron in it's outer most shell and it is easy for atom to lose this electron from outer most shell to make itself stable.

So after losing this electron positive charge on the upper right side of the atom will occur with the number of electron lose that is Na+1 .

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of sodium carbonate = 10.6 g

Volume of water = 1.25 L

Molarity of solution = ?

Solution:

First of all we will calculate the moles of solute.

Number of moles = mass/molar mass

Number of moles = 10.6 g/ 106 g/mol

Number of moles = 0.1 mol

Formula:

Molarity = moles of solute / volume of solution in L

Now we will put the values in formula.

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M

Answer:

There are 70 grams of KOH

Explanation:

First, we calculate the weight of 1 mol of KOH:

Weight 1 mol KOH: Weight K + Weight 0 + Weight H=  39g+ 1g+ 16g= 56 g/mol

1 mol-------56 g KOH

1,25 mol----x= (1,25 molx56 g KOH)/1 mol= 70 g KOH

Answer:

The right field is oceanography

Answer:

To react with 0.5 moles of zinc 1 mole of hydrochloric acid is required

Explanation:

Given data:

Number of moles of HCl = ?

Number of moles of Zn = 0.50 mol

Chemical equation:

Zn + 2HCl  → H₂ + ZnCl₂

Now we will compare the moles of zinc and HCl.

                       Zn       :        HCl

                         1        :            2

                       0.50   :         2×0.5 = 1 mol

So, to react with 0.5 moles of zinc 1 mole of hydrochloric acid is required.

To react with 0.50 moles of Zn, 1.0 mole of HCl is required according to the stoichiometry of the balanced chemical equation.

To determine how many moles of HCl are needed to react with 0.50 moles of Zn, we look at the balanced chemical equation:

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

According to the stoichiometry of the reaction, 1 mole of Zn reacts with 2 moles of HCl. Therefore, to react with 0.50 moles of Zn, we would need double that amount of HCl, which is 1.0 mole of HCl.

Answer: 2500 ml

Explanation:

To dilute a 500 mL solution of 5 M HCl to a 1 M HCl solution, 2000 mL of water must be added, using the formula M1V1 = M2V2 with the values substituted respectively.

The question involves diluting a concentrated solution to a lower concentration, specifically diluting a 500 mL solution of 5 M HCl to obtain a 1 M HCl solution. To solve this, the dilution equation, M1V1 = M2V2, is used. In this equation, M represents molarity, and V represents volume. Initially, we have M1=5 M, V1=500 mL, and M2=1 M. We need to find V2, the final volume after dilution.

Therefore, to dilute the 500 mL solution of 5 M HCl to a 1 M solution, 2000 mL of water needs to be added.

Global warming is primarily driven by human activities that release greenhouse gases into the atmosphere.

The burning of fossil fuels (coal, oil, and natural gas) for energy production and transportation is the largest contributor, releasing carbon dioxide (CO₂) and methane (CH₄). Deforestation and land-use changes also play a significant role, as trees absorb CO₂, but their removal releases it back into the atmosphere.

Industrial processes, agriculture, and waste management release additional greenhouse gases. These gases trap heat in the Earth's atmosphere, leading to an increase in average global temperatures, disruptions in weather patterns, rising sea levels, and other climate-related impacts.

Learn more about Global warming, here:

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Answer:

A) pH = 2.8

B) pH = 5.5

C) pH = 8.9

D) pH = 13.72

Explanation:

a) [H⁺]  = 1.6 × 10⁻³ M

pH = -log [H⁺]

pH = -log [1.6 × 10⁻³ ]

pH = 2.8

b) [H⁺]  = 3 × 10⁻⁶

pH = -log [H⁺]

pH = -log [3 × 10⁻⁶ ]

pH = 5.5

c) [OH⁻] = 8.2 × 10⁻⁶

pOH = -log[OH]

pOH = -log[8.2 × 10⁻⁶]

pOH = 5.1

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 5.1

pH = 8.9

d) [OH⁻] = 0.53 M

pOH = -log[OH]

pOH = -log[0.53]

pOH = 0.28

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 0.28

pH = 13.72

Answer:

[tex]2.82\cdot 10^9 y[/tex]

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

[tex]m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}}[/tex] (1)

where

[tex]m_0[/tex] is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

[tex]\tau[/tex] is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

[tex]\tau=7.04\cdot 10^8 y[/tex]

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

[tex]\frac{m(t)}{m_0}=\frac{6.25}{100}[/tex]

Substituting into (1) and solving for t, we can find how much time has passed:

[tex]t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y[/tex]

Answer:

Arrow from sedimentary to metamorphic

Arrow from igneous to metamorphic

Explanation:

Metamorphic rocks can only be created under high pressure and temperature/chemical involvement

Answer:

mass=density x volume

Explanation:

Final answer:

Density can be calculated by dividing the mass of a substance by its volume. The formula is Density = mass / volume.

Explanation:

The density of a substance can be calculated by dividing its mass by its volume. For example, let's say we have a sample of a substance with a mass of 50 grams and a volume of 20 cubic centimeters. To find the density, we would divide the mass by the volume:

Density = mass / volume

So in this case, the density would be:

Density = 50g / 20 cm3 = 2.5 g/cm3

Thus, the density of the substance is 2.5 grams per cubic centimeter.

Answer:

n = 1.9 ×10⁻⁵ mol

Explanation:

Given data:

Volume of hydrogen gas = 455 mm

Pressure of hydrogen gas = 101.3 kpa

Temperature = 29.1°C

Partial pressure of water vapor = 4.0 kpa

Number of moles of hydrogen gas = ?

Solution:

First of all we will convert the units.

Pressure of hydrogen gas = 101.3 kpa= 101.3/101 =  1 atm

Partial pressure of water vapor = 4.0 kpa = 4.0/ 101 = 0.04 atm

Temperature = 29.1 + 273 = 302.1 K

Volume of hydrogen gas = 455 / 1×10⁶ = 0.000455 L

Now we will calculate the total pressure.

Total pressure = Partial pressure of hydrogen gas + partial pressure of water vapors

Total pressure = 1 atm + 0.04 atm

Total pressure = 1.04 atm

Now we will calculate the number of moles;

PV = nRT

n = PV/RT

n =  1.04 atm × 0.000455 L / 0.0821 atm.L / mol.K × 302.1 K

n = 0.00047 /24.80/mol

n = 1.9 ×10⁻⁵ mol

Answer:

First, calculate the partial pressure of hydrogen by subtracting the total pressure of the hydrogen–water vapor mixture from the partial pressure of water vapor:

101.3 kPa − 4.0 kPa = 97.3 kPa.

Convert the temperature to kelvins:

29.1°C + 273.15 = 302.25 K.

Convert milliliters to liters by dividing by 1,000 to get 0.455 L.

Since the pressure is in kilopascals, use the R value 8.314 .

Now substitute the known values into the ideal gas equation:

n =  

n =  

n =  

n = 0.0176176 mol

n = 0.0176 mol

Explanation:

PLATO ANSWER!

Answer:

Explanation:

Any species that undergoes oxidation is itself a reducing agent or reductant.

The species that undergoes reduction in the course of a chemical reaction is an oxidant or reducing agent.

Any specie that loses electrons to another undergoes oxidation and is a reductant.

Species that gains electrons are called oxidant.

Answer:

Mass of water = 21.6 g

Explanation:

Given data:

Mass of C₂H₆ = 15 g

Mass of O₂ = 45 g

Mass of water produced = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂     →       4CO₂ + 6H₂O

Number of moles of C₂H₆:

Number of moles = mass/ molar mass

Number of moles = 15 g/ 30 g/mol

Number of moles = 0.5 mol

Number of moles of O₂ :

Number of moles = mass/ molar mass

Number of moles = 45 g/ 32 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of C₂H₆ and O₂ with H₂O.

                           C₂H₆           :                H₂O

                             2               :                  6

                           0.5              :          6/2×0.5 = 1.5

                            O₂              :                H₂O

                             7               :                  6

                           1.4               :           6/7×1.4 = 1.2

The number of moles of water produced by  oxygen are less so it will limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 1.2 mol × 18 g/mol

Mass = 21.6 g

Answer:

NaClo3 is the reactant here.

Explanation:

In the reaction below:

                        [tex]H_{2} + O_{2}[/tex] ----------------------> 2[tex]H_{2} O[/tex]

Here       [tex]H_{2}[/tex] and [tex]O_{2}[/tex] are reactant, they take part in chemical reaction to form water as a product.