13._SeClo+ _02 → _SeO2 + _Cl2

Answer:

3. V = 0.2673 L

4. V = 2.4314 L

5. V = 0.262 L

6. V = 2.224 L

Explanation:

3. assuming ideal gas:

∴ R = 0.082 atm.L/K.mol

∴ V1 = 225 L

∴ T1 = 175 K

∴ P1 = 150 KPa = 1.48038 atm

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(175 K))/((1.48038 atm)(225 L))

⇒ n = 0.043 mol

∴ T2 = 112 K

∴ P2 = P1 = 150 KPa = 1.48038 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(112 K)(0.043 mol))/(1.48038 atm)

⇒ V2 = 0.2673 L

4. gas is heated at a constant pressure

∴ T1 = 180 K

∴ P = 1 atm

∴ V1 = 44.8 L

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(180 K))/((1 atm)(44.8 L))

⇒ n = 0.3295 mol

∴ T2 = 90 K

⇒ V2 = RT2n/P

⇒ V2 = ((0.082 atm.L/K.mol)(90 K)(0.3295 mol))/(1 atm)

⇒ V2 = 2.4314 L

5.  V1 = 200 L

∴ P1 = 50 KPa = 0.4935 atm

∴ T1 = 271 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(271 K))/((0.4935 atm)(200 L))

⇒ n = 0.2251 mol

∴ P2 = 100 Kpa = 0.9869 atm

∴ T2 = 14 K

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(14 K)(0.2251 mol))/(0.9869 atm)

⇒ V2 = 0.262 L

6.a)  ∴ V1 = 24.6 L

∴ P1 = 10 atm

∴ T1 = 25°C = 298 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(298 K))/((10 atm)(24.6 L))

⇒ n = 0.0993 mol

∴ T2 = 273 K

∴ P2 = 101.3 KPa = 0.9997 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(273 K)(0.0993 mol))/(0.9997 atm)

⇒ V2 = 2.224 L

The volume of a gas at different temperatures while keeping pressure constant can be calculated using Gay-Lussac's law. For the first question, we use the initial volume and temperature to find the final volume when the temperature changes to 112 K, while pressure remains constant.

The volume of a gas at different temperatures and pressures, while some variables are kept constant, can be calculated using the combined gas law when both temperature and pressure change, or Gay-Lussac's law when only temperature changes and pressure stays constant, or Boyle's law when only pressure changes and temperature stays constant.

For the first question: The initial conditions are a volume of 225 L at a temperature of 175 K, and we're asked to find the final volume at 112 K while keeping pressure constant.

Using Gay-Lussac's law: V1/T1 = V2/T2, we rearrange to solve for V2:

V2 = V1 * T2/T1

V2 = 225 L * 112 K/175 K

After performing the calculation, you find the new volume at 112 K.

The correct option is D.

The heat of vaporization is defined as the amount of heat needed to turn 1g of a liquid into a vapor, without a rise in the temperature of the liquid.

That is, water has a high heat of vaporization, the amount of energy needed to change one gram of a liquid substance to gas at a constant temperature. Water's heat of vaporization is around 540 cal/g at 100 °C, water's boiling point.

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The mass of a nitrogen dioxide (NO2) molecule is approximately 46 atomic mass units (amu) as per the concept of molar mass.

Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.This is because the atomic masses  of nitrogen is 14 amu and  that of nitrogen is 16 amu, respectively. Since there are two oxygen atoms and one nitrogen atom in an NO₂ molecule, the total mass is calculated as follows:

[tex]2\times16+1\times14=46 \ amu[/tex]

Therefore, the mass of a nitrogen dioxide molecule is approximately 46 amu.

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Answer:

Explanation:

Bronsted Base is an H+ acceptor

No good answer Bronstead base does not accept hydroxide or electrons

Answer:

Bronsted-Lowry bases include both proton acceptors and hydroxide ions.

Explanation:

Bronsted Lowry base theory includes all bases that can act as proton acceptors. This includes Arrhenius bases include bases that can produce hydroxide ions in solution, such as sodium hydroxide, and more traditional proton acceptors like ammonia, NH3..

The correct characteristics of medusae are: swim freely, have tentacles, mouths open downward.

Medusae are the free-swimming, jellyfish-like form of certain aquatic animals, typically found in the phylum Cnidaria. They are characterized by their ability to swim freely in the water, which distinguishes them from the sessile, or immobile, polyps that are another life stage of cnidarians. Medusae have tentacles that hang down from their bell-shaped bodies, which they use to capture prey. These tentacles are often equipped with stinging cells called nematocysts that help to immobilize their prey. The mouth of the medusa is located on the underside of the body, facing downward, and leads to a gastrovascular cavity where digestion takes place.

To summarize, the following are the characteristics of medusae:

- Swim freely: Medusae are capable of locomotion and can move through the water column.

- Have tentacles: They possess tentacles that extend from their bodies, which are used for capturing food.

- Mouths open downward: The mouth is situated on the ventral side of the medusa, facing downward, which is suitable for bringing captured prey into the gastrovascular cavity for digestion.

The other options listed do not accurately describe medusae:

- Are sessile: This is incorrect because medusae are free-swimming, not immobile.

- Lack tentacles: This is incorrect because tentacles are a defining feature of medusae.

- Mouths open upward: This is incorrect because the mouth of a medusa opens downward.

This is an example of "Skyscrapers".

Explanation:

Answer:

its sum about the engernier proces

Explanation:

just did i on apex

Answer: 277.8 L

Explanation: Use Ideal gas law equation:

PV= nRT

At STP: P= 1atm T = 273 K

V= nRT/ P

= 12.4 moles He ( 0.08205 L.atm/mole.K) ( 273 K) / 1 atm

= 277.8 L

Answer:

Its c.

Explanation:

When the density and temperature at the core of the gravitationally collapsing nebula reaches values when nuclear fusion is triggered and sustained, that marks the birth of the star.

‘ you don’t likeee me dasss fineee kk byeee’

Answer:

The answer is D. H+ increases in solution.

Explanation:

One water molecule gains a hydrogen and therefore takes on a positive charge, while the other water molecule loses a hydrogen atom and therefore becomes negatively charged.

More information:

(https://www2.nau.edu/lrm22/lessons/acids_and_bases/acids_and_bases.html#:~:text=One%20water%20molecule%20gains%20a,and%20it%20makes%20things%20acidic.)

1. CaO + H₂O [tex]\rightarrow[/tex] Ca(OH)₂

2. P₄ + 5O₂ [tex]\rightarrow[/tex] P₂O₅

3. 2Ca + O₂ [tex]\rightarrow[/tex] 2CaO

4. 8Cu + 2S₈ [tex]\rightarrow[/tex] [tex]8CuS_2[/tex]

5. CaO + H₂O [tex]\rightarrow[/tex] Ca(OH)₂

6. S₈ + 8O₂ [tex]\rightarrow[/tex] 8SO₂

7. 3H₂ + N₂ [tex]\rightarrow[/tex] 2NH₃

8. H₂ + Cl₂ [tex]\rightarrow[/tex] 2HCl

9. 16Ag + S₈ [tex]\rightarrow[/tex] 8Ag₂S

10. 4Cr + 3O₂ [tex]\rightarrow[/tex] 2Cr₂O₃

11. 2Al + 3Br₂ [tex]\rightarrow[/tex] 2AlBr₃

12. 2Na + I₂ [tex]\rightarrow[/tex] 2NaI

13. 2H₂ + O₂ [tex]\rightarrow[/tex] 2H₂O

14. 4Al + 3O₂ [tex]\rightarrow[/tex] 2Al₂O₃

1. CaO + H₂O -> Ca(OH)₂: The balanced equation is CaO + H₂O [tex]\rightarrow[/tex] Ca(OH)₂. This chemical equation is already balanced, as there is an equal number of calcium (Ca), oxygen (O), and hydrogen (H) atoms on both sides.

2. P₄ + O₂ -> P₂O₅: The balanced equation is P₄ + 5O₂ [tex]\rightarrow[/tex] P₂O₅. Balancing involves placing a coefficient of 5 in front of O₂ to ensure an equal number of phosphorus (P) and oxygen (O) atoms on both sides.

3. Ca + O₂ -> CaO: The balanced equation is 2Ca + O₂ [tex]\rightarrow[/tex] 2CaO. By placing a coefficient of 2 in front of Ca and CaO, the number of calcium (Ca) and oxygen (O) atoms is balanced.

4. Cu + S₈ -> CuS: The balanced equation is 8Cu + 2S₈ [tex]\rightarrow[/tex] [tex]8CuS_2[/tex]. By placing a coefficient of 8 in front of Cu and a coefficient of 2 in front of S, the number of calcium (Cu) and oxygen (S) atoms is balanced.

5. CaO + H₂O -> Ca(OH)₂: The balanced equation is CaO + H₂O [tex]\rightarrow[/tex] Ca(OH)₂, as the number of calcium (Ca), oxygen (O), and hydrogen (H) atoms is already equal on both sides.

6. S₈ + O₂ -> SO₂: The balanced equation is S₈ + 8O₂ [tex]\rightarrow[/tex] 8SO₂. Balancing involves placing a coefficient of 8 in front of O₂ to ensure an equal number of sulfur (S) and oxygen (O) atoms on both sides.

7. H₂ + N₂ -> NH₃: The balanced equation is 3H₂ + N₂ [tex]\rightarrow[/tex] 2NH₃. By placing coefficients of 3, 1, and 2 in front of H₂, N₂, and NH₃ respectively, the equation is balanced.

8. H₂ + Cl₂ -> 2HCl: The balanced equation is H₂ + Cl₂ [tex]\rightarrow[/tex] 2HCl. Balancing involves placing a coefficient of 2 in front of (HCl) to ensure an equal number of hydrogen (H) and chlorine (Cl) atoms on both sides.

9. Ag + S₈ -> Ag₂S: The balanced equation is 16Ag + S₈ [tex]\rightarrow[/tex] 8Ag₂S. By placing a coefficient of 16 in front of Ag and a coeffiecient of 8 in front of the product of Ag and S, so the number of calcium (Ag) and oxygen (S) atoms is balanced.

10. Cr + O₂ -> Cr₂O₃: The balanced equation is 4Cr + 3O₂ [tex]\rightarrow[/tex] 2Cr₂O₃. Balancing involves placing coefficients of 4 and 3 in front of (Cr) and (O₂) respectively to equalize the number of chromium (Cr) and oxygen (O) atoms.

11. Al + Br₂ -> AlBr₃: The balanced equation is 2Al + 3Br₂ [tex]\rightarrow[/tex] 2AlBr₃. Balancing involves placing coefficients of 2 and 3 in front of Al and Br₂ respectively to ensure an equal number of aluminum (Al) and bromine (Br) atoms.

12. Na + I₂ -> NaI: The balanced equation is 2Na + I₂ [tex]\rightarrow[/tex] 2NaI, as coefficients of 2 are placed in front of Na and NaI to achieve a balanced reaction.

13. H₂ + O₂ -> 2H₂O: The balanced equation is 2H₂ + O₂ [tex]\rightarrow[/tex] 2H₂O. Balancing involves placing coefficients of 2 in front of H₂ and H₂O to ensure an equal number of hydrogen (H) and oxygen (O) atoms on both sides.

14. Al + O₂ -> Al₂O₃: The balanced equation is 4Al + 3O₂ [tex]\rightarrow[/tex] 2Al₂O₃. Balancing involves placing coefficients of 4 and 3 in front of Al and O₂ respectively to equalize the number of aluminum (Al) and oxygen (O) atoms.

Answer:

0.33M

Explanation:

Molarity is asking, in Laymens terms:

"If I took a litre of this stuff, how much stuff is gonna be in it?"

Diving deeper, we use litres instead of millilitres or nanolitres because that's usually what we're working with. We use moles rather than mass because mass varies; different substances have different molar masses, so describing something in g/L makes no sense if you're comparing two different solutions.

Anyway, go find the number of moles:

n=m/mm

n=27g/342.34g/mol

n=0.078870mol

The next question you've gotta ask yourself is:

What if I had a litre of it?

V = 0.2366L

M=n/V

M=0.078870mol/0.2366L

M=0.33M

The molarity of the Dr. Pepper made with imperial cane sugar is 0.334 M. This is calculated by first converting the mass of sugar into moles and the volume of water from mL to L, and then using these values in the molarity equation.

To calculate the molarity of a solution, we can use the formula: Molarity (M) = moles of solute/liters of solution. To apply this to your question, we first need to convert the mass of cane sugar (C12H22O11) into moles. The molecular weight of cane sugar (C12H22O11) is approximately 342.3 g/mol. Therefore, 27 g of sugar is approximately equal to 0.0789 moles.

Next, we need to convert the volume of water from mL to L. Hence, 236.6 mL is equal to 0.2366 L. Now, we can use these values in our molarity equation: M = 0.0789 moles/ 0.2366 L = 0.334 M. Therefore, the molarity of the Dr. Pepper made with imperial cane sugar is around 0.334 M.

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Answer:

                    Charge on Phosphate is -3 (PO₄³⁻)

Explanation:

                     Ions or polyatomic ions are formed when an atom or molecule loses or gains electron(s) respectively.

Example:

              Formation of ions.

                           Na  →  Na⁺  +  e⁻ (Na loses one electron)

                           Cl₂  +  2 e⁻  →  2 Cl⁻ (Cl gains electron)

In polyatomic ions a charge is present on a molecule which has either two or more atoms.

Example:

               CO₃²⁻ , SO₄⁻ , NH₄⁺ e.t.c.

In statement the  K₃PO₄ polyatomic ionic compound. It is made up of three K⁺ ions and one Phosphate ion (PO₄ˣ⁻) ion.

As we know K belongs to group 1 metals so it has one valence electron and thus, forms a cation of +1 charge. So, for a neutral polyatomic ionic compound the overall charge on K₃PO₄ should be zero. Hence,

                                         K (3) + PO₄ (X)  =  0

Or,

                                         +3 + X = 0

Or,

                                         X  =  0 - 3

                                         X  =  -3

Therefore, the charge on phosphate is -3.

The charge of phosphate in K3PO4 is -3.

The charge of phosphate in K3PO4 can be determined using the table provided. From the table, we can see that K+ has a charge of +1. Since there are three K+ ions in K3PO4, their total charge is +3. So, the charge of phosphate in K3PO4 is -3.

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Answer:

In a chemical equation, chemicals that react are the reactants, while chemicals that are produced are the products/by products. Both sides of the equation must be balanced.

\

Explanation

When writing a chemical equation, reactants reacts to produce products. For example in the equation for formation of water, hydrogen combines with oxygen as 2H₂ +O₂→2H₂O where the first part before the arrow represent the reactants and the next part after the arrow are the products. Reactants are on the left where as products are on the right.Coefficient 2, in this cases is used for balancing the equation

The coefficient of the reactant diatomic oxygen (O2) is incorrect in the provided chemical equation. The corrected equation for the combustion of butane is 2C4H10 + 13O2 -> 8CO2 +10H2O.

The given equation is 2C4H10 + 10O2 -> 8CO2 +10H2O. The coefficient of diatomic oxygen (O2), a reactant, is incorrect. It's essential to balance the number of atoms on both sides of a chemical equation to abide by the law of conservation of matter. The correct equation should be 2C4H10 + 13O2 -> 8CO2 +10H2O. This represents the combustion of butane.

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Answer: Option D. There is no net change to the system.

Explanation:

Answer:

B location A will experience water scarcity because plastic absorbs

Explanation:

Answer: I believe its D

Explanation:

Im doing the science test rn

Answer:

In the typical periodic table, each element is listed by its element symbol and atomic number. For example, “H” denotes hydrogen, “Li” denotes lithium, and so on. Most elements are represented by the first letter or first two letters of their English name, but there are some exceptions.

Each element has a symbol,one or two letters that represent the element much as your initials represent you. The symbol of an element represents one atom of that element.

...

Symbol Element

Cf californium

C carbon

Ce cerium

Cs cesium

Explanation:

The element is the purest form of the atom that is composed of single species. Elements are represented by one or two letter symbols, like He and H.

The purest and the most simplified form of an atom is said to be called an element. Each and every element is said to have a respective atomic mass and atomic number that are denoted with symbols in the periodic table.

The elements are represented as one or two letter symbols in the table along with the atomic number and masses as the superscript and subscript. For example, a hydrogen atom is represented as H, helium as He, neon as Ne, carbon as C, calcium as Ca, oxygen as O, sodium as Na, nitrogen as N, etc.

Therefore, the element in a periodic table is represented by one or two alphabetical symbols.

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Answer:

                     Pressure  =  2.45 atm

Explanation:

                    The balance chemical equation for the decomposition of hydrogen peroxide is as follow;

                                 2 H₂O₂ ₍aq₎ → 2 H₂O ₍l₎ + O₂ ₍g₎

Step 1: Calculate Moles of H₂O₂ as;

                     Moles  =  Mass / M.Mass

                     Moles  =  68.0 g / 34.01 g/mol

                     Moles  =  1.99 moles

Step 2: Calculate Moles of O₂ gas produced:

According to equation,

2 moles of H₂O₂ produced  =  1 mole of O₂

So,

1.99 moles of H₂O₂ will produce  =  X moles of O₂

Solving for X,

                     X  =  1.99 mol × 1 mol / 2 mol

                      X =  0.995 moles of O₂

Step 3: Calculate pressure exerted by O₂ gas as;

According to ideal gas equaton,

                                     P V  =  n R T

Or,

                                     P  =  n R T / V

Putting values,

                   P  =  0.995 mol × 0.08205 L.atm.K⁻¹.mol⁻¹ × 300 K / 10 L

                   P  =  2.45 atm

Answer:

ot

Explanation:

Answer:

true

Explanation:

Answer:

                      Elements in same group have same chemical properties due to same number of valence electrons in valence shell.

Explanation:

                   Chemical properties are those properties which results in transforming the starting material to a entirely new substance with different chemical and physical properties. This transformation takes place after a chemical reaction. Hence, the chemical reactivity of some atoms is greater than the others and vice versa.

                    In periodic table it is found that the elements in the same group have almost same chemical behaviour. For example, elements of group 8 (or 18) are almost non reactive, while that of group 1 and group 7 are found very reactive and show same chemical behaviour like group 1 elements forms +1 ion while group 7 elements form -1 ions as the group 1 metals have single valence shell electron which upon losing allow the atom to attain stability and the halogen having 7 electrons in valence shell upon accepting one electron allow them to attain a octet of stability respectively.

Elements in the same group of the periodic table have similar chemical properties because they have the same number of valence electrons in their outer shell, which governs their chemical behavior.

Elements in the same group of the periodic table have similar chemical properties because they have the same number of valence electrons in their outermost shell. Valence electrons are primarily responsible for the chemical behavior of an element. They are involved in bonding with other atoms and determine the reactivity of the element. For example, Group 1 elements (alkali metals) each have one valence electron and behave very similarly, exhibiting high reactivity. On the contrary, Group 8 elements (noble gases) each have a full complement of eight valence electrons in their outermost shell making them extremely stable and unreactive.

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An element belongs to group 17 of the periodic table. This element is most likely a nonmetal. A solid of this element would have a dull appearance.

Group 17 of the periodic table consists of the halogens, which are nonmetals. These elements are characterized by their high electronegativity and reactivity. They typically form diatomic molecules (e.g., [tex]F_2, Cl_2[/tex]) and have seven valence electrons, which makes them very receptive to gaining an electron to achieve a stable electron configuration.

The physical properties of halogens vary, but solid halogens are generally brittle and have a dull appearance due to their nonmetallic nature. Unlike metals, which have a shiny luster, nonmetals do not reflect light well and thus appear dull. This is because the outer electrons in nonmetals are more tightly held by the nucleus, resulting in poor electrical conductivity and a lack of the metallic luster that is characteristic of metals, where the delocalized electrons can move freely and reflect light.

(A) An element belonging to group 17 of the periodic table is most likely a halogen. A solid of this element would have a shiny appearance.

- Group 17 of the periodic table consists of the halogens: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At).

- Halogens are typically nonmetals and exist as diatomic molecules in their elemental form (F₂, Cl₂, Br₂, I₂, At₂).

- In their solid state, halogens generally have a shiny appearance due to their molecular structure and interactions.

Complete question:

An element belongs to group 17 of the periodic table. This element is most likely a ____. A solid of this element would have a ____ appearance.

A. Halogen; shiny  

B. Metal; dull  

C. Alkali metal; metallic  

D. Noble gas; transparent

Answer: 12.04x10^23 molecules of Na2O

Explanation:

Answer:

A single quantity that measures the ionization energy of the valence electrons of an electron. Where a is number of electrons in s subshell and Is is Ionization energy of that subshell. AVEE measures two important qualities: 1.

Explanation:

Final answer:

The AVEE measures the average velocity (Vav) and displacement (Ax), which are essential in the context of work done by an electric force in a uniform electric field.

Explanation:

The AVEE, referring to the average electric potential energy, is used to measure two main quantities in physics: average velocity (Vav) and displacement (Ax). The average electric potential energy (AVEE) is involved when considering the work done by the electric force in moving a charge from one point to another, particularly in a uniform electric field. The concept of AVEE is essential in understanding how charges interact within an electric field. The equation AV = APE and APE = qAV help underline the relationship between the average electric potential energy and these measured quantities.

Answer: 1.21x10²³ formula units Ca( ClO3)2

Explanation: solution attached:

Convert mass of Ca(ClO3)2 to moles

Convert moles of Ca(ClO3)2 to formula units using Avogadro's number

Answer:

B

Explanation:

Answer:

To express y in terms of x is to find an expression that relates the value of x with y. This is to write a model, function, expression or formula that permits to input a value for x and the outcome will be the value of y. .For example if you have y = 2x, y is in terms of x and you can input different values of x to obtain corresponding values (outputs) of y.

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Explanation:

Final answer:

To express y in terms of x, you manipulate an equation to make y the subject, using substitution and algebraic manipulation for simple equations, or differentiation and implicit differentiation for more complex relationships.

Explanation:

To express y in terms of x, one typically manipulates a given equation or set of equations, solving for y to make it the subject. The process may involve various mathematical techniques, including substitution, algebraic manipulation, and differentiation when dealing with functions of multiple variables. An example of expressing y in terms of x can be seen in a simple linear equation, such as y = mx + b, where m is the slope and b is the y-intercept. In this case, y is already expressed in terms of x.

In more complex relationships, such as the nonlinear equation x + y = exp(xy), one might take a derivative with respect to x to get dy/dx and solve that differential equation for y in terms of x, considering implicit differentiation if necessary.

Answer:

the answer is 58000000000 nanometers

Different conversion units are used to evaluate different parameters. Therefore, 5.8 ×10¹⁰nm  in 0.058 km.

Unit conversion is a multi-step procedure that includes multiplying or dividing a number by a numerical factor. Weight, distance, as well as temperature may all be measured in many ways. Distance is expressed in kilometers, mass in kilos, and temperature in degrees Celsius in many nations.

Unit converting is a multi-step procedure that requires multiplying or dividing by a numerical number or, more specifically, a conversion factor. The technique may also require selecting the appropriate number of important digits and rounding. Different conversion units are used to evaluate different parameters.

1km= 10¹²nm

0.058 km = 0.058 ×10¹²= 5.8 ×10¹⁰nm

Therefore,  5.8 ×10¹⁰nm in 0.058 km.

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Answer:

A. is most likely the answer

Answer: option A. 9.45L

Explanation:

P1 = 98.7atm

P2 = 102.7atm

T1 = 25°C = 25 + 273 =298K

T2 = 20°C = 20 +273 = 293K

V1 = 10L

V2 =

P1V1 /T1 = P2V2 /T2

98.7x10/298 = 102.7xV2/293

298x102.7xV2 = 98.7x10x293

V2 = (98.7x10x293) /(298x102.7)

V2 = 9.45L

Yo sup??

The correct answer is option D ie

n + A----> B + C + n

Its similar to bombarding a U 235 ore.

Hope this helps.

Answer:

Answer is D, I've done the exam I know for sure.

Explanation:

n + A → B + C + n

Hope you all get a good grade :))

Answer:

the environment modifies i believe, or no new members come in or go out

Explanation:

as an environment modifies, the population would have to adapt to this modification, which causes change over time in a population. and if no new members come in or go out, the population may increase or decrease over time.