100 pyramid shaped chocolate candies with a square base of 12 mm size and height of 15 mm are melted in a cylinder coil pot if the part has a radius of 75 mm what is the height of the melted candies in the pot.

Answer:

7) 6 is not a perfect square, sqrt(6) can't be written in a fraction form

8) 2 is not a perfect cube, cuberoot of 2 can't be written in a fraction form

9) 3/2 is already a fraction, so clearly rational

Answer:

False

Step-by-step explanation:

We are told that there is a 33% probability that physics students belong to ethnic minorities, therefore if the sample is 10 people, the amount would be given as follows:

10 * 33% = 3.3 people would be from ethnic minorities. What means of those 10 no more than 4 (to round the number) people belong to an ethnic minority.

Therefore, this statement is false, because it does not represent exactly the probability established in the university.

It is possible to clarify that what affirmation is true part because it fulfills what it says, because the probability says that 4 or less, and the affirmation says that 6 or less, however, the affirmation mentions that it corresponds to the probability of 33% and that if it is false, to correspond it should be between 51% and 60%.

Answer:

8 headbands can be made.

Step-by-step explanation:

dividing both sides by 16.5, the material needed for one, leaves the equation as h=8, because 132 divided by 16.5 equals 8

Brinley can make 8 hands from the elastic she has.

What is the unitary method?

The unitary method is a method in which you find the value of a unit and then the value of a required number of units. Suppose you go to the market to purchase 6 apples. The shopkeeper tells you that he is selling 10 apples for Rs 100. In this case, the apples are the units, and the cost of the apples is the value.

Given here, A headband needs 16 and a half inches of elastic and Brinley has 132 inches of elastic

Therefore the number of headbands that she could make is

= 132/16.5

=8 Headbands.

Hence, Brinley can make 8 hands from the elastic she has.

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Answer:

Veggie

Step-by-step explanation:

I corrected your question for a better situation.

At a party there were four large submarine sandwiches all the same size . During the party 2/3 of the chicken sandwich three over 4 of the tuna sandwich 7/12 of the roast beef sandwich and 5/6 of the veggie sandwich were eating which sandwich had the least amount left

Here is my answer:

So the sandwich had the least amount is Veggie

Answer:

The total amount spent during 2003 was $725.78.

Step-by-step explanation:

Given:

During the 2004 season, New York theater goers bought 11.3 million tickets for a total of $749.0 . Theater goers spent a total of 3.2% more than the year before.

Now, to find the total amount that was spent during 2003.

Let the amount spent during 2003 be [tex]x.[/tex]

The amount spent during 2004 = $749.0.

As, given theater goers spent a total of 3.2% more than the year before.

So, we put equation to get the amount spent during 2003:

[tex]x+3.2\%\ of\ x=749[/tex]

[tex]x+\frac{3.2}{100} \times x=749[/tex]

[tex]x+\frac{3.2x}{100}=749[/tex]

[tex]\frac{100x+3.2x}{100} =749[/tex]

[tex]\frac{103.2x}{100} =749[/tex]

Multiplying both sides by 100 we get:

[tex]103.2x=74900[/tex]

Dividing both sides by 103.2 we get:

[tex]x=\$725.78[/tex]

Therefore, the total amount spent during 2003 was $725.78.

Answer:

The answer to the question is

The probability of winning second prize (that is, picking five of the six winning numbers) with a 6/44 lottery, as played in Connecticut, Missouri, Oregon, and Virginia is 3.49905×10⁻⁵≡ 0.00003 to five decimal places.

Step-by-step explanation:

The probability of winning the second prize or picking five of the six winning numbers) with a 6/44 lottery is given by

Number of 5 sets of numbers in 44 = ₄₄C₅ = 1086008 ways

Number of 5 set of winning numbers in 44 = 1

Number of ways of picking the last number to make it 6 numbers is given by

44 - 5 lucky numbers - The 1 winning number = 38

Therefore, there are 38 ways from 1086008 of selecting the 5 second place winning numbers

Therefore the probability of picking the 5 second place winning numbers is [tex]\frac{38}{1086008}[/tex] = 3.49905×10⁻⁵

Answer:

C) -5

Step-by-step explanation:

-1 4/5 x= 9.

Change the left side to an improper fraction

(5*1+4)/5 = 9/5

-9/5 x =9

Multiply each side by -5/9 to isolate x

-5/9 * 9/5x = 9 * (-5/9)

x = -5

Answer:

x=-5

Step-by-step explanation:

-1 4/5x=9

-9/5x=9

-9x=9*5

-9x=45

x=45/(-9)

x=-5

Answer:

[tex]t=\frac{70.1-65.2}{\frac{2.52}{\sqrt{30}}}=10.65[/tex]    

[tex]p_v =P(t_{(29)}>10.65)=7.76x10^{-12}[/tex]  

And the best conclusion for this case would be:

D. The p-value is less than 0.00001. There is sufficient data to reject the null hypothesis.

Step-by-step explanation:

Data given and notation  

[tex]\bar X=70.1[/tex] represent the sample mean

[tex]\sigma=2.52[/tex] represent the population standard deviation  

[tex]n=30[/tex] sample size  

[tex]\mu_o =65.2[/tex] represent the value that we want to test

[tex]\alpha[/tex] represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

[tex]p_v[/tex] represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 65.2, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 65.2[/tex]  

Alternative hypothesis:[tex]\mu > 65.2[/tex]  

If we analyze the size for the sample is = 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

[tex]t=\frac{70.1-65.2}{\frac{2.52}{\sqrt{30}}}=10.65[/tex]    

P-value

The first step is calculate the degrees of freedom, on this case:  

[tex]df=n-1=30-1=29[/tex]  

Since is a one side right tailed test the p value would be:  

[tex]p_v =P(t_{(29)}>10.65)=7.76x10^{-12}[/tex]  

And the best conclusion for this case would be:

D. The p-value is less than 0.00001. There is sufficient data to reject the null hypothesis.

The correct option is D. The p-value is less than [tex]0.00001.[/tex] There is sufficient data to reject the null hypothesis.

Hypotheses:

Null hypothesis [tex](\(H_0\)): \(\mu_1 = \mu_2\)[/tex] (the mean height of contemporary males is equal to the mean height of eighteenth-century males)

Alternative hypothesis [tex](\(H_1\)): \(\mu_1 > \mu_2\)[/tex] (the mean height of contemporary males is greater than the mean height of eighteenth-century males)

Given Data:

Sample mean for contemporary males [tex](\(\bar{x}_1\)) = 70.1 inches[/tex]

Sample standard deviation for contemporary males [tex](\(s_1\)) = 2.52 inches[/tex]

Sample size for contemporary males [tex](\(n_1\)) = 30[/tex]

Sample mean for eighteenth-century males [tex](\(\bar{x}_2\)) = 65.2 inches[/tex]

Sample standard deviation for eighteenth-century males [tex](\(s_2\)) = 3.51\ inches[/tex]

Sample size for eighteenth-century males [tex](\(n_2\)) = 30[/tex]

Test Statistic:

We use a two-sample t-test for the difference of means:

[tex]\[t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}}\][/tex]

Substituting the given values:

[tex]\[t = \frac{70.1 - 65.2}{\sqrt{\frac{2.52^2}{30} + \frac{3.51^2}{30}}}\][/tex]

First, calculate the variances and their respective terms:

[tex]\[s_1^2 = 2.52^2 = 6.3504, \quad s_2^2 = 3.51^2 = 12.3201\][/tex]

[tex]\[\frac{s_1^2}{n_1} = \frac{6.3504}{30} = 0.21168, \quad \frac{s_2^2}{n_2} = \frac{12.3201}{30} = 0.41067\][/tex]

[tex]\[\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}} = \sqrt{0.21168 + 0.41067} = \sqrt{0.62235} = 0.7889\][/tex]

Now calculate the t-value:

[tex]\[t = \frac{70.1 - 65.2}{0.7889} = \frac{4.9}{0.7889} = 6.21\][/tex]

Degrees of Freedom:

Since the sample sizes are the same, we can use the following approximation for degrees of freedom [tex]df[/tex]

[tex]\[df = n_1 + n_2 - 2 = 30 + 30 - 2 = 58\][/tex]

P-value:

Using a t-distribution table or a calculator for a one-tailed test with [tex]58[/tex] degrees of freedom, we find that a t-value of [tex]6.21[/tex] corresponds to a p-value much less than [tex]0.00001.[/tex]

The swimmer will travel a distance of 55.92 meters when swimming from one corner to the opposite corner of an Olympic-size swimming pool.

Given, the length and width of the pool form the two sides of the right-angled triangle, and the distance the swimmer will travel is the hypotenuse.

Using the Pythagorean theorem, we can calculate the distance as follows:

Distance² = Length² + Width²

Distance² = 50² + 25²

Distance² = 2500 + 625

Distance² = 3125

Distance = √3125

Distance = 55.90 meters

Therefore, a swimmer will travel approximately 55.92 meters.

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Final answer:

To determine the distance a swimmer travels across an Olympic-sized pool from corner to opposite, the Pythagorean theorem is used, giving approximately 55.90 meters as the distance.

Explanation:

The student's question entails calculating distances and speeds in different swimming and water current scenarios, which is a classic physics problem involving kinematics and geometry. However, since it involves calculations and applying formulae, particularly the Pythagorean theorem, and rate, time, and distance relationships, it falls under the subject of Mathematics.

To Calculate the Distance Swum Across an Olympic-sized Pool

For an Olympic-sized pool that is 50 meters in length and 25 meters in width, a swimmer traveling from one corner to the opposite would traverse a diagonal. To calculate this diagonal distance, we use the Pythagorean theorem:

Diagonal2 = Length2 + Width2

Diagonal = √(Length2 + Width2)

Substitute the given values:

Diagonal = √(502 + 252) = √(2500 + 625)

Diagonal = √(3125) meters

The swimmer will travel approximately √(3125) meters, which is about 55.90 meters.

Answer:

Correct option: 3. Cluster Sampling.

Step-by-step explanation:

Cluster sampling method is the type of sampling where first the entire population is divided into groups and then a random sample of fixed size is selected from each group.

In this case also, the researcher first divides the population of students in Scion School of Business into groups according to their class standing.

Then he selects 50 students from each of these groups to create a representative sample of the entire student body.

Thus, the sampling method used is Cluster Sampling.

Answer:

270725 different ways

Step-by-step explanation:

The problem tells us that the order of the letters does not matter. Therefore, in the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

We have to n = 52 and r = 4

C (52, 4) = 52! / 4! * (52-4)! = 52! / (4! * 48!) = 270725

Which means that there are 270725 different ways in total to make that raffle

Answer:

a) The approximate probability that more than 25 chips are defective is 0.1075.

b)  The approximate probability of having between 20 and 30 defecitve chips is 0.44.

Step-by-step explanation:

Lets call X the total amount of defective chips. X has Binomial distribution with  parameters n=1000, p =0.02. Using the Central Limit Theorem, we can compute approximate probabilities for X using a normal variable with equal mean and standard deviation.

The mean of X is np = 1000*0.2 = 20, and the standard deviation is √np(1-p) = √(20*0.98) = 4.427

We will work with a random variable Y with parameters μ=20, σ=4.427. We will take the standarization of Y, W, given by

[tex] W = \frac{Y-\mu}{\sigma} = \frac{Y-20}{4.427} [/tex]

The values of the cummmulative distribution function of the standard normal random variable W, which we will denote [tex] \phi [/tex] , can be found in the attached file. Now we can compute both probabilities. In order to avoid trouble with integer values, we will correct Y from continuity.

a)

[tex]P(X > 25) = P(X > 25.5) \approx P(Y>25.5) = P(\frac{Y-20}{4.427} > \frac{25.5-20}{4.427}) =\\P(W > 1.2423) = 1-\phi(1.2423) = 1-0.8925 = 0.1075[/tex]

Hence the approximate probability that more than 25 chips are defective is 0.1075.

b)

[tex]P(20<X<30) = P(20.5 < X < 29.5) \approx P(20.5<Y>29.5) = \\P(\frac{20.5-20}{4.427} < \frac{Y-20}{4.427} < \frac{29.5-20}{4.427}) = P(0.1129 < W < 2.14) = \phi(2.14)-\phi(0.1129) = \\0.9838-0.5438 = 0.44[/tex]

As a result, the approximate probability of having between 20 and 30 defecitve chips is 0.44.

Final answer:

To approximate the probabilities of defective chips where 2% are defective from a lot of 1000, the binomial distribution is used, with more complex probability calculations often requiring statistical software. Both (a) more than 25 defective and (b) between 20 and 30 defective scenarios can be estimated using normal approximation due to the large sample size and small defect probability.

Explanation:

To approximate the probability of defective chips in the scenario where 2% of the semiconductor chips produced are defective, we can use the binomial distribution as an approximation because the sample size is large (n=1000) and the probability of a defect (p=0.02) is small.

For part (a), more than 25 chips are defective, we are looking for P(X>25). The calculation for this is more complex and typically done using statistical software or a calculator with binomial capabilities.

For part (b), between 20 and 30 chips are defective, we need to find the probability that X is between 20 and 30 inclusively, or P(20 ≤ X ≤ 30). This requires calculating the cumulative probability for 20 through 30 and then subtracting the lower end from the higher end.

In real-world applications, as the number of trials is large and the probability of success is small, the binomial distribution can be approximated by a normal distribution. The mean (μ) of the distribution is np and the variance (σ2) is np(1-p), which would give us μ = 20 and σ2 = 19.6 for this example. We can then use the standard normal table or a calculator to find the probabilities for parts (a) and (b).

Approximately 85.33% of the exam scores are between 68 and 77.99 points.

To find the proportion of exam scores between 68 and 77.99 points in a normally distributed set, we can use the Z-score formula:

[tex]\[ Z = \frac{X - \mu}{\sigma} \][/tex]

where X is the score, [tex]\( \mu \)[/tex] is the mean, and [tex]\( \sigma \)[/tex] is the standard deviation.

Given:

- Mean [tex]\( \mu = 71.33 \)[/tex]

- Standard deviation [tex]\( \sigma = 3 \)[/tex]

- We need to find the proportion of scores between [tex]\( X_1 = 68 \)[/tex] and [tex]\( X_2 = 77.99 \)[/tex].

1. Calculate the Z-scores for [tex]\( X_1 = 68 \)[/tex]:

[tex]\[ Z_1 = \frac{68 - 71.33}{3} = \frac{-3.33}{3} = -1.11 \][/tex]

2. Calculate the Z-scores for [tex]\( X_2 = 77.99 \)[/tex]:

[tex]\[ Z_2 = \frac{77.99 - 71.33}{3} = \frac{6.66}{3} = 2.22 \][/tex]

Next, we look up these Z-scores in the standard normal distribution table or use a calculator to find the corresponding proportions:

- The proportion corresponding to [tex]\( Z_1 = -1.11 \)[/tex] is approximately 0.1335.

- The proportion corresponding to [tex]\( Z_2 = 2.22 \)[/tex] is approximately 0.9868.

The proportion of scores between [tex]\( X_1 = 68 \)[/tex] and [tex]\( X_2 = 77.99 \)[/tex] is the difference between these two proportions:

[tex]\[ P(68 < X < 77.99) = P(Z < 2.22) - P(Z < -1.11) \][/tex]

[tex]\[ P(68 < X < 77.99) = 0.9868 - 0.1335 = 0.8533 \][/tex]

Answer:

Step-by-step explanation:

Given that Alice and Bob race two toy trains around a circular track. The trains move in the same direction and they meet every 120 seconds. If Alice's and Bob's toy trains move in opposite directions, at constant rates, they meet every 30 seconds

Circular track is 1800 m.

Let speed be x and y respectively

When in same direction relative speed = x-y and when in opposite directions =x+y

30(x+y) = 1800

x+y= 60

120(x-y) = 1800

x-y = 15

Solving x = 37.5 m/hr and y = 12.5 per hour.

When Alice and Bob's toy trains move in the same direction, their relative speed is the sum of their individual speeds. When they move in opposite directions, their relative speed is the difference between their individual speeds. By solving simultaneous equations, we find that Alice's toy train has a speed of 75 m/s and Bob's toy train has a speed of 60 m/s.

Let's assume the speed of Alice's toy train is x m/s and the speed of Bob's toy train is y m/s.

When the trains move in the same direction, they meet every 120 seconds. Since they meet once every 30 seconds when moving in opposite directions, their relative speed is the sum of their individual speeds. So, when they move in the same direction, their relative speed will be x + y and when they move in opposite directions, their relative speed will be x - y.

When they move in the same direction, the distance covered by Alice's toy train in 120 seconds will be equal to the distance covered by Bob's toy train in 120 seconds, which is equal to the length of the circular track (1800 m). So, the equation can be written as:

Simplifying the equation, we get:

Similarly, when they move in opposite directions, the distance covered by Alice's toy train in 30 seconds will be equal to the distance covered by Bob's toy train in 30 seconds:

Simplifying the equation, we get:

Solving the equations simultaneously, we find that x = 75 m/s and y = -60 m/s. Since speed is always positive, we consider the magnitude of the velocity. Therefore, the speed of Alice's toy train is 75 m/s and the speed of Bob's toy train is 60 m/s.

Answer:

The correct option is

d) (179.20, 212.716)

Step-by-step explanation:

We have out of a random sample of 1000, 345 carried more than a bag

Therefore in the question our X = 345 passengers carry more than a piece of luggage

n = 1000

Therefore the probability of a passenger carrying more than one luggage = 345/1000 = 0.345

The confidence interval estimator of p is given by

[tex]p'+/-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }[/tex] where p' = 0.345 = probability of desired outcome

n = 1000 = Population size

z at 95 %   = Confidence interval estimate, the value is sought from the distribution table as z value is 1.96 at 95 % confidence level

We have  [tex]0.345+/-1.96\sqrt{\frac{0.345*(0.655)}{1000} }[/tex] which gives

0.3745 or 0.3155

Which gives the range of confidential interval estimate as

212.695 to 179.224 which is equivalent to

d) (179.20, 212.716).

To determine the interval estimate of the number of passengers carrying more than one piece of luggage on the plane, we use the formula for the confidence interval for a proportion. The interval estimate is (0.3132, 0.3768), so we can expect the number to be between 313 and 377 passengers.

To determine the interval estimate of the number of passengers that you would expect to carry more than one piece of luggage on the plane, we can use the formula for the confidence interval for a proportion. First, we calculate the sample proportion of passengers carrying more than one bag, which is 345/1000 = 0.345. Then, we find the standard error using SE = sqrt(p(1-p)/n), where p is the sample proportion and n is the sample size. Substituting the values, we get SE = sqrt(0.345(1-0.345)/1000) = 0.0162.

Next, we find the margin of error by multiplying the standard error by the critical value for the desired level of confidence. Since the problem does not specify a level of confidence, we will use a 95% confidence level, which corresponds to a critical value of 1.96. The margin of error is therefore 1.96 * 0.0162 = 0.0318.

Finally, we construct the confidence interval by subtracting and adding the margin of error from the sample proportion. The interval estimate is given by (0.345 - 0.0318, 0.345 + 0.0318), which simplifies to (0.3132, 0.3768). Therefore, we can expect the number of passengers carrying more than one piece of luggage on the plane to be between 313 and 377.

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Answer:

W = 15 ft. and L = 30 ft.

Step-by-step explanation:

Perimeter = 90 ft.

Twice as long as it is wide: L=2W

P = 2(L + W) = 2(2W + W) = 6W

90 = 6W

W = 15 ft. and L = 30 ft.

Answer:

The dimensions are: Width= 15ft

Length=30ft

Step-by-step explanation:

Perimeter of fence=90feet

He wants to make a rectangle with dimensions length and with.

The rectangle length is twice as long as the width= L= 2W

Perimeter of a rectangle = 2(L + W)

90= 2(2W +W)

90= 6W

90/6=W=15ft

L=2W= 2× 15=30ft

Answer: the power required to do the same work in 1 hour is 30 j/h

Step-by-step explanation:

If two variables vary inversely, an increase in one of the variables causes a decrease in the other variable and vice versa.

The power P required to do a fixed amount of work varies inversely as the time t. If we introduce a constant of variation, k, the expression would be

P = k/t

If a power of 15 J/h is required to do a fixed amount of work in 2 hours, it means that

15 = k/2

k = 15 × 2 = 30

The equation becomes

P = 30/t

Therefore, the power required to do the same work in 1 hour is

P = 30/1 = 30 j/h

The quadratic function in vertex form is [tex]y=\frac{1}{2} (x-5)^{2}-2[/tex].

Solution:

The equation of a quadratic in  vertex form  is [tex]y=a(x-h)^{2}+k[/tex].

where  (h, k) are the coordinates of the vertex and "a"  is a multiplier.

Here (h, k) = (5, –2)

Substitute this in the vertex form.

[tex]y=a(x-5)^{2}+(-2)[/tex]

[tex]y=a(x-5)^{2}-2[/tex] – – – – (1)

Passes through the point (7, 0).

Here x = 7 and y = 0.

Substitute this in equation (1), we get

[tex]0=a(7-5)^{2}-2[/tex]

[tex]0=4a-2[/tex]

Add 2 on both sides.

2 = 4a

Divide 2 on both sides, we get

[tex]$a=\frac{1}{2}[/tex]

Substitute the value of a in equation (1),

[tex]$y=\frac{1}{2} (x-5)^{2}-2[/tex]

The quadratic function in vertex form is [tex]y=\frac{1}{2} (x-5)^{2}-2[/tex].

Answer:

Option C) Quadratic regression model

Step-by-step explanation:

Quadratic regression model

where x is the independent variable and [tex]\hat{y}[/tex] is the dependent variable.

Thus, the correct answer is

Option C) Quadratic regression model

The (c) quadratic regression model is used to model a nonlinear relationship between the independent and dependent variables by including the independent variable and the square of the independent variable.

The correct answer to this question is C. Quadratic regression model. In statistics, a quadratic regression model is used to model a nonlinear relationship between the independent and the dependent variables. This is achieved by including the independent variable and the square of the independent variable in the model. For example, if 'x' is the independent variable, the model would include both 'x' and 'x²'. The quadratic term allows for the model to fit simple curved relationships between the dependent and independent variable. The other models listed, such as multiple regression model, least squares regression model and a simple regression model, tend to represent linear relationships.

Here is a simple illustrative example: suppose you wanted to model the relation between the amount of fertilizer used (independent variable 'x') and the height of a plant (dependent variable 'y'). If the relation isn't linear (meaning more fertilizer does not always result in more growth, and growth rate declines after a certain point, forming a curved pattern in the data), you could use a quadratic regression model

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Answer:

D. 28

Step-by-step explanation:

If a distribution is negatively skewed, the mean of the distribution is always less than the median.

If the median of a negatively skewed distribution is 31, then from the given options, the only value that is less than 31 is 28.

Therefore the mean could be 28.

The correct answer is D

Answer:

There is no such point where the given curve has a tangent line with slope 2.

Step-by-step explanation:

We have been given a curve [tex]y=4x^3+7x-5[/tex]. We are asked to show that the given curve has no tangent line with slope 2.

First of all, we will find the derivative of given curve as shown below:

[tex]y'=\frac{d}{dx}(4x^3)+\frac{d}{dx}(7x)-\frac{d}{dx}(5)[/tex]

[tex]y'=4\cdot 3x^{3-1}+7x^{1-1}-0[/tex]

[tex]y'=12x^{2}+7x^{0}[/tex]

[tex]y'=12x^{2}+7(1)[/tex]

[tex]y'=12x^{2}+7[/tex]

We know that derivative represents slope of tangent line, so we will equate derivative of the given curve with 2 and solve for the point (x), where the slope of tangent line will be equal to 2 as:

[tex]12x^2+7=2[/tex]

[tex]12x^2+7-7=2-7[/tex]

[tex]12x^2=-5[/tex]

[tex]x^2=-\frac{5}{12}[/tex]

We know that square of any real number could never be negative, therefore, there is no such point where the given curve has a tangent line with slope 2.

Final answer:

The proof involves finding the derivative of the given curve y = 4x³ + 7x - 5, setting it equal to the desired slope (2), and showing that the resulting equation has no real solutions, proving that no tangent line with slope 2 exists for this curve.

Explanation:

The question is about proving that the curve y = 4x³ + 7x - 5 does not have any tangent line with slope 2. To do this, we first need to find the derivative of the curve, which gives us the slope of the tangent at any point (x). The derivative of y with respect to x is given by y' = 12x² + 7. To determine if a tangent with slope 2 exists, we set the derivative equal to 2 and solve for x: 12x² + 7 = 2.

Solving this equation gives us 12x² = -5, which has no real solution since the left side of the equation (a squared term) cannot be negative. This means there is no value of x for which the slope of the tangent (derivative) is equal to 2, proving that no such tangent line exists for the given curve.

Answer:

C

Step-by-step explanation:

I think you missed attaching the picture, so hope my photo fits your questions well!

We must consider the median of the data sets, it may  represent the center of the dispersion measure. Then we see answer C is the most suitable one, this is because it's median is approximately to $60.

Answer:

The center of the circle is (-2 , 3) ⇒ 3rd answer

Step-by-step explanation:

The equation of a circle is (x - h)² + (y - k)² = r², where

∵ The equation of the circle is x² + 4x + y² - 6y = 12

- Lets make a completing square for x² + 4x

∵ x² = (x)(x)

∵ 4x ÷ 2 = 2x

- That means the second term of the bracket (x + ...)² is 2

∴ The bracket is (x + 2)

∵ (x + 2)² = x² + 4x + 4

∴ We must add 4 and subtract 4 in the equation of the circle

∴ (x² + 4x + 4) - 4 + y² - 6y = 12

Lets make a completing square for y² - 6y

∵ y² = (y)(y)

∵ -6y ÷ 2 = -3y

- That means the second term of the bracket (y + ....) is -3

∴ The bracket is (y - 3)

∵ (y - 3)² = y² - 6y + 9

∴ We must add 9 and subtract 9 in the equation of the circle

∴ (x² + 4x + 4) - 4 + (y² - 6y + 9) - 9= 12

Now lets simplify the equation

∵ (x + 2)² + (y - 3)² - 13 = 12

- Add 13 to both sides

∴ (x + 2)² + (y - 3)² = 25

- Compare it with the form of the equation of the circle to

   find h and k

∵ (x - h)² + (y - k)² = r²

∴ h = -2 and k = 3

The center of the circle is (-2 , 3)

Answer:

C

Step-by-step explanation:

A function is a special kind of relation in which each valid input gives exactly one output.

C {(22, 10), (23, 10), (24, 7), (25, 5)}

So C is the correct option.

Answer:

Step-by-step explanation:

1/2 3

Answer: Area of sector = 11.8 square meters

Step-by-step explanation:

The formula for determining the area of a sector is expressed as

Area of sector = θ/360 × πr²

Where

θ represents the central angle.

r represents the radius of the circle.

π is a constant whose value is 3.14

From the information given,

Radius, r = 3 m

θ = 150 degrees

Therefore,

Area of sector = 150/360 × 3.14 × 3²

Area of sector = 11.8 square meters rounded up to the nearest tenth.

Answer:

Correct option is b. Procedure results in a binomial distribution.

Step-by-step explanation:

Consider that X is Binomial random variable. The properties that are satisfied by X are:

Suppose a roulette wheel is spun and the number of times the ball lands on '16' is observed.

If the random variable X is defined as the number of times the ball lands on '16', then the random variable X follows a Binomial distribution.

Because,

Thus, the correct option is b. Procedure results in a binomial distribution.

Answer:

(a)Area of the bedroom=96 square inches

(b)Area of the living room =144 square inches

(c)Area of the dollhouse that is not of the bedroom or living room =336 square inches.

Step-by-step explanation:

The area of the bedroom is 1/6 the area of the entire dollhouse

The area of the living room is 3/2 times the area of the bedroom.

The area of the entire dollhouse is 576 square inches

Let the area of bedroom=b

Let the area of living room=l

(a) The area of the bedroom is 1/6 the area of the entire dollhouse

[tex]b=\frac{1}{6}X576=96[/tex] square inches

(b)The area, in square inches, of the living room

The area of the living room is 3/2 times the area of the bedroom

l= [tex]\frac{3}{2}X96=144[/tex] square inches

(c)The total area of the house =576 square inches

Area of the bedroom=96 square inches

Area of the living room =144 square inches

Area of the dollhouse that is not of the bedroom or living room

=576-(96+144)=576-240=336 square inches.

The area of the living room is 3/2 times the area of the bedroom

This is gotten by subtracting the area of the bedroom and living room from the total area of the house.

Answer:

x+2x+$3+$5=$1131

Step-by-step explanation:

Take students to be x then the adults be 2x and the dollars being played and the total money.Then you will take the $3+$8 and subtract from $1131 dollars then you'll get x

Answer: The system of equations that represent this situation is

x = 2y

5x + 3y = 1131

Step-by-step explanation:

Let x represent the number of adult tickets sold on the first night of the play.

Let y represent the number of student tickets sold on the first night of the play.

On the first night of the play, twice as many adults attended the play as students. This means that

x = 2y

Students tickets cost $3 and adults tickets cost $5. The total amount of money earned from tickets sales was $1,131. This means that

5x + 3y = 1131- - - - - - - - - 1

There are 7 states with Monarch butterflies, 17 states with honeybees, and 6 states with ladybugs as their official insect.

Two or more expressions with an Equal sign is called as Equation.

Let us consider  M, H, and L to represent the number of states with Monarch butterflies, honeybees, and ladybugs as their official insect, respectively.

We know that M + H + L = 30, since there are 30 states in total.

From the problem statement, we also know that:

M = L + 1 (1)

H = 3L - 1 (2)

We can use equations (1) and (2) to solve for M, H, and L:

M + H + L = 30

Substituting equation (1) and (2) into this equation:

(L + 1) + (3L - 1) + L = 30

5L = 30

L = 6

So there are 6 states with ladybugs as their official insect. Using equation (1) and (2), we can then find:

M = L + 1 = 7

H = 3L - 1 = 17

Hence,  there are 7 states with Monarch butterflies, 17 states with honeybees, and 6 states with ladybugs as their official insect.

To learn more on Equation:

https://brainly.com/question/10413253

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Final answer:

To solve this problem, assign variables to represent the number of states that have each kind of insect. Use the given information to set up equations and solve simultaneously to find the values of 'm', 'h', and 'l'.

Explanation:

To solve this problem, let's assign variables to represent the number of states that have each kind of insect as their state insect. Let 'm' represent the number of states with Monarch butterflies, 'h' represent the number of states with honeybees, and 'l' represent the number of states with ladybugs as their official insect.

According to the problem, we have the following information:

'm' = 'l' + 1   (The number of states with Monarch butterflies is one more than the number of states with ladybugs)

'h' = 3('l') - 1   (The number of states with honeybees is three times the number of states with ladybugs minus one)

We also know that the total number of states is 30. So we can set up the following equation:

m + h + l = 30

Now, we can solve these equations simultaneously to find the values of 'm', 'h', and 'l'.

Using the first equation, we substitute 'l + 1' for 'm' in the second equation:

h = 3('l') - 1

h = 3(l + 1) - 1

h = 3l + 3 - 1

h = 3l + 2

Now, we substitute 'l + 1' for 'm' and '3l + 2' for 'h' in the third equation:

(l + 1) + (3l + 2) + l = 30

Simplifying the equation:

5l + 3 = 30

5l = 27

l = 5.4

Since 'l' represents the number of states with ladybugs, we can't have a fraction of a state. Therefore, we round 'l' down to the nearest whole number:

l = 5

Substituting this value back into the equations, we find that 'm' = 6 and 'h' = 14.

Therefore, there are 6 states with Monarch butterflies as their official insect, 14 states with honeybees, and 5 states with ladybugs.

Answer:

Step-by-step explanation:

Let x represent the total sales made in a year.

Employees at Driscoll's Electronics as a base salary plus a 20% Commission on their total sales for the year. If the base salary is $40,000, it means that if the employee makes a total sales of $x in a year, the total equation to represent earnings would be

0.2x + 40000

b) if Stewart wants to make $65,000 this year, it means that

0.2x + 40000 = 65000

0.2x = 65000 - 40000

0.2x = 25000

x = 25000/0.2

x = 125000

c) 52,000 + 0.3s = 82,000

The base salary is $52000

The percentage of commission from sales is 30%