Answer: 30+18x C is correct
Step-by-step explanation: You distribute the 6 to both of the values in the parenthesis.
Answer:
C 30 + 18x
Step-by-step explanation:
6(5 + 3x)
Distribute the 6 to both terms inside the parentheses
6*5 +6*3x
30 +18x
Factor the polynomial:
x^2 + 5x − 14 =
x^2 − 10x + 16 =
Answer:
the first one is: (x-2)(x+7)
the second one is: (x-2)(x-8)
I had this question and got it right.
To factor the polynomial x^2 + 5x - 14, use the method of finding two numbers that multiply to give the constant term and add up to give the coefficient of x. For x^2 - 10x + 16, use the same method to find the two numbers.
Explanation:To factor the polynomial x^2 + 5x - 14, we look for two numbers that multiply to give the constant term (-14) and add up to give the coefficient of x (5). In this case, the numbers are 7 and -2. So we can rewrite the polynomial as (x + 7)(x - 2).
To factor the polynomial x^2 - 10x + 16, we look for two numbers that multiply to give the constant term (16) and add up to give the coefficient of x (-10). In this case, the numbers are -2 and -8. So we can rewrite the polynomial as (x - 2)(x - 8).
What is the 5th term in the binomial expansion
(a+b)^7
Answer:
5th term is 35a^4b^3
Step-by-step explanation:
We need to find the 5th term in binomial expansion (a+b)^7
The binomial theorem is:
[tex](x+y)^n = \sum_{n=0}^{k} {n\choose k}x^ky^{n-k}[/tex]
We are given
x=a,
y =b
n=7
and k= 4 since we have to find 5th term but k starts from zero
putting the values
[tex]={7\choose 4}a^4b^{7-4}\\={7\choose 4}a^4b^{3}\\=\frac{7!}{4!(7-4)!}a^4b^3\\=35a^4b^3[/tex]
So, 5th term is 35a^4b^3
Answer:
On Apex
Step-by-step explanation:
35a^4 b^3
Use the properties of exponents to rewrite the expression.
3•b•b•b•b•b•c•c•c•c•c
Answer:
3 b^5 c^5
Step-by-step explanation:
3•b•b•b•b•b•c•c•c•c•c
There is 1 number 3 = 3
There are 5 letter b = b^5
There are 5 letter c = c^5
3 * b^5 * c^5
3 b^5 c^5
Answer:
In 3•b•b•b•b•b•c•c•c•c•c, there is one three, five b's, and five c's. By simplifying the expression, we get 3[tex]b^{5}c^{5}[/tex].
what best describes the sequence 256,128,64,32
Answer:
It's a geometric sequence.
Step-by-step explanation:
Note that the next term = the previous term multiplied by 0.5.
This is a geometric sequence with first term 256 and common ratio 0.5.
The nth term = 256(0.5)^(n-1).
What is the slope of the line represented by the equation y=-3x+1?
When a line is represented in the slope intercept formula as in the question you must remember that it is always set up like so...
y = mx + b
m is the slope and b is the y-intercept of the line
Since in the equation y = -3x + 1 the m is -3 then the slope is -3
Hope this helped!
~Just a girl in love with Shawn Mendes
What is the product of (5r+2)(3r-4)
Answer:
[tex]\large\boxed{(5r+2)(3r-4)=15r^2-14r-8}[/tex]
Step-by-step explanation:
[tex](5r+2)(3r-4)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(5r)(3r)+(5r)(-4)+(2)(3r)+(2)(-4)\\\\=15r^2-20r+6r-8\qquad\text{combine like terms}\\\\=15r^2+(-20r+6r)-8\\\\=15r^2-14r-8[/tex]
Write the following phrase as an expression.
x to the 9th
What’s equivalent to z+(z+6)
Answer:
2z + 6
Step-by-step explanation:
Since nothing can be done with the brackets we can take those out. We would end up with
z + z + 6
As you can see we have two z's and we can add those together. This would give us our answer:
2z + 6
If 3p-q=6 and 2p+3q=4 find q
Answer:
q=-6 and q=4/3 or 1.33Step-by-step explanation:3p-q=63(0)-q=6(Substitute 0 for p)-q=6(Divide by -1)q=-62p+3q=42(0)+3q=4(Substitute 0 for p)3q=4(Divide by 3)q=4/3 or 1.33What is the equation for the hyperbola shown? PLEASE HELP
ANSWER
[tex]\frac{ {y}^{2} }{ 25} - \frac{ {x}^{2} }{ 64} = 1 [/tex]
EXPLANATION
The given hyperbola has a vertical transverse axis and its center is at the origin.
The standard equation of such a parabola is:
[tex] \frac{ {y}^{2} }{ {a}^{2} } - \frac{ {x}^{2} }{ {b}^{2} } = 1 [/tex]
Where 2a=10 is the length of the transverse axis and 2b=16 is the length of the conjugate axis.
This implies that
[tex]a = 5 \: \: and \: \: b = 8[/tex]
Hence the required equation of the hyperbola is:
[tex]\frac{ {y}^{2} }{ {5}^{2} } - \frac{ {x}^{2} }{ {8}^{2} } = 1 [/tex]
This simplifies to,
[tex]\frac{ {y}^{2} }{ 25} - \frac{ {x}^{2} }{ 64} = 1 [/tex]
Answer:
[tex]\frac{(y^2}{25}-\frac{x^2}{64}=1[/tex]
Step-by-step explanation:
We have been given an image of a hyperbola. We are asked to write an equation for our given hyperbola.
We can see that our given hyperbola is a vertical hyperbola as it opens upwards and downwards.
We know that equation of a vertical hyperbola is in form [tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1[/tex], where, [tex](h,k)[/tex] represents center of hyperbola.
'a' is vertex of hyperbola and 'b' is co-vertex.
We can see that center of parabola is at origin (0,0).
We can see that vertex of parabola is at point [tex](0,5)\text{ and }(0,-5)[/tex], so value of a is 5.
We can see that co-vertex of parabola is at point [tex](8,0)\text{ and }(-8,0)[/tex], so value of b is 8.
[tex]\frac{(y-0)^2}{5^2}-\frac{(x-0)^2}{8^2}=1[/tex]
Therefore, our required equation would be [tex]\frac{(y^2}{25}-\frac{x^2}{64}=1[/tex].
n the diagram, what is mVSR?
Not enough information, please attach a photo next time.
which of the following points are solutions to the system of inequalities shown below?
check all that apply
y≥ 4x+3
x>1
answers:
a. (1,19)
b. (1,-1)
c. (4,11)
d. (4,19)
e. (1,11)
f. (2,11)
Answer:
f
Step-by-step explanation:
4x+3
x>1 x=2
4*2+3= 11
y>or = to 11
Lucy can assemble a computer by herself in 35 minutes. Manny does the same job in 50 minutes. How long will it take them to assemble a computer working together?
Answer:
Step-by-step explanation:
I think its 15 I just subtracted the two numbers
Answer: about 20.6 minutes
Step-by-step explanation:
Given : Lucy can assemble a computer by herself in 35 minutes.
Manny does the same job in 50 minutes.
Let t be the time taken by both of them working together.
Then, we have
[tex]\dfrac{1}{t}=\dfrac{1}{35}+\dfrac{1}{50}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{35+50}{35\times50}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{85}{1750}\\\\\Rightarrow\ t=\dfrac{1750}{85}=20.5882352941\approx20.6[/tex]
Hence, it will take approx 20.6 minutes to assemble a computer working together.
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.
What is the approximate difference between m∠C and m∠A?
Answer:
The approximate difference between m∠C and m∠A is 45° to the nearest degree
Step-by-step explanation:
* Lets talk about the right triangle
- It has one right angle and two acute angles
- The side opposite the the right angle is called hypotenuse
- The other sides are called the legs of the right angle
- In ΔABC
∵ AC is the hypotenuse
∴ ∠B is the right angle
∴ AB and BC are the legs of the right angle
∴ Angles A and C are the acute angles
∵ m∠B = 90°
- The sum of the measures of the interior angles of a Δ is 180°
∴ m∠A + m∠C = 180° - 90° = 90°
- We will use trigonometry to find the measures of angles A and C
- sin A is the ratio between the opposite side to angle ∠A and the
hypotenuse
∵ BC is the opposite side of angle A
∴ sin A = BC/AC
∵ BC = 5 cm
∵ AC = 13 cm
∴ sin A = 5/13
- Lets find m∠∠A by using sin ^-1
∴ m∠A = [tex]sin^{-1}\frac{5}{13}=22.62[/tex]
- Lets use the rule of the sum of angles A and C to find the measure
of the angle C
∵ m∠A + m∠C = 90°
∴ 22.62° + m∠C = 90 ⇒ subtract 22.62 from both sides
∴ m∠C = 67.38°
- Lets find the difference between m∠C and m∠A
∴ The approximate difference between m∠C and m∠A is:
67.38° - 22.62° = 44.78° ≅ 45° to the nearest degree
If y varies inversely as x and y = 18 when x = 4, what is y when x = 242
Answer:
y = [tex]\frac{36}{121}[/tex]
Step-by-step explanation:
Given that y varies inversely as x then the equation relating them is
y = [tex]\frac{k}{x}[/tex] ← k is the constant of variation
To find k use the condition y = 18 when x = 4
k = yx = 18 × 4 = 72, so
y = [tex]\frac{72}{x}[/tex] ← equation of variation
When x = 242, then
y = [tex]\frac{72}{242}[/tex] = [tex]\frac{36}{121}[/tex]
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
The equation of this circle is (x + )2 + (y + )2 =
.
Reset
Answer:
(x-5)^2+(y+4)^2=100
Step-by-step explanation:
As we know the given points
Center = (5, -4)
and
Point on circle = (-3,2)
The distance between point on circle and center will give us the radius of circle
So,
The formula for distance is:
[tex]\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10[/tex]
The standard form of equation of circle is:
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where h and k are the coordinates of the center. So putting in the value:
[tex](x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100[/tex]
Let f(x) = x + 1 and G(x)=1/x What is the range of (F*G)(X)
[tex]
f(x)=x+1 \\
g(x)=\dfrac{1}{x} \\
(f\cdot g)(x)=(x+1)\dfrac{1}{x} \\
(f\cdot g)(x)=\underline{\dfrac{x+1}{x}} \\ \\
0=\dfrac{x+1}{x} \\
0=\dfrac{x}{x}+\dfrac{1}{x} \\
0=1+\dfrac{1}{x} \\
-1=\dfrac{1}{x} \\
-x=1 \\
x=1
[/tex]
ANSWER
[tex]y \ne1[/tex]
EXPLANATION
The given functions are
[tex]f(x) = x + 1[/tex]
and
[tex]g(x) = \frac{1}{x} [/tex]
We want to find
[tex](f \times g)(x)[/tex]
We use function properties to obtain:
[tex](f \times g)(x) = f(x) \times g(x)[/tex]
[tex](f \times g)(x) = (x + 1) \times \frac{1}{x} = \frac{x + 1}{x} [/tex]
There is a horizontal asymptote at:
[tex]y = 1[/tex]
Let
[tex]y = \frac{x + 1}{x} [/tex]
[tex]xy = x + 1[/tex]
[tex]xy - x = 1[/tex]
[tex]x(y - 1) = 1[/tex]
[tex]x = \frac{1}{y - 1} [/tex]
The range is
[tex]y \ne1[/tex]
Or
[tex]( - \infty ,1) \cup(1, \infty )[/tex]
In what form is the following linear equation written?
3x – 2y=4
O
A. Point-slope
O
B. Standard
Slope-intercept
O
D. Rise-run
SUBMIT
Answer:
B. StandardStep-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The standard form of an equation of a line:
[tex]Ax+By=C[/tex]
The general fom of an equation of a line:
[tex]Ax+By+C[/tex]
We have the equation 3x - 2y = 4 in standard form.
Jessica and Martha each have a bag of cookies with unequal quantities. They have 30 cookies total between the two of them. Each of them ate 6 cookies from their bag. The product of the number of cookies left in each bag is not more than 80.
How many more cookies will Jessica have Martha?
If x represents the number of cookies Jessica started with, complete the statements below.
The inequality that describes the relationship between the number of cookies each one of them has is x^2 - ____ x +224 >= 0.
Jessica has at least ____ cookies more than Martha.
Answer:
Part 1) The inequality that describes the relationship between the number of cookies each one of them has is [tex]x^{2} -30x+224\geq 0[/tex]
Part 2) Jessica has at least 2 cookies more than Martha
Step-by-step explanation:
Part 1) Find the inequality that describes the relationship between the number of cookies each one of them has
Let
x----> the number of cookies when Jessica started
30-x ----> the number of cookies when Martha started
we know that
Each of them ate 6 cookies from their bag
so
The cookies left in each bag are
(x-6) ----> Jessica
and (30-x-6)=(24-x) ---> Martha
The product is equal to (x-6)(24-x)
The product of the number of cookies left in each bag is not more than 80.
so
[tex](x-6)(24-x)\leq 80\\ \\24x-x^{2}-144+6x\leq 80\\ \\-x^{2} +30x-144-80\leq 0\\ \\-x^{2} +30x-224\leq 0[/tex]
Multiply by -1 both sides
[tex]x^{2} -30x+224\geq 0[/tex]
Part 2) Solve the quadratic equation
[tex]x^{2} -30x+224\geq 0[/tex]
Solve by graphing
The solution is x=16 cookies
so
(30-x)=30-16=14 cookies
therefore
The number of cookies when Jessica started was 16 cookies
The number of cookies when Martha started was 14 cookies
The number of cookies left in each bag is equal to
Jessica
16-6=10 cookies
Martha
14-6=8 cookies
Jessica has at least 2 cookies more than Martha
part 1- 30
part 2- 2
To simplify it at least those are the answers
solve |2x-5|=4 pleasee
Answer:
x = 1/2 and x = 9/2
Step-by-step explanation:
To solve this equation: |2x-5|=4 we need two evaluate two cases:
|2x-5| = 2x-5 when x>5/2 ✅
|2x-5| = -2x+5 when x<5/2✅
Then, if x>5/2:
2x-5 = 4 ➡ x = 9/2
Then, if x>5/2:
-2x+5 = 4 ➡ x = 1/2
Then, the two solutions are: x = 1/2 and x = 9/2
Answer:
X= 1/2
Step-by-step explanation:
∆ABC has side lengths of 10 units, 20 units, and 24 units. ∆XYZ is similar to ∆ABC, and the length of its longest side is 60 units. The perimeter of ∆XYZ is units. If the height of ∆ABC, with respect to its longest side being the base, is 8 units, the area of ∆XYZ is square units.
Answer: Perimeter = 135 units Area = 1200 Square units
Step-by-step explanation: I think you want the perimeter and area of XYZ so that's what I will answer for.
First, we are given that ABC and XYZ are proportional and that their longest sides are 24 units and 60 units respectively.
Using this, we can say XYZ = ABC * 5/2 (60/24 = 5/2)
Therefore, the other two sides of XYZ are 50 and 25.
We can get the perimeter using 60 + 50 + 25, that equals 135 units
Next, since the height of ABC was 8 units with 24 units being its base, it's likely safe to say the height = 1/3 base
We will apply with to triangle XYZ, height = 1/3 * 60 = 20
20 units * 60 units = 1200 square units
The perimeter and area of the ΔXYZ are 135 units and 600 sq. units. Where similar triangles are related by a scale factor.
How to find the scale factor for similar triangles?The ratio of their respective sides of two similar triangles gives the scale factor. I.e.,
Consider ΔABC and ΔDEF are two similar triangles
Then its scale factor = DE/AB = EF/BC = DF/AC
The scale factor is also defined as follows:
(Scale factor)² = (Area of the triangle DEF)/(Area of the triangle ABC)
or
Scale factor = (perimeter of ΔDEF)/(perimeter of ΔABC)
Finding the scale factor:Given that the sides of the triangle ABC are 10 units, 20 units, and 24 units. The longest side is 24 units.
The triangle XYZ has the longest side of length 60 units.
Since ΔABC ~ ΔXYZ
So, the ratio of their longest sides gives the scale factor. I.e.,
Scale factor = 60/24 = 2.5
Calculating the perimeter of the ΔXYZ:The perimeter of the ΔXYZ is calculated by
Scale factor = (perimeter of the ΔXYZ)/(perimeter of the ΔABC)
⇒ 2.5 = (perimeter of the ΔXYZ)/(10 + 20 + 24)
⇒ perimeter of the ΔXYZ = 2.5 × 54
∴ the perimeter of the ΔXYZ = 135 units
Calculating the area of the ΔXYZ:The area of the ΔXYZ is calculated by
(Scale factor)² = (area of the ΔXYZ)/(area of the ΔABC)
So, the area of the ΔABC, whose height h = 8 units and base b = 24 units is
Area of the ΔABC = 1/2 × b × h
= 1/2 × 24 × 8
= 96 sq. units
Thus,
(Scale factor)² = (area of the ΔXYZ)/(area of the ΔABC)
⇒ (2.5)² = (area of the ΔXYZ)/(96)
⇒ area of the ΔXYZ = (2.5)² × 96
∴ area of the ΔXYZ = 600 sq units
Thus, the perimeter and area of the ΔXYZ are 135 units and 600 sq. units.
Learn more about the scale factor of similar triangles here:
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Which of the following equations represents an ellipse with a minor axis of length 10 and foci located at (3,6) and (7,6)?
Answer:
It is choice A.
Step-by-step explanation:
The general form is (x - h)^2 / a^2 + (x - k)^2/b^2 = 1 where (h, k) is the center, 2a = major axis and 2b = minor axis.
The ellipse in the question has a^2 > b^2 so the major axis is parallel to the x axis.
The minor axis which is parallel to the y-axis is of length 10 so b^2 = (1/2 * 10)^2
= 25 so we can eliminate C.
The center of the ellipse = the midpoint of a line joining the focii so it is:
( 3+ 7)/2, 6)
= (5,6).
As (h, k) is the center we have h = 5 and k = 6.
So it is choice A.
The equation of the eclipse will be [tex]\frac{(x-5)^2}{29} +\frac{(y-6)^2}{25} =1[/tex] i.e. option A.
What is equation of the ellipse?The standard equation of the ellipse is [tex]\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2} =1[/tex].
Here,
(h, k) is the center, and 2a and 2b are major and minor axis.
We have,
Length of minor axis = 10
i.e. 2b = 10
And, b = 5
And,
Foci (c) located at (3,6) and (7,6),
i.e. Major axis is parallel to x-axis. [Because y is constant]
And,
The foci (c) always lie on the major axis.
And,
c² = a² - b²
Now,
The center of an ellipse is the midpoint of both the major and minor axes, i.e. the midpoint of a line joining the foci (c),
i.e. Center [tex]=( \frac{x_1 + x_2 }{2}, \frac{y_1 + y_2}{2}) =( \frac{3+7}{2}, \frac{6+6}{2}) =(5, 6)[/tex]
Now,
Foci (c) = 5 - 3 = 2
So,
c² = a² - b²
i.e.
2² = a² - 5²
4 = a² - 25
⇒ a² = 29
And, b² = 5² = 25
So,
h = 5 and k = 6
Now,
Putting the values in the standard form of equation of the ellipse,
i.e.
[tex]\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2} =1[/tex]
i.e.
[tex]\frac{(x-5)^2}{29} +\frac{(y-6)^2}{25} =1[/tex]
So, this is the equation of the eclipse i.e. option A.
Hence, we can say that the equation of the eclipse will be [tex]\frac{(x-5)^2}{29} +\frac{(y-6)^2}{25} =1[/tex] i.e. option A.
To know more about equation of the eclipse click here
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If f(x) = 4x2 and g(x) = x+1, find (*•g)(x).
Answer:
(f · g)(x) = 4x³ + 4x²Step-by-step explanation:
(f · g)(x) = f(x) · g(x)
We have f(x) = 4x² and g(x) = x + 1. Substitute:
(f · g)(x) = (4x²)(x + 1) use the distributive property
(f · g)(x) = (4x²)(x) + (4x²)(1)
(f · g)(x) = 4x³ + 4x²
The formula to determine energy is E=1/2mv2? What is the formula solved for v?
Answer:
v = √( [tex]\frac{2E}{m}[/tex] )
Step-by-step explanation:
E=1/2mv²
v² = ( [tex]\frac{2E}{m}[/tex] )
v = √( [tex]\frac{2E}{m}[/tex] )
Answer:
[tex]v=\sqrt{\frac{2E}{m}}[/tex]
Step-by-step explanation:
[tex]E= \frac{1}{2} mv^2[/tex]
Solve the equation for v
To remove fraction , multiply both sides by 2
[tex]2 \cdot E= \frac{1}{2} mv^2 \cdot 2[/tex]
[tex]2E=mv^2[/tex]
Divide both sides by 'm' to isolate v^2
[tex] \frac{2E}{m}=v^2[/tex]
Now to remove square from V, we take square root on both sides
[tex]\sqrt{\frac{2E}{m}} =v[/tex]
[tex]v=\sqrt{\frac{2E}{m}}[/tex]
wich expression is equivalent 1/4-3/4x
Answer:1/4(1-3x)
Step-by-step explanation:
Adimas found the mean of her 11 math test scores for the first semester.
x = ≈ 81
Using 81 as the mean, find the variance of her grades rounded to the nearest hundredth.
σ2 =
Find the standard deviation of her grades rounded to the nearest hundredth.
σ =
Answer: O^2= 71.36
O=8.45
Answer:
The complete question is attached.
To find the variance and deviation, we have to use their definition or formulas:
Standard deviation.[tex]\sigma=\sqrt{\frac{\sum (x- \mu)^{2} }{N}}[/tex]
So, first we have to find the difference between each number and the mean:
76-81=-5
87-81=6
65-81=-16
88-81=7
67-81=-14
84-81=3
77-81=-4
82-81=1
91-81=10
85-81=4
90-81=9
Now, we have to elevate each difference to the squared power and then sum all:
[tex]25+36+256+49+196+9+16+1+100+16+81=785[/tex]
Then, we replace in the formula:
[tex]\sigma=\sqrt{\frac{785}{11}} \approx 8.45[/tex]
Variance.The variance is just the squared power of the standard deviation. So:
[tex]\sigma^{2}=(8.45)^{2}=71.40[/tex]
If triangle abc is similar to triangle mno how do I solve for value of missing side
ABC 1.2cm and 3.0cm
Mno 0.96 and x
Answer:
=2.4 cm
Step-by-step explanation:
In similar plane figures, the ratio of corresponding sides is a constant.
This constant is the linear scale factor.
In the provided example, 1.2cm corresponds to 0.96 while 3.0 corresponds to x
Thus, 1.2 cm/0.96 cm=3.0 cm/x
x=(3.0 cm×0.96 cm)/1.2 cm
=2.4 cm.
Answer:
1.44 cm
Step-by-step explanation:
PLS HELP! WILL GIVE BRAINLIEST.
Answer:
Rotation of 90 degrees clockwise and then Dilation (scale factor) of 0.5
Drag each tile to the correct box.
Find the y-intercept of each exponential function and order the functions from least to greatest y-intercept.
Answer:
The functions ordered from least to greatest y-intercept are
1) h(x) -----> y-intercept -1
2) g(x) ----> y-intercept 1
3) f(x) ----> y-intercept 2
Step-by-step explanation:
we know that
The y-intercept (or initial value) is the value of y when the value of x is equal to zero
Part 1) Find the y-intercept of g(x)
Remember that the initial value of the fuction is equal to the y-intercept
a=1 -----> is the initial value
therefore
The y-intercept of g(x) is 1
Part 2) Find the y-intercept of f(x)
Observing the table
For x=0
f(x)=2
therefore
The y-intercept of f(x) is 2
Part 3) Find the y-intercept of h(x)
Observing the graph
For x=0
h(x)=-1
therefore
The y-intercept of h(x) is -1
Answer:
1 3 2
Step-by-step explanation:
If an acute angle increases, then its supplement
Answer:
gets smaller.
Step-by-step explanation:
Quick Answer
To give you a short quick answer, the supplement is going to have to decrease or get smaller.
Example
Suppose the acute angle is 10 (anything under 90 will do).
Then the supplement is going to be 180 - 10 = 170
Now suppose the acute angle increase to 50 degrees.
That means the supplement will go from 180 - 50 = 130
Conclusion
As the acute angle gets bigger, the supplement gets smaller. This is an important idea to get clear. Bigger and Smaller or More or Less can be ugly little words, so anytime you come across them, pay attention. It will make your life in science so much easier.