1) Which is a characteristic of a metal? A) It looks dull. B) It feels brittle. C) It is a good insulator. D) It is a good conductor of electricity. 2)

Answer:

Option B) C and D

Explanation:

The amount of charge passing through a resistor each second corresponds to the definition of current, so the problem is asking "which resistors have the same amount of current".

Let's keep in mind that:

- When two resistors are in series (=they are connected into the same branch of the circuit), the current flowing through each resistor is the same

- When two resistors are in parallel (=they are connected into different branches), the potential difference across each resistor is the same

Looking at the previous definitions, we have to find the two resistors in the circuit that are connected in series. We see that resistors C and D are in the same branch, so they are in series: therefore, the current flowing through resistor C and D is the same.

Answer:

gamma, becasue the alpha particals would be blocked by the wall between you. radiation gives off gamma particals and Alpha particals mostly.

Explanation:

Gamma decay would be most likely deflected.

When an unstable atomic nucleus loses energy by radiation, the process is referred to as radioactive decay.

A substance is defined as radioactive if it has unstable nuclei. The three most common kinds of decay are alpha decay, beta decay, and gamma decay, all of which involve the emission of one or more particles.

The definition of alpha decay refers to a typical kind of radioactive decay when a nucleus generates an alpha particle.

A nucleus releases beta particles as it undergoes beta decay, a typical kind of radioactive decay.

A nucleus undergoes gamma decay when it transforms from a state with a greater energy to one with a lower energy by emitting electromagnetic radiation (photons).

Hence,

Gamma decay would be most likely deflected.

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B, larceny because that's theft of personal property.

Answer:water is more dense

Explanation:

Answer:

[tex]P_a = P_b[/tex]

Explanation:

As per Pascal's law we know that when liquid is at rest then the pressure due to liquid at all points lying at the same level will be same

So here as per given figure we know that two points are lying at the same level under the water level

As per pascal's law the pressure at point points will be same

So correct answer will be

[tex]P_a = P_b[/tex]

Answer:

C. It can be magnetized

Explanation:

As we know that Ferromagnetic materials are made up of small domains which can be treated as small magnets.

These small magnets are aligned in random directions so that the net magnetic field due to all small domains will cancel out and it gives no magnetic field by their own.

Now when these type of ferromagnetic substances are placed in external magnetic field then due to the external field these all domains are aligned in the direction of external magnetic field.

Due to this alignment of domains ferromagnetic substance produce their own field and this phenomenon is known as magnetization

So here correct answer will be

C. It can be magnetized

Answer:

C. It can be magnetized

Answer:

Paramagnetic materials are attracted by external magnetic fields whereas diamagnetic materials are repelled. Paramagnetic materials have at least one unpaired electron in the system, but diamagnetic materials have all their electrons paired.

Explanation:

Diamagnetic materials are weakly repelled by magnetic fields due to induced dipoles aligning oppositely, while paramagnetic materials are weakly attracted due to their unpaired electrons aligning with the field. Copper and gold are examples of diamagnetic materials, whereas aluminum and magnesium are examples of paramagnetic materials.

Diamagnetic and paramagnetic materials respond differently to magnetic fields due to their distinct atomic properties.

Diamagnetism is characterized by a weak repulsion from magnetic fields. This occurs because the atoms in diamagnetic materials have no permanent magnetic dipole moments. When an external magnetic field is applied, it induces magnetic dipoles within the atoms. These induced dipoles align oppositely to the applied field, creating a repulsive effect. When the field is removed, the induced magnetic effect vanishes.

Examples of diamagnetic materials include copper, gold, and silicon.

Paramagnetism involves a weak attraction to magnetic fields. The atoms in paramagnetic materials have unpaired electrons, which results in permanent magnetic dipole moments. When an external magnetic field is applied, these dipoles tend to align with the field, enhancing its effect. However, this alignment is temporary and disappears when the external field is removed.

Examples of paramagnetic materials include aluminum, magnesium, and platinum.

Answer:

ligma

Explanation:

Answer: 27.3 days.

Explanation: The Moon actually takes 27.3 days to complete one orbit around Earth. The Moon takes 29.5 days to complete one cycle of phases.

Work = (force) x (distance)

Work = (30 N) x (15 m)

Work = 450 Joules

Power = (work done) / (time to do the work)

Power = (450 Joules) / 8 seconds)

Power = 56.25 watts

Gel electrophoresis is called to the  technique used by scientists for analytical purposes, in life sciences laboratories to separate macromolecules (DNA, RNA, and proteins from various sources).

The process consists of separating the molecules according to their size and electric charge. This is done with a gel (a gelatinous substance extracted from seaweed, called agarose) of controllable porosity placed in an ionic buffer environment. This is how the gel acts as a molecular sieve that separates larger molecules from the smaller ones, because each molecule has different size and charge and will move through the gel at different speeds.

That is, the smaller molecules move more quickly through the gel while the larger ones are left behind.

Gel electrophoresis is a technique used in biology to separate nucleic acids such as DNA based on size. The negatively charged nucleic acids move through a semisolid gel when an electric field is applied, with smaller molecules moving faster than larger ones. The fragments can be observed as bands on the gel, their distance from the top depending on their size.

Gel electrophoresis is a technique used to separate nucleic acids, such as DNA fragments, based on their size. This separation occurs because nucleic acids, which carry a negative charge, move through a semi-solid, porous gel when subjected to an electric field. They load near the gel's negative electrode and move towards the positive one at the opposite end. The speed at which these molecules move depends on their size, with smaller ones moving faster through the gel's pores than larger ones. This difference in migration rate enables the separation. When observed with fluorescent or colored dyes, distinct fragments of nucleic acids appear as bands at specific distances from the top of the gel, based on their size.

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Answer:

A.

Explanation:

Answer: Option A

Explanation: Waves (mechanical and electromagnetic) can transfer energy when they impact into something.

When a boat speeds in the water, the boat itself pushes water around it generating mechanical waves in the water, those mechanical waves now travel on the surface of the water. When those mechanical waves impact the buoy, the waves also move the buoy, and now the buy is in a "wave-like" motion (you can model the movement of the buoy as a mechanical wave, that goes up and down), so this is a good example of energy transfer.

The moment of inertia [tex]\( I_2 \)[/tex] of sphere 2 exceeds the moment of inertia [tex]\( I_1 \)[/tex] of sphere 1 by a factor of 4.

The moment of inertia I of a solid sphere is given by the formula:

[tex]\[ I = \frac{2}{5} m r^2 \][/tex]

Where:

- m = mass of the sphere

- r = radius of the sphere

Given that sphere 2 has twice the radius of sphere 1, we can express the radius of sphere 2 as 2r, where r is the radius of sphere 1.

Now, let's consider the moment of inertia for each sphere:

1. Sphere 1 (with radius r):

[tex]\[ I_1 = \frac{2}{5} m r^2 \][/tex]

2. Sphere 2 (with radius (2r):

[tex]\[ I_2 = \frac{2}{5} m (2r)^2 \][/tex]

We can simplify [tex]\( I_2 \)[/tex] as follows:

[tex]\[ I_2 = \frac{2}{5} m (4r^2) = \frac{8}{5} m r^2 \][/tex]

Now, to find the factor by which [tex]\( I_2 \)[/tex] exceeds [tex]\( I_1 \)[/tex], we divide [tex]\( I_2 \)[/tex] by [tex]\( I_1 \)[/tex]:

[tex]\[ \text{Factor} = \frac{I_2}{I_1} = \frac{\frac{8}{5} m r^2}{\frac{2}{5} m r^2} \][/tex]

[tex]\[ \text{Factor} = \frac{\frac{8}{5}}{\frac{2}{5}} = \frac{8}{2} = 4 \][/tex]

So, the moment of inertia [tex]\( I_2 \)[/tex] of sphere 2 exceeds the moment of inertia [tex]\( I_1 \)[/tex] of sphere 1 by a factor of 4.

Complete Correct Question:

You have steel solid spheres. Sphere 2 has twice the radius of sphere 1. by what factor does the moment of inertia of sphere 2 exceed the moment of inertia of sphere 1?

A. 2

B. 4

C. 32

D. 8

E. 16

F. 64

from farthest to the nearest

Neptune

Uranus

saturn

Jupiter

mars

earth

venus

mercury

Answer:

I mean since this is just telling where the normal line of the planets is and not a Jovian etc.

Explanation:

It's just asking the order from smallest to greatest. Just flip it the other direction if it's largest to smallest.

Answer:

different poles

Explanation:

different poles attract to each other while same poles repel each other . just remember the old saying opposites attract and likes repel .

Answer: There are a lot of answers, so I will give a short answer to everyone:

1) The magnetic objects only come in dipolar form, so the poles attracted to each other are the different poles (negative to positive9

2) Magnets are surrounded by a field called Magnetic Field.

3) Bar magnets have two poles, as i already said, magnets commonly come in dipolar (two) forms.

4) Ferric materials, so the correct option is iron, cobalt, and nickel.

5) Electrons are the fundamental negative charges. Are the ones responsible of the electromagnetism (which includes the magnteism)

6) False, the magnetic field strength decreases as the distance to the source increases.

7) Electromagnets, as the name implies.

8) Turkish is actually the only benefit, the problem is that they need energy to work, so electromagnets are not actually beneficial for the environment.

9) by the molten iron in the Earth's core.

10) True, doorbells use magnetic fields to make a small piece of metal to vibrate and impact against metal to make noise, scrap yards are moved with big magnets, and the electric guitar and basses need electromagnetism to work, the pickups on those instruments have tiny magnets inside.

11) False, electromagnets do not have theoretical a limit on the magnetic field that they can create.

12) The diagram is missing.

The magnets will connect only if the poles that are facing each other are different.

Answer:

= 54,000 Joules or 54 kJ

Explanation:

Electrical energy is given by the formula;

E = VIt; where V is the potential difference in volts, I is the current and t is the time in seconds.

Therefore;

Electrical energy = 120 V × 0.50 A × 15 ×60 seconds

                            = 54,000 Joules

Thus; the electrical energy is 54,000 joules or 54 kJ

determining the dates of old objects using radioactive elements is called what radiometric dating

Answer: radiometric

Answer: Radiometric

Explanation: Apex

The first human made object made to orbit earth was the Soviet Union's Sputnik 1, it launched the 4th of October 1957.

Final answer:

The first human-made object to orbit Earth was the Soviet satellite Sputnik 1, launched on October 4, 1957. It marked the beginning of the Space Age and initiated the study of orbitography.

Explanation:

The first object made by humans to orbit Earth was Sputnik 1, launched by the Soviet Union on October 4, 1957. This pioneering artificial satellite emitted a beeping radio signal, symbolizing the commencement of the Space Age and marking a historically significant moment in human exploration of space. It didn't carry cameras, but it transmitted a signal that brought awareness to the world about human capabilities in space.

Sputnik's launch set the scene for the future of orbital space, initiating a new field of knowledge referred to as orbitography, which studies the movements and characteristics of objects in Earth's orbital space. Following Sputnik, thousands of satellites and space debris have since populated Earth's orbit, with scientific and technological advancements continuing to push the boundaries of space exploration.

de Broglie wavelength (λ) is given by the equation

λ = h/p

where h=Planck’s constant whose value is 6.62 x 10^(−34) joule-seconds and

p = momentum of the particle(here electron)

In terms of kinetic energy(E) momentum(p) can be written as,

p=(2mE)^1/2

where m=mass of the particle.

Hence λ becomes

1 λ = h(2mE)^-1/2

Given here, E = 13.6 eV = 13.6×1.6×10^-19 joule

m(mass of electron)= 9.1×10^-31 kg

Putting these values in equation (1) we get ,

λ =0.332×10^(-9) meter

=3.32×10^(-10) meter

=3.32 Å

De Broglie wavelength of an electron in the ground state of the hydrogen atom is about 3.33 × 10⁻¹⁰ m

[tex]\texttt{ }[/tex]

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :

[tex]\large {\boxed {E = h \times f}}[/tex]

where:

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

[tex]\texttt{ }[/tex]

Let's recall De Broglie's Wavelength Formula as follows:

[tex]\boxed{\lambda = \frac{h}{mv}}[/tex]

where:

λ = wavelength ( m )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

m = mass of object ( kg )

v = velocity of object ( m/s )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

energy of the ground state of the hydrogem atom = E = 13.6 eV = 2.176 × 10⁻¹⁸ J

Asked:

wavelength of electron = λ = ?

Solution:

Firstly , we will calculate the speed of the electron :

[tex]E = E_k[/tex]

[tex]E = \frac{1}{2}mv^2[/tex]

[tex]v^2 = 2E \div m[/tex]

[tex]\boxed{v = \sqrt{ 2E \div m } }[/tex] → Equation A

[tex]\texttt{ }[/tex]

Next, we will use the formula of The Broglie's Wavelength:

[tex]\lambda = \frac{h}{mv}[/tex]

[tex]\lambda = \frac{h}{m\sqrt{ 2E \div m }}[/tex] ← Equation A

[tex]\lambda = \frac{6.63 \times 10^{-34}}{9.11 \times 10^{-31} \sqrt{ 2 \times 2.176 \times 10^{-18} \div 9.11 \times 10^{-31} }}[/tex]

[tex]\boxed{\lambda = 3.33 \times 10^{-10} \texttt{ m}}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: College

Subject: Physics

Chapter: Quantum Physics

Answer:

pressure and temperature (assuming volume is constant)

Explanation:

Answer:

the answer is C on edge.

Explanation:

(a) 0.0068 Wb

Since the plane of the coil is perpendicular to the magnetic field, the magnetic flux through the coil is given by

[tex]\Phi = NBA[/tex]

where

N = 200 is the number of loops in the coil

B is the magnetic field intensity

[tex]A=8.5 cm^2 = 8.5\cdot 10^{-4} m^2[/tex] is the area of the coil

At the beginning, we have

[tex]B_i = 0.060 T[/tex]

so the initial magnetic flux is

[tex]B_i = (200)(0.060 T)(8.5\cdot 10^{-4} m^2)=0.0102 Wb[/tex]

at the end, we have

[tex]B_f=0.020 T[/tex]

so the final magnetic flux is

[tex]B_f = (200)(0.020 T)(8.5\cdot 10^{-4} m^2)=0.0034 Wb[/tex]

So the magnitude of the change in the external magnetic flux through the coil is

[tex]\Delta \Phi = |\Phi_f - \Phi_i|=|0.0034 Wb-0.0102 Wb|=0.0068 Wb[/tex]

(b) 0.567 V

The magnitude of the average voltage (emf) induced in the coil is given by Faraday-Newmann law

[tex]\epsilon= \frac{\Delta \Phi}{\Delta t}[/tex]

where

[tex]\Delta \Phi = 0.0068 Wb[/tex] is the variation of magnetic flux

[tex]\Delta t = 12 ms = 0.012 s[/tex] is the time interval

Substituting into the formula, we find

[tex]\epsilon=\frac{0.0068 Wb}{0.012 s}=0.567 V[/tex]

(c) 0.142 A

The average current in the coil can be found by using Ohm's law:

[tex]I=\frac{V}{R}[/tex]

where

I is the current

V is the voltage

R is the resistance

Here we have:

V = 0.567 V (induced voltage)

[tex]R=4.0 \Omega[/tex] (resistance of the coil)

Solving for I, we find

[tex]I=\frac{0.567 V}{4.0 \Omega}=0.142 A[/tex]

We calculate the change in magnetic flux with ΔΦ = n*A*(Bf - Bi). The average induced voltage (or emf) can be computed using Faraday’s Law (ΔV = - ΔΦ / Δt). The average current is calculated using Ohm's Law (I = ΔV / R).

This question involves the concepts of electromagnetic induction and Ohm's Law. To solve the problem, we'll use Faraday's Law of electromagnetic induction and Ohm's law.

(a) The magnitude of change in external magnetic flux enclosed by the coil is calculated using the formula: ΔΦ = n*A*(Bf - Bi) where ΔΦ is the change in flux, n is the number of loops, A is the cross-sectional area, Bf is the final magnetic field strength, and Bi is the initial magnetic field strength. Using the given values, ΔΦ = 200 * (8.5E-4 m²) * (0.020 T - 0.060 T) = -0.0068 Weber.

(b)The average voltage (or emf) induced in the coil as the external flux is changing is given by Faraday’s law: ΔV = - ΔΦ / Δt, where Δt is the change in time. Thus, ΔV = - (-0.0068 Wb) / 12E-3 s = 0.57 V.

(c)Finally, the average current in the coil can be found using Ohm's Law: I = ΔV / R, where R is the resistance. Hence, I = 0.57 V / 4.0 Ω = 0.1425 A.

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Answer:

They will be attracted.

Explanation:

They will be attracted because the negatives block the positive in the right balloon and positive attracts negative. Also, the positive attracts the negative in the left balloon. Therefore, they will be attracted. Hope this helps.

Answer:

they will atract eachother

Explanation:

A) [tex]4.6\cdot 10^{11} m[/tex]

The period of the orbit of the clumps around the black hole is

[tex]T=27 h \cdot (3600 s/h)=97,200 s[/tex]

While their orbital speed is

[tex]v=30,000 km/s=3.0\cdot 10^7 m/s[/tex]

And the orbital speed is equal to the ratio between the circumference of the orbit and the orbital period:

[tex]v=\frac{2\pi r}{T}[/tex]

So re-arranging the equation, we find the radius of the orbit of the clumps:

[tex]r=\frac{vT}{2\pi}=\frac{(3.0\cdot 10^7 m/s)(97,200 s)}{2\pi}=4.6\cdot 10^{11} m[/tex]

B) [tex]6.2\cdot 10^{36}kg, 3.1\cdot 10^6 M_s[/tex]

The mass of the black hole can be found by equalizing the gravitational attraction between the black hole and the clumps to the centripetal force:

[tex]G\frac{Mm}{r^2} = m\frac{v^2}{r}[/tex]

where G is the gravitational constant, M the mass of the black hole, m the mass of the clumps.

Solving for M,

[tex]M=\frac{v^2r}{G}=\frac{(3.0\cdot 10^7 m/s)^2(4.6\cdot 10^{11} m)}{6.67\cdot 10^{-11}}=6.2\cdot 10^{36}kg[/tex]

And since 1 solar mass is

[tex]M_s = 2.0\cdot 10^{30} kg[/tex]

the mass of the black hole in multuple of solar masses is

[tex]M=\frac{6.2\cdot 10^{36}kg}{2.0\cdot 10^{30} kg}=3.1\cdot 10^6 M_s[/tex]

C)  [tex]9.2\cdot 10^9 m[/tex]

The radius of the event horizon of a black hole is given by

[tex]R=\frac{2GM}{c^2}[/tex]

where

G is the gravitational constant

M is the mass of the black hole

c is the speed of light

Substituting, we find

[tex]R=\frac{2(6.67\cdot 10^{-11})(6.2\cdot 10^{36}kg)}{(3.0\cdot 10^8 m/s)^2}=9.2\cdot 10^9 m[/tex]

Explanation of distance from the black hole, mass calculation, and event horizon radius for the given scenario.

A. How far are these clumps from the center of the black hole?

To calculate the distance, we can use the formula for orbital speed: v = 2πr / T. Given T = 27 hours and v = 30,000 km/s, we can find r. r = v * T / (2π) = 30,000 km/s * 27 hours / (2π) = 405,389 km from the center of the black hole.

B. What is the mass of this black hole, assuming circular orbits?

Using Kepler's third law, we have M = r * v^2 / G, where G is the gravitational constant. Plugging in the values, we can find the mass both in kilograms and as a multiple of our sun's mass.

C. What is the radius of its event horizon?

The event horizon radius of a black hole is given by the formula r = 2GM / c^2, where G is the gravitational constant, M is the mass, and c is the speed of light.

DIFFERENT in amplitude.

It depends on the "gain" of the amplifier. If gain is less than 1, output amplitude is smaller. If gain is more than 1, output amplitude is greater

A transistor circuit amplifies the signal applied to its input by increasing its amplitude. This is achieved through controlling a large current with a small input voltage or current, a principle that enables sound amplification in devices like microphones and loudspeakers.

A transistor circuit is used as an amplifier to increase the amplitude of the signal applied to its input. Transistor amplifiers work by using a small input voltage or current to control a much larger current flow through the circuit. This principle allows devices like microphones and loudspeakers to operate; for example, sound waves cause the diaphragm inside a microphone to move, which in turn varies the voltage applied to the base of a transistor. This small change in the base voltage controls a larger current that flows to the loudspeaker, effectively amplifying the sound. The amount by which the signal is amplified is referred to as the gain, which can be expressed in terms of voltage gain (the ratio of output voltage to input voltage) or current gain (the ratio of output current to input current).

It's important to note, however, that amplifiers can introduce distortion if the input signal amplitude increases beyond the maximum output amplitude the circuit can handle, leading to cutoff peaks in the output signal.

answers to electronic devices quiz

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Answer:

Protons = 50

Mass number = 119

Explanation:

A neutral of tin, Sn, has a Z value of 50 and neutrons are 69.

Z is the atomic number. The atomic number is equal to number of protons or number of electrons in an atom that is neutral i.e:

Z = PROTONS = ELECTRONS

So the number of protons = 50 since Z is 50

>>>>>>>>>>>>>>>¦

The bulk of the mass of an atom is concentrated in the nucleus. To calculate mass number, we simply sum all the elementary particles in the nucleus i.e protons and neutrons. These particles are called the nucleons.

Mass number (A) = P + N

= 50 + 69

= 119

Answer: 119

Explanation:

B.

because N -pole and S-pole attrack

Answer:

Opposite poles attract each other, similar poles repel.

Explanation:

(Unlike or different poles)

The charge transferred during a lightning strike with a current of 2.50 x[tex]10^4[/tex]A lasting for 40.0 microseconds is calculated as 1.00 C using the formula Q = I x t.

The amount of charge transferred during a lightning strike can be calculated by using the formula Q = I x t, where Q is the charge in coulombs (C), I is the current in amperes (A), and t is the time in seconds (s). Given that the current during a lightning strike is 2.50 x [tex]10^4[/tex] A and it lasts for 40.0 microseconds (which is 40.0 x [tex]10^{-6}[/tex] seconds), we can calculate the charge transferred from the cloud to the earth.

By substituting the given values into the formula, we get:

Q = ([tex]2.50 \times 10^4 A) \times (40.0 \times 10^{-6} s[/tex]) = 1.00 C.

Thus, 1 coulomb of charge is transferred from the cloud to the earth during such a lightning strike.

The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thus CO2 diffuses_______ C3H8.

Slower Than

Faster Than

The Same As

Slower than

Answer:  [tex]CO_2[/tex] gas diffuses faster than [tex]C_3H_8[/tex]

Explanation:

Diffusion of a gas is defined as the amount of volume of gas displaced in a given amount of time. The diffusion of gas is determined by using Graham's Law.

This law states that the rate of diffusion of gas is inversely proportional to the square root of its molar mass. The equation given by this law follows:

[tex]\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}[/tex]

More the molar mass of the gas, its rate of effusion will be less and vice-versa.

We are given:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of propane = 44.10 g/mol

As, the molar mass of carbon dioxide is less than the molar mass of propane by 0.1 unit, so rate of diffusion of carbon dioxide is faster than the rate of effusion of propane.

Hence, [tex]CO_2[/tex] gas diffuses faster than [tex]C_3H_8[/tex]

Using the mirror formula.

1/v + 1/u = 1/f

1/9.5 + 1/3.2 = 1/f

1/f = 3.2 + 9.5 / 9.5 * 3.2

1/f = 4.82 cm

Radius = 2f

Radius = 2 x 4.82

Radius = 9.64 cm

Answer:

Radius of curvature, R =  9.64 cm              

Explanation:

It is given that,

Object distance, u = -9.5 cm

Image distance, v = 3.2 cm

We have to find the radius of curvature of the mirror. The relationship between focal length and the radius of curvature as R = 2 f where f is the focal length of the mirror.

Using Mirror's formulas as :

[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]

[tex]\dfrac{1}{3.2}+\dfrac{1}{-9.5}=\dfrac{1}{f}[/tex]

f = 4.82 cm

And radius of curvature of the mirror becomes, R = 9.64 cm. Hence, this is the required solution.