Answer:
The correct answer is option B. 18
Step-by-step explanation:
It is given an expression : 3 × (50 – 62) ÷ 2
To find the answer we have to use BODMAS principle
BODMAS means that the order of operations
B- Bracket, O - of , D - Division, M - Multiplication, A - Addition and
S - Subtraction
To find the correct option
Step 1: Do the bracket first
3 × (50 – 62) ÷ 2 = 3 × (-12) ÷ 2
Step 2: Division
3 × (-12) ÷ 2 = 3 x (-6)
Step 3 : Multiplication
3 x (-6) = -18
The correct option is option B. 18
Match each function formula with the corresponding transformation of the parent function y = (x - 1)2 1. y = - (x - 1)2 Reflected over the y-axis 2. y = (x - 1)2 + 1 Reflected over the x-axis 3. y = (x + 1)2 Translated right by 1 unit 4. y = (x - 2)2 Translated down by 3 units 5. y = (x - 1)2 - 3 Translated up by 1 unit 6. y = (x + 3)2 Translated left by 4 units
Answer:
y = -(x-1)² . . . . reflected over the x-axisy = (x-1)² +1 . . . . translated up by 1 unity = (x+1)² . . . . reflected over the y-axisy = (x-2)² . . . . translated right by 1 unity = (x-1)² -3 . . . . translated down by 3 unitsy = (x+3)² . . . . translated left by 4 unitsStep-by-step explanation:
Since you have studied transformations, you are familiar with the effect of different modifications of the parent function:
f(x-a) . . . translates right by "a" unitsf(x) +a . . . translates up by "a" unitsa·f(x) . . . vertically scales by a factor of "a". When a < 0, reflects across the x-axisf(ax) . . . horizontally compresses by a factor of "a". When a < 0, reflects across the y-axis.Note that in the given list of transformed functions, there is one that is (x+1)². This is equivalent to both f(x+2) and to f(-x). The latter is a little harder to see, until we realize that (-x-1)² = (x+1)². That is, this transformed function can be considered to be either a translation of (x-1)² left by 2 units, or a reflection over the y-axis.
Below is the beginning of the construction of a line parallel to the y-axis through point P. What is the next step of this construction?
A. Measure the distance from the intersection of the transversal to point P.
B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis.
C. Draw another transversal.
D. Connect the arc intersections using a straight edge.
Thanks!
Answer:
B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis
Step-by-step explanation:
Creating a parallel line through a point involves copying the angle a transversal makes with the given line. The copied angle has the given point as its vertex, and the transversal as one side.
Copying an angle uses the steps of ...
draw an arc through the sides of the given angledraw an arc with the same radius centered at the new vertex...The step this question is referring to is the first bullet above. The given angle is the angle between the transversal and the y-axis.
Complete a two-column proof for each problem.
In a difficult position right now all help is welcomed tyty
Answer:
D is the midpoint of AC Given
∠BDC ≅ ∠BDA Given
BD ≅ BD Reflexive Property
AD ≅ DC Definition of line segment bisector
ΔADB ≅ ΔCBD CPCTC (Congruent Parts of Congruent Triangles are Congruent)
~
Write the equation of a line that goes through point (0, −8) and has a slope of 0.
A.) x = -8
B.) x = 0
C.) y = - 8
D.) y = 0
Answer:
C.) y = - 8
Step-by-step explanation:
If the line has a slope of 0, it is a horizontal line. That means y= a value
Since we have the point (0,-8)
y = -8
Final answer:
The equation of a line that goes through point (0, -8) with a slope of 0 is y = -8.(Option c)
Explanation:
We need to find the equation of a line that goes through the point (0, -8) and has a slope of 0. The general equation for a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since the slope (m) is 0, the line is horizontal.
A horizontal line has an equation of the form y = b, where b is the y-coordinate of every point on the line. As the line goes through (0, -8), we can see that the y-coordinate is -8 for all points on this line. Therefore, the equation of this line is C) y = -8.
Ben drew 3 two-dimensional shapes that had II angles in all. Draw shapes Ben could have drawn.
The figure is attached to show the shapes Ben could have drawn
He could have drawn 2 four angled polygon , 1 triangle and 1 pentagon , 2 triangles .
What are Two Dimensional Shapes ?The shapes which lie on two coordinate axis and has length ,and breadth are called Two dimensional shapes.
A polygon is included in two dimensional shapes.
It is given in the question that
Ben drew 3 two-dimensional shapes that had 11 angles in all.
11 angles mean
2 four angled polygon , 1 triangle2 quadrilaterals ( rectangle , square , rhombus etc.) and a triangle
1 pentagon , 2 trianglesA figure is attached for the above stated answer .
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Need help with a math question
Answer:
[tex]z =3\sqrt{13}[/tex]
Step-by-step explanation:
In the figure you can identify up to 3 straight triangles.
To solve the problem, write the Pythagorean theorem for each triangle.
Triangle 1
[tex]13^2 = z^2 + x^2[/tex]
Triangle 2
[tex]z^2 = y^2 + 9^2[/tex]
Triangle 3
[tex]x^2 = y^2 + 4^2[/tex]
Now substitute equation 2 and equation 3 in equation 1 and solve for y.
[tex]13^2 = y^2 + 9^2 + y^2 + 4^2[/tex]
[tex]13^2 = 2y^2 + 9^2 + 4^2[/tex]
[tex]169 = 2y^2 + 81 + 16[/tex]
[tex]2y^2 =72[/tex]
[tex]y^2 =36[/tex]
[tex]y =6[/tex]
substitute the value of y in the second equation and solve for z
[tex]z^2 = 6^2 + 9^2[/tex]
[tex]z^2 = 36 + 81[/tex]
[tex]z^2 = 117[/tex]
[tex]z = \sqrt{117}[/tex]
[tex]z =3\sqrt{13}[/tex]
In △ M N O , points R and T are the midpoints of their respective sides. MT and OR intersect at point C.
1. 14 units
2. None of the listed answers are correct
3. 15 units
4. 16.5 units
5. 12.5 units
Answer:
3. 15 units
Step-by-step explanation:
When medians intersect, the point of intersection divides the median into parts in the ratio 2:1. That is ...
OC : CR = 2 : 1 = 4 units : 2 units . . . . . . OR = (4+2) units = 6 units
MC : CT = 2 : 1 = 6 units : 3 units . . . . . . MT = (6+3) units = 9 units
The sum of lengths OR + MT is ...
6 units + 9 units = 15 units
The given question is incomplete. Without information about dimensions or additional information of the triangle or the lines, we cannot solve for lengths.
Explanation:Unfortunately, the question is incomplete, so it is impossible to answer it accurately. In the given situation, we have a triangle △MNO and points R and T are the midpoints of their respective sides. The lines MT and OR intersect at a point C. However, without explicit dimensions or additional information about the triangle or the lines, we cannot determine the length of any line segment. In geometry problems like this, it's crucial to have a complete set of given information before proceeding with the solution.
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Divide the binomial by the monomial to find the quotient.
48x^4y-72x^6y^2
-------------------------
-12x^2y
Answer:
-4x² +6x⁴y
Step-by-step explanation:
Deal with it term by term, factor by factor.
[tex]\dfrac{48x^4y-72x^6y^2}{-12x^2y}=\dfrac{48x^4y}{-12x^2y}+\dfrac{-72x^6y^2}{-12x^2y}\\\\=\dfrac{48}{-12}\cdot\dfrac{x^4}{x^2}\cdot\dfrac{y}{y}+\dfrac{-72}{-12}\cdot\dfrac{x^6}{x^2}\cdot\dfrac{y^2}{y}=-4x^2+6x^4y[/tex]
Final answer:
To divide the binomial by the monomial, divide each term's coefficients and subtract their exponents, resulting in the quotient [tex]-4x^2 + 6x^4y[/tex].
Explanation:
To divide the given binomial by the monomial, we divide each term in the numerator by the term in the denominator. In this case, we need to divide both terms of the binomial [tex]48x^4y - 72x^6y^2[/tex] by the monomial[tex]-12x^2y[/tex]. This involves dividing the coefficients (the numbers in front of the variables) and subtracting the exponents for like bases according to the rules of division of exponentials.
Starting with the first term:
[tex]\frac{48x^4y}{ -12x^2y} = -4x^{(4-2)}y^{(1-1)} = -4x^2y^0 = -4x^2[/tex]
Now the second term:
[tex]\frac{-72x^6y^2}{-12x^2y } = 6x^{(6-2)}y^{(2-1)} = 6x^4y[/tex]
The final quotient of dividing the binomial by the monomial is:
[tex]-4x^2 + 6x^4y[/tex]
Anzelm wants to burn 540 calories while jogging. Jogging burns about 12 calories per minute. When Anzelm goes jogging, he usually plans to stop and rest for about 5 minutes. Complete the equation below to find the total number of minutes (including rest) that Anzelm should plan to be out jogging. Use m to represent the total minutes ___( __–__) = ___
Answer:
12(m -5) = 540
Step-by-step explanation:
The left side of the equation is in the form of a product. A suitable product is ...
(calories/minute) × (minutes jogging) = (calories burned)
If m represent Anzelm's total minutes, then m-5 will represent the number of minutes actually jogging. This is what goes inside parentheses, so we have ...
(12 calories per minute) × ((m -5) minutes) = 540 calories
Leaving off the units, which we know are consistent, we have ...
12 (m -5) = 540
Answer:
12(m-5) = 540
Step-by-step explanation:
∵ The total calories have to burn = 540,
Also, here m represents the total time spent by Anzelm,
If he/she spent 5 minutes in rest,
Then the time he/she spent in jogging = (m - 5) minutes,
If the number of calories burnt in one minute = 12,
So, the number of calories burnt in (m-5) minutes = 12(m-5),
Therefore, for burning the whole calories,
Calories burnt by him/her = total calories
⇒ 12(m-5) = 540
Which is the required equation.
The cost of a long-distance phone call is $0.45 for the first minute and $0.36 for each additional minute. If the
total charge for a long-distance call is $6.93, how many minutes was the call?
The call was for
minutes.
Answer:
19 minutes
Step-by-step explanation:
cost = .45+.36m
If we take 6.93 minus .45 for the minute, we get 6.48. We take 6.48 and divide it by .36 for each additional minute, which is 18. We take the 18 and add one more minute to it since .45 was covered for the first minute.
The long-distance phone call that cost $6.93 was 19 minutes long. This was calculated by first deducting the cost of the first minute from the total cost, then dividing the remaining cost by the cost of each additional minute, and finally adding back the first minute.
Explanation:The subject of this question is mathematics, and it involves understanding the cost structure of a long-distance phone call. So here's how we solve the problem:
Subtract the first minute's cost from the total cost. So, $6.93 - $0.45 = $6.48.Then divide the remaining total by the cost of each additional minute. So, $6.48 / $0.36 = 18 additional minutes.Last, add back in the first minute that we subtracted at the start. So, 18 minutes + 1 minute = 19 minutes total.Therefore, the duration of the long-distance phone call that cost $6.93 was 19 minutes.
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Please explain how you got this answer.
-Aparri
Answer:
She got a 87 on her chemistry test
Step-by-step explanation:
(72 + 85 + 92 + x)/4 = 84
249 + x = 336
x = 87
Solve: e^2x+5= 4 (for those who want the answer to this!)
Answer:
Step-by-step explanation:
With the way it is written, there are no values of x that make the equation true.
A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude of 41,000 feet. Model the most fuel-efficient altitudes using a compound inequality.
x ≥ 29,000 and x ≤ 41,000
x ≤ 29,000 and x ≥ 41,000
x ≥ 41,000 and x ≥ 29,000
x ≤ 41,000 and x ≤ 29,000
Answer:
[tex]x\geq 29,000[/tex] and [tex]x\leq 41,000[/tex]
Step-by-step explanation:
Let
x -----> the altitude of a commercial aircraft
we know that
The expression " A minimum altitude of 29,000 feet" is equal to
[tex]x\geq 29,000[/tex]
All real numbers greater than or equal to 29,000 ft
The expression " A maximum altitude of 41,000 feet" is equal to
[tex]x\leq 41,000[/tex]
All real numbers less than or equal to 41,000 ft
therefore
The compound inequality is equal to
[tex]x\geq 29,000[/tex] and [tex]x\leq 41,000[/tex]
All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft
The solution is the interval ------> [29,000,41,000]
option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using compound inequality.
We need to identify the correct compound inequality describing the altitude at which the aircraft operates most efficiently. The best fuel efficiency altitudes range from 29,000 ft to 41,000 ft, meaning the altitude must be at least 29,000 ft and at most 41,000 ft.
So, to represent that the altitude must be at least 29000 ft we use the mathematical expression:
[tex]x\geq 29,000[/tex]
To represent that the altitude must be 41000 ft at most we use the mathematical expression:
[tex]x\leq 41,000[/tex]
These two expression can be represented as a compound inequality as follows:
[tex]x\geq 29,000\[/tex] and [tex]x\leq 41,000[/tex]
Therefore, option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using a compound inequality.
Please answer this question correctly for 30 points and brainliest!!
Answer:
22 quarters
Step-by-step explanation:
Let q represent the number of quarters in the bank. Then 60-q is the number of nickels, and the total value of the coins is ...
0.25q + 0.05(60 -q) = 7.40
0.20q + 3.00 = 7.40 . . . . . . . . simplify
0.20q = 4.40 . . . . . . . . . . . . . . subtract 3.00
q = 4.40/0.20 = 22 . . . . . . . . . divide by the coefficient of q
There are 22 quarters in the piggy bank.
_____
Check
The other 60-22 = 38 coins are nickels, so the total value is ...
0.25×22 + 0.05×38 = 5.50 + 1.90 = 7.40 . . . . . . the required amount
Step-by-step answer:
Here's a different way to solve the problem, mentally.
Mixture of 60 coins composed of nickels (5 cents) and quarters (25 cents).
Total value = 7.40.
IF all coins were quarters, value would be 60*0.25 = $15
That makes too many quarters.
To conform to the value of $7.40, we need to reduce the mix by $15-7.40 = 7.60.
Each exchange of quarters and nickels reduces the value by $0.25-0.05=0.20.
It takes 7.60 / 0.20 = 38 exchanges.
So there are 38 nickels and 22 quarters.
If an object is dropped from a height of 144 feet, the function h(t) = -16t2 + 144 gives the height of the object after t seconds. When will the object hit the ground?
Answer:
3 seconds is correct.
Step-by-step explanation:
The object hit the ground at 3 seconds
What are equations?An equation is a mathematical statement which equate two algebraic expressions. An equation has an equal to (=) sign in between the expression.
How to find when will the object hit the ground?
According to the problem,
An object is dropped from a height of 144 feetThe given function is h(t) = -16t2 + 144.
When the object reaches the ground h(t) becomes 0
So, the equation will be 0 = -16t2 + 144.
Solving the equation we get t = 3 seconds
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What should be the next letter in the following series? A z e b i y o _ ?_
Answer: c
Step-by-step explanation:
Notice the pattern (vowel, consonant, vowel, consonant):
A: first vowel z: last consonant
e: second vowel b: first consonant
i: third vowel y: second to the last consonant
o: fourth vowel c: second consonant
Someone please help me with this...
Answer:
The total number of points you score is dependent variable Because it change when x is change.
The number of question you answer correctly is independent variable Because it can change itself when you got more correct answers.
what is the measure of DEF
Answer:
The measure of arc DEF is 204° ⇒ answer C
Step-by-step explanation:
* Lets talk about some facts in the circle
- If the vertex of an angle on the circle and the two sides of the
angle are chords in the circle, then this angle is called
an inscribed angle
- Each inscribed angle subtended by the opposite arc, the arc name
is the starting point and the ending point of the angle
- The measure of any circle is 360°
# Ex: ∠CAB is inscribed angle subtended by arc CB
- There is a relation between the inscribed angle and its
subtended arc, the measure of the inscribed angle equals half
the measure of its subtended arc
* Now lets solve the problem
- ∠DEF is an inscribed angle subtended by arc DF
∴ m∠DEF = (1/2) measure of arc DF
∵ The measure of ∠DEF = 78°
∴ 78° = (1/2) measure of arc DF ⇒ multiply both sides by 2
∴ The measure of arc DF = 78° × 2 = 156°
∵ The measure of arc DF + The measure of arc DEF = The measure of
the circle
∵ The measure of the circle = 360°
∵ The measure of the arc DF = 156°
∴ 156° + measure of arc DEF = 360° ⇒ subtract 156 from both sides
∴ The measure of arc DEF = 360° - 156° = 204°
* The measure of arc DEF is 204°
Answer: OPTION C.
Step-by-step explanation:
By definition:
[tex]Inscribed\ Angle = \frac{1}{2} Intercepted\ Arc[/tex]
Then we can calculate the measure of DF. This is:
[tex]78\°=\frac{1}{2}DF\\\\DF=(2)(78\°)\\\\DF=156\°[/tex]
We know that there are 360 degrees in a circle, therefore, in order to find the measure of DEF, we need to make the following subtraction:
[tex]DE[/tex][tex]F[/tex][tex]=360\°-156\°[/tex]
[tex]DE[/tex][tex]F[/tex][tex]=204\°[/tex]
You can observe that this matches with the option C.
The product shown is a difference of squares. What is the missing constant term in the second factor?
(–5x – 3)(–5x +?
Answer:
[tex]\boxed{3)}[/tex]
Step-by-step explanation:
A difference of squares has the form (a - b)(a + b)
Your expression is (-5x - 3)(-5x + ?
Let's compare this with your expression.
[tex]\begin{array}{cclccl}(a & - & b) & (a & + & b)\\\downarrow & & \downarrow & \downarrow & & \downarrow \\(-5x & - & 3) & (-5x & + & \mathbf{3)} \\\end{array}\\\\\text{The missing term is }\boxed{\mathbf{3)}}[/tex]
Combine Radicals/Fractional Exponents
Image Below, Will Give Brainliest~
What is the product of a b and c
[tex]\mathsf{Given :\;\;\dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{64x^3y^3}}}[/tex]
[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{4^3x^3y^3}}}[/tex]
[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{(4xy)^3}}}[/tex]
[tex]\bigstar\;\;\textsf{We know that : \boxed{\mathsf{\sqrt[n]{a} = a^{\dfrac{1}{n}}}}}[/tex]
[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{(4xy)^{\dfrac{3}{3}}}}}[/tex]
[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{4xy}}}[/tex]
[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) \left(\dfrac{x^{\dfrac{-3}{2}}}{{x}}\right)\left(\dfrac{y^{-2}}{y}\right)}[/tex]
[tex]\bigstar\;\;\textsf{We know that : \boxed{\dfrac{a^m}{a^n} = a^{m - n}}}}[/tex]
[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3}{2} - 1\right)}}y^{(-2 - 1)}}[/tex]
[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3 - 2}{2}\right)}}y^{-3}}[/tex]
[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-5}{2}\right)}}y^{-3}}[/tex]
[tex]\textsf{Comparing the above with $\mathbf{ax^by^c}$, We can notice that :}[/tex]
[tex]\bigstar\;\;\mathsf{a = \dfrac{5}{4}}[/tex]
[tex]\bigstar\;\;\mathsf{b = \dfrac{-5}{2}}[/tex]
[tex]\bigstar\;\;\mathsf{c = -3}[/tex]
[tex]\implies \mathsf{Product\;of\;a,\;b\;and\;c = \left(\dfrac{5}{4}\times \dfrac{-5}{2} \times -3\right)}[/tex]
[tex]\implies \mathsf{Product\;of\;a,\;b\;and\;c = \dfrac{75}{8}}[/tex]
A survey found that 78% of students do their homework before 10:00 P.M. Predict how many students out of 975 do their homework before 10:00 P.M.
a.
about 761
b.
about 78
c.
about 800
d.
about 13
Which description best describes the solution to the following system of equations?
y = –x + 4
y = 3x + 3 (4 points)
Line y = –x + 4 intersects the line y = 3x + 3.
Lines y = –x + 4 and y = 3x + 3 intersect the x-axis.
Lines y = –x + 4 and y = 3x + 3 intersect the y-axis.
Line y = –x + 4 intersects the origin.
Answer:
Line y = –x + 4 intersects the line y = 3x + 3
Step-by-step explanation:
The solution is described as the point of intersection of the two lines. The description above is the only one that says anything about that.
___
Comments on other answer choices
Any line with finite non-zero slope intersects both the x- and y-axes. That fact does not describe the solution to a system of equations.
Any linear equation with an added (non-zero) constant will not intersect the origin. These two equations have +4 and +3 added, so neither line intersects the origin.
NEED HELP FAST PULEASEE
Please help fast asap
What is the probability of drawing three black cards, one at a time with replacement, from a standard deck of 52 cards?
A.'3/52
Its not b
C.1/8
d.75/676
Need help fasttt
GIve p(6,6) and q=(-5,-3) find the magnitude of 2p+3q
A.2 sqr3
B. 3 sqr2
its not C
D.14
According to NFL statistics, the Cincinnati Bengals will lose 13 out of 16 games, regardless of opponent. What are the odds of Cincinnati losing a game?
A.3;13
its not b
C.13;3
D16;13
Determine which trigonometric function to use to solve for the hypotenuse. Then,
solve for the length of the hypotneuse.
b=9
A=55.8
A.cosin, .062
B.sin,10.8
C.sin,16.0
its not D
Answer:
6
Step-by-step explanation:
If tuvw is an an isoaceles trapezoid with tu parallel to wv, name a pair of similar traingles. Explain
Answer:
TUW ~ UTV, TWV ~ UVW
Step-by-step explanation:
An isosceles trapezoid is symmetrical about the perpendicular bisector of its bases. A triangle formed by deleting a vertex on one side of that line of symmetry will be similar to the corresponding triangle formed by deleting the symmetrically opposite vertex on the other side. The two pairs listed above are the possibilities.
Rebecca buys a table that was priced $650. There is a 8% sales tax in her state. Fortunately, it was 25% off! So she only
paid $:
Answer:
$526.50
amount×discount=?
650×.25= 162.5
total-discount=?
650-162.5= 487.5
new amount×sales tax=?
487.5×.08= 39
new amount+tax=total
487.5+39= 526.5
Total=$526.50
A salesperson obtained a systematic sample of size 20 from a list of 500 clients. to do so, he randomly selected a number from 1 to 25, obtaining the number 18. he included in the sample the 18th client on the list and every 25th client thereafter. list the numbers that correspond to the 20 clients selected
The salesperson selected clients 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493 through systematic sampling from a list of 500 clients.
Explanation:This is a question related to systematic sampling, which is a statistical method where elements are selected from an ordered sampling frame. In this case, the 20 clients were selected beginning with the 18th client and then continuing every 25th client.
To find the specific client numbers selected, we would follow the pattern by adding 25 to the prior number starting from 18. Keep adding until you reach 20 numbers. Let me list them for you:
18 (Starting client) 43 (18 + 25) 68 (43 + 25) 93 (68 + 25) 118 (93 + 25) 143 (118 + 25) 168 (143 + 25) 193 (168 + 25) 218 (193 + 25) 243 (218 + 25) 268 (243 + 25) 293 (268 + 25) 318 (293 + 25) 343 (318 + 25) 368 (343 + 25) 393 (368 + 25) 418 (393 + 25) 443 (418 + 25) 468 (443 + 25) 493 (468 + 25) Learn more about systematic sampling here:
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The salesperson used systematic sampling to select clients from the list. Starting with the 18th client, the salesperson then selected every 25th client thereafter. The client numbers selected were 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493.
Explanation:In this scenario, the salesperson obtained a systematic sample by first selecting the 18th client and then every 25th client thereafter from a list of 500 clients. This method of sampling is called systematic sampling. It's a type of sampling where we select items from an ordered population using a fixed, periodic interval after a random start. So, the numbers of the clients selected would be: 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493.
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If the given sequence is a geometric sequence, find the common ratio.
3/3, 3/12, 3/48, 3/192, 3/768
a. 4
b. 1/30
c. 30
d. 1/4
Answer:
d. 1/4
Step-by-step explanation:
The ratio of adjacent terms is the common ratio:
(3/12)/(3/3) = 3/12 = 1/4
What is the opposite of squaring a number
The opposite of squaring a number is taking the square root. They are inverse operations.
The opposite of squaring a number is taking the square root of the number. They are inverse operations.
What is a perfect square?A perfect square is a number system that can be expressed as the
square of a given number from the same system.
Perfect squares are those integers whose square root is an integer.
Let x-a be the closest perfect square less than x,
Let x-a be the closest perfect square less than x, and let x+b be the closest perfect square more than x, then we get x-a < x < x+b (no perfect square in between x-a and x+b, except possibly x itself).
Then, we get:
[tex]\sqrt{x-a} < \sqrt{x} < \sqrt{x+b}[/tex]
Thus, these are the closest integers, less than and more than the value of[tex]\sqrt{x}[/tex]. (assuming x is a non-negative value).
The opposite of squaring a number is taking the square root of the number. They are inverse operations.
Learn more about square root here:
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Mr de guzman bought 7 1/2 of meat.He used 2 3/4 for afritada,3 1/8 kg for menudo and the rest for pochero.How many kilograms of meat did he used for pochero?
Answer:
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Step-by-step explanation:
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HELP awarding 60 points and brainliest answer!!!
Answer:
A
Step-by-step explanation:
Choice A is right because there is no dot above the two.
Choice B is not right because there is 2 dots above 1 and not 3.
Choice C is not right because the data doesn't go passed 5 to get to 8
Choice D is not right because it was 5 games because there is 5 dots above 3
The answer would be A. the team never scored exactly 2 goals in a single game
If you look at the number two on the dot plot you can see that there are NO dots above it. This means that the team never scored exactly 2 goals.
It can't be B. because they scored exactly 1 goal for 2 games NOT 3
It can't be C. because no where on the graph is the number 8. They never scored 8 goals. Five is actually the highest number of goals they ever scored.
It can't be D. because they scored 3 goals in a game for 5 games not for 4 games
Hope this helped!
~Just a girl in love with Shawn Mendes