Answer: v² = u² + 2as
2as = v² - u²
a = (v² - u²) / 2s
a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m)
a = (400 m²/s² - 36 m²/s²) / (100 m)
a = (364 m²/s²) / (100 m)
a = 3.64 m/s²
Explanation:
Answer:1m/s^-2
Explanation:V=u+at where;
V(final velocity)=50m/s
U(Initial velocity)=20m/s
a(acceleration)=?
t(time)=30seconds
Therefore; 50=20+a(30)
Collect like terms
50-20=30a
30=30a
Divide both side by 30
a=1ms^-2
If an atom has 13 protons and is currently electrically neutral, what must happen to give the same atom a positive charge of +2e?
The atom must lose 2 electrons
Explanation:
An atom consists of three types of particles:
- Protons, in the nucleus, with positive electric charge [tex]+e[/tex]
- Neutrons, in the nucleus, with no electric charge
- Electrons, orbiting around the nucleus, with negative electric charge [tex]-e[/tex]
As a result, the net electric charge of an atom is given by the number of protons minus the number of electrons:
Q = #p - #e
For a neutral atom, the number of protons and electrons is the same, so the net charge is zero.
In order for an atom to have a positive charge of +2, it means that there must be 2 protons more than the number of electrons. Since atoms exchange electrons (and not protons), this means that the atom must have "lost" 2 electrons.
In this problem, we have an atom with 13 protons: this means that initially it also has 13 electrons. However, later the atom lost 2 electrons, and as a result, the final charge is +2e.
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Four parallel-plate capacitors are constructed using square plates, and each has a dielectric inserted between the plates.?
Rank the capacitance of each capacitor in order from highest to lowest.
A = side length (L/2) ; distance between plates (d) ; dielectric current (k)
B = side length (L) ; distance between plates (d/2) ; dielectric current (4k)
C = side length (2L) ; distance between plates (d) ; dielectric current (2k)
D = side length (L) ; distance between plates (2d) ; dielectric current (2k)
Final answer:
The capacitance of the parallel-plate capacitors can be ranked from highest to lowest as follows: C, A, B, D.
Explanation:
The capacitance of a parallel-plate capacitor depends on the area of the plates (A) and the distance between them (d). The larger the area of the plates, the greater the charge they can store, so the capacitance is greater for a larger A. Similarly, the closer the plates are together, the stronger the attraction between the charges, so the capacitance is greater for a smaller d.
Based on this information, we can rank the capacitance of each capacitor:
Capacitor C: It has the largest side length and the same distance between plates as capacitor A, so it will have the highest capacitance.Capacitor A: It has a smaller side length and the same distance between plates as capacitor B, so it will have a lower capacitance than C, but higher than B and D.Capacitor B: It has a larger side length and half the distance between plates compared to capacitor A, so it will have a lower capacitance than A and C, but higher than D.Capacitor D: It has the smallest side length and double the distance between plates compared to capacitor A, so it will have the lowest capacitance.Humans require organ systems to carry out life processes. Single-celled organisms do not have organ systems and yet they are able to carry out life processes. This is because
Human organ systems lack the organelles found in single-celled organisms
A human cell is more efficient than the cell of a single-celled organism
It is not necessary for single-celled organisms to maintain homeostasis
Organelles present in single-celled organisms act in a manner similar to organ systems
Answer: is Organelles present in single-celled organisms act in a manner similar to organ systems
Explanation:
Multicellular organisms organ system play a critical role for the smooth functioning of whole body. Millions of cells combined to make an organism. The role of organ system in whole body is to provides oxygen and nutrients to the cells and eliminates the toxic material such as carbon dioxide. Organ systems like, respiratory system, digestion system, and cardiovascular play an important role in the human body to perform various functions for its survival.
Unlike multicellular organisms the unicellular only consists of single cell e.g. prokaryotic organisms and eukaryotic organisms namely, Amoeba, Euglena, salmonella, Fungi etc. Single celled organisms are able to carry out all processes mandatory for the sustenance of life with the help of single cell only e.g. respiration and digestion.They can survive with the help of single cell. Unlike multicellular organisms unicellular do not require multiple number of cell for its survival.
Organelles present in single-celled organisms act very similar to organ systems in multicellular organisms.
Organelles:
They are the small bio-molecular system that carry out the vital processes inside a cell.
For example-
Mitochondria produce energy in the cell.Nucleus is the information center that run the whole cell like a human brain.Lysosomes digest the objects inside the cell, work as digestive system inside the body.Therefore, organelles present in single-celled organisms act very similar to organ systems in multicellular organisms.
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Multicellular organisms
organ system play a critical role for the smooth functioning of whole body. Millions of cells combined to make an organism. The role of organ system in whole body is to provides oxygen and nutrients to the cells and eliminates the toxic material such as carbon dioxide. Organ systems like, respiratory system, digestion system, and cardiovascular play an important role in the human body to perform various functions for its survival.
Unlike multicellular organisms the unicellular only consists of single cell e.g. prokaryotic organisms and eukaryotic organisms namely, Amoeba, Euglena, salmonella, Fungi etc. Single celled organisms are able to carry out all processes mandatory for the sustenance of life with the help of single cell only e.g. respiration and digestion.They can survive with the help of single cell. Unlike multicellular organisms unicellular do not require multiple number of cell for its survival
An electric dipole is formed from two charges, , spaced 1.0 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (x,y) = (0,10) in cm is 360 N/C. a. Calculate the dipole moment and charge q. b. Calculate the electric field strength at the point (x,y) = (10, 0) in cm.
Answer:
q = 3.703*10^-9
dipole moment = 3.703*10^-11
E @ (10,0) = 331.977 N/C
Explanation:
Given:
Coordinates
+ q = (0,-0.5) cm
- q = (0,0.5) cm
E = 360 N/C @ (0,10)
Solution:
[tex]Electric Field Strength @ (0,10) = \frac{k*q}{R^2}\\[/tex]
Note: +q (away from charge) and -q (towards the charge)
[tex]E = k*q*(\frac{1}{R^2_{1}} - \frac{1}{R^2_{2} })\\ 360 = (9*10^9)*q*(\frac{1}{0.095^2} - \frac{1}{0.105^2 })\\\\q =1.99 *10^-9[/tex]
Dipole moment = q.(space between two charges)
= (3.703*10^-9 * 0.01)
= 3.703*10^-11
Electric Field Strength @ (10,0)
[tex]E = 2*k*q*(\frac{1}{R^2})*cos(Q)\\ \\Q = arctan(\frac{10}{0.5}) = 87.138 degrees\\R = \sqrt{10^2 + 0.5^2} = 10.01249 cm\\E = 2* (9*10^9)*(3.703*10^-9)*\frac{cos (87.138)}{0.1001249^2}\\E = 331.977 N/C[/tex]
Answer:
a. dipole moment = 2.003 × 10⁻¹³ Cm, charge = 2.003 × 10⁻¹¹ C b. 8.96 N/C
Explanation:
a. The electric field due to a dipole is given by
E = p/2πεy³ where p = dipole moment and y = distance of dipole to point of electric field = 10 cm = 0.10 m. E = electric field strength at (0,10) = 360 N/C
So, E = p/2πεy³
p = 2πεy³E = 2π × 8.854 × 10⁻¹² × (0.10 m)³ × 360 N/C = 2.003 × 10⁻¹³ Cm
Also, p = qd where q = charge and d = distance of charges apart = 1.0 cm = 0.01 m
q = p/d = 2.003 × 10⁻¹³ Cm/0.01 m = 2.003 × 10⁻¹¹ C
b. The electric field at point (10,0)
E = qx/[πε√(d² + 4x²)]³ which is the electric field at an axis perpendicular to the dipole where x = 10 cm = 0.10 m
E = 2.003 × 10⁻¹¹ C × 0.10/π × 8.854 × 10⁻¹²√(0.01² + 4×(0.1)²)³ = 8.96 N/C.
A client has developed dystrophic calcification as a result of macroscopic deposition of calcium salts. The tissue that would be most affected would be?
Answer:
Tissues that are damaged or injured.
Explanation:
Dystrophic calcification involves the deposition of calcium in soft tissues despite no disturbance in the calcium metabolism, and this is often seen at damaged tissues.
Examples of areas in the body where dystrophic calcification can occur include atherosclerotic plaques and damaged heart valves.
In solar thermal electric generation, the sun’s energy is concentrated by ___ to heat the fluid in a pipe that is used to generate electricity.
Answer:
Mirrors
Explanation:
In Solar thermal power generation system, mirrors are used to collect and focus sunlight onto a fluid pipe to produce high temperature required to generate electricity.
There are two main components: mirrors capture and focus light onto a receiver. The heat transfer fluid is circulated in the receiver. Steam is produced which is converted to mechanical energy in a turbine. It powers a generator and electricity is produced.
In solar thermal electric generation, concave mirrors are used to concentrate sunlight onto a pipe in a system known as a parabolic trough. The heat is transferred via heat exchanger to produce steam, which generates electricity through a steam turbine-generator setup.
In solar thermal electric generation, the sun's energy is concentrated by concave mirrors or reflectors to heat the fluid in a pipe that is used to generate electricity. These mirrors are often part of a system known as a parabolic trough or concentrating collector, which has the approximate shape of a section of a cylinder, specifically one-quarter of a full cylinder. The mirrors focus sunlight onto a blackened pipe containing a special fluid.
Once this fluid is heated, it is then pumped through a heat exchanger where its thermal energy is transferred to water to produce steam. This steam drives a turbine connected to a generator, producing electricity through a conventional steam cycle. This entire process is a part of larger solar thermal power plants, which utilize solar collectors with two components: mirrors to collect and focus sunlight, and a receiver to collect the heat transferred to the fluid.
1.
The collision shown here is ____________.
elastic
inelastic
2.
Any work being done is done against the force of __________.
friction
mass
3.
With an inelastic collision, you have to use the conservation of ____.
matter
momentum
Answer:
2. Friction
3. Momentum
Explanation:
For elastic collision, the total kinetic energy before and after collision are same while for inelastic collision, kinetic energy is converted to other forms apart from kinetic energy for example we get sound energy or rotational energy. Since in this case there's no diagram, we can't make a conclusion. However, in real life, all collisions are inelastic
2
Work is always done against frictional force
3
The law of conservation of momentum is used in an inelastic collision
Answer:
1) Inelastic
2) Friction
3)Momentum
Explanation:
USATestprep
A motorcycle, which has an initial linear speed of 6.3 m/s, decelerates to a speed of 1.9 m/s in 4.6 s. Each wheel has a radius of 0.68 m and is rotating in a counterclockwise (positive) direction.a) the constant angular acceleration (in rad/s2) andb) the angular displacement (in rad) of each wheel?
Answer:
Explanation:
Given
initial velocity of motorcycle [tex]u=6.3\ m/s[/tex]
final velocity [tex]v=1.9\ m/s[/tex]
time taken [tex]t=4.6\ s[/tex]
radius of wheel [tex]r=0.68\ m[/tex]
using v=u+at
where a=acceleration
[tex]1.9=6.3+a\times 4.6[/tex]
[tex]a=-0.956\ m/s^2[/tex]
angular acceleration [tex]\alpha =\frac{a}{r}[/tex]
[tex]\alpha =\frac{-0.956}{0.68}=-1.406\ rad/s^2[/tex]
[tex]Displacement=average\ velocity\times time[/tex]
[tex]Displacement=\frac{u+v}{2}\times t[/tex]
[tex]Displacement=\frac{1.9+6.3}{2}\times 4.6=18.86\ m[/tex]
Angular displacement [tex]\theta =\frac{Linear\ displacement}{radius}[/tex]
Angular displacement [tex]\theta =\frac{18.86}{0.68}=27.73\ rad[/tex]
Answer:
Explanation:
initial velocity, u = 6.3 m/s
final speed, v = 1.9 m/s
time, t = 4.6 s
radius, r = 0.68 m
(a)
initial angular velocity, ωo = u / r = 6.3 / 0.68 = 9.26 rad/s
final angular velocity, ω = v / r = 1.9 / 0.68 = 2.79 rad/s
Let α be the angular acceleration
Use first equation of motion
ω = ωo + αt
2.79 = 9.26 + α x 4.6
α = - 1.41 rad/s²
(b) Let Ф be the angular displacement
Use third equation of motion
ω² = ωo² + 2 αФ
2.79² = 9.26² - 2 x 1.41 x Ф
Ф = 27.6 rad
Two tiny beads are 25 cm apart with no other charged objects or fields present. Bead A has a net charge of magnitude 10 nC and bead B has a net charge of magnitude 1 nC. Which one of the following statements is true about the magnitudes of the electric forces on these beads?A. The force on A is 100 times the force on B.B. The force on B is 10 times the force on A.C. The force on B is 100 times the force on A.D. The force on A is 10 times the force on B.E. The force on A is exactly equal to the force on B.
Answer:
E. The force on A is exactly equal to the force on B.
Explanation:
The force between two charges is given by
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
where
[tex]q_1[/tex] = Charge on particle 1
[tex]q_2[/tex] = Charge on particle 2
r = Distance between the charges
k = Coulomb constant = [tex]8.99\times 10^{9}\ Nm^2/C^2[/tex]
[tex]F=\dfrac{8.99\times 10^9\times 10\times 10^{-9}\times 1\times 10^{-9}}{(25\times 10^{-2})^2}\\\Rightarrow F=0.0000014384\ N[/tex]
This force will be exerted on both the charges equally.
So, The force on A is exactly equal to the force on B
A dragster and driver together have mass891.3 kg.The dragster, starting from rest,attains a speed of 25.2 m/s in 0.62 s.Find the average acceleration of the drag-ster during this time interval.
Answer:
40.645 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s². Mathematically,
a = (v-u)/t................................. Equation 1
Where a = acceleration, v = velocity, u = initial velocity, t = time.
Given: v = 25.2 m/s, u = 0 m/s, t = 0.62 s.
Substituting into equation 1
a = (25.2-0)/0.62
a = 25.2/0.62
a = 40.645 m/s²
Hence the average acceleration of the drag-star = 40.645 m/s²
An AM radio station broadcasts at a frequency of 600 kHz. If these waves have a speed of 3 x 108 m/s, then what is their wavelength in meters?
Answer: 500metres
Explanation:
Wavelength is defined as the distance between two successive crest and troughs. The relationship between the wavelength (¶), frequency (f) and velocity of the wave(v) is given by v= f¶
Therefore wavelength ¶ = v/f
Given the velocity = 3×10^8m/s
frequency = 600kHz = 600,000Hz
Wavelength =3×10^8/600,000
Wavelength = 500meters
Their wavelength in meters is 500meters
Snowflakes begin to form when water in the atmosphere freezes it causes the water molecules to bond into a hexagonal shape. Is this sentence correct?
Answer:
Yes! This sentence is correct.
Explanation:
So the complete question along with options is:
Q. Snowflakes begin to form when water in the atmosphere freezes it causes the water molecules to bond into a hexagonal shape.
a) no change
b) freezes, causing
c) freezes, it causes
d) freezes, this causes.
The coorect option is c.
Which threats are characterized by possibly long periods of preparation (years is not uncommon), tremendous financial backing, a large and organized group of attackers, and attempts to subvert insiders or to plant individuals inside a potential target in advance of a planned attack?
Answer:
Highly structured or planned threat
Explanation:
This type of threat is an highly structured threat that is been planned using every available tools and machineries. The attack of this type consist of three phases, the preparation phase; where all the information and resources needed is been planned and source for. The execution phase; the attackers plane how to carry out the action, the techniques and technology needed for the success of the operation is carried out and tested. The post execution phase; the attackers planned there escape from any trouble that may arise and how not to leave any spot that will make them to be identified.
This type of threat requires to put the security outfit or the entire agency on red alert to ensure effective engagement before the attackers execute their actions.
A 66-kg diver jumps off a 9.7-m tower. (a) Find the diver's velocity when he hits the water. (b) The diver comes to a stop 2.0 m below the surface. Find the net force exerted on the diver while in the water.
Answer:
(a) 13.795 m/s.
(b) -3140.28 N.
Explanation:
(a) Using newton's equation of motion,
v² = u² + 2gs.......................... Equation 1
Where v = final velocity, u = initial velocity, s = height of the tower, g = acceleration due to gravity.
Given: s = 9.7 m, u = 0 m/s ( jump from a height), g = 9.81 m/s².
Substitute into equation 1
v² = 0² + 2×9.81×9.7
v² = 190.314
v = √(190.314)
v = 13.795 m/s.
Hence the velocity of the driver when he hits the water = 13.795 m/s.
(b)
F = ma.................... Equation 2
Where F = force exerted on the diver, m = mass of the diver, a = acceleration of the diver below the water surface.
Also using
v² = u² + 2as ............ Equation 3
Note: At the point when the diver enters the water, u = 13.795 m/s, and at the point when the diver comes to a complete stop, v = 0 m/s
Given: s = 2.0 m, u = 13.795 m/s, v = 0 m/s
Substitute into equation 3
0² = 13.795²+2(2a)
0 = 190.30203 + 4a
-4a = 190.30203
a = 190.30203/-4
a = -47.58 m/s²
Also given: m = 66 kg,
Substitute into equation 3
F = (-47.58)(66)
F = -3140.28
Note: The Force is negative because it act against the motion of the diver.
Hence the net force exerted on the diver while in the water = -3140.28 N.
Suppose that volumes of four stars in the Milky Way are 2.7 x 1018 km3, 6.9 x 1012 km3, 2.2 x 1012 km3, and 4.9 x 1021 km3. What is the order of the stars from least to greatest volume?
Answer:
The order is Star 3 < Star 2 < Star 1 < Star 4
Explanation:
Lets name the stars with their written order.
Star 1: 2.7 x 10^18 km3
Star 2: 6.9 x 10^12 km3
Star 3: 2.2 x 10^12 km3
Star 4: 4.9 x 10^21 km3
Star with lowest power of 10 has the least volume. Therefore, star 2 and star 3 would be the stars with least volume. Star 2's coefficient is better than Star 3. Thus, the order will be Star 3 < Star 2 < Star 1 < Star 4.
You are in a spaceship moving in a straight line at constant speed. You cannot see out of the ship. Assuming perfectly uniform motion, what can you do to prove you are moving?
Answer:
There is no experiment to prove that you are in motion
Explanation:
A frame of reference which has constant velocity is known as an inertial frame of reference. Motion is relative. One can detect one's motion only when one observes change in position with respect to a fixed body.
Thus, if you are in a spaceship moving at a constant speed in a straight line and unable to look outside, you would not be able to prove that you are moving. Everything within the spaceship would have same speed. If you will throw any object within the spaceship, then the parameters measured by you would also not show that the spaceship is in motion.
On the scale of the cosmic calendar, in which the history of the universe is compressed to 1 year, how long has human civilization (i.e., since ancient Egypt) existed?
A. About half the year
B. About a month about a month about a month
C. A few hours
D. A few seconds
E. Less than a millionth of a second
Answer:
D. A few seconds
Explanation:
Cosmic Calendar is a way of visualizing the history/timeline of the whole universe in just one year. It starts with Big Bang happening on January 1st midnight. The current moment is taken on the December 31st just before the midnight. Every second on this calendar accounts for around 435 years.
The earliest remains of life are thought to have surfaced on September 14. The primitive humans arrived at 22:24 on December 31st. The ancient Egyptian civilization arrived only at 23:59:48 on December 31st. So seen at a cosmic scale the human civilization is just 12 seconds old.
The engine of a 1540-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road. Is your answer realistic?
Answer:
7.92 s
Explanation:
Power: This can be defined as the rate at which energy is used. The S.I unit of
Watt (W).
Mathematically power can be represented as,
P = E/t
Pt = E............................. Equation 1
Where P = power of the engine, t = time, E = Energy.
But,
E = 1/2m(Δv)²................. Equation 2
Where m = mass of the automobile, Δv = change in velocity of the car = final velocity - initial velocity.
Substitute the value of E in equation 2 into equation 1
Pt = 1/2m(Δv)²................................. Equation 3
making t the subject of the equation,
t = 1/2m(Δv)²/P ........................ Equation 4
Given: m = 1540 kg, P = 75 kW = 75000 W, Δv = 100-0 = 100 km/h (initial velocity of the car = 0 km/h)
100(1000/3600) m/s = 27.78 m/s
Substitute into equation 4
t = 1/2(1540)(27.78)²/75000
t = 594230.87/75000
t = 7.92 second.
Thus The time required to accelerate the car = 7.92 seconds.
It is not realistic period the time period is too short.
The car takes approximately 7.8 seconds to accelerate from rest to a speed of 100 km/h, given the power rating and mass that was provided in the question.
Explanation:The process to solve this physics problem involves steps in calculating the work done on the car and then the time required for this work at the given power. To begin with, we can translate the speed of 100 km/h to m/s, which would be 27.8 m/s. Afterward, using the kinetic energy formula (K.E = 1/2 * m * v²), the work done on the car to achieve this speed can be calculated, which is 585840 Joules.
The next step is to compute the time. We know that Power = Work Done / Time, where power has been provided (75 kW = 75000 Watts) and we just computed the work done, so we can rearrange this equation to solve for time. This gives a resulting time of approximately 7.8 seconds. This may seem a short amount of time, but it's plausible for a high-powered sports car to reach 100 km/h in around this time frame.
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You are not harmed by contact with a charged metal ball, even though its voltage may be very high. Is the reason similar to why you are not harmed by the hotter- than-1000°C sparks from a fireworks sparkler?
Final answer:
You are not harmed by a charged metal ball or by fireworks sparks because the actual exposure (amount of charge and duration for the ball, and size and duration for the sparks) is insufficient to cause injury.
Explanation:
The reason you are not harmed by contact with a charged metal ball, even if its voltage may be very high, is similar to why you are not harmed by the hotter-than-1000°C sparks from a fireworks sparkler. In both cases, it is the amount of charge and the duration of the contact that determine the danger of the electric shock, not just the voltage alone. For the metal ball, even though the voltage is very high, the resulting current is usually very low because the charge moves to the outer surface and is quickly neutralized by surrounding materials. Consequently, the exposure to the charge is so brief that it doesn't cause harm. Similarly, with the sparks from a sparkler, they may be extremely hot, but they are small and lose their heat quickly upon contact with the skin, so they don't transfer enough energy to cause a burn.
How high will a 1.30-kg rock go from the point of release if thrown straight up by someone who does 80.0 J of work on it? Neglect air resistance.
Explanation:
The work done on the stone is kinetic energy.
Kinetic energy = 80 J
We have
Kinetic energy = 0.5 x Mass x Velocity²
Mass = 1.30 kg
80 = 0.5 x 1.30 x Velocity²
Velocity = 11.09 m/s
We have equation of motion v² = u² + 2as
Initial velocity, u = 11.09 m/s
Acceleration, a = -9.81 m/s²
Final velocity, v = 0 m/s
Substituting
v² = u² + 2as
0² = 11.09² + 2 x -9.81 x s
s = 6.27 m
Height it will go is 6.27 m
To find the height a 1.30-kg rock will reach when thrown vertically upwards after 80.0 J of work is done on it, convert the work into potential energy and use the formula PE = mgh. The rock will reach a height of about 6.14 meters.
Work-energy principle: The work done on an object when thrown vertically upwards is stored as potential energy at the highest point of the rock's trajectory. In this case, with 80.0 J of work done on a 1.30-kg rock, the rock will reach a height determined by the conversion from work to potential energy.
Calculating the height: By converting the work done into potential energy and using the formula PE = mgh, where PE is the potential energy, m is the mass, g is the acceleration due to gravity (9.81 m/s^2), and h is the height, you can calculate the height the rock will reach.
Answer: The rock will reach a height of approximately 6.14 meters from the point of release.
In modern radiotherapy, superconducting wire coils are used to create magnetic fields that focus particle beams in order to deliver the maximum dose of ionizing radiation to a tumor site while minimizing the destruction of healthy tissue. For what type of radiation would this technique NOT be useful?
Answer:Gamma Photons
Explanation: Gamma photons are photons that are parts of the electromagnetic radiation,they are of a very short wave length of less than about 0.01nanometer.,which means they travel with a very high speed and a very high energy of about 100,00volts. Gamma photons can KILL HEALTHY AND LIVING CELLS, that is why it is mainly used to KILL CANCEROUS CELLS/TUMORS but in modern radiology the use of superconducting wire coils are not employed or used to create magnetic fields for Gamma photons.
A spaceship is traveling toward Earth while giving off a constant radio signal with a wavelength of 1 meter (m). What will the signal look like to people on Earth?
Answer:
Less than 1 m
Explanation:
When objects are getting closer to each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the blue shift of waves. Here, the wavelength reduces.
In the opposite case the when objects are getting farther from each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the red shift. Here, the wavelength increases.
In this case the spaceship is getting close to Earth hence the wavelength will be lower than 1 m.
Explaining how a radio signal from a spaceship appears redshifted to observers on Earth.
Redshift: When a spaceship traveling towards Earth emits a radio signal with a wavelength of 1 meter, it will appear redshifted to people on Earth, meaning the wavelength will increase due to the Doppler effect caused by the relative motion between the spaceship and Earth.
Doppler Effect: This change in wavelength can help observers determine the speed and direction of the spaceship based on how much the signal is redshifted.
Frequency and Wavelength: As the signal travels towards Earth, its wavelength will change, affecting how it is perceived by observers on Earth in terms of frequency and color.
The wave model of light is needed to explain many of the phenomena discussed in this chapter. Which of the following can be understood WITHOUT appealing to the wave model?a. sharp-edged shadows b. double-slit interference c. thin-film interference d. single-slit diffraction
Answer:
the correct answer is A Sherp-edged shadows
Explanation:
The wave model describes the path of light as the propagation of a cosenoidal wave, in this case when two beams of light interact, they do so through the supervision of the cosines of each one.
In the lightning model, the light wave characteristics are not taken into account, this model is used for the so-called geometric optics, which explains many phenomena, image formation, reflection phenomena and shadow formation defined in the corners , since in this model the light is nine rectilinear from one point to another.
With this explanation we see that the correct answer is to
Final answer:
Sharp-edged shadows can be understood without the wave model of light, as they can be explained by the ray model. Double-slit interference, thin-film interference, and single-slit diffraction require the wave model to account for light's wave properties, such as diffraction and interference.
Explanation:
The phenomena that can be understood without appealing to the wave model of light is sharp-edged shadows. This is because sharp-edged shadows can be explained using the ray model of light, which treats light as straight lines that travel from a source and create shadows when they are obstructed by an object. The other phenomena listed, including double-slit interference, thin-film interference, and single-slit diffraction, require an understanding of the wave properties of light, such as diffraction and interference, to be properly understood.
According to Huygens's principle, diffraction is the bending of waves around the edges of an object or through an opening. Interference occurs when waves superimpose and either constructively or destructively interfere with each other, giving rise to the various patterns seen in these phenomena. The ray model of light is insufficient to explain these effects because it does not account for the wave-like behaviors of light, such as bending and superposition of waves.
A nerve signal is transmitted through a neuron when an excess of Na+ ions suddenly enters the axon, a long cylindrical part of the neuron. Axons are approximately 10.0 μm in diameter, and measurements show that about 5.60×1011 Na+ions per meter (each of charge +e) enter during this process. Although the axon is a long cylinder, the charge does not all enter everywhere at the same time. A plausible model would be a series of nearly point charges moving along the axon. Let us look at a 0.100 mm length of the axon and model it as a point charge.
1) What electric field (magnitude and direction) does the sudden influx of charge produce at the surface of the body if the axon is 5.00 cm below the skin? Note that distance to the skin is much greater than the length of the charged axon so that the axon charge is effectiely point-like.,
2) If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a 0.100 mm length of the axon? Answer in C
3) the field is directed away from the axon or the field is directed into the axon
The electric field produced at the surface of the body due to the sudden influx of charge in the axon can be calculated using Coulomb's law. If the charge that enters each meter of the axon is distributed uniformly along it, the total charge that enters a 0.100 mm length of the axon can be calculated. The electric field produced by the influx of Na+ ions is directed away from the axon.
Explanation:1) The electric field produced at the surface of the body due to the sudden influx of charge in the axon can be calculated using Coulomb's law. The formula for electric field is E = k * (Q / r^2), where k is the electrostatic constant, Q is the charge, and r is the distance. By substituting the given values, we can find the magnitude and direction of the electric field.
2) If the charge that enters each meter of the axon is distributed uniformly along it, we can calculate the total charge that enters a 0.100 mm length of the axon by multiplying the charge per meter by the length in meters.
3) Since the excess of Na+ ions enter the axon, the electric field produced by them will be directed away from the axon.
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A 0.5 kg ball is dropped from rest at a point 1.2m above the floor. The ball rebounds straight upward to a height of 0.7m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor.
Answer:
4.281 kgm/s upward
Explanation:
Impulse:This can be defined product of force and time. The S.I unit of impulse is Ns.
From Newton's second law of motion,
Impulse = Change in momentum.
I = mΔv....................... Equation 1.
Where m = mass of the ball, Δv = change in velocity of the ball
and Δv = v -u
Where u = velocity of the ball before it hit the floor, v = velocity of the ball after if hit the floor
I = m(v-u) -------------- Equation 2
But
the initial kinetic energy of the ball = potential energy at the initial height (1.2 m above)
1/2mu² = mgh₁
Where h₁ = initial height. or height of the ball before collision
making u the subject of the equation,
u = √(2gh₁)........................ Equation 3
Where h₁ = 1.2 m g = 9.81 m/s²
Substitute into equation 3
u = √(2×1.2×9.81)
u =√(23.544)
u = -4.852 m/s.
Note: u is negative because the ball was moving downward at the first instance.
Similarly,
v = √(2gh₂)............................. Equation 3
h₂ = height of the ball after collision
Given: h₂ = 0.7 m, g = 9.81 m/s²
Substitute into equation
v = √(2×9.81×0.7)
v = √13.734
v = 3.71 m/s.
Also given: m = 0.5 kg,
Substituting into equation 2
I = 0.5(3.71-(4.852)
I = 0.5(8.562)
I = 4.281 kgm/s. Upward.
Thus the impulse = 4.281 kgm/s upward
What is the sharpness of the light and the amount of voltage when you put the magnet through the lower number of coils first vs the higher number of coils
Answer:hjvuihi
Explanation:lk
Mark made a business trip of 214 miles. He averaged 53mph for the first part of the trip and 54mph for the second part. If the trip took 4 hours, how long did he travel at each rate?
Answer:
He travel for 2 h at the first part and 2 h for the second part.
Explanation:
given information:
business trip's distance, [tex]s_{tot}[/tex] = 214 miles
v₁ = 53 mph
v₂ = 54 mph
t₁ = t
t₂ = 4 - t
now lets find the distance of each speed
s₁ = v₁ t₁ = 53 t₁
s₂ = v₂ t₂ = 54 t₂
[tex]s_{tot}[/tex] = s₁ + s₂
214 = 53 t₁ + 54 t₂
214 = 53t + 54 (4-t)
214 = 53t + 216 - 54 t
t = 216 - 214
= 2 h
t₁ = t = 2 h
t₂ = 4 - t = 4 -2 = 2h
Intensive properties can be: Select the correct answer below:
1. physical properties
2. chemical properties
3. either physical or chemical properties
4. none of the above answer
Answer: The answer is 3 either physical or chemical properties
Explanation:
because all properties of matter are either physical or chemical
Hope this helps :)
Intensive properties, which are characteristic of a substance and do not depend on the amount of material, can be either physical or chemical properties. For example, boiling point and density are physical intensive properties, whereas flammability is a chemical intensive property.
Explanation:The correct answer is 3, intensive properties can be either physical or chemical properties. In chemistry, intensive properties are those that do not depend on the amount of the material present. They are characteristic of the substance and help us identify it. Examples of intensive properties include density, boiling point, or color. These can be either physical properties like boiling point and density, which do not alter the chemical composition of the substance, or chemical properties like flammability, which do involve a chemical reaction.
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Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 seconds. Compute the power developed by the student.
Answer:
140 watt
Explanation:
We are given that
Force applied by student ,F=28 N
Weight pulled by students=70 N
Displacement,s=15 m
Time=3 s
We have to find the power developed by the student.
Work done=w=[tex]F\times s[/tex]
Work done by the student=[tex]28\times 15=420 J[/tex]
Power=[tex]\frac{work\;done}{time}[/tex]
Using the formula
Power=[tex]\frac{420}{3}=140watt[/tex]
Hence, the power developed by the students=140 watt
To determine the power developed by the student pulling the weight, we use the equation P = Fv, with a force of 28.0 N and a velocity of 5.0 m/s, which yields a power of 140.0 Watts.
Explanation:To calculate the power developed by the student pulling the weight, we can use the formula for power when the force is applied along the direction of the displacement: P = Fv, where P is power, F is force, and v is velocity. Power is the rate at which work is done or energy is transferred over time. In this case, the student does work by applying a force to pull the weight across the tabletop.
The student pulls the weight for a distance of 15.0 meters in 3.0 seconds, which means the velocity (v) of the weight is v = distance/time = 15.0 m / 3.0 s = 5.0 m/s. We are given the force (F) as 28.0 Newtons. Therefore, the power (P) developed by the student is:
P = Fv = 28.0 N × 5.0 m/s = 140.0 Watts.
An airplane has been loaded in such a manner that the CG is located aft of the aft CG limit. One undesirable flight characteristic a pilot might experience with this airplane would be ______.a. a longer takeoff run.
b. difficulty in recovering from a stalled condition.
c. stalling at higher-than-normal airspeed.
Answer:
Option B is correct ( difficulty in recovering from a stalled condition.)
Explanation:
Option B is correct ( difficulty in recovering from a stalled condition.)
If you load airplane in such manners CG has changed then it will have huge impact on the longitudinal stability. Due to this airplane would face difficulty in recovering from a stalled condition.
Stall is the phenomena in which air resistance is increased on the wings which causes decrease in lift. So it is important to remain with in CG limit put by manufacturer to avoid stall condition.
One undesirable flight characteristic a pilot might experience with this plane is : ( B ) difficulty in recovering from a stalled condition.
CG Limit effect
When loading an aircraft the CG limit should not be exceeded as stated by the manufacturer, this is because when the aircraft is loaded above the limit the longitudinal stability of the aircraft will be affected because more air resistance will be exerted on the wings of the plane which leads to a condition known as stall
Hence we can conclude that one undesirable flight characteristic a pilot might experience with this plane is difficulty in recovering from a stalled condition.
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